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NumberSystemsMuhaiminBinMunir
DeptofCSE,MIST
1.
Counting
3
1 1 1 1 1 1 1
1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1
1 1 1 1 1 1
2.a
NumberSystems
Decimal Numbers
Basics-Base10NumberSystem
5
Consists of TWOThings:
✘ A BASE or RADIXValue
✘ A SET of DIGITS
✗ Digits are symbols representing allvalues
less than the radix value.
Example is the Common DecimalSystem:
✘ RADIX (BASE) =10
✘ Digit Set ={0,1,2,3,4,5,6,7, 8,9}
231. 54
6
hundreds | tens | ones tenth | hundredth
2x100+3x10+1x1+5/10+4/100
2x10²+3x10¹+1x100+ 5x10-1+4x10-2
200 + 30 + 1 + 0.5 + 0.04
GeneralRepresentation
7
an - 1rn- 1+an - 2rn - 2 +an - 3rn - 3+….+a2r2 +a1r1+a0r0
+
a-1r-1+a-2r-2 +a-3r-3 +…..+a-mr-m
Here,
r =radix or base
ai =digit in i-thposition/coefficients
n=number of digits before decimalplace
2.b
NumberSystems
Binary Numbers
Basics-Base2NumberSystem
✘ RADIX (BASE) =2
✘ Digit Set ={0,1}
Convert a Binary Number into a Decimal Number
Just put the radix value two (r=2)in thegeneral
representation of decimalnumbers.
9
1011. 01
8’s | 4’s | 2’s | 1’s ½ | ¼th
1x8+0x4+1x2+1x1+ 0/2+1/4
1x23+0x22+1x21+1x20+ 0x2-1 +1x2-2
0 + 0.258 + 0 + 2 + 1 +
1
20
=11. 5
2.c
NumberSystems
Hexadecimal Numbers &
Octal Numbers
Basics
12
Octal Numbers(Base 8 Number System)
✘ RADIX (BASE) =8
✘ Digit Set ={0,1,2,3,4,5,6, 7}
Hexadecimal Numbers(Base 16Number System)
✘ RADIX (BASE) =16
✘ Digit Set ={0,1,2,3,4,5,6,7,8,9,A,B, C,D,E,F}
HexadecimalandOctaltoDecimalNumberConversion
Hexadecimal Octal
6 E 7 1 5 . 2
256’s|16’s|1’s 8’s|1’s. ⅛th
6x256+14(E)x16+7x1 1x8+5x1+2/8
=1536+224+7 =8+5+0.25
=1767 =13.25
13
3
Conversions
✘ Divide the number
by the ‘Base’(2)
✘ Take the remainder
(either 0 or 1)as a
coefficient
✘ Take the quotient
and repeat the
division
Decimal(Integer)toBinary
Example: 14
Quo Rem Coeff
14/2 7 0 a0 =0
7/2 3 1 a1=1
3/2 1 1 a2 =1
1/2 0 1 a3 =1
15
(14)10=(a3a2a1a0)2 =(1110)2
✘ Multiply the number
by the ‘Base’(2)
✘ Take the integer
(either 0 or 1)asa
coefficient
✘ Take the resultant
fraction and repeat
the multiplication
Decimal(Fraction)toBinary
Coeff
16
a-1=1
a-2 =0
-3
Example: 0.625
Int Frac
0.625 x 2 1 .25
0.25 x 2 0 .5
0.5 x 2 1 .0 a =1
(0.625)10=(0.a-1a-2a-3)2 =(0.101)2
DecimaltoOctal
Coeff
a-1=2
Example: 0.3125
Int Frac
0.3125 x 8 2 .5
0.5 x 8 4 .0 a-2 =4
(0.3125)10=(0.a-1a-2)8=(0.24)8
Coeff
17
175/8
21/8
Example: 175
Quo Rem
21 7 a0 =7
2 5 a1 =5
2/8 0 2 a2 =2
(175)10=(a2a1a0)8 =(275)8
✘ Represent the binary
number in groups of 3
bits.
✗ 8 =23Hence, 3 bits
✘ Replace 3bit
representation with
octal digits.
BinarytoOctalandVice-versa
Example: (10110.01)2
010 110. 010
2 6 . 2
0 1 2 3 4 5 6 7
000 001 010 011 100 101 110 111
18
✘ Convert octal to
binary as an
intermediate step.
✘ Convert binary to
hexadecimal.
OctaltoHexadecimalandVice-versa
Example: (26.2)8
010 110. 010
00010110. 0100
1 6 . 4
19
“Practiceputsbrainsinyourmuscles”
20
SamSnead
HowtoCountto1000bytwohands
4.a
BinaryArithmetic
Addition and Multiplication
+
111111
111101 61
10111 +23
1010100 84
101
11
5
3
101 15
+ 1010
1111
x x
4.b
BinaryArithmetic
Subtraction and Complements
SubtractionusingComplements
Two types (for each base-rsystem)
✘ Diminishing radix complement (r - 1’scomplement)
✘ Radix complement (r’scomplement)
For n-digit numberN
rn- 1- N
rn- N
r - 1’scomplement
r’s complement
26
DiminishedRadixComplement
27
✘ Example for 6-digit decimal numbers:
9’s complement is (rn –1)–N =(106–1)–N =999999 –N
9’s complement of 546700:
999999 –546700 =453299
✘ Example for 7-digit binary numbers:
1’scomplement is (rn –1)–N =(27–1)–N =1111111–N
1’scomplement of 1011000:
1111111–1011000=0100111
RadixComplement
28
The r's complement ofan n-digit number Nin base r is
defined as rn–Nfor N≠0and as 0for N=0.
The r's complement can also be obtained by adding 1to
the (r −1)'s complement, since rn–N=[(rn−1)–N]+1
Example: 10’scomplement of 246700is
106- N =1000000 - 246700 =753300
✘ Take 1’scomplement then add 1
✘ Toggle all bits to the left of the first ‘1’from the
right
RadixComplement(BinaryNumbers)
1
01010000 29
10110000 10110010
01001111
01001110
M–N
✘ Add Mto r’s complement of N
sum=M+(rn–N)=M–N +rn
✘ If M>N,Sum will have an end carry rn,discard it
✘ If M<N,Sum will not have an end carry and
sum=rn–(N–M)(r’scomplementof N–M)
So M–N=–(r’scomplementof Sum)
SubtractionwithradixComplement
65438-5623
65438
10’scomplement
5623
94377
15981531
05623
5623-65438
32
10’scomplement
65438
34562
40185
Therefore,theansweris:–(10'scomplementof40185)=−59815.
10110010-10011111
10110010
2’scomplement
10011111
01100001
10001001133
10011111
10011111-10110010
Therefore,theanswer:–(2'scomplementof11101101)=−10011
34
2’scomplement
10110010
01001110
11101101
Subtraction of unsigned numbers can also be done by
means of the (r−1)'scomplement.
Remember that the (r−1)'scomplement is oneless
then the r 'scomplement.
SubtractionwithDiminishedradixComplement
36
10110010
10110010-10011111
1’scomplement
10011111
01100000
100010010
00010010+1=10011
37
10011111
10011111-10110010
1’scomplement
10110010
01001101
11101100
Therefore,theanswer:–(1'scomplementof11101100)=−10011
4.c
BinaryArithmetic
Signed Binary Numbers
To represent negative integers, we need a notation for
negative values.
It is customary to represent the sign with a bit placed
in the leftmost position of the number since binary
digits.
The convention is to make the sign bit 0 for positive
and 1for negative.
SignedBinaryNumbers
SignedBinaryNumbersArithmeticAddiTion
40
-6 11111010
+5 00000101 - 5 11111011
+11 00001011 +11 00001011
+16 00010000 +6100000110
+5 00000101 -5 11111011
-11 11110101 -11 11110101
-16111110000
SignedBinaryNumbersArithmeticSubtraction
41
Funfact: Signed Binary Subtraction is Basically
Binary Additions.
Cuz, (±A) - (+B) =(±A) +(-B)
And (±A) - (- B) =(±A) +(+ B)
(-6)-(-13) =11111010-11110011
=11111010+00001101
=00000111(+7)
Binary Code: ASCII
42
Character code
ASCII Chart
SelfStudyMaterials
Binary Code: BCD
Code
BCD Arithmetics,
Examples, Decimal
Arithmetic
Binary Code: Other
Decimal Codes
BCD (8421),2421,Excess 3,
8-4-2-1codings, Gray
Code
43
THANKS!
Any questions?
You can find me atmuhaiminbinmunir@gmail.com
44

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Number system converted