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9.6 Binomial Theorem
Chapter 9 Sequences, Probability, and Counting
Theory
Concepts and Objectives
⚫ The objectives for this section are
⚫ Apply the Binomial Theorem.
Binomial Series
⚫ A binomial squared becomes
⚫ A binomial cubed becomes
( )
+ = + +
2 2 2
2
a b a ab b
( ) ( )( )
+ = + +
3 2
a b a b a b
( )( )
= + + +
2 2
2
a b a ab b
= + + + + +
2 2
3 3
2 2
2 2
a b a b ab
a b b
a
= + + +
3 2 2 3
3 3
a a b ab b
Binomial Series (cont.)
⚫ As you may recall from Algebra II, the coefficients
correspond to rows from Pascal’s Triangle
0 1
1 1 1
2 1 2 1
3 1 3 3 1
4 1 4 6 4 1
5 1 5 10 10 5 1
6 1 6 15 20 15 6 1
Binomial Series (cont.)
⚫ Example: Expand ( )
+
5
2 1
x
Binomial Series (cont.)
⚫ Example: Expand
a = 2x and b = 1; the exponents begin and end at 5
(a goes down while b goes up). Looking at row 5 on the
triangle, our coefficients are 1, 5, 10, 10, 5, 1, so we write
our expression as follows:
(Notice that the exponents apply to the entire term of the
binomial, not just the variable.)
( )
+
5
2 1
x
( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( )
+ + + + +
5 4 3 2 2 3 4 5
5 10 1
1 1 1
2 2 2 1
2 1
5 2
0
x x x x x
= + + + + +
5 4 3 2
32 80 80 40 10 1
x x x x x
+ + + + +
5 4 3 2 2 3 4 5
5 10 10 5
a a a a a
b b b b b
Binomial Series (cont.)
⚫ Consider the binomial series :
If we multiply the coefficient of a term by a fraction
consisting of the exponent of a over the term number,
we get the coefficient of the next number.
( )
+
7
a b
= + + + + + + +
7 6 5 2 4 3 3 4 2 5 6 7
7 21 35 35 21 7
a a b a b a b a b a b ab b
8
7
6
5
4
3
2
1
   
= =
   
   
exp. 7
coeff. 1 7,
term # 1
 
=
 
 
6
7 21,
2
 
 
 
5
21 =35, ...
3
Binomial Series (cont.)
⚫ Now let’s see what happens to if we don’t
simplify the fractions as we calculate them:
( )
+
8
a b
1
2
3
4
5
8
a
7
8
1
a b
6 2
8 7
1 2
a b
5 3
8 7 6
1 2 3
a b
4 4
8 7 6 5
1 2 3 4
a b
Do you see the pattern?
What is it?
Binomial Series (cont.)
⚫ The coefficients of a binomial series can be written as
factorials. For example, let’s look at the coefficient for
the fourth term:
=
8 7 6 8 7 6
1 2 3 1 2 3
=
8 7 6 5!
1 2 3 5!
=
8!
3! 5!
Binomial Series (cont.)
⚫ Looking back at the original expression:
Notice how the numbers in the coefficient expression
are found elsewhere in the expression.
⚫ 8 is the value of the exponent to which (a + b) is
raised.
⚫ 5 is the value of a’s exponent and 3 is the value of b’s.
⚫ The exponent of b is always one less than the term
number (4).
( )
+ = + +
5 3
8 !
... ...
! !
5
3
8
a b a b
Binomial Theorem
⚫ The formula for the term containing br of (a + b)n,
therefore, is
or nCr
⚫ Example: Find the term containing y6 of
( )
−
−
!
! !
n r r
n
a b
r n r
n
r
 
=  
 
( )
10
8
x y
−
Binomial Theorem (cont.)
⚫ The formula for the term containing br of (a + b)n,
therefore, is
or nCr
⚫ Example: Find the term containing y6 of
( )
−
−
!
! !
n r r
n
a b
r n r
n
r
 
=  
 
( )
10
8
x y
−
( )( ) ( ) ( )
6
10 6 4 6
10
8 210 262144
6
x y x y
−
 
− =
 
  4 6
55,050,240x y
=
Binomial Theorem (cont.)
⚫ Example: Find the term in which contains f 9.
( )
15
e f
−
Binomial Theorem (cont.)
⚫ Example: Find the term in which contains f 9.
Since n = 15, n – r = 15 – 9 = 6. Therefore the term is
(When dealing with negative terms such as f, recall that
even exponents will produce positive terms and odd
exponents will produce negative terms.)
( )
15
e f
−
( )
9
6 6 9
15
5005
6
e f e f
 
− = −
 
 
Binomial Theorem (cont.)
⚫ Similarly, the kth term of binomial expansion of
is found by realizing that the exponent of b will be k – 1,
which gives us the formula:
(replace r with k – 1)
( )
n
a b
+
( )
1 1
1
n k k
n
a b
k
− − −
 
 
−
 
Binomial Theorem (cont.)
⚫ Example: Find the 4th term of ( )
12
2c d
−
Binomial Theorem (cont.)
⚫ Example: Find the 4th term of
n = 12, k = 4, which means that k – 1 = 3
( )
12
2c d
−
( ) ( ) ( )( )
9 3 9 3
12
2 220 512
3
c d c d
 
− = −
 
 
9 3
112,640c d
= −
Binomial Theorem
⚫ Your calculator can also find the coefficient:
4th term of
n = 12, k – 1 = 3, n – (k –1) = 9
2l9¢b5312,3·
( )
12
2c d
−
Binomial Theorem (cont.)
⚫ Desmos can also find the coefficient using a function
called nCr(n, r):
4th term of
n = 12, k – 1 = 3, n – (k –1) = 9
( )
12
2c d
−
( ) ( )
9 3
12
2
3
c d
 
−
 
 
Binomial Theorem Practice
⚫ Example: Expand ( )
−
5
2 3
x
Binomial Theorem Practice
⚫ Example: Expand ( )
−
5
2 3
x
( ) ( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ( )
5 0 4 1 3 2
2 3 1 4 0 5
5 5 5
2 3 2 3 2 3
0 1 2
5 5 5
2 3 2 3 2 3
3 4 5
x x x
x x x
     
= − + − + −
     
     
     
+ − + − + −
     
     
Binomial Theorem Practice
⚫ Example: Expand ( )
−
5
2 3
x
( ) ( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ( )
5 0 4 1 3 2
2 3 1 4 0 5
5 5 5
2 3 2 3 2 3
0 1 2
5 5 5
2 3 2 3 2 3
3 4 5
x x x
x x x
     
= − + − + −
     
     
     
+ − + − + −
     
     
( )( )( ) ( )( )( ) ( )( )( )
( )( )( ) ( )( )( ) ( )( )( )
5 4 3
2
1 32 1 5 16 3 10 8 9
10 4 27 5 2 81 1 1 243
x x x
x x
= + − +
+ − + + −
Binomial Theorem Practice
⚫ Example: Expand ( )
−
5
2 3
x
( ) ( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( ) ( ) ( )
5 0 4 1 3 2
2 3 1 4 0 5
5 5 5
2 3 2 3 2 3
0 1 2
5 5 5
2 3 2 3 2 3
3 4 5
x x x
x x x
     
= − + − + −
     
     
     
+ − + − + −
     
     
( )( )( ) ( )( )( ) ( )( )( )
( )( )( ) ( )( )( ) ( )( )( )
5 4 3
2
1 32 1 5 16 3 10 8 9
10 4 27 5 2 81 1 1 243
x x x
x x
= + − +
+ − + + −
5 4 3 2
32 240 720 1080 810 243
x x x x x
= − + − + −
Classwork
⚫ College Algebra 2e
⚫ 9.6: 8-36 (4); 9.5: 36-52 (4); 9.4: 46-62 (even)
⚫ 9.6 Classwork Check
⚫ Quiz 9.5

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9.6 Binomial Theorem

  • 1. 9.6 Binomial Theorem Chapter 9 Sequences, Probability, and Counting Theory
  • 2. Concepts and Objectives ⚫ The objectives for this section are ⚫ Apply the Binomial Theorem.
  • 3. Binomial Series ⚫ A binomial squared becomes ⚫ A binomial cubed becomes ( ) + = + + 2 2 2 2 a b a ab b ( ) ( )( ) + = + + 3 2 a b a b a b ( )( ) = + + + 2 2 2 a b a ab b = + + + + + 2 2 3 3 2 2 2 2 a b a b ab a b b a = + + + 3 2 2 3 3 3 a a b ab b
  • 4. Binomial Series (cont.) ⚫ As you may recall from Algebra II, the coefficients correspond to rows from Pascal’s Triangle 0 1 1 1 1 2 1 2 1 3 1 3 3 1 4 1 4 6 4 1 5 1 5 10 10 5 1 6 1 6 15 20 15 6 1
  • 5. Binomial Series (cont.) ⚫ Example: Expand ( ) + 5 2 1 x
  • 6. Binomial Series (cont.) ⚫ Example: Expand a = 2x and b = 1; the exponents begin and end at 5 (a goes down while b goes up). Looking at row 5 on the triangle, our coefficients are 1, 5, 10, 10, 5, 1, so we write our expression as follows: (Notice that the exponents apply to the entire term of the binomial, not just the variable.) ( ) + 5 2 1 x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) + + + + + 5 4 3 2 2 3 4 5 5 10 1 1 1 1 2 2 2 1 2 1 5 2 0 x x x x x = + + + + + 5 4 3 2 32 80 80 40 10 1 x x x x x + + + + + 5 4 3 2 2 3 4 5 5 10 10 5 a a a a a b b b b b
  • 7. Binomial Series (cont.) ⚫ Consider the binomial series : If we multiply the coefficient of a term by a fraction consisting of the exponent of a over the term number, we get the coefficient of the next number. ( ) + 7 a b = + + + + + + + 7 6 5 2 4 3 3 4 2 5 6 7 7 21 35 35 21 7 a a b a b a b a b a b ab b 8 7 6 5 4 3 2 1     = =         exp. 7 coeff. 1 7, term # 1   =     6 7 21, 2       5 21 =35, ... 3
  • 8. Binomial Series (cont.) ⚫ Now let’s see what happens to if we don’t simplify the fractions as we calculate them: ( ) + 8 a b 1 2 3 4 5 8 a 7 8 1 a b 6 2 8 7 1 2 a b 5 3 8 7 6 1 2 3 a b 4 4 8 7 6 5 1 2 3 4 a b Do you see the pattern? What is it?
  • 9. Binomial Series (cont.) ⚫ The coefficients of a binomial series can be written as factorials. For example, let’s look at the coefficient for the fourth term: = 8 7 6 8 7 6 1 2 3 1 2 3 = 8 7 6 5! 1 2 3 5! = 8! 3! 5!
  • 10. Binomial Series (cont.) ⚫ Looking back at the original expression: Notice how the numbers in the coefficient expression are found elsewhere in the expression. ⚫ 8 is the value of the exponent to which (a + b) is raised. ⚫ 5 is the value of a’s exponent and 3 is the value of b’s. ⚫ The exponent of b is always one less than the term number (4). ( ) + = + + 5 3 8 ! ... ... ! ! 5 3 8 a b a b
  • 11. Binomial Theorem ⚫ The formula for the term containing br of (a + b)n, therefore, is or nCr ⚫ Example: Find the term containing y6 of ( ) − − ! ! ! n r r n a b r n r n r   =     ( ) 10 8 x y −
  • 12. Binomial Theorem (cont.) ⚫ The formula for the term containing br of (a + b)n, therefore, is or nCr ⚫ Example: Find the term containing y6 of ( ) − − ! ! ! n r r n a b r n r n r   =     ( ) 10 8 x y − ( )( ) ( ) ( ) 6 10 6 4 6 10 8 210 262144 6 x y x y −   − =     4 6 55,050,240x y =
  • 13. Binomial Theorem (cont.) ⚫ Example: Find the term in which contains f 9. ( ) 15 e f −
  • 14. Binomial Theorem (cont.) ⚫ Example: Find the term in which contains f 9. Since n = 15, n – r = 15 – 9 = 6. Therefore the term is (When dealing with negative terms such as f, recall that even exponents will produce positive terms and odd exponents will produce negative terms.) ( ) 15 e f − ( ) 9 6 6 9 15 5005 6 e f e f   − = −    
  • 15. Binomial Theorem (cont.) ⚫ Similarly, the kth term of binomial expansion of is found by realizing that the exponent of b will be k – 1, which gives us the formula: (replace r with k – 1) ( ) n a b + ( ) 1 1 1 n k k n a b k − − −     −  
  • 16. Binomial Theorem (cont.) ⚫ Example: Find the 4th term of ( ) 12 2c d −
  • 17. Binomial Theorem (cont.) ⚫ Example: Find the 4th term of n = 12, k = 4, which means that k – 1 = 3 ( ) 12 2c d − ( ) ( ) ( )( ) 9 3 9 3 12 2 220 512 3 c d c d   − = −     9 3 112,640c d = −
  • 18. Binomial Theorem ⚫ Your calculator can also find the coefficient: 4th term of n = 12, k – 1 = 3, n – (k –1) = 9 2l9¢b5312,3· ( ) 12 2c d −
  • 19. Binomial Theorem (cont.) ⚫ Desmos can also find the coefficient using a function called nCr(n, r): 4th term of n = 12, k – 1 = 3, n – (k –1) = 9 ( ) 12 2c d − ( ) ( ) 9 3 12 2 3 c d   −    
  • 20. Binomial Theorem Practice ⚫ Example: Expand ( ) − 5 2 3 x
  • 21. Binomial Theorem Practice ⚫ Example: Expand ( ) − 5 2 3 x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 5 0 4 1 3 2 2 3 1 4 0 5 5 5 5 2 3 2 3 2 3 0 1 2 5 5 5 2 3 2 3 2 3 3 4 5 x x x x x x       = − + − + −                   + − + − + −            
  • 22. Binomial Theorem Practice ⚫ Example: Expand ( ) − 5 2 3 x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 5 0 4 1 3 2 2 3 1 4 0 5 5 5 5 2 3 2 3 2 3 0 1 2 5 5 5 2 3 2 3 2 3 3 4 5 x x x x x x       = − + − + −                   + − + − + −             ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) 5 4 3 2 1 32 1 5 16 3 10 8 9 10 4 27 5 2 81 1 1 243 x x x x x = + − + + − + + −
  • 23. Binomial Theorem Practice ⚫ Example: Expand ( ) − 5 2 3 x ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 5 0 4 1 3 2 2 3 1 4 0 5 5 5 5 2 3 2 3 2 3 0 1 2 5 5 5 2 3 2 3 2 3 3 4 5 x x x x x x       = − + − + −                   + − + − + −             ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) ( )( )( ) 5 4 3 2 1 32 1 5 16 3 10 8 9 10 4 27 5 2 81 1 1 243 x x x x x = + − + + − + + − 5 4 3 2 32 240 720 1080 810 243 x x x x x = − + − + −
  • 24. Classwork ⚫ College Algebra 2e ⚫ 9.6: 8-36 (4); 9.5: 36-52 (4); 9.4: 46-62 (even) ⚫ 9.6 Classwork Check ⚫ Quiz 9.5