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REDOX REACTIONS
Overview and Practice
Review
• Redox reactions involve the transfer of electrons
from one reactant to another
• When there is oxidation, there is also reduction
• The substance that loses electrons = oxidized
and is the reducing agent
• The substance that gains electrons = reduced
and is oxidizing agent
2 Questions to Ask
• Does one gain electrons? If yes, then it has been reduced
• Does one lose electrons? If yes, then it has been oxidized
Example
Ethane burns in oxygen:
C2H6 + O2  CO2 + H2O
Steps:
1. Assign oxidation numbers (in red)
C2
-3 H6
+1 + O2
0  C +4O2
-2 + H +1
2O-2
Steps Continued
2. Write down which ones gain and which ones lose
electrons
Oxygen gained electrons (0 charge to -2 charge)
Carbon lost electrons (-3 charge to +4)
3. Determine which one is reduced and is the oxidizing
agent:
Oxygen is reduced and is the oxidizing agent
4. Determine which one is oxidized and is the reducing
agent:
Carbon is oxidized and is the reducing agent
Practice
Try out the 4 steps on the reaction below:
Cl2 + 2KI  I2 + 2KCl
Go to the next slide to see if you are correct!
1. Assign oxidation numbers:
Cl2
0 + 2K+1 I-1  I2
0 + 2K+1Cl-1
2. Which ones gain and which ones lose electrons:
Cl gains electrons
I loses electrons
3. Determine which one is reduced and is oxidizing agent:
Cl is reduced and is oxidizing agent
4. Determine which one is oxidized and is reducing agent:
I is oxidized and is reducing agent

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Redox reactions

  • 2. Review • Redox reactions involve the transfer of electrons from one reactant to another • When there is oxidation, there is also reduction • The substance that loses electrons = oxidized and is the reducing agent • The substance that gains electrons = reduced and is oxidizing agent
  • 3. 2 Questions to Ask • Does one gain electrons? If yes, then it has been reduced • Does one lose electrons? If yes, then it has been oxidized
  • 4. Example Ethane burns in oxygen: C2H6 + O2  CO2 + H2O Steps: 1. Assign oxidation numbers (in red) C2 -3 H6 +1 + O2 0  C +4O2 -2 + H +1 2O-2
  • 5. Steps Continued 2. Write down which ones gain and which ones lose electrons Oxygen gained electrons (0 charge to -2 charge) Carbon lost electrons (-3 charge to +4) 3. Determine which one is reduced and is the oxidizing agent: Oxygen is reduced and is the oxidizing agent 4. Determine which one is oxidized and is the reducing agent: Carbon is oxidized and is the reducing agent
  • 6. Practice Try out the 4 steps on the reaction below: Cl2 + 2KI  I2 + 2KCl Go to the next slide to see if you are correct!
  • 7. 1. Assign oxidation numbers: Cl2 0 + 2K+1 I-1  I2 0 + 2K+1Cl-1 2. Which ones gain and which ones lose electrons: Cl gains electrons I loses electrons 3. Determine which one is reduced and is oxidizing agent: Cl is reduced and is oxidizing agent 4. Determine which one is oxidized and is reducing agent: I is oxidized and is reducing agent