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Òðàíñôîðìàòîðûí îðëóóëãûí ñõåì, ¿íäñýí òýãøèòãýë,
             âåêòîðûí äèàãðàìì. Òóñãàé çîðèóëàëòûí òðàíñôîðìàòîð.
                Ãóðâàí ôàçûí Òðàíñôîðìàòîðûí á¿ëãèéí õîëáîëò


                           Òðàíñôîðìàòîðûí îðóóëãûí á¿ä¿¿â÷
       Òðàíñôîðìàòîð          íü       õîîðîíäîî       ñîðîíçîí   õîëáîîòîé      õî¸ð öàõèëãààí
õýëõýýíýýñ òîãòäîã. Ïðàêòèê äýýð ºãºãäñºí,                 U2 õ¿÷äëýýð ÿíç á¿ðèéí à÷ààëàëûí
¿åä U2 õ¿÷äýëèéã îëîõ øààðäëàãà ãàðäàã. Åð íü òðàíñôîðìàòîðò òîîöîî õèéõèéí
òóëä    ò¿¿íèé      îðëóóëãûí á¿ä¿¿â÷èéã               àøèãëàõ    íü   õàìãèéí    òîõèðîìæòîé.
Òðàíñôîðìàòîðûí            îðëóóëãûí á¿ðýí         á¿ä¿¿â÷èéã çóðàã 8.3à äýýð ¿ç¿¿ëýâ.
Òºäèéëºí      íàðèéâ÷ëàë øààðäàãäàõã¿é                 ïðàêòèê òîîöîîíä ò¿¿íèé îðëóóëãûí
õÿëáàð÷èëñàí á¿ä¿¿â÷èéã àøèãëàæ áîëíî.




                           Òðàíñôîðìàòîðûí õî¸ðäîã÷ õ¿÷äëèéí
                              ººð÷ëºëò áà ãàäààä õàìààðàìæ
Òðàíñôîðìàòîðûí õîîñîí ÿâàëò áà à÷ààëàëòàé ¿å¿äèéí õî¸ðäóãààð îðîîìãèéí
çàëãóóð äýýðõ õ¿÷äýë¿¿äèéè àðèÔìåòèê ÿëãàâðûã ò¿¿íèé õî¸ðäîã÷ Δ U ãýíý.
       ΔU = U 20 − U 2 .
Ïðàêòèêò õî¸ðäîã÷ õ¿÷äýëèéí ºâð÷ëºëòèéã òîäîðõîéëîõîä äàðààõ òîìü¸îã
àøèãëàäàã.
ΔU = βI1H ( Rσ Cosϕ 2 + X σ Sinϕ 2).
Òðàíñôîðìàòîðûí U2 õ¿÷äýëèéí I2 ã¿éäëýýñ õàìààðñàí õàìààðëûã ãàäààä
õàìààðàìæ ãýíý. 4-ð çóðàã äýýð 3 òºðëèéí øèíæ ÷àíàðòàé.
à÷ààëàëòàé ¿åèéí ãàäààä õàìààðàìæóóäûã õàìààðóóëàâ. Áàãòààìæ øèíæòýé
à÷ààëëûí ¿åä 11 2 õ¿÷äýë õîîñîí ÿâàëòûí ¿åèéí 11 20 õ¿÷äëýýñ èõ áàéæ áîëîõ
 ì.


                                                   1
Áîäëîãî      2.   Òðàíñôîðìàòîðûí      îðëóóëãûí     á¿ä¿¿â÷èéí      õºðâ¿¿ëýãäñýí
õî¸ðäóãààð
îðîîìãóóäûí R2'=1,66Îì; Õ2'=10,8Îì; I2'=1,44À: U2'=210Â          áîë òýäãýýðèéí
æèíõýíý óòãóóäûã îë. Ñ¿ëæýýíèé õ¿÷äýë 11,=220Â, íýã îðîîäîñò îíîãäîõ
õ¿÷äýë
11â=2Â/îðîîäîñ, õî¸ðäóãààð îðîîìãèéí îðîîäîñ W2=34B
Áîäîëò.     U2=UâW2=2õ34=68; ê=U,/U=220/68=3,24;
             R2=R2'/ê=1,66/3,24=0.51 Îì; Õ2=Õ2'/ê=10,8/3,24=3,330ì;
             I2=ÊI2'=3,24õ1,44=4,67À; U2=U2'/ê=210/3,24=64,8Â.


                      Ãóðâàí Ôàçûí òðàíñôîðìàòîð áà
                  òðàíñôîðìàòîðûí õîëáîëòûí á¿ëýã
    Ãóðâàí Ôàçûí ã¿éäëèéã õóâèðãàõûí òóëä ãóðâàí Ôàçûí òðàíñôîðìàòîð
õýðýãëýíý. Ãóðâàí Ôàçûí òðàíñôîðìàòîð íü íýã Ôàçûí ãóðâàí òðàíñôîðìàòîðûã
íýã åðåíõèé ñèñòåìä íýãòãýñýí õèéöòýé áàéíà. Ãîë òºëºâ ãóðâàí øèëáýò ãóðâàí
Ôàçûí òðàíñôîðìàòîð õýðýãëýíý (Çóðàã 8.5).
    Îðîîìãóóä îä (V) áó ó ãóðâàëæèí (À) õîëáîëòîîð õîëáîãäîíî. 8.5-ð çóðàã
äýýð õî¸ð îðîîìîã õîåóëàà îä õîëáîëòòîé áàéíà.




          Çóðàã 8.4                 Çóðàã 8.5
    Íýã   øèëáýíä      áàéðëàñàí   îðîîìãóóäàä   Ôàçààðàà    äàâõàöñàí     ÖÕÕ    -
óóä èíäóêöëýãäýíý. Èæèë íýðèéí ºíäºð áà íàì õ¿÷äëèéí îðîîìãóóäûí
øóãàìûí ÖÕÕ,
Æèøýý íü áà Ôàçààðàà äàâõöàõ áóþó ýñâýë 30˚, 60˚, 90˚………330˚ øèëæèëò áàéæ
áîëíî.
                                         2
ºíäºð áà íàì õ¿÷äëèéí îðîîìãóóäûí èæèë íýðòýé øóãàìûí ÖÕÕ - ¿¿äèéí
õîîðîíäîõ ºíöºã òðàíñôîðìàòðûí õîëáîëòûí á¿ëãèéã òîäîðõîéëíî. Ýíý ºíöºãèéí
õýìæýýã íýã íýãæèä 30 õàðãàëçàõ òîîãîîð òýìäýãëýíý. Æèøýý íü 8.6 ð çóðàã äýýð
¿ç¿¿ëñýí Y/∆ õîëáîëòòîé òðàíñôîðìàòðûí õîëáîëòûí á¿ëýã 150˚:30˚=5 áóþó Y/∆-5
8.7 ð çóðàã äýýð ¿ç¿¿ëñýí òðàíñôîðìàòðûí õîëáîëòûí á¿ëýã 180˚:30˚=6 áóþó Y/∆-6
áàéíà.




                                        3
Òðàíñôîðìàòîðûí àøèãò ¿éëèéí êîýÔÔèöèåíò
     Òóõàéí à÷ààëëûí ¿åä òðàíñôîðìàòîðûí õýðýãëýã÷èä ºã÷ áàéãàà Ð2 àøèãòàé
÷àäëûã ñ¿ëæýýíýýñ ò¿¿íèé àâ÷ áàéãàà Ð, àíõäàã÷ ÷àäàëä õàðüöóóëñàí η õàðüöààã
òðàíñôîðìàòîðûí àøèãò ¿éëèéí êîýÔÔèöèåíò ãýíý.
     P2
η=      ;
     P1




     Õó÷íèé òðàíñôîðìàòîðò îéðîëöîîãîîð ò!=0,95-0,99 áàéäàã ó÷èð òóóíèéã
òîäîðõîéëîõîä åíäåð íàðèéâ÷ëàë øààðäàãäàíà. Ýíý çîðèëãûã õàíãàõûí
òóëä ïðàêòèêò äàðààõ òîì ¸îã àøèãëàæ òîîöîî õèéäýã:




     P2       βS H Cosϕ3
η=      =                         ;
     P β S H Cosϕ 2 + P0 + β 2 Pδ
      1




Áîäëîãî .5. Õýâèéí Sí = 6,Çê ÷àäàëòàé òðàíñôîðìàòîðûí àëäàãäàë
õîîñîí ÿâàëòûí ¿åä Ðî = 26,5Âò, áîãèíî õîëáîëòûí ¿åä 128Âò áàéâ. ÷àäëûí
êîýÔÔèöèåíò ÑîçÔ2 = 0,8 áîë òðàíñôîðìàòîðûí õýâèéí à÷ààëàëòàé ¿åèéí
àøèãò ¿éëèéí êîýÔÔèöèåíòûã òîäîðõîéë.
        Áîäîëò. Õýâèéí à÷ààëàëòàé óåä β=1 òóë
             1 * 6300 * 0.8
η=                                  = 0.97
     1 • 6300 * 0.8 + 26.5 + 1 *128


                        8.10. Òðàíñôîðìàòîðûí õèéö áà òºðºë
     Õ¿÷íèé ãóðâàí Ôàçûí òðàíñôîðìàòîð èõýâ÷ëýí òîñîí õºðãºëòòýé õèéãääýã.
Îðîîìîã áàéðëàñàí ãóðâàí øèëáýò ãàí çóðõýâ÷ õóóäàñ ãàíãààð íÿãò òàãëàãäàíà
Ñàâ òðàíñôîðìàòîðûí òîñîîð ä¿¿ðãýãäýíý. ºíäºð áà íàì õ¿÷äëèéí
îðîîìãóóäûí         ãàðãàëãóóä        òðàíñôîðìàòîðûí   òàãàíä   áýõëýãäñýí   âààðàí
òóñãààðëàã÷ààð ãàäàãø ãàðíà. Àæèëëàãààíû ÿâöàä òðàíñôîðìàòîðûí òîñ
õàëæ , òýëýõ ó÷èð òðàíñôîðìàòîðûí äýýä òàã äýýð òðàíñôîðìàòîðòàé
õîîëîéãîîð õîëáîãäñîí òýëóóð ñàâ áàéðëàíà.
     Òðàíñôîðìàòîðûí òîñ òóñãààðëàõ áà õºðãºõ õî¸ð ¿¿ðýã ã¿éöýòãýíý.




                                              4

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Òðàíñôîðìàòîðûí îðóóëãûí á¿ä¿¿â÷

  • 1. Òðàíñôîðìàòîðûí îðëóóëãûí ñõåì, ¿íäñýí òýãøèòãýë, âåêòîðûí äèàãðàìì. Òóñãàé çîðèóëàëòûí òðàíñôîðìàòîð. Ãóðâàí ôàçûí Òðàíñôîðìàòîðûí á¿ëãèéí õîëáîëò Òðàíñôîðìàòîðûí îðóóëãûí á¿ä¿¿â÷ Òðàíñôîðìàòîð íü õîîðîíäîî ñîðîíçîí õîëáîîòîé õî¸ð öàõèëãààí õýëõýýíýýñ òîãòäîã. Ïðàêòèê äýýð ºãºãäñºí, U2 õ¿÷äëýýð ÿíç á¿ðèéí à÷ààëàëûí ¿åä U2 õ¿÷äýëèéã îëîõ øààðäëàãà ãàðäàã. Åð íü òðàíñôîðìàòîðò òîîöîî õèéõèéí òóëä ò¿¿íèé îðëóóëãûí á¿ä¿¿â÷èéã àøèãëàõ íü õàìãèéí òîõèðîìæòîé. Òðàíñôîðìàòîðûí îðëóóëãûí á¿ðýí á¿ä¿¿â÷èéã çóðàã 8.3à äýýð ¿ç¿¿ëýâ. Òºäèéëºí íàðèéâ÷ëàë øààðäàãäàõã¿é ïðàêòèê òîîöîîíä ò¿¿íèé îðëóóëãûí õÿëáàð÷èëñàí á¿ä¿¿â÷èéã àøèãëàæ áîëíî. Òðàíñôîðìàòîðûí õî¸ðäîã÷ õ¿÷äëèéí ººð÷ëºëò áà ãàäààä õàìààðàìæ Òðàíñôîðìàòîðûí õîîñîí ÿâàëò áà à÷ààëàëòàé ¿å¿äèéí õî¸ðäóãààð îðîîìãèéí çàëãóóð äýýðõ õ¿÷äýë¿¿äèéè àðèÔìåòèê ÿëãàâðûã ò¿¿íèé õî¸ðäîã÷ Δ U ãýíý. ΔU = U 20 − U 2 . Ïðàêòèêò õî¸ðäîã÷ õ¿÷äýëèéí ºâð÷ëºëòèéã òîäîðõîéëîõîä äàðààõ òîìü¸îã àøèãëàäàã. ΔU = βI1H ( Rσ Cosϕ 2 + X σ Sinϕ 2). Òðàíñôîðìàòîðûí U2 õ¿÷äýëèéí I2 ã¿éäëýýñ õàìààðñàí õàìààðëûã ãàäààä õàìààðàìæ ãýíý. 4-ð çóðàã äýýð 3 òºðëèéí øèíæ ÷àíàðòàé. à÷ààëàëòàé ¿åèéí ãàäààä õàìààðàìæóóäûã õàìààðóóëàâ. Áàãòààìæ øèíæòýé à÷ààëëûí ¿åä 11 2 õ¿÷äýë õîîñîí ÿâàëòûí ¿åèéí 11 20 õ¿÷äëýýñ èõ áàéæ áîëîõ ì. 1
  • 2. Áîäëîãî 2. Òðàíñôîðìàòîðûí îðëóóëãûí á¿ä¿¿â÷èéí õºðâ¿¿ëýãäñýí õî¸ðäóãààð îðîîìãóóäûí R2'=1,66Îì; Õ2'=10,8Îì; I2'=1,44À: U2'=210 áîë òýäãýýðèéí æèíõýíý óòãóóäûã îë. Ñ¿ëæýýíèé õ¿÷äýë 11,=220Â, íýã îðîîäîñò îíîãäîõ õ¿÷äýë 11â=2Â/îðîîäîñ, õî¸ðäóãààð îðîîìãèéí îðîîäîñ W2=34B Áîäîëò. U2=UâW2=2õ34=68; ê=U,/U=220/68=3,24; R2=R2'/ê=1,66/3,24=0.51 Îì; Õ2=Õ2'/ê=10,8/3,24=3,330ì; I2=ÊI2'=3,24õ1,44=4,67À; U2=U2'/ê=210/3,24=64,8Â. Ãóðâàí Ôàçûí òðàíñôîðìàòîð áà òðàíñôîðìàòîðûí õîëáîëòûí á¿ëýã Ãóðâàí Ôàçûí ã¿éäëèéã õóâèðãàõûí òóëä ãóðâàí Ôàçûí òðàíñôîðìàòîð õýðýãëýíý. Ãóðâàí Ôàçûí òðàíñôîðìàòîð íü íýã Ôàçûí ãóðâàí òðàíñôîðìàòîðûã íýã åðåíõèé ñèñòåìä íýãòãýñýí õèéöòýé áàéíà. Ãîë òºëºâ ãóðâàí øèëáýò ãóðâàí Ôàçûí òðàíñôîðìàòîð õýðýãëýíý (Çóðàã 8.5). Îðîîìãóóä îä (V) áó ó ãóðâàëæèí (À) õîëáîëòîîð õîëáîãäîíî. 8.5-ð çóðàã äýýð õî¸ð îðîîìîã õîåóëàà îä õîëáîëòòîé áàéíà. Çóðàã 8.4 Çóðàã 8.5 Íýã øèëáýíä áàéðëàñàí îðîîìãóóäàä Ôàçààðàà äàâõàöñàí ÖÕÕ - óóä èíäóêöëýãäýíý. Èæèë íýðèéí ºíäºð áà íàì õ¿÷äëèéí îðîîìãóóäûí øóãàìûí ÖÕÕ, Æèøýý íü áà Ôàçààðàà äàâõöàõ áóþó ýñâýë 30˚, 60˚, 90˚………330˚ øèëæèëò áàéæ áîëíî. 2
  • 3. ºíäºð áà íàì õ¿÷äëèéí îðîîìãóóäûí èæèë íýðòýé øóãàìûí ÖÕÕ - ¿¿äèéí õîîðîíäîõ ºíöºã òðàíñôîðìàòðûí õîëáîëòûí á¿ëãèéã òîäîðõîéëíî. Ýíý ºíöºãèéí õýìæýýã íýã íýãæèä 30 õàðãàëçàõ òîîãîîð òýìäýãëýíý. Æèøýý íü 8.6 ð çóðàã äýýð ¿ç¿¿ëñýí Y/∆ õîëáîëòòîé òðàíñôîðìàòðûí õîëáîëòûí á¿ëýã 150˚:30˚=5 áóþó Y/∆-5 8.7 ð çóðàã äýýð ¿ç¿¿ëñýí òðàíñôîðìàòðûí õîëáîëòûí á¿ëýã 180˚:30˚=6 áóþó Y/∆-6 áàéíà. 3
  • 4. Òðàíñôîðìàòîðûí àøèãò ¿éëèéí êîýÔÔèöèåíò Òóõàéí à÷ààëëûí ¿åä òðàíñôîðìàòîðûí õýðýãëýã÷èä ºã÷ áàéãàà Ð2 àøèãòàé ÷àäëûã ñ¿ëæýýíýýñ ò¿¿íèé àâ÷ áàéãàà Ð, àíõäàã÷ ÷àäàëä õàðüöóóëñàí η õàðüöààã òðàíñôîðìàòîðûí àøèãò ¿éëèéí êîýÔÔèöèåíò ãýíý. P2 η= ; P1 Õó÷íèé òðàíñôîðìàòîðò îéðîëöîîãîîð ò!=0,95-0,99 áàéäàã ó÷èð òóóíèéã òîäîðõîéëîõîä åíäåð íàðèéâ÷ëàë øààðäàãäàíà. Ýíý çîðèëãûã õàíãàõûí òóëä ïðàêòèêò äàðààõ òîì ¸îã àøèãëàæ òîîöîî õèéäýã: P2 βS H Cosϕ3 η= = ; P β S H Cosϕ 2 + P0 + β 2 Pδ 1 Áîäëîãî .5. Õýâèéí Sí = 6,Çê ÷àäàëòàé òðàíñôîðìàòîðûí àëäàãäàë õîîñîí ÿâàëòûí ¿åä Ðî = 26,5Âò, áîãèíî õîëáîëòûí ¿åä 128Âò áàéâ. ÷àäëûí êîýÔÔèöèåíò ÑîçÔ2 = 0,8 áîë òðàíñôîðìàòîðûí õýâèéí à÷ààëàëòàé ¿åèéí àøèãò ¿éëèéí êîýÔÔèöèåíòûã òîäîðõîéë. Áîäîëò. Õýâèéí à÷ààëàëòàé óåä β=1 òóë 1 * 6300 * 0.8 η= = 0.97 1 • 6300 * 0.8 + 26.5 + 1 *128 8.10. Òðàíñôîðìàòîðûí õèéö áà òºðºë Õ¿÷íèé ãóðâàí Ôàçûí òðàíñôîðìàòîð èõýâ÷ëýí òîñîí õºðãºëòòýé õèéãääýã. Îðîîìîã áàéðëàñàí ãóðâàí øèëáýò ãàí çóðõýâ÷ õóóäàñ ãàíãààð íÿãò òàãëàãäàíà Ñàâ òðàíñôîðìàòîðûí òîñîîð ä¿¿ðãýãäýíý. ºíäºð áà íàì õ¿÷äëèéí îðîîìãóóäûí ãàðãàëãóóä òðàíñôîðìàòîðûí òàãàíä áýõëýãäñýí âààðàí òóñãààðëàã÷ààð ãàäàãø ãàðíà. Àæèëëàãààíû ÿâöàä òðàíñôîðìàòîðûí òîñ õàëæ , òýëýõ ó÷èð òðàíñôîðìàòîðûí äýýä òàã äýýð òðàíñôîðìàòîðòàé õîîëîéãîîð õîëáîãäñîí òýëóóð ñàâ áàéðëàíà. Òðàíñôîðìàòîðûí òîñ òóñãààðëàõ áà õºðãºõ õî¸ð ¿¿ðýã ã¿éöýòãýíý. 4