The most critical shortcomings of these assumptions are1.The flow .pdf

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The most critical shortcomings of these assumptions are 1.The flow of water is considered to be one dimensional but in reality it is three dimensional. 2.Darcy\'s law does not seem to hold good at high hydraulic gradients. Solution The most critical shortcomings of these assumptions are 1.The flow of water is considered to be one dimensional but in reality it is three dimensional. 2.Darcy\'s law does not seem to hold good at high hydraulic gradients..

The most critical shortcomings of these assumptions are
1.The flow of water is considered to be one dimensional but in reality it is three dimensional.
2.Darcy's law does not seem to hold good at high hydraulic gradients.
Solution
The most critical shortcomings of these assumptions are
1.The flow of water is considered to be one dimensional but in reality it is three dimensional.
2.Darcy's law does not seem to hold good at high hydraulic gradients.

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The following statements are true: 1. The tendency of water to minimize it\'s interaction with non-polar substances is known as hydrophobic effect. ( in hydrophobic, hydro refers to water and phobic refers to fear. ) 2.Hydrophobic molecules donot dissolve in water due to lack of Hydrogen bonding between it\'s molecules and water molecules. 3. Amphipathic substances are the structural basis of biological bilayer membranes. ( Ex. Animal Cellwalls) Solution The following statements are true: 1. The tendency of water to minimize it\'s interaction with non-polar substances is known as hydrophobic effect. ( in hydrophobic, hydro refers to water and phobic refers to fear. ) 2.Hydrophobic molecules donot dissolve in water due to lack of Hydrogen bonding between it\'s molecules and water molecules. 3. Amphipathic substances are the structural basis of biological bilayer membranes. ( Ex. Animal Cellwalls).

The following statements are true1. The tendency of water to mini.pdf

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The data is Quantitative as there are numbers , and its an observational study, where they studies about the H.pylori in the cause of ulceration. 2. From table -II, we see that among the 22 patients having Ulcer, 18 have infection of H.pylori. Out of 16, 8 were with infection. Gastritis and Duodenitis. Out of 22, 18 patients with gastric ulcers had bacteria, and four had both the ulcers, and all were Helicobacter positive. With gastric ulcer 77% had bacteria, and with duodenal ulcer 100% had bacteria. 4 patients with ulcers became negative for bacteria is significant as they had taken NSAIS drugs which are known to cause ulcers. Although gastric colonization with H.pylori, induces histologic gastritis in all infected individuals, only a small portion of them develop any significant sign and symptom for this colonization. It sestimated that H. pylori, infected patients have a 10-20% lifetime risk of developing ulcer disease. The risk of development of these diseases in the presence of H.pylori, depends on a variety of bacteria, host, and environmental factors, that relate to the pattern and severity of gastritis. Thus a patient can show normal examination. Solution The data is Quantitative as there are numbers , and its an observational study, where they studies about the H.pylori in the cause of ulceration. 2. From table -II, we see that among the 22 patients having Ulcer, 18 have infection of H.pylori. Out of 16, 8 were with infection. Gastritis and Duodenitis. Out of 22, 18 patients with gastric ulcers had bacteria, and four had both the ulcers, and all were Helicobacter positive. With gastric ulcer 77% had bacteria, and with duodenal ulcer 100% had bacteria. 4 patients with ulcers became negative for bacteria is significant as they had taken NSAIS drugs which are known to cause ulcers. Although gastric colonization with H.pylori, induces histologic gastritis in all infected individuals, only a small portion of them develop any significant sign and symptom for this colonization. It sestimated that H. pylori, infected patients have a 10-20% lifetime risk of developing ulcer disease. The risk of development of these diseases in the presence of H.pylori, depends on a variety of bacteria, host, and environmental factors, that relate to the pattern and severity of gastritis. Thus a patient can show normal examination..

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Solution 1 ) The purpose of criminal law is to help maintain social order and stability . The purpose of criminal law is to establish a system of prohibitions , penalties and correctional measures to deal with conduct that unjustifiably or inexcusably causes or threatens harm to those individual or public interests for which state protection is appropriate . 2) Classification according to the nature of crimes Mala in se : These are acts that are immoral or wrong in themselves or acts that are naturally evil . Ex : Murder, rape , arson , burglary etc Mala prohibita : These crimes are not naturally evil , but are prohibited by statute because they infringe upon the right of the others . This type of act is not wrong in some societies but wrong in other societies . Example : Traffic offenses , gambling etc . Classification according to degree : a) Felonies : Crimes that are punishable by death or imprisonment in a state prision or penitentiary are felonies . b) Misdemeanors : Crimes or offenses not amounting to felonies are Misdemeanors . They are offenses for which the punishment is other than death or imprisonment in a state prison , or that have not been designated felonies by statute. c) Treason : Treason is the only crime described in the constitution and it is given a higher classification than felony . 3) Example of white-collar crimes are bank fraud, blackmail , bribery , computer fraud, counterfeiting , credit card fraud , currency schemes, embezzelement , environmental schemes . The punishment for these crimes should be recovery of all the money made by white collar crimes and to put the white collar criminals in prision ..

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num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 CPP Code #include #include using namespace std; //Declaring Global variable int sum=0; //Function declarations void readFromFile(); void writeToFile(); /* Function implementation which will * read the numbers from the file and calculates the sum of * the numbers which are multiples of 2 or 5 */ void readFromFile() { int number,sum=0; //fileInput reference ifstream dataIn; //Opening input file dataIn.open(\"D:\\\ um.txt\"); while(dataIn>>number) { if(number%2==0 || number%5==0) { sum+=number; } } //closing the input stream dataIn.close(); } /* Function implementation which will * display the sum into another text file */ void writeToFile() { //fileoutput reference ofstream myfile; //Opening the file myfile.open (\"D:\\\ um1.txt\"); //Writing the contents to the file myfile <<\"The Sum of Multiples of 2 or 5 is :\"< Solution num.txt(Save this file under D Drive.Then the path of the file is D:\\\ um.txt) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 CPP Code #include #include using namespace std; //Declaring Global variable int sum=0; //Function declarations void readFromFile(); void writeToFile(); /* Function implementation which will * read the numbers from the file and calculates the sum of * the numbers which are multiples of 2 or 5 */ void readFromFile() { int number,sum=0; //fileInput reference ifstream dataIn; //Opening input file dataIn.open(\"D:\\\ um.txt\"); while(dataIn>>number) { if(number%2==0 || number%5==0) { sum+=number; } } //closing the input stream dataIn.close(); } /* Function implementation which will * display the sum into another text file */ void writeToFile() { //fileoutput reference ofstream myfile; //Opening the file myfile.open (\"D:\\\ um1.txt\"); //Writing the contents to the file myfile <<\"The Sum of Multiples of 2 or 5 is :\"<.

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Information security means protecting information (data) and information systems from unauthorized access, use, disclosure, disruption, modification, or destruction. Information Security management is a process of defining the security controls in order to protect the information assets. Security Program[edit] The first action of a management program to implement information security is to have a security program in place. Though some argue the first act would be to gain some real \"proof of concept\" and \"explainable thru display on the monitor screen\" security knowledge. Start with maybe understanding where OS passwords are stored within the code inside a file within a directory. If you don\'t understand Operating Systems at the root directory level maybe you should seek out advice from somebody who does before even beginning to implement security program management and objectives. Security Program Objectives Security Management Responsibilities Approaches to Build a Security Program Since advancement is directly tied to how well you can convince others, who often fall outside of your of job duties and department, as to your higher value to the company as stated by your own effective written communication this leads to amazing resume writers and take no blame style of email responses that seems to definitely lead to the eventual failure of company\'s standards and actual knowledge. It is often covered up by relationships which form at the power levels within any group of people and those who are considered so-called experts having no real idea what is really involved under the hood of the reports/applications they use and no proof presented in emails written when self declared claims of their expertise is made or blame is to be put on another. Security Controls[edit] Security Controls can be classified into three categories Administrative Controls which include Technical or Logical Controls which include Physical Controls which include The Elements of Security[edit] Vulnerability Threat Risk Exposure Countermeasure or Safeguard The Relation Between the Security Elements Core Information Security Principles[edit] The three fundamental principles of security are availability, integrity, and confidentiality and are commonly referred to as CIA or AIC triad which also form the main objective of any security program. The level of security required to accomplish these principles differs per company, because each has its own unique combination of business and security goals and requirements. All security controls, mechanisms, and safeguards are implemented to provide one or more of these principles. All risks, threats, and vulnerabilities are measured for their potential capability to compromise one or all of the AIC principles Confidentiality[edit] Integrity[edit] Availability[edit] Information Security Management Governance[edit] Security Governance[edit] Governance is the set of responsibilities and practices exercised by the board and executi.

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Given that T is unitary |T| = 1 |I-ieH| =1 det (-T) = (-1)ndet T Hence det (ieH-1) = (-1)n det ieH = 1+(-1)n i.e. det ieH can be either 0 or 2 To prove that H is equal to its own conjugate transpose Solution Given that T is unitary |T| = 1 |I-ieH| =1 det (-T) = (-1)ndet T Hence det (ieH-1) = (-1)n det ieH = 1+(-1)n i.e. det ieH can be either 0 or 2 To prove that H is equal to its own conjugate transpose.

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Gene expression Gene expression is the process by which the genetic code - the nucleotide sequence - of a gene is used to direct protein synthesis and produce the structures of the cell. Genes that code for amino acid sequences are known as \'structural genes\'. The process of gene expression involves two main stages: Transcription: the production of messenger RNA (mRNA) by the enzyme RNA polymerase, and the processing of the resulting mRNA molecule. Translation: the use of mRNA to direct protein synthesis, and the subsequent post-translational processing of the protein molecule. Some genes are responsible for the production of other forms of RNA that play a role in translation, including transfer RNA (tRNA) and ribosomal RNA (rRNA). A structural gene involves a number of different components: · Exons. Exons code for amino acids and collectively determine the amino acid sequence of the protein product. It is these portions of the gene that are represented in final mature mRNA molecule. · Introns. Introns are portions of the gene that do not code for amino acids, and are removed (spliced) from the mRNA molecule before translation. Gene control regions · Start site. A start site for transcription. · A promoter. A region a few hundred nucleotides \'upstream\' of the gene (toward the 5\' end). It is not transcribed into mRNA, but plays a role in controlling the transcription of the gene. Transcription factors bind to specific nucleotide sequences in the promoter region and assist in the binding of RNA polymerases. · Enhancers. Some transcription factors (called activators) bind to regions called \'enhancers\' that increase the rate of transcription. These sites may be thousands of nucleotides from the coding sequences or within an intron. Some enhancers are conditional and only work in the presence of other factors as well as transcription factors. · Silencers. Some transcription factors (called repressors) bind to regions called \'silencers\' that depress the rate of transcription. Transcription Transcription involves four steps: Transcription is the process of RNA synthesis, controlled by the interaction of promoters and enhancers. Several different types of RNA are produced, including messenger RNA(mRNA), which specifies the sequence of amino acids in the protein product, plus transfer RNA (tRNA) and ribosomal RNA (rRNA), which play a role in the translation process. 1. Initiation. The DNA molecule unwinds and separates to form a small open complex. RNA polymerase binds to the promoter of the template strand. 2. Elongation. RNA polymerase moves along the template strand, synthesising an mRNA molecule. In prokaryotes RNA polymerase is a holoenzyme consisting of a number of subunits, including a sigma factor (transcription factor) that recognises the promoter. In eukaryotes there are three RNA polymerases: I, II and III. The process includes a proofreading mechanism. 3. Termination. In prokaryotes there are two ways in which transcription is ter.

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Dysfunctional intercellular communication may result in various conditions such as disturbances in homeostasis, disturbed physiological conditions leading to various diseases, metastasis of diseases, cancer promotion and reproductive dysfunction. Therefore, intercellular communication plays an important role in various physiological and metabolic functions in cells. Communication failure disturb entire cellular processes. But, in some types of cancers, intercellular communication through gap junctions must be dysfunctional to stop te development of cancer. Solution Dysfunctional intercellular communication may result in various conditions such as disturbances in homeostasis, disturbed physiological conditions leading to various diseases, metastasis of diseases, cancer promotion and reproductive dysfunction. Therefore, intercellular communication plays an important role in various physiological and metabolic functions in cells. Communication failure disturb entire cellular processes. But, in some types of cancers, intercellular communication through gap junctions must be dysfunctional to stop te development of cancer..

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Correcty option. C. Phenotype The visible expressions (traits or characteristics like shape, size, color, etc.) of a gene is called its phenotype. So, the fur color (a visible expression) in dog is a phenotype. The genetic constitution (make up) of an organism with respect to one or more specified traits is called its genotype. For example, if gene color in dog is mediated by gene F, then gene F at both loci (maternal and fraternal) constitute the genotype of the dog with respect to the trait “fur color”. A diploid organism (here dog) interties two sets of haploid genome- one from its mother and another from father. By “both loci”, it is meant that gene F on the maternally inherited chromosome and gene F from fraternally inherited chromosome. Two or more forms of a gene are called allele. For example, gene F responsible for fur color in dogs may exist in two forms- F and f – one being on maternal chromosome (say, allele F) and the other being on fraternal chromosome (say, allele f). Genes and alleles are visible by eyes. They reside on DNA. It is the expression (product) of the gene that becomes visible and is called a phenotype. Solution Correcty option. C. Phenotype The visible expressions (traits or characteristics like shape, size, color, etc.) of a gene is called its phenotype. So, the fur color (a visible expression) in dog is a phenotype. The genetic constitution (make up) of an organism with respect to one or more specified traits is called its genotype. For example, if gene color in dog is mediated by gene F, then gene F at both loci (maternal and fraternal) constitute the genotype of the dog with respect to the trait “fur color”. A diploid organism (here dog) interties two sets of haploid genome- one from its mother and another from father. By “both loci”, it is meant that gene F on the maternally inherited chromosome and gene F from fraternally inherited chromosome. Two or more forms of a gene are called allele. For example, gene F responsible for fur color in dogs may exist in two forms- F and f – one being on maternal chromosome (say, allele F) and the other being on fraternal chromosome (say, allele f). Genes and alleles are visible by eyes. They reside on DNA. It is the expression (product) of the gene that becomes visible and is called a phenotype..

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Code: public class program2 { public static void main(String[] args) { int arr[][]={{0,2},{2,1,2,7,8},{2,1,0,6}}; System.out.println(method(arr)); } public static int method(int arr[][]){ int counter=0; for(int i=0;i Solution Code: public class program2 { public static void main(String[] args) { int arr[][]={{0,2},{2,1,2,7,8},{2,1,0,6}}; System.out.println(method(arr)); } public static int method(int arr[][]){ int counter=0; for(int i=0;i.

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Mastering JNKVV Entrance Exam: Previous Year Question Paper Analysis for MSc Ag Genetics and Plant Breeding Welcome to our comprehensive guide to cracking the JNKVV Entrance Examination for MSc in Agricultural Genetics and Plant Breeding. we'll dive deep into the analysis of previous year question papers, providing you with valuable insights, tips, and strategies to excel in this competitive exam. The Jawaharlal Nehru Krishi Vishwa Vidyalaya (JNKVV) is one of India's premier agricultural universities, and gaining admission to its MSc program in Genetics and Plant Breeding is a significant achievement. This video aims to help you prepare effectively by analyzing past question papers, highlighting important topics, and suggesting the best study strategies. Understanding the Exam Pattern Before we delve into the questions, it's crucial to understand the structure of the JNKVV entrance exam. The exam typically comprises multiple-choice questions (MCQs) that test your knowledge across various domains of genetics and plant breeding. The key areas usually covered include: Fundamentals of Genetics: - Mendelian inheritance - Chromosome structure and function - Genetic variation and mutation Plant Breeding Techniques - Hybridization methods - Selection techniques - Breeding for disease resistance Molecular Genetics - DNA replication, transcription, and translation - Molecular markers in plant breeding - Genomics and genetic engineering 4. Quantitative Genetics: - Heritability and genetic advance - Statistical methods in plant breeding - QTL mapping #### Detailed Question Paper Analysis Now, let's analyze a previous year’s question paper to understand the types of questions asked and the best ways to approach them. Section 1: Fundamentals of Genetics Example Question: Which of the following is NOT a part of Mendel's Laws? - A) Law of Segregation - B) Law of Independent Assortment - C) Law of Dominance - D) Law of Uniformity Analysis: This question tests your basic understanding of Mendelian genetics. To tackle such questions, ensure you are well-versed with the core principles of genetics. Revising basic concepts from standard textbooks like "Principles of Genetics" by Gardner et al. can be highly beneficial. Section 2: Plant Breeding Techniques Example Question: In plant breeding, the method where two plants with desirable traits are crossed is known as: - A) Backcrossing - B) Hybridization - C) Mutation breeding - D) Polyploidy Analysis: Questions in this section often require applied knowledge of breeding techniques. Focus on understanding the different methods of plant breeding, their applications, and examples. Books like "Plant Breeding: Principles and Methods" by B.D. Singh can provide comprehensive coverage of these topics.

MSc Ag Genetics & Plant Breeding: Insights from Previous Year JNKVV Entrance ...

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