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Physics Helpline
L K Satapathy
3D Geometry QA 10
Physics Helpline
L K Satapathy
3 D Geometry QA 10
Question : The equation of a plane passing through the line of intersection of the
planes x + 2y + 3z = 2 and x – y + z = 3 and at a distance of units from the
point ( 3 , 1 , – 1 ) is
( )5 11 17 ( ) 2 3 2 1 ( ) 3 ( ) 2 1 2a x y z b x y c x y z d x y           
Answer :
Equation of plane passing through the line of intersection of the planes
x + 2y + 3z = 2 and x – y + z = 3 is given by
( 2 3 2) ( 3) 0x y z x y z       
(1 ) (2 ) (3 ) 2 3 0 . . . (1)x y z           
Plane (1) is at a distance of units from the point ( 3 , 1 , – 1 )
2
3
2 2 2
3(1 ) (2 ) (3 ) 2 3 2
3(1 ) (2 ) (3 )
   
  
      
 
    
2
3
Physics Helpline
L K Satapathy
3 D Geometry QA 10
2 2 2
3 3 2 3 2 3 2
32 1 4 4 6 9
   
     
       
       
2 2
2 2 1
3 33 4 14 3 4 14
 
   
   
   
2 2 73 3 4 14 4 14 0
2
             
7(1) ( 2 3 2) ( 3) 0
2
x y z x y z        
2( 2 3 2) 7( 3) 0x y z x y z        
5 11 17 0x y z     
5 1 [ ]1 17x y z Ans   
Correct option = (a)
Physics Helpline
L K Satapathy
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3D Geometry QA 10

  • 1. Physics Helpline L K Satapathy 3D Geometry QA 10
  • 2. Physics Helpline L K Satapathy 3 D Geometry QA 10 Question : The equation of a plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x – y + z = 3 and at a distance of units from the point ( 3 , 1 , – 1 ) is ( )5 11 17 ( ) 2 3 2 1 ( ) 3 ( ) 2 1 2a x y z b x y c x y z d x y            Answer : Equation of plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x – y + z = 3 is given by ( 2 3 2) ( 3) 0x y z x y z        (1 ) (2 ) (3 ) 2 3 0 . . . (1)x y z            Plane (1) is at a distance of units from the point ( 3 , 1 , – 1 ) 2 3 2 2 2 3(1 ) (2 ) (3 ) 2 3 2 3(1 ) (2 ) (3 )                      2 3
  • 3. Physics Helpline L K Satapathy 3 D Geometry QA 10 2 2 2 3 3 2 3 2 3 2 32 1 4 4 6 9                           2 2 2 2 1 3 33 4 14 3 4 14               2 2 73 3 4 14 4 14 0 2               7(1) ( 2 3 2) ( 3) 0 2 x y z x y z         2( 2 3 2) 7( 3) 0x y z x y z         5 11 17 0x y z      5 1 [ ]1 17x y z Ans    Correct option = (a)
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