1
SEMI – DETAILED LESSON PLAN IN MATH 8
I. OBJECTIVE
At the end of the lesson, students should be able to:
graph a linear function’s (a) domain; (b) range; (c) table of values; (d)
intercepts; and (e) slope M8AL-IId-e-1
 Graph a linear function’s intercepts.
 Appreciate the industry and innovativeness of the people
making these things/products.
II. SUBJECT MATTER
A. CONTENT:
Graphs of Linear Equations: Using X – Intercept and Y - Intercept
B. REFERENCE/S: Mathematics Learner’s Material for Grade 8 pp. 173 –
174, Mathematics Teacher’s Guide for Grade 8 pp. 202 –203 DLHTM IV.
A .4 , DLHTM IV.A.22, DLHTM IV.A.17, DLHTM IV.A.26
C. MATERIALS: laptop, LCD projector, LCD screen, Activity Sheets
D. VALUES:
III. PROCEDURE
A. ACTIVITY
Can you name the picture on the graph? Who can name them?
Where can we buy these products?
Suppose points A, B, C, and D represent the location of the stores selling
these products. Indicate the name of each point in the Cartesian plane. Then,
connect each pair of points A and B, C and D to form a line.
Appreciation of Local Products
2
A. ANALYSIS
Were you able to name and connect the points correctly? Explain.
You have learned that two points determine a line. A linear
equation can also be described by its graph. Those lines formed are
graphs of linear equations. Graphing linear equations can be done using
x – and y – intercepts.
B. ABSTRACTION
The x- and y-intercepts of the line could represent two points, which are
(a, 0) and (0, b). Thus, the intercepts are enough to graph the linear equation.
1
2
3
1 2 3 4-1-2-3-4
-1
-2
-3
-4
A
B C
D
3
To graph the equation y = 2x + 1 using this method, you need to solve the
x-intercept by letting y = 0 and the y-intercept by letting x = 0.
Letting y = 0, the equation y = 2x + 1 becomes
0 = 2x + 1 Substitution
2x + 1 = 0 Symmetric Property of Equality
2x = -1 Addition Property of Equality
x = −
1
2
Multiplication Property of Equality
Thus, one point is at (−
1
2
, 0).
Letting x = 0, y = 2x + 1 becomes
y = 2(0) + 1 Substitution
y = 0 + 1 Simplification
y = 1 Simplification
Thus, another point is at (0,1).
The x-intercept a is −
1
2
while the y-intercept b is 1.
Now, plot the x- and y-intercepts, then connect them.
1
1 2-1-2
-1
(0, 1)
(−
1
2
, 0) y = 2x+1
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Generalization:
Based on our discussion, how do you graph a linear
equation using x – and y – intercepts?
Remember:
The x-intercept is the abscissa of the coordinates of the
point in which the graph intersects the x-axis. However, the y-
intercept is the ordinate of the coordinates of the point in which
the graph intersects the y-axis.
Values Integration:
Going back to the products we have learned from the
activity, are those products helpful to the livelihood of the
Maasinhon? What can we do to help them? What can you say
about the products? What can you say about the makers of these
products?
C. APPLICATION
a. Graph the linear equation y = 5x – 10 using x – intercept and y –
intercept.
b. Graph each linear equation whose x – intercept a and y – intercept
b are given below.
1. a = 2 and b = 1
2. a = 4 and b = -1
A. ASSESSMENT
1. Using the x – intercept and the y – intercept, graph the following
equations.
a. y = 3x + 9
b. y = 2x – 10
Appreciation of Local Products
-2
5
2. Graph each linear equation whose x-intercept a and y-intercept b
are given below.
a) a = -2 and b = -7
b) a = 12 and b = -2
(Note: You may also construct a multiple choice test question in this part of
the lesson to get immediately the MPS result of the learner’s performance.)
B. ASSIGNMENT
Study page 174 of the LM, Graphs of Linear Equations
Using Slope and Y – Intercept. Then, answer Exercise 10 numbers
1 to 4 on page 175. Write your answer in a one – whole graphing
paper.
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Prepared by: JOEGEN A. LIMAS, Maria Clara Integrated School

Contextualized Lesson Plan in Math 8 Graphs of Linear Equations using Intercepts

  • 1.
    1 SEMI – DETAILEDLESSON PLAN IN MATH 8 I. OBJECTIVE At the end of the lesson, students should be able to: graph a linear function’s (a) domain; (b) range; (c) table of values; (d) intercepts; and (e) slope M8AL-IId-e-1  Graph a linear function’s intercepts.  Appreciate the industry and innovativeness of the people making these things/products. II. SUBJECT MATTER A. CONTENT: Graphs of Linear Equations: Using X – Intercept and Y - Intercept B. REFERENCE/S: Mathematics Learner’s Material for Grade 8 pp. 173 – 174, Mathematics Teacher’s Guide for Grade 8 pp. 202 –203 DLHTM IV. A .4 , DLHTM IV.A.22, DLHTM IV.A.17, DLHTM IV.A.26 C. MATERIALS: laptop, LCD projector, LCD screen, Activity Sheets D. VALUES: III. PROCEDURE A. ACTIVITY Can you name the picture on the graph? Who can name them? Where can we buy these products? Suppose points A, B, C, and D represent the location of the stores selling these products. Indicate the name of each point in the Cartesian plane. Then, connect each pair of points A and B, C and D to form a line. Appreciation of Local Products
  • 2.
    2 A. ANALYSIS Were youable to name and connect the points correctly? Explain. You have learned that two points determine a line. A linear equation can also be described by its graph. Those lines formed are graphs of linear equations. Graphing linear equations can be done using x – and y – intercepts. B. ABSTRACTION The x- and y-intercepts of the line could represent two points, which are (a, 0) and (0, b). Thus, the intercepts are enough to graph the linear equation. 1 2 3 1 2 3 4-1-2-3-4 -1 -2 -3 -4 A B C D
  • 3.
    3 To graph theequation y = 2x + 1 using this method, you need to solve the x-intercept by letting y = 0 and the y-intercept by letting x = 0. Letting y = 0, the equation y = 2x + 1 becomes 0 = 2x + 1 Substitution 2x + 1 = 0 Symmetric Property of Equality 2x = -1 Addition Property of Equality x = − 1 2 Multiplication Property of Equality Thus, one point is at (− 1 2 , 0). Letting x = 0, y = 2x + 1 becomes y = 2(0) + 1 Substitution y = 0 + 1 Simplification y = 1 Simplification Thus, another point is at (0,1). The x-intercept a is − 1 2 while the y-intercept b is 1. Now, plot the x- and y-intercepts, then connect them. 1 1 2-1-2 -1 (0, 1) (− 1 2 , 0) y = 2x+1
  • 4.
    4 Generalization: Based on ourdiscussion, how do you graph a linear equation using x – and y – intercepts? Remember: The x-intercept is the abscissa of the coordinates of the point in which the graph intersects the x-axis. However, the y- intercept is the ordinate of the coordinates of the point in which the graph intersects the y-axis. Values Integration: Going back to the products we have learned from the activity, are those products helpful to the livelihood of the Maasinhon? What can we do to help them? What can you say about the products? What can you say about the makers of these products? C. APPLICATION a. Graph the linear equation y = 5x – 10 using x – intercept and y – intercept. b. Graph each linear equation whose x – intercept a and y – intercept b are given below. 1. a = 2 and b = 1 2. a = 4 and b = -1 A. ASSESSMENT 1. Using the x – intercept and the y – intercept, graph the following equations. a. y = 3x + 9 b. y = 2x – 10 Appreciation of Local Products -2
  • 5.
    5 2. Graph eachlinear equation whose x-intercept a and y-intercept b are given below. a) a = -2 and b = -7 b) a = 12 and b = -2 (Note: You may also construct a multiple choice test question in this part of the lesson to get immediately the MPS result of the learner’s performance.) B. ASSIGNMENT Study page 174 of the LM, Graphs of Linear Equations Using Slope and Y – Intercept. Then, answer Exercise 10 numbers 1 to 4 on page 175. Write your answer in a one – whole graphing paper.
  • 6.
    6 Prepared by: JOEGENA. LIMAS, Maria Clara Integrated School