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Òðàíñôîðìàòîðûí ¿íäñýí îéëãîëò.
       1ôàçûí òðàíñôîðìàòîðûí àæèëëàõ çàð÷èì. Òðàíñôîðìàòîðûí
                õîîñîí ÿâàëò, áîãèíî õîëáîëòûí òóðøèëò


                    Òðàíñôîðìàòîðûí àæèëëàõ çàð÷èì
      Öàõèëãààí     ýð÷èì     õ¿÷èéã   öàõèëãààí     ñòàíöààñ       õýðýãëýã÷   õ¿ðòýë
äàìæóóëàõàä íýã õ¿÷äëèéí ã¿éäëèéã äàâòàìæèéí ººð õ¿÷äëèéí ã¿éäýëä
õýä    õýäýí   óäàà     õóâèðãàäàã.    Ýíý    õóâèðãàëòûã   ºñãºõ    áó ó   áóóðóóëàõ
òðàíñôîðìàòîðò ã¿éöýòãýíý.
      Òðàíñôîðìàòîð íü öàõèëãààí òåõíèêèéí ãàí õóóäñóóäûã øàõàæ õèéñýí
ç¿ðõýâ÷ äýýð áàéðëàñàí õî¸ð áó ó õýä õýäýí îðîîìãîîñ òîãòîíî.
Çóðàã 1 äýýð W1 áà W2 îðîîäîñ á¿õèé õî¸ð îðîîìîãòîé òðàíñôîðìàòîðûã
ä¿ðñëýâ. Òðàíñôîðìàòîðûí íýãä¿ãýýð îðîîìãèéã U, õ¿÷äýëòýé ñ¿ëæýýíä
çàëãàõàä ýíý îðîîìãîîð I, ã¿éäýë ã¿éæ Ô ñîðîíçîí óðñãàë ¿¿ñãýíý. Ñîðîíçîí
óðñãàë ãàí ç¿ðõýâ÷ýýð áèò¿¿ð÷ õî¸ð îðîîìîãò öàõèëãààí õºäºëãºã÷ õ¿÷
èíäóêöëýãäýíý.




             Çóðàã 1 Ëåíöèéí õóóëü ¸ñîîð îðîîìãóóäàä èíäóêöëýãäýõ
             ÖÕÕ-íèé ýãøèí çóóðûí óòãà         ºãººä Ô = Ômsin wt ãýâýë

               å = wWÔmCoswt=EmCoswt
áîëíî. Ýíä (w=2ïf- ºíöºã äàâòàìæ, Åm-ÖÕÕ-íèé àìïëèòóä,
Òýãâýë îðîîìãóóäûï ÖÕÕ-í¿¿äèéí ¿éë÷ëýõ óòãóóä

                          E1 ì
                      E1 =     = 4.44 fW1Cm
                            2
                          E
                      E2 = 2 M = 4.44 fW2Cm
                             2

áàéíà.     Ýíäýýñ    óçýõýä   îðîîìãóóäàä     èíäóêöëýãäýõ    ÖÕÕ-¿¿äèéí        õýìæýý
      çºâõºí îðîîìãóóäûí îðîîäñûí òîîãîîð ÿëãàãäàõ àæýý.
      Òðàíñôîðìàòîðûí îðîîìãóóäûí ÖÕÕ-í¿¿äèéí õàðüöààã
òðàíñôîðìàòîðûí õóâèðãàõ (òðàíñôîðìàöëàõ)êîýÔÔèöèåíò ãýíý.
      E1
K=
      E2
Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åèéí õî¸ðäóãààð îðîîìãèéí çàëãóóð
äýýðõ U 20 õ¿÷äýë ýíý îðîîìîãò èíäóêöëýãäñýí Å2 ÖÕÕ-òýé òýíö¿¿ áàéõ áà Å,

ÖÕÕ ñ¿ëæýýíèé U 1 , õ¿÷äëýýñ º÷¿¿õýí áàãà ÿëãàãäàõ ó÷èð

                        E1 W1 V1
                  K=       =   =
                        E 2 W 2 V2
áàéíà.
Õýðýâ          òðàíñôîðìëòîðûí         õî¸ðäóãààð îðîîìîãò         ZE à÷àà      (õýðýãëýã÷)
çàëãàâàë ýíý îðîîìãîîð 12 ã¿éäýë ã¿éæ ZE õýðýãëýã÷ òýæýýãäýíý.


                  Òðàíñôîðìàòîðûí ñîðîíçîí õºäºëãºã÷ õ¿÷íèé òýãøèòãýë
      Ñóëæýýíä õîëáîãäñîí òðàíñôîðìàòîðûí õî¸ðäóãààð îðîîìîãò Zà à÷àà
çàëãàâàë Å2 ÖÕÕ-íèé ¿éë÷ëýëýýð ýíý îðîîìîãò 12 ã¿éäýë ¿¿ñíý. ¿¿íòýé íýãýí
çýðýã íýãäóãýýð îðîîìãèéí ã¿éäýë èõýñíý (ýíåðãè õàäãàëàãäàõ õóóëü åñîîð
òðàíñôîðìàòîð           à÷ààëàëä     ºã÷   áàéãàà   ó÷èð   òóóíä    õàðãàëçàõ     ýíåðãèéã
ñ¿ëæýýíýýñ àâíà).
      Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åä 10Ì1 ñîðîíçîí õºäºëãºã÷ õ¿÷
(ÑÕÕ) ¿¿ñíý Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åä òîãòîîãäñîí 1Ë » Å1
õàðüöàà ò¿¿íèé à÷ààëàëòàé ¿åä ÷ áàðàã ººð÷ëºãäºõã¿é. Èéì ó÷ðààñ Å1 ÖÕÕ-
òýé ïðîïîðöèîíàëü Ô ñîðîíçîí óðãñãàë òðàíñôîðìàòîðûí àæëûí á¿õ ãîðèìûí
¿åä òîãòìîë áàðüäàã. ¿¿íèéã òîîöîîä. òðàíñôïðìàòîðûí ¿íäñýí ñîðîíçîí
óðñãàë Ô òóóíèé à÷ààëàëòàé ¿åä íýãäóãýýð áà õî¸ðäóãààð îðîîìãóóäûí ÑÕÕ-
íèé õàìòûí ¿éë÷ëýëýýð, õàðèí õîîñîí ÿâàëòûí óåä çºâõºí íýãäóãýýð
îðîîìãèéí ÑÕÕ-ýýð áèé áîëîõ ó÷èð òðàíñôîðìàòîðûí ÑÕÕ-íèé òýãøèòãýëèéã
áè÷âýë:
       I1W1 + I W2 = I 0W1

Ýíý òýãøèòãýëýýñ ¿çýõýä I 1 » I            0   ó÷èð, õî¸ðäóãààð îðîîìãèéí I 1W1 ÑÕÕ
íýãä¿ãýýð îðîîìãèéíõòîé õàðüöóóëàõàä ñîðîíçîí ñóëðóóëàõ ¿éë÷ëýëòýé áàéãààã
õàðæ áîëíî.


     Òðàíñôîðìàòîðûí ¿íäñýí òýãøèòãýë¿¿ä áà âåêòîðóóäûí äèàãðàìì
Òðàíñôîðìàòîðûí íýãä¿ãýýð áà õî¸ðäóãààð õýëõýýíä (õ¿ðýýíä) ÊèðõãîÔûí
õî¸ðäóãààð õóóëèéã õýðýãëýâýë:
 &     & &
U1 = − E1 + I1Z1;
&       &    &
E2 = −U 2 + I 2 Z 2 ;
Òðàíñôîðìàòîðûí ñîðîíçîí õºäºëãºã÷ õ¿÷íèé òýãøèòãýëýýñ
&
& & I        & &
I1 = I 0 2 = I 0 − I 2
         k
Òðàíñôîðìàòîðûí à÷ààëàëòàé ¿åèéí âåêòîð –äèàãðàììûã 2-ð çóðàãò ä¿ðñëýâ.




                         Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ãîðèì
     Òðàíñôîðìàòîðûí ñîðîíçîí äàìæóóëàã÷ äàõü õóéëàðñàí ã¿éäýë áà ñîðîíçîí
õîöðîëîîð (ãèñòðåçèñ) áèé áîëîõ ñîðîíçîí àëäàãäëûã õîîñîí ÿâàëòûí òóðøëàãààð
òîäîðõîéëíî (çóðàã 3.).




Ñ¿ëæýýíèé õ¿÷äýë òîãòìîë áàéõ òîõèîëäîëä òðàíñôîðìàòîðûí àæëûí àëü ÷
ãîðèìûí ¿åä ñîðîíçîí óðñãàë ¿íäñýíäýý òîãòìîë áàéõ ó÷èð òðàíñôîðìàòîð
äàõü ñîðîíçîí àëäàãäàë à÷ààëëààñ ¿ë õàìààðíà. Èéìä õîîñîí ÿâàëòûí ¿åä
òðàíñôîðìàòîðûí ñ¿ëæýýíýýñ õýðýãëýæ áàéãàà ÷àäëûã ñîðîíçîí àëäàãäàë ãýæ
¿çýæ áîëíî. Õîîñîí ÿâàëòûí òóðøèëòûí U=U1H, I0 , Ðb Ôàçûí óòãóóäààð îðëóóëãûí
á¿ä¿¿â÷èéí ñîðîíçîí ñàëààíû ïàðàìåòðóóäûã òîäîðõîéëíî.
U1H
 Z 0 = Z1 + Z C ≈
                     I0
                    P0
 R0 = R1 + RC ≈          ;
                    I 02
 X 0 = X 1 + X C ≈ Z 02 − R02


                        Òðàíñôîðìàòîðûí áîãèíî õîëáîîíû òóðøèëò
Òðàíñôîðìàòîðûí õýâèéí ãîðèìä õàðãàëçàõ ò¿¿íèé öàõèëãààí àëäàãäëûã




òóðøèëòààð òîäîðõîéëíî (Çóðàã 4).
Ýíý òóðøèëòàíä òðàíñôîðìàòîðûí õî¸ðäóãààð îðîîìãèéã øóóä áîãèíî õîëáîæ,
àíõäàã÷ îðîîìãèéí çàëãóóð äýýð îðîîìãóóäààð ã¿éõ ã¿éäë¿¿ä õýâèéí óòãàòàé
òýíö¿¿ áàéõ õ¿÷äýë ºãíº. Ýíý õ¿÷äëèéã òðàíñôîðìàòîðûí áîãèíî õîëáîîíû
õ¿÷äýë ãýíý. Ò¿¿íèéã èõýâ÷ëýí õýâèéí õ¿÷äëèéí õóóëèàð èëýðõèéëíý


                                    Us
                             Uþ =       • 100 ٪
                                    V1H
     Òóðøèëòûí ¿ºä àíõäàã÷ îðîîìîãò çàëãàñàí âàòòìåòð (áó ó ãóðâàí Ôàçûí
òðàíñôîðìàòîðò                âàòòìåòðóóä)        òðàíñôîðìàòîðûí   õýâèéí   à÷ààëàëä
õàðãàëçàõ öàõèëãààí àëäàãäëûã çààíà.
      P =P
       σ  η

Áîãèíî çàëãààíû òóðøèëòûí ¿ºèéí ñîðîíçîí àëäàãäàë º÷¿¿õýí áàãà ó÷èð
ò¿¿íèéã òîîöîõã¿é áàéæ áîëíî.
Òóðøèëòûí P6, U6, U1h Ôàçûí óòãóóäûã àøèãëàí òðàíñôîðìàòîðûí áîãèíî
õîëáîîíû ïàðàìåòðóóäûã òîäîðõîéëíî.
                     U
 Zσ = Z 1 + Z 2 =       ;
                    U1H
                    Pσ
 Rσ = R1 + R2 =        ;
                    Iσ
 X σ = X 1 + X 2 = Zσ − Rσ
                    2    2

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Òðàíñôîðìàòîðûí àæèëëàõ çàð÷èì

  • 1. Òðàíñôîðìàòîðûí ¿íäñýí îéëãîëò. 1ôàçûí òðàíñôîðìàòîðûí àæèëëàõ çàð÷èì. Òðàíñôîðìàòîðûí õîîñîí ÿâàëò, áîãèíî õîëáîëòûí òóðøèëò Òðàíñôîðìàòîðûí àæèëëàõ çàð÷èì Öàõèëãààí ýð÷èì õ¿÷èéã öàõèëãààí ñòàíöààñ õýðýãëýã÷ õ¿ðòýë äàìæóóëàõàä íýã õ¿÷äëèéí ã¿éäëèéã äàâòàìæèéí ººð õ¿÷äëèéí ã¿éäýëä õýä õýäýí óäàà õóâèðãàäàã. Ýíý õóâèðãàëòûã ºñãºõ áó ó áóóðóóëàõ òðàíñôîðìàòîðò ã¿éöýòãýíý. Òðàíñôîðìàòîð íü öàõèëãààí òåõíèêèéí ãàí õóóäñóóäûã øàõàæ õèéñýí ç¿ðõýâ÷ äýýð áàéðëàñàí õî¸ð áó ó õýä õýäýí îðîîìãîîñ òîãòîíî. Çóðàã 1 äýýð W1 áà W2 îðîîäîñ á¿õèé õî¸ð îðîîìîãòîé òðàíñôîðìàòîðûã ä¿ðñëýâ. Òðàíñôîðìàòîðûí íýãä¿ãýýð îðîîìãèéã U, õ¿÷äýëòýé ñ¿ëæýýíä çàëãàõàä ýíý îðîîìãîîð I, ã¿éäýë ã¿éæ Ô ñîðîíçîí óðñãàë ¿¿ñãýíý. Ñîðîíçîí óðñãàë ãàí ç¿ðõýâ÷ýýð áèò¿¿ð÷ õî¸ð îðîîìîãò öàõèëãààí õºäºëãºã÷ õ¿÷ èíäóêöëýãäýíý. Çóðàã 1 Ëåíöèéí õóóëü ¸ñîîð îðîîìãóóäàä èíäóêöëýãäýõ ÖÕÕ-íèé ýãøèí çóóðûí óòãà ºãººä Ô = Ômsin wt ãýâýë å = wWÔmCoswt=EmCoswt áîëíî. Ýíä (w=2ïf- ºíöºã äàâòàìæ, Åm-ÖÕÕ-íèé àìïëèòóä, Òýãâýë îðîîìãóóäûï ÖÕÕ-í¿¿äèéí ¿éë÷ëýõ óòãóóä E1 ì E1 = = 4.44 fW1Cm 2 E E2 = 2 M = 4.44 fW2Cm 2 áàéíà. Ýíäýýñ óçýõýä îðîîìãóóäàä èíäóêöëýãäýõ ÖÕÕ-¿¿äèéí õýìæýý çºâõºí îðîîìãóóäûí îðîîäñûí òîîãîîð ÿëãàãäàõ àæýý. Òðàíñôîðìàòîðûí îðîîìãóóäûí ÖÕÕ-í¿¿äèéí õàðüöààã òðàíñôîðìàòîðûí õóâèðãàõ (òðàíñôîðìàöëàõ)êîýÔÔèöèåíò ãýíý. E1 K= E2
  • 2. Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åèéí õî¸ðäóãààð îðîîìãèéí çàëãóóð äýýðõ U 20 õ¿÷äýë ýíý îðîîìîãò èíäóêöëýãäñýí Å2 ÖÕÕ-òýé òýíö¿¿ áàéõ áà Å, ÖÕÕ ñ¿ëæýýíèé U 1 , õ¿÷äëýýñ º÷¿¿õýí áàãà ÿëãàãäàõ ó÷èð E1 W1 V1 K= = = E 2 W 2 V2 áàéíà. Õýðýâ òðàíñôîðìëòîðûí õî¸ðäóãààð îðîîìîãò ZE à÷àà (õýðýãëýã÷) çàëãàâàë ýíý îðîîìãîîð 12 ã¿éäýë ã¿éæ ZE õýðýãëýã÷ òýæýýãäýíý. Òðàíñôîðìàòîðûí ñîðîíçîí õºäºëãºã÷ õ¿÷íèé òýãøèòãýë Ñóëæýýíä õîëáîãäñîí òðàíñôîðìàòîðûí õî¸ðäóãààð îðîîìîãò Zà à÷àà çàëãàâàë Å2 ÖÕÕ-íèé ¿éë÷ëýëýýð ýíý îðîîìîãò 12 ã¿éäýë ¿¿ñíý. ¿¿íòýé íýãýí çýðýã íýãäóãýýð îðîîìãèéí ã¿éäýë èõýñíý (ýíåðãè õàäãàëàãäàõ õóóëü åñîîð òðàíñôîðìàòîð à÷ààëàëä ºã÷ áàéãàà ó÷èð òóóíä õàðãàëçàõ ýíåðãèéã ñ¿ëæýýíýýñ àâíà). Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åä 10Ì1 ñîðîíçîí õºäºëãºã÷ õ¿÷ (ÑÕÕ) ¿¿ñíý Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ¿åä òîãòîîãäñîí 1Ë » Å1 õàðüöàà ò¿¿íèé à÷ààëàëòàé ¿åä ÷ áàðàã ººð÷ëºãäºõã¿é. Èéì ó÷ðààñ Å1 ÖÕÕ- òýé ïðîïîðöèîíàëü Ô ñîðîíçîí óðãñãàë òðàíñôîðìàòîðûí àæëûí á¿õ ãîðèìûí ¿åä òîãòìîë áàðüäàã. ¿¿íèéã òîîöîîä. òðàíñôïðìàòîðûí ¿íäñýí ñîðîíçîí óðñãàë Ô òóóíèé à÷ààëàëòàé ¿åä íýãäóãýýð áà õî¸ðäóãààð îðîîìãóóäûí ÑÕÕ- íèé õàìòûí ¿éë÷ëýëýýð, õàðèí õîîñîí ÿâàëòûí óåä çºâõºí íýãäóãýýð îðîîìãèéí ÑÕÕ-ýýð áèé áîëîõ ó÷èð òðàíñôîðìàòîðûí ÑÕÕ-íèé òýãøèòãýëèéã áè÷âýë: I1W1 + I W2 = I 0W1 Ýíý òýãøèòãýëýýñ ¿çýõýä I 1 » I 0 ó÷èð, õî¸ðäóãààð îðîîìãèéí I 1W1 ÑÕÕ íýãä¿ãýýð îðîîìãèéíõòîé õàðüöóóëàõàä ñîðîíçîí ñóëðóóëàõ ¿éë÷ëýëòýé áàéãààã õàðæ áîëíî. Òðàíñôîðìàòîðûí ¿íäñýí òýãøèòãýë¿¿ä áà âåêòîðóóäûí äèàãðàìì Òðàíñôîðìàòîðûí íýãä¿ãýýð áà õî¸ðäóãààð õýëõýýíä (õ¿ðýýíä) ÊèðõãîÔûí õî¸ðäóãààð õóóëèéã õýðýãëýâýë: & & & U1 = − E1 + I1Z1; & & & E2 = −U 2 + I 2 Z 2 ; Òðàíñôîðìàòîðûí ñîðîíçîí õºäºëãºã÷ õ¿÷íèé òýãøèòãýëýýñ
  • 3. & & & I & & I1 = I 0 2 = I 0 − I 2 k Òðàíñôîðìàòîðûí à÷ààëàëòàé ¿åèéí âåêòîð –äèàãðàììûã 2-ð çóðàãò ä¿ðñëýâ. Òðàíñôîðìàòîðûí õîîñîí ÿâàëòûí ãîðèì Òðàíñôîðìàòîðûí ñîðîíçîí äàìæóóëàã÷ äàõü õóéëàðñàí ã¿éäýë áà ñîðîíçîí õîöðîëîîð (ãèñòðåçèñ) áèé áîëîõ ñîðîíçîí àëäàãäëûã õîîñîí ÿâàëòûí òóðøëàãààð òîäîðõîéëíî (çóðàã 3.). Ñ¿ëæýýíèé õ¿÷äýë òîãòìîë áàéõ òîõèîëäîëä òðàíñôîðìàòîðûí àæëûí àëü ÷ ãîðèìûí ¿åä ñîðîíçîí óðñãàë ¿íäñýíäýý òîãòìîë áàéõ ó÷èð òðàíñôîðìàòîð äàõü ñîðîíçîí àëäàãäàë à÷ààëëààñ ¿ë õàìààðíà. Èéìä õîîñîí ÿâàëòûí ¿åä òðàíñôîðìàòîðûí ñ¿ëæýýíýýñ õýðýãëýæ áàéãàà ÷àäëûã ñîðîíçîí àëäàãäàë ãýæ ¿çýæ áîëíî. Õîîñîí ÿâàëòûí òóðøèëòûí U=U1H, I0 , Ðb Ôàçûí óòãóóäààð îðëóóëãûí á¿ä¿¿â÷èéí ñîðîíçîí ñàëààíû ïàðàìåòðóóäûã òîäîðõîéëíî.
  • 4. U1H Z 0 = Z1 + Z C ≈ I0 P0 R0 = R1 + RC ≈ ; I 02 X 0 = X 1 + X C ≈ Z 02 − R02 Òðàíñôîðìàòîðûí áîãèíî õîëáîîíû òóðøèëò Òðàíñôîðìàòîðûí õýâèéí ãîðèìä õàðãàëçàõ ò¿¿íèé öàõèëãààí àëäàãäëûã òóðøèëòààð òîäîðõîéëíî (Çóðàã 4). Ýíý òóðøèëòàíä òðàíñôîðìàòîðûí õî¸ðäóãààð îðîîìãèéã øóóä áîãèíî õîëáîæ, àíõäàã÷ îðîîìãèéí çàëãóóð äýýð îðîîìãóóäààð ã¿éõ ã¿éäë¿¿ä õýâèéí óòãàòàé òýíö¿¿ áàéõ õ¿÷äýë ºãíº. Ýíý õ¿÷äëèéã òðàíñôîðìàòîðûí áîãèíî õîëáîîíû õ¿÷äýë ãýíý. Ò¿¿íèéã èõýâ÷ëýí õýâèéí õ¿÷äëèéí õóóëèàð èëýðõèéëíý Us Uþ = • 100 ٪ V1H Òóðøèëòûí ¿ºä àíõäàã÷ îðîîìîãò çàëãàñàí âàòòìåòð (áó ó ãóðâàí Ôàçûí òðàíñôîðìàòîðò âàòòìåòðóóä) òðàíñôîðìàòîðûí õýâèéí à÷ààëàëä õàðãàëçàõ öàõèëãààí àëäàãäëûã çààíà. P =P σ η Áîãèíî çàëãààíû òóðøèëòûí ¿ºèéí ñîðîíçîí àëäàãäàë º÷¿¿õýí áàãà ó÷èð ò¿¿íèéã òîîöîõã¿é áàéæ áîëíî. Òóðøèëòûí P6, U6, U1h Ôàçûí óòãóóäûã àøèãëàí òðàíñôîðìàòîðûí áîãèíî õîëáîîíû ïàðàìåòðóóäûã òîäîðõîéëíî. U Zσ = Z 1 + Z 2 = ; U1H Pσ Rσ = R1 + R2 = ; Iσ X σ = X 1 + X 2 = Zσ − Rσ 2 2