The document provides a detailed lesson plan on solving problems related to the perimeters and areas of rectangles and parallelograms. It defines key concepts such as perimeter, area, and their respective formulas, illustrating how to calculate them using examples. The lesson emphasizes the properties of shapes and includes steps for problem-solving in geometry.

1. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn

2. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. Perimeter is similar to ____________.

3. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment

4. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. Area is similar to ______.

5. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. number of square units needed to cover an object’s surface Area is similar to ______. a plane

6. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________.

7. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure

8. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure.

9. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum

10. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is:

11. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is: 15 ft + 12 ft + 18 ft + 6 ft + 6 ft + 9 ft = 66 ft

12. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. )

13. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. ) (of a rectangle)

14. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 17 ft 8 ft

15. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 34 ft + 16 ft = 50 ft 17 ft 8 ft

16. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 2(17 ft + 8 ft) = 34 ft + 16 ft = 50 ft = 2(25 ft) = 50 ft 17 ft 8 ft

17. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________.

18. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface

19. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6

20. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6

21. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. The area of a rectangle can also be found by multiplying the length and the width. 3 6

22. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle l w 14 in. 10 in.

23. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in.

24. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in. NOTE: units indicate area is being calculated

25. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________.

26. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle

27. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height

28. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height base height

29. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height Base – the bottom of a geometric figure. Height – measured from top to bottom, perpendicular to the base. base height

30. A Plan for Problem Solving Find the area of the parallelogram:

31. A Plan for Problem Solving Find the area of the parallelogram:

32. A Plan for Problem Solving Find the area of the parallelogram:

33. §1.6 A Plan for Problem Solving End of Lesson