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Exponential and Logarithmic
Equations
Chapter 4 Inverse, Exponential, and Logarithmic
Functions
Concepts and Objectives
⚫ Exponential and Logarithmic Equations
⚫ Identify e and ln x.
⚫ Set up and solve exponential and logarithmic
equations.
e
⚫ Suppose that $1 is invested at 100% interest per year,
compounded n times per year.
⚫ According to the formula, the compound amount at
the end of 1 year will be
⚫ As n increases, the value of A gets closer to some fixed
number, which is called e.
⚫ e is approximately 2.718281828.
⚫ Blind Date
1
1
n
A
n
 
= + 
 
Natural Logarithms
⚫ Logarithms with base e are called natural logarithms,
since they occur in the life sciences and economics in
natural situations that involve growth and decay.
⚫ The base e logarithm of x is written ln x.
⚫ Therefore, e and ln x are inverse functions.
ln
lnx x
e e x= =
Exponential Equations
⚫ Example: Solve . Round to the nearest
thousandth.
If x > 0, y > 0, a > 0, and a  1, then
x = y if and only if logax = logay
− +
=2 1 2
3 0.4x x
− = +2 log3 log3 log0.4 2log0.4x x
Exponential Equations
⚫ Example: Solve . Round to the nearest
thousandth.
If x > 0, y > 0, a > 0, and a  1, then
x = y if and only if logax = logay
− +
=2 1 2
3 0.4x x
− +
=2 1 2
log3 log0.4x x
( ) ( )=− +2 1 2log3 log0.4x x
− = +log0.l 4og32 log3 2log0.4x x
− = +log0.42 log3 2log g0.4 lo 3x x
( )− = +2log3 log0.4 2log0.4 log3x
+
=  −
−
2log0.4 log3
0.236
2log3 log0.4
x
− = +2 log3 log0.4 2log0.4 log3x x
Properties of Logs, Revisited
⚫ You could also finish this as
+
=
−
2log0.4 log3
2log3 log0.4
x
+
=
−
2
2
log0.4 log3
log3 log0.4
( )=
 
 
 
log 0.16 3
9
log
0.4
=
log0.48
log22.5
This is an
exact answer.
Solving a Logarithmic Equation
⚫ Example: Solve ( ) ( )log 6 log 2 logx x x+ − + =
Solving a Logarithmic Equation
⚫ Example: Solve ( ) ( )log 6 log 2 logx x x+ − + =
6
log log
2
x
x
x
+
=
+
6
2
x
x
x
+
=
+
( )6 2x x x+ = +
2
6 2x x x+ = +
2
6 0x x+ − =
( )( )3 2 0x x+ − =
3, 2x = −
= + −2
0 6x x
If we plug in –3, x+2
is negative. We can’t
take the log of a
negative number, so
our answer is 2.
Solving a Base e Equation
⚫ Example: Solve and round your answer to the
nearest thousandth.
2
200x
e =
Solving a Base e Equation
⚫ Example: Solve and round your answer to the
nearest thousandth.
2
200x
e =
2
ln ln200x
e =
2
ln200x =
ln200x = 
2.302x  
=
2
l 00ln n2x
e
Solving a Base e Equation
⚫ Example: Solve ( )ln
ln ln 3 ln2x
e x− − =
Solving a Base e Equation
⚫ Example: Solve ( )ln
ln ln 3 ln2x
e x− − =
( )− − =ln ln 3 ln2xx
( )− − =ln
ln ln 3 ln2x
xe
ln ln2
3
x
x
=
−
2
3
x
x
=
−
2 6x x= −
6 x=
( )= −2 3x x
Classwork
⚫ College Algebra
⚫ Page 464: 12-20 (even), page 442: 28, 30, 60-70
(even), page 429: 80-84 (even)

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Solving Exponential and Logarithmic Equations

  • 1. Exponential and Logarithmic Equations Chapter 4 Inverse, Exponential, and Logarithmic Functions
  • 2. Concepts and Objectives ⚫ Exponential and Logarithmic Equations ⚫ Identify e and ln x. ⚫ Set up and solve exponential and logarithmic equations.
  • 3. e ⚫ Suppose that $1 is invested at 100% interest per year, compounded n times per year. ⚫ According to the formula, the compound amount at the end of 1 year will be ⚫ As n increases, the value of A gets closer to some fixed number, which is called e. ⚫ e is approximately 2.718281828. ⚫ Blind Date 1 1 n A n   = +   
  • 4. Natural Logarithms ⚫ Logarithms with base e are called natural logarithms, since they occur in the life sciences and economics in natural situations that involve growth and decay. ⚫ The base e logarithm of x is written ln x. ⚫ Therefore, e and ln x are inverse functions. ln lnx x e e x= =
  • 5. Exponential Equations ⚫ Example: Solve . Round to the nearest thousandth. If x > 0, y > 0, a > 0, and a  1, then x = y if and only if logax = logay − + =2 1 2 3 0.4x x
  • 6. − = +2 log3 log3 log0.4 2log0.4x x Exponential Equations ⚫ Example: Solve . Round to the nearest thousandth. If x > 0, y > 0, a > 0, and a  1, then x = y if and only if logax = logay − + =2 1 2 3 0.4x x − + =2 1 2 log3 log0.4x x ( ) ( )=− +2 1 2log3 log0.4x x − = +log0.l 4og32 log3 2log0.4x x − = +log0.42 log3 2log g0.4 lo 3x x ( )− = +2log3 log0.4 2log0.4 log3x + =  − − 2log0.4 log3 0.236 2log3 log0.4 x − = +2 log3 log0.4 2log0.4 log3x x
  • 7. Properties of Logs, Revisited ⚫ You could also finish this as + = − 2log0.4 log3 2log3 log0.4 x + = − 2 2 log0.4 log3 log3 log0.4 ( )=       log 0.16 3 9 log 0.4 = log0.48 log22.5 This is an exact answer.
  • 8. Solving a Logarithmic Equation ⚫ Example: Solve ( ) ( )log 6 log 2 logx x x+ − + =
  • 9. Solving a Logarithmic Equation ⚫ Example: Solve ( ) ( )log 6 log 2 logx x x+ − + = 6 log log 2 x x x + = + 6 2 x x x + = + ( )6 2x x x+ = + 2 6 2x x x+ = + 2 6 0x x+ − = ( )( )3 2 0x x+ − = 3, 2x = − = + −2 0 6x x If we plug in –3, x+2 is negative. We can’t take the log of a negative number, so our answer is 2.
  • 10. Solving a Base e Equation ⚫ Example: Solve and round your answer to the nearest thousandth. 2 200x e =
  • 11. Solving a Base e Equation ⚫ Example: Solve and round your answer to the nearest thousandth. 2 200x e = 2 ln ln200x e = 2 ln200x = ln200x =  2.302x   = 2 l 00ln n2x e
  • 12. Solving a Base e Equation ⚫ Example: Solve ( )ln ln ln 3 ln2x e x− − =
  • 13. Solving a Base e Equation ⚫ Example: Solve ( )ln ln ln 3 ln2x e x− − = ( )− − =ln ln 3 ln2xx ( )− − =ln ln ln 3 ln2x xe ln ln2 3 x x = − 2 3 x x = − 2 6x x= − 6 x= ( )= −2 3x x
  • 14. Classwork ⚫ College Algebra ⚫ Page 464: 12-20 (even), page 442: 28, 30, 60-70 (even), page 429: 80-84 (even)