Given that T is unitary |T| = 1 |I-ieH| =1 det (-T) = (-1)ndet T Hence det (ieH-1) = (-1)n det ieH = 1+(-1)n i.e. det ieH can be either 0 or 2 To prove that H is equal to its own conjugate transpose Solution Given that T is unitary |T| = 1 |I-ieH| =1 det (-T) = (-1)ndet T Hence det (ieH-1) = (-1)n det ieH = 1+(-1)n i.e. det ieH can be either 0 or 2 To prove that H is equal to its own conjugate transpose.