On a Sunday in April, dog bite victims arrive at Carver Memorial Hospital at a historical rate of 0.6 victim per day. On a given Sunday in April, what is the probability that exactly two dog bite victims will arrive? Solution Given X~Poisson(=0.6) P(X=x)=(0.6^x)*exp(-0.6)/x! So the probability is P(X=2)=(0.6^2)*exp(-0.6)/2=0.09878609.