The document is a worksheet for exploring functions and operations using a TI-84 Plus calculator. It contains 5 questions asking the student to: 1) find the roots of a quadratic equation, 2) solve a system of linear equations using matrices, 3) graph a quadratic function, 4) evaluate a polynomial at a given value, and 5) evaluate a quadratic function at multiple values. The student is guided through the steps to perform each calculation using the appropriate buttons and commands on the TI-84 Plus calculator.

1. WEST VISAYAS STATE UNIVERSITY La Paz, Iloilo City College of Education - Graduate School Names: Lyny A. Gopole Course: MAEd - Mathematics Teacher: Rosemarie G. Galvez Subject: MATH 518 – ICT in Mathematics Paper No. 4 Worksheet Title: Exploring TI-84 Plus Reference: TI-8 Plus and TI-84 Plus Silver Edition Getting Started Guide Casiofx-991ES Plus User’s Guide Exploring TI-84 Plus
Name: ______________________________________________________________________________________ Level: _____Grade 9_____
Directions: Answer the following using TI-84 Plus.
1.) Find the roots of the equation x2 – 13x = 48.
2.) Using matrices, solve the system of linear equations
3x + 3y = 24
and 2x + y = 13.
3.) Graph the function y = 12 x2 + 1.
4.) Find the value of 2x3 – 5x2 – 7x + 10 when x = -0.5.
5.) Evaluate x2 + 4x at x = 2, x = 3, and x = 4.
ACTIVITY

2. WEST VISAYAS STATE UNIVERSITY La Paz, Iloilo City College of Education - Graduate School Exploring TI-84 Plus
1.) Find the roots of the equation x2 – 13x = 48.
Steps:
a.)
b.)
c.)
d.)
Note: x = line allows you to input a guess that should be very close to the answer.
Press Result
MATH
ENTER
X,T,Ѳ,n
x2
̶
1 3
X,T,Ѳ,n
̶
4 8
ENTER
ANSWER KEY
MATH NUM CPX PRB
6↑fMin(
7:fMax(
8:nDeriv(
9:fnInt(
0:summation Σ(
A:logBASE(
B:Solver
EQUATION SOLVER
eqn:0=
EQUATION SOLVER
eqn:0=X2-13X-48
X2-13X-48=0
X=0
bound={-1Ε99, 1...

3. WEST VISAYAS STATE UNIVERSITY
La Paz, Iloilo City
College of Education - Graduate School
Exploring TI-84 Plus
e.)
f.)2 0
g.)
Answer: The two roots are -3 and 16. Since you did not enter a guess, the TI-84 Plus
used the value stored in x (the default is 0) and first returned the answer
nearest 0. To find the other roots, you must enter another guess. In this
activity, we entered 20.
2.) Using matrices, solve the system of linear equations
3x + 3y = 24
and 2x + y = 13.
Steps:
a.)
Press Result
ALPHA
[SOLVE]
ALPHA
[SOLVE]
Press Result
2nd
[MATRIX]
X2-13X-48=0
●X=0
bound={-1Ε99, 1...
●left-rt=0
X2-13X-48=0
X=20
bound={-1Ε99, 1...
left-rt=0
X2-13X-48=0
●X=16
bound={-1Ε99, 1...
●left-rt=0
NAMES MATH EDIT
1: [A] 2X2
2: [B]
3: [C]
4: [D]
5: [E]
6: [F]
7↓ [G]

4. WEST VISAYAS STATE UNIVERSITY
La Paz, Iloilo City
College of Education - Graduate School
Exploring TI-84 Plus
b.)
c.)
d.)
e.)
f.)
Press Result
ENTER
2
ENTER
3
ENTER
3
ENTER
3
ENTER
2
4
ENTER
2
ENTER
1
ENTER
1
3
ENTER
2nd
[QUIT]
2nd
[MATRIX]
MATRIX[B] 1 X1
[ 0]
MATRIX[B] 2 X3
[ 0 0 0 ]
[ 0 0 0 ]
1,1 = 0
MATRIX[B] 2 X3
[ 3 3 24 ]
[ 2 1 13 ]
2,3 = 13
NAMES MATH EDIT
1:det(
2:T
3: dim(
4: Fill(
5: identity(
6: randM(
7↓augment(
NAMES MATH EDIT
0↑cumSum(
A:ref(
B:rref(
C:rowSwap(
D:row+(
E:*row(
F:*row+(

5. WEST VISAYAS STATE UNIVERSITY
La Paz, Iloilo City
College of Education - Graduate School
Exploring TI-84 Plus
g.)
h.)
i.)
Note: rrefand ref are methods to solve systems of equations that are comparable to the
elimination and substitution methods. You can also use commands such as rowSwap,
row+, *row, and *row+ to do your elimination or substitution methods step by step.
Answer: You can interpret the resulting matrix as:
[ 1 0 5 ] represents 1X + 0Y = 5 or X = 5
[ 0 1 3 ] represents 0X + 1Y = 3 or Y = 3
The solution to the system of equations
x – 2y = 4
and 2x + 3y = 3 is X = 5 and Y = 3.
Press Result
ENTER
2nd
[MATRIX]
ENTER
)
ENTER
rref(
rref([B])
105013
rref([B])

6. WEST VISAYAS STATE UNIVERSITY
La Paz, Iloilo City
College of Education - Graduate School
Exploring TI-84 Plus
3.) Graph the function y = 12 x2 + 1.
Steps:
a.)
Note: If Y1 is not empty, press
If there are additional entries in the
Y= Editor, press
as needed to clear entries.
b.)
Note: The highlighted = means this function
will graph.
c.)
d.)
Use arrow keys to trace along the curve.
Note: The default window settings are
-10< x < 10 and -10 < y < 10.
Press Result
Y=
CLEAR
CLEAR
1
ALPHA
[F1]
ENTER
2
X,T,Ѳ,n
x2
+
1
GRAPH
TRACE
Plot1 Plot2 Plot3
Y1=
Y2=
Y3=
Y4=
Y5=
Y6=
Y7=
Plot1 Plot2 Plot3
Y1= 12 푥2+1
___________________
Y2=
Y3=
Y4=
Y5=

7. WEST VISAYAS STATE UNIVERSITY La Paz, Iloilo City College of Education - Graduate School Exploring TI-84 Plus
4.) Find the value of 2x3 – 5x2 – 7x + 10 when x = -0.5.
Steps:
a.)
b.)
Answer: The value of 2x3 – 5x2 – 7x + 10 when x = -0.5 is 12.
Press Result
(-)
0
.
5
STO
X,T,Ѳ,n
ENTER
2
X,T,Ѳ,n
^
3
−
5
ENTER
x2
−
7
X,T,Ѳ,n
+
1 0
ENTER
-0.5→X
-.5
-0.5→X
-.5
2X3-5x2-7x+10
12

8. WEST VISAYAS STATE UNIVERSITY
La Paz, Iloilo City
College of Education - Graduate School
Exploring TI-84 Plus
5.) Evaluate x2 + 4 at x = 2, x = 3, and x = 4.
Steps:
a.)
b.)
c.)
Answer: The value of x2 + 4 at x = 2, x = 3, and x = 4 is 8, 13, and 20 respectively.
Press Result
2
STO
X,T,Ѳ,n
ENTER
X,T,Ѳ,n
x2
+
4
ENTER
3
STO
X,T,Ѳ,n
ENTER
ENTER
ENTER
4
STO
X,T,Ѳ,n
ENTER
ENTER
ENTER
2→X
2
x2+4
8
x2+4
8
3→X
3
x2+4
13
x2+4
13
4→X
4
x2+4
20