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 Asam Lemah
• Mengalami ionisasi tidak sempurna di dalam larutannya.
• Derajat ionisasinya  1 ( < 1)
• Contoh asam lemah: H2C2O4, HNO2, CH3COOH, H3PO4, dan HF.
• Konsentrasi ion hidrogen untuk asam lemah:
tetapan kesetimbangan asam
lemah
konsentrasi molar asam
Contoh Soal:
Hitung konsentrasi H+ dalam larutan HNO2 0,05 M! (Ka = 5 × 10–4)

 

    
4 3
[H ] [HA]
5 10 0,05 M 5 10 M
a
K
Back Next
Home
 Basa Lemah
• Mengalami ionisasi tidak sempurna di dalam larutannya.
• Derajat ionisasinya  1 ( < 1)
• Contoh basa lemah: NH4OH, Be(OH)2, AgOH, dan Zn(OH)2.
• Konsentrasi ion hidroksida untuk basa lemah:
tetapan kesetimbangan basa
lemah
konsentrasi molar basa
Contoh Soal:
Hitung konsentrasi OH– dalam larutan NH4OH 0,2 M! (Kb = 2 × 10–5)

 

    
5 3
[OH ] [BOH]
2 10 0,2 M 2 10 M
b
K
konsentrasi molar basa
Back Next
Home
Derajat keasaman merupakan ukuran konsentrasi asam dalam
suatu zat, yang sering dinyatakan dalam pH.
Untuk asam:
Untuk basa:
pH = 7  larutan bersifat netral
pH < 7  larutan bersifat asam
pH > 7  larutan bersifat basa
Back Next
Home
 pH Asam Lemah
Hitung pH larutan CH3COOH 0,1 M! (Ka = 10–5)
.Penyelesaian
[H+] =
pH = – log [H+]
= – log (10–3) = 3
Jadi, pH larutan tersebut adalah 3
Contoh Soal
5 1 6 3
3
[CH COOH] 10 10 10 10 M
a
K    
   
Back Next
Home
 pH Basa Lemah
Hitung pH larutan pH larutan NH4OH 0,05 M! (Kb = 2 ×
10–5)
Penyelesaian
[OH–] =
pOH = – log [OH– ]
= – log (10–3) = 3
pH = 14 – pOH = 14 – 3 = 11
Jadi, pH larutan tersebut adalah 11.
Contoh Soal
5 2 6 3
4
[NH OH] 2 10 5 10 10 10 M
b
K    
     
Derajat ionisasi asam lemah
dan basa lemah
Back Next
Home
 Konsentrasi larutan dapat diubah-ubah dengan pengenceran.
MA = konsentrasi awal (M)
MB = konsentrasi akhir (M)
VA = volum awal (L atau mL)
VB = volum akhir (L atau mL)
M = konsentrasi atau molaritas larutan
(M)
gr = massa zat (gram)
Mr = massa molekul relatif zat
(gram/mol)
V = volum larutan (mL)
 Konsentrasi larutan dinyatakan dalam molaritas larutan (M).
Pada pengenceran berlaku persamaan berikut.
 Suatu basa lemah NH4OH mempunyai konsentrasi 0,5 M
dan terionisasi sebanyak 10%. Harga pOH dan pH secara
berturut-turut adalah …
 Berapa ml air yang harus di campur dengan 100 ml
larutan NaOH 0,5 M sehingga konsentrasinya menjadi
0,2 M?
 Untuk membuat 500 ml larutan H2SO4 0,05 M
dibutuhlan larutan H2SO4 5 M sebanyak........
 Sebanyak 10 mL larutan asam asetat dengan pH = 3
dicampurkan dengan 90 mL air. Berapakah pH larutan
asam asetat itu sekarang? (Ka = 10pangkat−𝟓)

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Ppt asam basa 3 upload spada

  • 2. Back Next Home  Asam Lemah • Mengalami ionisasi tidak sempurna di dalam larutannya. • Derajat ionisasinya  1 ( < 1) • Contoh asam lemah: H2C2O4, HNO2, CH3COOH, H3PO4, dan HF. • Konsentrasi ion hidrogen untuk asam lemah: tetapan kesetimbangan asam lemah konsentrasi molar asam Contoh Soal: Hitung konsentrasi H+ dalam larutan HNO2 0,05 M! (Ka = 5 × 10–4)          4 3 [H ] [HA] 5 10 0,05 M 5 10 M a K
  • 3. Back Next Home  Basa Lemah • Mengalami ionisasi tidak sempurna di dalam larutannya. • Derajat ionisasinya  1 ( < 1) • Contoh basa lemah: NH4OH, Be(OH)2, AgOH, dan Zn(OH)2. • Konsentrasi ion hidroksida untuk basa lemah: tetapan kesetimbangan basa lemah konsentrasi molar basa Contoh Soal: Hitung konsentrasi OH– dalam larutan NH4OH 0,2 M! (Kb = 2 × 10–5)          5 3 [OH ] [BOH] 2 10 0,2 M 2 10 M b K konsentrasi molar basa
  • 4. Back Next Home Derajat keasaman merupakan ukuran konsentrasi asam dalam suatu zat, yang sering dinyatakan dalam pH. Untuk asam: Untuk basa: pH = 7  larutan bersifat netral pH < 7  larutan bersifat asam pH > 7  larutan bersifat basa
  • 5. Back Next Home  pH Asam Lemah Hitung pH larutan CH3COOH 0,1 M! (Ka = 10–5) .Penyelesaian [H+] = pH = – log [H+] = – log (10–3) = 3 Jadi, pH larutan tersebut adalah 3 Contoh Soal 5 1 6 3 3 [CH COOH] 10 10 10 10 M a K        
  • 6. Back Next Home  pH Basa Lemah Hitung pH larutan pH larutan NH4OH 0,05 M! (Kb = 2 × 10–5) Penyelesaian [OH–] = pOH = – log [OH– ] = – log (10–3) = 3 pH = 14 – pOH = 14 – 3 = 11 Jadi, pH larutan tersebut adalah 11. Contoh Soal 5 2 6 3 4 [NH OH] 2 10 5 10 10 10 M b K          
  • 7. Derajat ionisasi asam lemah dan basa lemah
  • 8. Back Next Home  Konsentrasi larutan dapat diubah-ubah dengan pengenceran. MA = konsentrasi awal (M) MB = konsentrasi akhir (M) VA = volum awal (L atau mL) VB = volum akhir (L atau mL) M = konsentrasi atau molaritas larutan (M) gr = massa zat (gram) Mr = massa molekul relatif zat (gram/mol) V = volum larutan (mL)  Konsentrasi larutan dinyatakan dalam molaritas larutan (M). Pada pengenceran berlaku persamaan berikut.
  • 9.  Suatu basa lemah NH4OH mempunyai konsentrasi 0,5 M dan terionisasi sebanyak 10%. Harga pOH dan pH secara berturut-turut adalah …  Berapa ml air yang harus di campur dengan 100 ml larutan NaOH 0,5 M sehingga konsentrasinya menjadi 0,2 M?  Untuk membuat 500 ml larutan H2SO4 0,05 M dibutuhlan larutan H2SO4 5 M sebanyak........  Sebanyak 10 mL larutan asam asetat dengan pH = 3 dicampurkan dengan 90 mL air. Berapakah pH larutan asam asetat itu sekarang? (Ka = 10pangkat−𝟓)