Compound Interest
Example
Calculate the interest and the
final amount if $1000 is
borrowed for 1 year at 8%.
I = prt

p (r) (t)     I        A
1000 (.08) (1) 80      1080
What if the person did not pay back
the loan? What would be the new
amount owing if he didn't pay it back
for another year?
p (r) (t)     I        A
1000 (.08) (1) 80      $1080
1080 (.08) (1) 86.40   $1166.40
What if he still didn't pay it
back for another year?
p (r) (t)        I        A
1000 (.08) (1)   80       $1080
1080 (.08) (1)   86.40    $1166.40
1166.40 (.08) (1) 93.31   $1259.71
What about another year?
p (r) (t)        I         A
1000 (.08) (1)   80        $1080
1080 (.08) (1)   86.40     $1166.40
1166.40 (.08) (1) 93.31    $1259.71

1259.71 (.08) (1) 100.78   $1360.49
Another?
p (r) (t)        I         A
1000 (.08) (1)   80        $1080
1080 (.08) (1)   86.40     $1166.40
1166.40 (.08) (1) 93.31    $1259.71

1259.71 (.08) (1) 100.78   $1360.49
1360.46 (.08) (1) 108.84   $1469.32
This is called compound
interest. The interest builds
on itself. You pay interest on
the interest.
There is a formula to answer the
  example more quickly.

       A = p (1 + r/n) nt


A = the final amount (principal plus interest)
p = the principal
r = rate in decimal form
n = the number of times interest will be paid
      in a year
t = time in years
Example
          A = p (1 + r/n) nt


              p = 1000
              r = .08
              t =5
              n=1

                       (1)(5)
   A = 1000(1 + .08/1)
   A = $1469.32
example 2
How much is owed if $1000 is borrowed
for 2 year at 6% compounded semi-
annually.

           p = 1000
           r = .06
           t=2
           n=2

     A = 1000(1 + .06/2) 2(2)
     A = $1125.51
Daily = once a day = 365 times per year
Weekly = once a week = 52 times per year
Monthly = once a month = 12 times per year
Annually = once a year = 1 times per year

Semi-annually = every 6 months = 2 times per
year
Quarterly = every 3 months = 4 times per year

March 8 Compound Interest

  • 1.
  • 2.
    Example Calculate the interestand the final amount if $1000 is borrowed for 1 year at 8%.
  • 3.
    I = prt p(r) (t) I A 1000 (.08) (1) 80 1080
  • 4.
    What if theperson did not pay back the loan? What would be the new amount owing if he didn't pay it back for another year?
  • 5.
    p (r) (t) I A 1000 (.08) (1) 80 $1080 1080 (.08) (1) 86.40 $1166.40
  • 6.
    What if hestill didn't pay it back for another year?
  • 7.
    p (r) (t) I A 1000 (.08) (1) 80 $1080 1080 (.08) (1) 86.40 $1166.40 1166.40 (.08) (1) 93.31 $1259.71
  • 8.
  • 9.
    p (r) (t) I A 1000 (.08) (1) 80 $1080 1080 (.08) (1) 86.40 $1166.40 1166.40 (.08) (1) 93.31 $1259.71 1259.71 (.08) (1) 100.78 $1360.49
  • 10.
  • 11.
    p (r) (t) I A 1000 (.08) (1) 80 $1080 1080 (.08) (1) 86.40 $1166.40 1166.40 (.08) (1) 93.31 $1259.71 1259.71 (.08) (1) 100.78 $1360.49 1360.46 (.08) (1) 108.84 $1469.32
  • 12.
    This is calledcompound interest. The interest builds on itself. You pay interest on the interest.
  • 13.
    There is aformula to answer the example more quickly. A = p (1 + r/n) nt A = the final amount (principal plus interest) p = the principal r = rate in decimal form n = the number of times interest will be paid in a year t = time in years
  • 14.
    Example A = p (1 + r/n) nt p = 1000 r = .08 t =5 n=1 (1)(5) A = 1000(1 + .08/1) A = $1469.32
  • 15.
    example 2 How muchis owed if $1000 is borrowed for 2 year at 6% compounded semi- annually. p = 1000 r = .06 t=2 n=2 A = 1000(1 + .06/2) 2(2) A = $1125.51
  • 16.
    Daily = oncea day = 365 times per year Weekly = once a week = 52 times per year Monthly = once a month = 12 times per year Annually = once a year = 1 times per year Semi-annually = every 6 months = 2 times per year Quarterly = every 3 months = 4 times per year