Recall Each Oxygen has 4 Electrons in its 2p bonding orbital.
But Since it is 02- Total e- = 4(2)+1=9
Put 2 electrons in 2p, 4 in 2p with a remaining 3 electrons to be placed.
By Aufbau principal, the next 3 electrons must go in the lowest energy state which would be
2p*.
3/4 electrons fill the 2p* leaving 1 unpaired.
Bond order=(Bonding Electrons - Antibonding)/2
=(6-3)/2
B.O.=1.5
Therefore, we can conclude that O2- is relativly stable as it has 1 complete bond. It also has one
unpaired electron in 2p* antibonding orbital which gives it paramagnetic properties.
2s and 1 s orbitals both have 2 electrons in bonding and antibonding orbitals if you draw them
out, canceling out any bonds they might create. Only 9 electrons play a significant role in the
bonding of O2-
Solution
Recall Each Oxygen has 4 Electrons in its 2p bonding orbital.
But Since it is 02- Total e- = 4(2)+1=9
Put 2 electrons in 2p, 4 in 2p with a remaining 3 electrons to be placed.
By Aufbau principal, the next 3 electrons must go in the lowest energy state which would be
2p*.
3/4 electrons fill the 2p* leaving 1 unpaired.
Bond order=(Bonding Electrons - Antibonding)/2
=(6-3)/2
B.O.=1.5
Therefore, we can conclude that O2- is relativly stable as it has 1 complete bond. It also has one
unpaired electron in 2p* antibonding orbital which gives it paramagnetic properties.
2s and 1 s orbitals both have 2 electrons in bonding and antibonding orbitals if you draw them
out, canceling out any bonds they might create. Only 9 electrons play a significant role in the
bonding of O2-.
Now a normal O2 molecule has 12 electrons in the valence shell so, O.pdfaquacareser
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2
Solution
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2.
Now a normal O2 molecule has 12 electrons in the valence shell so, O.pdfaquacareser
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2
Solution
Now a normal O2 molecule has 12 electrons in the valence shell so, O2+ has 11 electrons in its
valence shell. The first two go in the s2s and the next two go in the s*2s. Now two go in the s2p.
Now thats 6 of the electrons. 4 electrons go in the p2p level and the remaining one goes in the
p*2p level. Now count that up and the bond order is 1/2 the number of bonding electrons minus
antibonding electrons:
Order = 1/2 (8 - 3) = 5/2.
QUESTION 4 Manganese has an elec tron configuration 1s 2s 2p 3s 3p 4s.docxrtodd432
QUESTION 4 Manganese has an elec tron configuration 1s 2s 2p 3s 3p 4s 3d3. Which electrons are considered valence electrons? 4s 3d O 3s23p 63d 3d 4s QUESTION 5 lling diagrams below correctly represents the electron configuration for the valence electrons of oxygen, O? 2s 2p 2s 2p 3s 3p 2s 2p 3s 3p
Solution
4)
valence shell is outermost shell
Here outermiost shell is n=4
SO, 4s2 is valance shell
Answer: 4s2
5)
Electronic configuration is 1s2 2s2 2p4
Noble gas having lesser electron than O and closest to it is Helium (He)
Number of electron in He = 2
electronic configuration of He is: 1s2
So, electronic configuration of O in noble gas form is: [He] 2s2 2p4
So, it should have 2 electrons in 2s and 4 electrons in 2p
Remember pairing of electrons do not start until all orbitals are singly occupied
So, option 4 is wrong
Answer: 1st option
.
What are Electron Configurations ex.docxajullo3333
What are Electron Configurations?
The electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells with number of electrons are placed in a sequence.
Based on differences in electronegativity- how would you characterize.docxjkristen1
Based on differences in electronegativity, how would you characterize the bonding in sulfur dioxide, SO2?
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
3800 Character(s) remaining
Solution
The atom with less electronegative is central atom and the atoms with more electronegtive are terminal atoms.
So, Sulphur with less electronegative is central atom and Oxygens are terminal atoms.
S ( Z = 16 ) 1st excited state electronic configuration is,
1s2 s2 2p6 3s2 3p3 3d1
S in its first exicted state undergoes sp2 hybirdisation due ot which it has 1 paired sp2 hybrid orbital and 2 unpaired sp2 hybrid orbitals. And also S has one p and one d orbital with unpaired electrons.
O (Z = 8) E.C is 1s2 2s2 2p4
Each O has two unpaired electrons in its valence shell.
The each sp2 unpaired hybrid orbital of S overlaps with one of the unpaired p - orbital ofeach oxygen along the internuclear axis to form single S - O sigma bond with each Oxygen.
The reamining unpaired pure p-orbitals of S overlaps with unpaired p - orbital of each oxygen perpendicular to the internuclear axis to form one pi bonds with each oxygen.
Still S ia remained with one lone pair of electons.
Due to this SO 2 is in bent shape and has the bond angle < 120 0
.
a) The electronic configuration of arsenic is1s2 2s2 2p6 3s2 3p6 3.pdfdilipanushkagallery
a) The electronic configuration of arsenic is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration]
The number of electron in each subshell is 2 8 18 5 (K,L,M,N)
b) one permissible quantum number would be 4,0,0,-1/2
c) paramagnetic element are those element that have unpaired electron in the outer most shell
and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3
electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3
unpaired electron in 4p. Hence it is paramagnetic.
d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As
combine with 3 atoms of another element either by covalent or ionic bond. This is because As
requires 3 electron to attend the noble gas configuration or the octet state
If we consider Na3As, Na will loses 1 e forming Na+
Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up
by As.
So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state.
Therefore the ground state is consistent.
Solution
a) The electronic configuration of arsenic is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration]
The number of electron in each subshell is 2 8 18 5 (K,L,M,N)
b) one permissible quantum number would be 4,0,0,-1/2
c) paramagnetic element are those element that have unpaired electron in the outer most shell
and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3
electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3
unpaired electron in 4p. Hence it is paramagnetic.
d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As
combine with 3 atoms of another element either by covalent or ionic bond. This is because As
requires 3 electron to attend the noble gas configuration or the octet state
If we consider Na3As, Na will loses 1 e forming Na+
Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up
by As.
So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state.
Therefore the ground state is consistent..
For Chem 1:
Significanceof the ELectron in Bonding
The Octet Rule
Lewis Symbol/Structures
Formal Charge
Polyatomic Ions
Types of Bonds (Ionic, Covalent, Coordinate Covalent, Metallic Bonds, Multiple Bonds)
Exceptions to the Octet Rules
Oxidation Number is not included in the class discussion and exam. ;D
You have 50 mL of each solution or .050 L. Molari.pdfreyazansari001
You have 50 mL of each solution or .050 L. Molarity is given by: Molarity =
Moles of Solute/Liters of
Solution
... which means ... Moles of Solute = Molarity * Liters of.
QUESTION 4 Manganese has an elec tron configuration 1s 2s 2p 3s 3p 4s.docxrtodd432
QUESTION 4 Manganese has an elec tron configuration 1s 2s 2p 3s 3p 4s 3d3. Which electrons are considered valence electrons? 4s 3d O 3s23p 63d 3d 4s QUESTION 5 lling diagrams below correctly represents the electron configuration for the valence electrons of oxygen, O? 2s 2p 2s 2p 3s 3p 2s 2p 3s 3p
Solution
4)
valence shell is outermost shell
Here outermiost shell is n=4
SO, 4s2 is valance shell
Answer: 4s2
5)
Electronic configuration is 1s2 2s2 2p4
Noble gas having lesser electron than O and closest to it is Helium (He)
Number of electron in He = 2
electronic configuration of He is: 1s2
So, electronic configuration of O in noble gas form is: [He] 2s2 2p4
So, it should have 2 electrons in 2s and 4 electrons in 2p
Remember pairing of electrons do not start until all orbitals are singly occupied
So, option 4 is wrong
Answer: 1st option
.
What are Electron Configurations ex.docxajullo3333
What are Electron Configurations?
The electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells with number of electrons are placed in a sequence.
Based on differences in electronegativity- how would you characterize.docxjkristen1
Based on differences in electronegativity, how would you characterize the bonding in sulfur dioxide, SO2?
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
3800 Character(s) remaining
Solution
The atom with less electronegative is central atom and the atoms with more electronegtive are terminal atoms.
So, Sulphur with less electronegative is central atom and Oxygens are terminal atoms.
S ( Z = 16 ) 1st excited state electronic configuration is,
1s2 s2 2p6 3s2 3p3 3d1
S in its first exicted state undergoes sp2 hybirdisation due ot which it has 1 paired sp2 hybrid orbital and 2 unpaired sp2 hybrid orbitals. And also S has one p and one d orbital with unpaired electrons.
O (Z = 8) E.C is 1s2 2s2 2p4
Each O has two unpaired electrons in its valence shell.
The each sp2 unpaired hybrid orbital of S overlaps with one of the unpaired p - orbital ofeach oxygen along the internuclear axis to form single S - O sigma bond with each Oxygen.
The reamining unpaired pure p-orbitals of S overlaps with unpaired p - orbital of each oxygen perpendicular to the internuclear axis to form one pi bonds with each oxygen.
Still S ia remained with one lone pair of electons.
Due to this SO 2 is in bent shape and has the bond angle < 120 0
.
a) The electronic configuration of arsenic is1s2 2s2 2p6 3s2 3p6 3.pdfdilipanushkagallery
a) The electronic configuration of arsenic is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration]
The number of electron in each subshell is 2 8 18 5 (K,L,M,N)
b) one permissible quantum number would be 4,0,0,-1/2
c) paramagnetic element are those element that have unpaired electron in the outer most shell
and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3
electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3
unpaired electron in 4p. Hence it is paramagnetic.
d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As
combine with 3 atoms of another element either by covalent or ionic bond. This is because As
requires 3 electron to attend the noble gas configuration or the octet state
If we consider Na3As, Na will loses 1 e forming Na+
Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up
by As.
So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state.
Therefore the ground state is consistent.
Solution
a) The electronic configuration of arsenic is
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ground state configuration]
The number of electron in each subshell is 2 8 18 5 (K,L,M,N)
b) one permissible quantum number would be 4,0,0,-1/2
c) paramagnetic element are those element that have unpaired electron in the outer most shell
and diamagnetic are the one that have paired electron. Now in Arsenic, in the 4p there are 3
electron which are distributed among the three sub-orbitals of P (Px, Py and Pz) so they have 3
unpaired electron in 4p. Hence it is paramagnetic.
d) Now the compound Na3As, AsCl3 and AsF3, if we look at it, in all the compound As
combine with 3 atoms of another element either by covalent or ionic bond. This is because As
requires 3 electron to attend the noble gas configuration or the octet state
If we consider Na3As, Na will loses 1 e forming Na+
Na======>Na+ + 1e , Since there are 3 Na, so there will be 3 electron. These 3 e are taken up
by As.
So the configuration becomes 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6. Hence it has attain octet state.
Therefore the ground state is consistent..
For Chem 1:
Significanceof the ELectron in Bonding
The Octet Rule
Lewis Symbol/Structures
Formal Charge
Polyatomic Ions
Types of Bonds (Ionic, Covalent, Coordinate Covalent, Metallic Bonds, Multiple Bonds)
Exceptions to the Octet Rules
Oxidation Number is not included in the class discussion and exam. ;D
You have 50 mL of each solution or .050 L. Molari.pdfreyazansari001
You have 50 mL of each solution or .050 L. Molarity is given by: Molarity =
Moles of Solute/Liters of
Solution
... which means ... Moles of Solute = Molarity * Liters of.
Step1 In SO2; sulphur atom is attached to two ele.pdfreyazansari001
Step1 In SO2; sulphur atom is attached to two electron withdrawing oxygen atoms
through double bonds. In SO3 ; sulphur atom is attached to 3 electron withdrawing oxygen atoms
through double bonds ; thus making sulphur atom in SO3 more electron deficient as compared to
SO2. Hence SO3 is more acidic.
Solution
Step1 In SO2; sulphur atom is attached to two electron withdrawing oxygen atoms
through double bonds. In SO3 ; sulphur atom is attached to 3 electron withdrawing oxygen atoms
through double bonds ; thus making sulphur atom in SO3 more electron deficient as compared to
SO2. Hence SO3 is more acidic..
Indicators typically measure pH. The reaction pr.pdfreyazansari001
Indicators typically measure pH. The reaction process must be slow in this case,
thus why the time was measured.
Solution
Indicators typically measure pH. The reaction process must be slow in this case,
thus why the time was measured..
i) we dont know the mixture so the reaction may.pdfreyazansari001
i) we don\'t know the mixture so the reaction may be unwanted/dangerous
Solution
i) we don\'t know the mixture so the reaction may be unwanted/dangerous.
Yes it is always true. The company pays for these resources by eit.pdfreyazansari001
Yes it is always true.
The company pays for these resources by either incurring liabilities (which is the Liabilities part
of the accounting equation) or by obtaining funding from investors (which is the Shareholders\'
Equity part of of the equation). Thus, you have resources with offsetting claims against those
resources, either from creditors or investors. All three components of the accounting equation
appear in the balance sheet, which reveals the financial position of a business at any given point
in time.
The Liabilities part of the equation is usually comprised of accounts payable that are owed to
suppliers, a variety of accrued liabilities, such as sales taxes and income taxes, and debt payable
to lenders.
The Shareholders\' Equity part of the equation is more complex than simply being the amount
paid to the company by investors. It is actually their initial investment, plus any subsequent
gains, minus any subsequent losses, minus any dividends or other withdrawals paid to the
investors.
You can see this relationship between assets, liabilities, and shareholders\' equity in the balance
sheet, where the total of all assets always equals the sum of the liabilities and shareholders\'
equity sections.
The reason why the accounting equation is so important is that is always true - and it forms the
basis for all accounting transactions. At a general level, this means that whenever there is a
recordable transaction, you choices for recording it all involve keeping the accounting equation
in balance.
Solution
Yes it is always true.
The company pays for these resources by either incurring liabilities (which is the Liabilities part
of the accounting equation) or by obtaining funding from investors (which is the Shareholders\'
Equity part of of the equation). Thus, you have resources with offsetting claims against those
resources, either from creditors or investors. All three components of the accounting equation
appear in the balance sheet, which reveals the financial position of a business at any given point
in time.
The Liabilities part of the equation is usually comprised of accounts payable that are owed to
suppliers, a variety of accrued liabilities, such as sales taxes and income taxes, and debt payable
to lenders.
The Shareholders\' Equity part of the equation is more complex than simply being the amount
paid to the company by investors. It is actually their initial investment, plus any subsequent
gains, minus any subsequent losses, minus any dividends or other withdrawals paid to the
investors.
You can see this relationship between assets, liabilities, and shareholders\' equity in the balance
sheet, where the total of all assets always equals the sum of the liabilities and shareholders\'
equity sections.
The reason why the accounting equation is so important is that is always true - and it forms the
basis for all accounting transactions. At a general level, this means that whenever there is a
recordable transaction, you choices for reco.
We can consider the following dataThe data is about students from .pdfreyazansari001
We can consider the following data
The data is about students from a School. All the students are from the same school but from
different grades
the variables are
Categorical
1. Sex - M/F takes two values
2. Grade - 1 to 12 takes 12 values
Continuous
3. Weight of the student in Pounds
4. Height of the student in Centimeters
Clearly the first two variables are categorical and takes 2 and 12 values each
the next two are continuous
They are inter-related as they belong to the same student.
Student Sex Grade Weight Height
1.
2.
3.
.
.
.
.
.
.
30.
This will be the format of the data.
Solution
We can consider the following data
The data is about students from a School. All the students are from the same school but from
different grades
the variables are
Categorical
1. Sex - M/F takes two values
2. Grade - 1 to 12 takes 12 values
Continuous
3. Weight of the student in Pounds
4. Height of the student in Centimeters
Clearly the first two variables are categorical and takes 2 and 12 values each
the next two are continuous
They are inter-related as they belong to the same student.
Student Sex Grade Weight Height
1.
2.
3.
.
.
.
.
.
.
30.
This will be the format of the data..
Transposons are the segments of DNA that can move around to differen.pdfreyazansari001
Transposons are the segments of DNA that can move around to different positions in the genome
of a single cell which may cause mutations or increase/decrease the amount of DNA in the
genome of the cell. Theycan potentially play an important role in evolution by copying and
transferring other genetic material. There is evidence that transposons and their host genomes
have co-evolved over long periods and that transposon activity may increase in response to
environmental factors. The movement of transposons is a source that increases genetic
variability. In particular, transposons contain regulatory genes that control transposon activity. It
is thought that these regulatory genes may evolve to control other genes as well.
Solution
Transposons are the segments of DNA that can move around to different positions in the genome
of a single cell which may cause mutations or increase/decrease the amount of DNA in the
genome of the cell. Theycan potentially play an important role in evolution by copying and
transferring other genetic material. There is evidence that transposons and their host genomes
have co-evolved over long periods and that transposon activity may increase in response to
environmental factors. The movement of transposons is a source that increases genetic
variability. In particular, transposons contain regulatory genes that control transposon activity. It
is thought that these regulatory genes may evolve to control other genes as well..
C)Weak Acid, HF note HF is a weak acid that can.pdfreyazansari001
C)Weak Acid, HF note: HF is a weak acid that cannot completely ionize in water.
Thus, it is a weak electrolyte.
Solution
C)Weak Acid, HF note: HF is a weak acid that cannot completely ionize in water.
Thus, it is a weak electrolyte..
The answers are well explained & appreciated . The graphs & photos r.pdfreyazansari001
The answers are well explained & appreciated . The graphs & photos represents snail population
to be significantly different in 1980s than that of 1871. The shells of the snails are thicker now
than that of previous one. There exist change in population along with modification i.e,
evolutionary changes.
Above written answers satisfies the question.
Solution
The answers are well explained & appreciated . The graphs & photos represents snail population
to be significantly different in 1980s than that of 1871. The shells of the snails are thicker now
than that of previous one. There exist change in population along with modification i.e,
evolutionary changes.
Above written answers satisfies the question..
Stages of cell cycleFlow Cytometry Measurement of Cellular DNA Co.pdfreyazansari001
Stages of cell cycle:
Flow Cytometry Measurement of Cellular DNA Content
The nuclear DNA content of a cell can be quantitatively measured at high speed by flow
cytometry. Initially, a fluorescent dye that binds stoichiometrically to the DNA is added to a
suspension of permeabilized single cells or nuclei. The principle is that the stained material has
incorporated an amount of dye proportional to the amount of DNA. The stained material is then
measured in the flow cytometer and the emitted fluorescent signal yields an electronic pulse with
a height (amplitude) proportional to the total fluorescence emission from the cell. Thereafter,
such fluorescence data are considered a measurement of the cellular DNA content. Samples
should be analyzed at rates below 1000 cells per second in order to yield a good signal of
discrimination between singlets or doublets. Since the data obtained is not a direct measure of
cellular DNA content, reference cells with various amounts of DNA should be included in order
to identify the position of the cells with the normal diploid amount of DNA. Some of the
common reference cells often used for DNA measurements are human leukocytes or red blood
cells from chicken and trout. Commonly DNA measurements are expressed as a DNA index of
the ratio of sample DNA peak channel to reference DNA peak channel.
The Analysis of the Cell Cycle
In addition to determining the relative cellular DNA content, flow cytometry also enables the
identification of the cell distribution during the various phases of the cell cycle. Four distinct
phases could be recognized in a proliferating cell population: the G1-, S- (DNA synthesis phase),
G2- and M-phase (mitosis). However, G2- and M-phase, which both have an identical DNA
content could not be discriminated based on their differences in DNA content. Diverse software
containing mathematical models that fit the DNA histogram of a singlet have been developed in
order to calculate the percentages of cells occupying the different phases of the cell cycle.
Regulations of CDK activity:
What Are Cyclin-Dependent Kinases?
Of the many proteins involved in cell cycle control, cyclin-dependent kinases (CDKs) are among
the most important. CDKs are a family of multifunctional enzymes that can modify various
protein substrates involved in cell cycle progression. Specifically, CDKs phosphorylate their
substrates by transferring phosphate groups from ATP to specific stretches of amino acids in the
substrates. Different types of eukaryotic cells contain different types and numbers of CDKs. For
example, yeast have only a single CDK, whereas vertebrates have four different ones.
As their name suggests, CDKs require the presence of cyclins to become active. Cyclins are a
family of proteins that have no enzymatic activity of their own but activate CDKs by binding to
them. CDKs must also be in a particular phosphorylation state — with some sites phosphorylated
and others dephosphorylated — in order for activation .
Solution.b.Formula = Net income Total stake holder equity 100.pdfreyazansari001
Solution
.
b.
Formula = Net income / Total stake holder equity *100
c.
Formula = EBIT / Interest Expense
d.
Firstly we calculate Total liabilities
Formula = Total asset - Stakeholder equity
Debt to equity ratio = Total libilities / Total assetsYearRate of
earned201454.4201339.0201251.3201135.4201049.9.
Solution 1It is clearly mentioned that Facebook is a publicly held.pdfreyazansari001
Solution
1
It is clearly mentioned that Facebook is a publicly held corporation. So it is a corporate form of
organization. The balance sheet of facebook corporation shows Common stocks. Common stocks
can only be issued by a corporation. Therefore, Facebook is a corporation..
Mushroom is the fruiting body of Basidiomycetes fungi. It is also kn.pdfreyazansari001
Mushroom is the fruiting body of Basidiomycetes fungi. It is also known as basidiocarp. The
Basidiomycetes contain two orders called Agaricales and Aphyllophorales. In agaricales, the
mushroom or fruiting body is fleshy. it contains parts like stipe or stalk, pileus and lamellae. On
lamellae, the basidia produce the basidiospores. The order Agaricales contain members like
Agaricus sps, Amanita sps, Cortinarius, Laccaria and Suillus sps. These are edible mushrooms.
Some mushrooms are highly poisonous.
Order Aphyllophorales contain mushrooms having coriaceous, leathery to woody fruiting bodies
and some are fleshy also. The members include Ramaria sps, Pycnoporous sps and Ganoderma
sps etc.
Since, mushroom is fruiting body, fleshy and edible, thus, picking a mushroom can be similar to
\"picking an apple off an apple tree.\"
Solution
Mushroom is the fruiting body of Basidiomycetes fungi. It is also known as basidiocarp. The
Basidiomycetes contain two orders called Agaricales and Aphyllophorales. In agaricales, the
mushroom or fruiting body is fleshy. it contains parts like stipe or stalk, pileus and lamellae. On
lamellae, the basidia produce the basidiospores. The order Agaricales contain members like
Agaricus sps, Amanita sps, Cortinarius, Laccaria and Suillus sps. These are edible mushrooms.
Some mushrooms are highly poisonous.
Order Aphyllophorales contain mushrooms having coriaceous, leathery to woody fruiting bodies
and some are fleshy also. The members include Ramaria sps, Pycnoporous sps and Ganoderma
sps etc.
Since, mushroom is fruiting body, fleshy and edible, thus, picking a mushroom can be similar to
\"picking an apple off an apple tree.\".
All isotopes of radium are highly radioactive, wi.pdfreyazansari001
All isotopes of radium are highly radioactive, with the most stable isotope being
radium-226, which has a half-life of 1601 years
Solution
All isotopes of radium are highly radioactive, with the most stable isotope being
radium-226, which has a half-life of 1601 years.
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Francesca Gottschalk - How can education support child empowerment.pptxEduSkills OECD
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
Introduction to AI for Nonprofits with Tapp NetworkTechSoup
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Acetabularia Information For Class 9 .docxvaibhavrinwa19
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Palestine last event orientationfvgnh .pptxRaedMohamed3
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Recall Each Oxygen has 4 Electrons in its 2p bonding orbital. But .pdf
1. Recall Each Oxygen has 4 Electrons in its 2p bonding orbital.
But Since it is 02- Total e- = 4(2)+1=9
Put 2 electrons in 2p, 4 in 2p with a remaining 3 electrons to be placed.
By Aufbau principal, the next 3 electrons must go in the lowest energy state which would be
2p*.
3/4 electrons fill the 2p* leaving 1 unpaired.
Bond order=(Bonding Electrons - Antibonding)/2
=(6-3)/2
B.O.=1.5
Therefore, we can conclude that O2- is relativly stable as it has 1 complete bond. It also has one
unpaired electron in 2p* antibonding orbital which gives it paramagnetic properties.
2s and 1 s orbitals both have 2 electrons in bonding and antibonding orbitals if you draw them
out, canceling out any bonds they might create. Only 9 electrons play a significant role in the
bonding of O2-
Solution
Recall Each Oxygen has 4 Electrons in its 2p bonding orbital.
But Since it is 02- Total e- = 4(2)+1=9
Put 2 electrons in 2p, 4 in 2p with a remaining 3 electrons to be placed.
By Aufbau principal, the next 3 electrons must go in the lowest energy state which would be
2p*.
3/4 electrons fill the 2p* leaving 1 unpaired.
Bond order=(Bonding Electrons - Antibonding)/2
=(6-3)/2
B.O.=1.5
Therefore, we can conclude that O2- is relativly stable as it has 1 complete bond. It also has one
unpaired electron in 2p* antibonding orbital which gives it paramagnetic properties.
2s and 1 s orbitals both have 2 electrons in bonding and antibonding orbitals if you draw them
out, canceling out any bonds they might create. Only 9 electrons play a significant role in the
bonding of O2-
