More Related Content Similar to Chapter 6 indices (20) Chapter 6 indices1. Module PMR
CHAPTER 6 : INDICES
NUMBERS IN INDEX FORM
Example:
Express in the form
of repeated
multiplication.
aaaaa ×××=4
1) 5
h 2) ( )3
h−
3)
2
e
d
4) 4
5 5) ( )3
1−
6)
4
3
2
7)
2
4
3
−
Example:
Write in index
notation.
h x h x h x h x h x h
=
8) g x g x g x g 9).
( ) ( ) ( )
( ) ( )dd
ddd
−×−
×−×−×− 10)
n
e
n
e
n
e
11) 7 x 7 x7 x 7 x 7 12)
(-11)(-11)(-11) 13)
7
2
7
2
7
2
7
2
14)
−
−
9
7
9
7
Example:
Evaluate
2222225
××××=
= 32
15) 3
10 16) ( )4
3−
17)
2
4
3
18)
3
4
1
−
19)
3
2
1
3
20) ( )3
4.0 21) ( )2
05.0−
LAWS OF INDICES
Indices 64
2. Module PMR
LAW 1 nmnm
aaa +
=×
Example:
Simplify
35
bb ×
35+
=b
8
b=
1) 62
gg × 2) 693
hhh ×× 3) ( ) ( )32
ee −×−
Example:
Simplify
43
22 ×
43
2 +
=
7
2=
4) 62
55 × 5) 683
666 ×× 6)( ) ( )45
33 −×−
Example:
Simplify
32
43 bb ×
( ) 32
43 +
×= b
5
12b=
7) 62
54 yy × 8) 43
310 ss ×
9)
45
8
3
2 kk ×
Example:
Simplify
7265
94 shsh ××
( ) 7675
94 ++
×= sh
1312
36 sh=
10) 232
37 mbm ××
11)
234
9
3
2
vvv ×× 12) papa ××− 443
36
LAW 2 nmnm
aaa −
=÷
Example:
Simplify
47
jj ÷
47−
= j
3
j=
1) 49
nn ÷
2) 2
5
a
a 3) 34
4 tt ÷
Example:
Simplify 45
÷ 42
= 45 - 2
= 43
4) 54
÷ 53
5) 2
4
7
7 6) 57
1010 −
÷
Example:
Simplify
35
412 aa ÷
35
4
12 −
= a
2
3a=
7) 45
540 gg ÷
8) 2
8
4
20
y
y 9) 510
2718 nn ÷
Example:
Simplify
10) 85
210 −
÷ uu
11) 2
4
2
18
−
w
w 12)
48
9
2
3 −
÷ mm
Indices 65
3. Module PMR
( )
9
36
36
36
2
2
6
12
612
z
z
z
zz
=
=
=
÷
+
−−
−
LAW 3 ( ) nmnm
aa ×
=
Example:
Simplify
( )
15
53
53
h
h
h
=
= ×
1) ( )24
k 2) ( ) 52 −
g 3) ( )27−
v
Example:
Simplify
( )
12
42
42
3
3
3
=
= ×
4) ( )35
4 5) ( ) 52
6
−
6) ( )35
7−
Example:
Simplify
( )
2015
5453
543
2
2
2
m
m
m
=
= ××
7) ( )234
ed 8) ( ) 423
52
−
9) ( )264
3 −
g
LAW 4 n
n
a
a
1
=−
Example:
Simplify
r
l −
r
l
1
=
1) k
c−
2) p
m−
3 3) t
dv−
Example:
Simplify
3
2−
= 3
2
1
4) 3
4−
5) 1
7−
6) 2
3−
Indices 66
4. Module PMR
8
1
=
Example:
Simplify
5
8
4
1
4 ×
= 58
44 −
×
= ( )58
4 −+
= 58
4 −
= 3
4
= 64
7) 2
3
8
1
8 × 8) ( )22
3
10
10
1
× 9)
( )32
8 1
m
m ×
LAW 5 10
=a
Example:
120
=
1)
0
3
2
=
2) ( )0
3− = 3) ( )0
5.4 =
LAW 6 FRACTIONAL INDICES
Example:
Rewrite by using
the root and power
symbol
9
3
2
3
9 =
1) 3
1
64 2) 5
1
32 3) 3
2
8
Example:
Write in the form of
index
53
22
3
5 =
1) 3
8 2)
3
5
10 3) 16
Example:
Evaluate
1) 3
1
27 2) 5
2
32 3) 4
3
81
Indices 67
5. Module PMR
( )
2
2
4
2
1
2
2
1
=
=
Example:
Simplify
2
3
6
3
2
3
4
3
2
3
4
9
9
9
99
=
=
=
×
+
1) 3
5
3
2
1010 ÷ 2) ( ) 42
1
6
gg × 3) ( ) 32
1
4 −−
÷ pp
COMBINATION OF LAWS
Example:
Simplify
2
2
2
2
0
936
936
=
=
=
÷×
−+
b
b
bbb
1) 317 −
×÷ ggg
2) 4
59
m
mm × 3) 435
232 ggg ÷×
Simplify
( )
33
3612
31622
3123
4
4
2
2
yx
yx
yxyx
yxxy
=
=
÷=
÷
−+
−
−
4) ( ) 132
2 −
÷xyyx 5) ( ) 2424
3 −−
× yxxy 6) ( ) yxxy 322
÷
Evaluate
2
1
2
1
8
1
3
1
3
3
1
=
=
7)
2
1
25
1
8)
2
1
9
4
9)
3
1
27
8
Evaluate 10) 322
284 ÷× 11) ( )327
93 ×−
12) ( ) 5
1
2
1
4
3242 ÷×
Indices 68
6. Module PMR
( )
( )
32
1
2
22
22
42
5
49
229
233
=
=
×=
×=
×
−
−
−
−
13) 5
3
4
1
3
1
32168 ×× 14) 23
2
327 −
÷
15) ( ) 223
999 −
×÷ 16) ( ) 506
rr ÷
17)
( )
2
252
4
4
ab
ba 18) ( ) 2324
666 ÷×−
19) ( ) 523
xx ÷
−−
20) Given .2166
2
=
−x
Find x .
21) Given that .1255 3
=−x
Find x .
22) If
64
13
=−
y . Find y .
Common Errors
Indices 69
7. Module PMR
Errors Correct Steps
1. 22
22 −
×
= ( )22
2 −+
= 0
2
= 2
1. 22
22 −
×
= ( )22
2 −+
= 0
2
= 1
2. 24
55 −
÷
= 24
5 −
= 2
5
2. 24
55 −
÷
= ( )24
5 −−
= 24
5 +
= 6
5
3. 4
52
−
×
k
kk
= 452 −+
k
= 3
k
3. 4
52
−
×
k
kk
= )4(52 −−+
k
= 47+
k
= 11
k
Questions based on PMR Format
1. Evaluate
3
1
2
3
16
−
2. Evaluate ( )2
3
284 −
cba
3. Find the value of 3
2
5
3
832
−
÷
4. Given that 2
1
3
4
2
8127 ÷=k .Find the value of .k
Indices 70
8. Module PMR
5. If 34347
=× −
aa , find the value of .a
6. Simplify 6
5
2
1
23 pp ×
7. Simplify 27
5
33
3
−
−
×
8. Simplify 372
4
−
×× aab
a
9. Simplify
( ) 521
432
prq
rqp
×
××
−
−
10. Simplify 34
25
−
−
×
××
km
mkk
PMR past year questions
2004
1. Given that 162 2
=−x
, calculate the value of x .
( 2 marks )
Indices 71
9. Module PMR
2. Simplify ( ) ( ) 953242
2 kmkmk ÷× .
( 3 marks )
2005
1. Evaluate
3
2
2
1
2
1
8
123 ×
.
( 3 marks )
2. Given ( )( ),333 212 xx
=−
calculate the value of x .
( 2 marks )
2006
1. Simplify 2
4
−
×
k
kk
.
( 2 marks )
2. Find the value of 2
3
2
1
2
2183 ×× .
( 3 marks )
Indices 72
10. Module PMR
2007
1. a). Find the value of 2
1
2
3
55 ÷ .
b). Simplify ( ) 234
hhg × .
( 3 marks )
2008
1. Simplify 4
52
m
mm ×−
.
( 2 marks )
2. Find the value of
a). 13
22 −
÷
b). ( )3
1
63
32 ×−
( 3 marks )
CHAPTER 6 : INDICES
ANSWERS
1. hhhhh ×××× 2. ( ) ( ) ( )hhh −×−×−
3.
×
e
d
e
d 4. 5555 ×××
Indices 73
11. Module PMR
5. ( ) ( ) ( )111 −×−×−
6.
×
×
×
3
2
3
2
3
2
3
2
7.
−×
−
4
3
4
3 8. 4
g
9. ( )5
d−
10.
3
n
e 11. 5
7 12. ( )3
11−
13.
4
7
2
14.
2
9
7
−
15. 1000 16. 81
17.
16
9
18.
64
1
− 19.
8
343
or
8
7
42
20. 0.064
21. 0.0025
LAW 1
1. 8
g 2. 18
h 3. ( )5
e− 4. 8
5
5. 17
6 6. ( )9
3− 7. 8
20y 8. 7
30s
9.
9
4
3
k 10. 34
21 bm 11. ( )35
7−
12. 57
18 pa−
LAW 2
1. 5
n 2. 3
a 3. t4 4. 5
5. 72
6. 12
10 7. g8 8. 6
5y
9.
5
3
2
n
10. 5 u13
11. 6
9w
12.
12
2
27
m
LAW 3
1. 8
k 2. 10−
g 3. 14−
v
4. 15
4 5. 10
6−
6. 15
7−
7. 68
ed 8. 812
52 −−
9. 128
3 −
g
LAW 4
1. k
c
1
2. p
m
3
3. t
v
d
4. 3
4
1
5.
7
1
6. 2
3
1
7. 8 8. 10 9. 2
m
LAW 5
1. 1 2. 1 3. 1
LAW 6
1. 3
64 2. 5
32 3.
2
3
8
1. 3
1
8 2. 5
3
10 3. 2
1
16
1. 3 2. 4 3. 27
4.
10
1 5. 7
g 6. p
COMBINATION OF LAWS
Indices 74
12. Module PMR
1. 3
g 2. 10
m 3. 4
3g 4. 45
8 yx
5. 62
9 yx−
6. 31
yx−
7.
5
1
5 1
=−
8.
3
2
9.
3
2 10. 128 11. 243 12. 8
13. 32 14. 81 15. 81 16. 5−
r
17. 83
4 ba 18. 1 19. x 20. 5=x
21. 6 22. 4
Questions Based on PMR Format
1.
4
1 2. 3126 −
cba 3. 32 4. 3
5. 7 6. 3
4
6 p 7. 10
3
1 8. 2−
b
9. qr
p
10. 2
1
km
PMR QUESTIONS
YEAR SOLUTION AND MARK SCHEME
SUB
MARK
FULL
MARK
2004 42
22 =−x
x or 42 =−x
6=x
1
1 2
2004 956844
2 kmkkm ÷×
96854
16 −+−
km
51
16 km −
1
1
1 3
2005
( )
( )
2
3
4
6
2
6
2
6
8
36
2
1
3
2
3
2
1
2
3
2
2
1
1
1
1
3
2005 212 +=− xx
122 +=− xx
3=x
1
1 2
Indices 75
13. Module PMR
2006
7
)2(14
k
k −−+
1
1 2
2006
( )
( ) 2
1
2
1
2
1
22
2
3
2
1
2
2233
2293
×××
×××
108
427
23 23
×
×
1
1
1
3
2007 a) 1
55 or
b) 123
3123
gh
horgh
1
1
1
3
2008
m
orm
mormormorm
12
45263
−
−+−−
1
1
2
2008 a) 1624
=
b) =
××−
× 3
1
6
3
1
3
32
4
9
9
2
1
32 21
=×
×−
1
1
1
3
Indices 76