October 23, 2015
 Review/Practice
Various Equations
 Class Work
Questions?
 Complete Equations
Class Work 1.4
Test on Equations &
Translations Tomorrow
Khan Academy: 10/21/15
Is the equation always, sometimes, or never true?
1. The width of a rectangle is 2 more than one-half the
length. The perimeter is 89 yards. Find the length & width.
P = 89
0.32x + 0.4 = 0.6x + 0.7 -0.55x Solve in decimal form:
𝟒
𝟓
-
𝟑
𝟒
𝟑
𝟒
𝒏 +
𝟏𝟖
𝟒
−
𝟏
𝟐
𝒏 +
𝟑
𝟐
= - 3
n = - 36
Solve: 2
𝟏
𝟑
-
𝟐
𝟓 Solve: 4
𝟑
𝟒
÷
𝟐
𝟑
Solve in fraction form with a denominator of 100: x + 3 = 6
2
A certain number, which first has 15 subtracted from it, then
has the difference multiplied by 7, will give a result of 28.
What’s the number? 7(x – 15) = 28 7x – 105 = 28
7x = 133; x = 19
Tell me the easier way to solve this
equation
x – 15 =
𝟐𝟖
𝟕
x – 15 = 4; x = 19
Be flexible, follow the path of least
resistance.
Translating
October 22, 2015

October 22, 2015

  • 1.
    October 23, 2015 Review/Practice Various Equations  Class Work Questions?  Complete Equations Class Work 1.4 Test on Equations & Translations Tomorrow
  • 3.
  • 4.
    Is the equationalways, sometimes, or never true?
  • 5.
    1. The widthof a rectangle is 2 more than one-half the length. The perimeter is 89 yards. Find the length & width. P = 89 0.32x + 0.4 = 0.6x + 0.7 -0.55x Solve in decimal form: 𝟒 𝟓 - 𝟑 𝟒 𝟑 𝟒 𝒏 + 𝟏𝟖 𝟒 − 𝟏 𝟐 𝒏 + 𝟑 𝟐 = - 3 n = - 36
  • 6.
    Solve: 2 𝟏 𝟑 - 𝟐 𝟓 Solve:4 𝟑 𝟒 ÷ 𝟐 𝟑 Solve in fraction form with a denominator of 100: x + 3 = 6 2
  • 7.
    A certain number,which first has 15 subtracted from it, then has the difference multiplied by 7, will give a result of 28. What’s the number? 7(x – 15) = 28 7x – 105 = 28 7x = 133; x = 19 Tell me the easier way to solve this equation x – 15 = 𝟐𝟖 𝟕 x – 15 = 4; x = 19 Be flexible, follow the path of least resistance. Translating