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Dr. A. S. Sayyad
Professor & Head
Department of Structural Engineering
Sanjivani College of Engineering, Kopargaon 423603.
(An Autonomous Institute, Affiliated to Savitribai Phule Pune University, Pune)
Finite Element Method In Civil Engineering
Shape functions for two
nodded bar element in (x, y)
coordinates
2 1
1 2
and
x x x x
N N
L L
 
 
Shape functions for two nodded bar element
in (x, y) coordinates
Let consider two nodded bar element of length L.
x1 and x2 are the Cartesian coordinates of nodes 1 and 2.
u1 and u2 are the displacements of nodes 1 and 2.
u is the displacement of any point in x-direction.
Total DOF = 02 (one at each node)
I) Displacement function
1 2
u x
 
 
In matrix form
    1
2
1
u x


 
  
 
    
u P 

--------------- (1)
where, [P] = Parametric matrix
II) Displacement function in-terms of nodal displacements
Express displacement function in terms of nodal displacements using the coordinates of
nodes x1 and x2.
1 1 1
2 2 2
1
1
u x
u x


    

   
 
    
    
e
x A 

where, [A] = Connectivity matrix
Obtained from Eq. (2) and put into the Eq. (1), we get
 

------------------- (2)
      
1
e
u P A x


    e
u N x

where [N] = Shape functions
    
1
N P A


III) Shape functions
    
   
1
1
1
2
1
1
1
N P A
x
N x
x



 
  
 
Inverse is obtained by using method of adjoin
      
1 2 1
1
1
1 1
2
x x
N P A x
 
 
   

 
1 2
2 1
1
2
N x x
N x x

   

   

   
2 1
1 2
and
x x x x
N N
L L
 
 
Sum of shape functions is always unity
Validation of properties of shape functions
2 1 2 1
1 2 1
x x x x x x L
N N
L L L L
  
     
At node 1, x=x1
2 1 1 1
1 2
1 and 0
x x L x x
N N
L L L
 
    
At node 2, x=x2
2 2 2 1
1 2
0 and 1
x x x x L
N N
L L L
 
    
Value of shape function at each node is equal to unity

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Lect20

  • 1. Dr. A. S. Sayyad Professor & Head Department of Structural Engineering Sanjivani College of Engineering, Kopargaon 423603. (An Autonomous Institute, Affiliated to Savitribai Phule Pune University, Pune) Finite Element Method In Civil Engineering Shape functions for two nodded bar element in (x, y) coordinates 2 1 1 2 and x x x x N N L L    
  • 2. Shape functions for two nodded bar element in (x, y) coordinates Let consider two nodded bar element of length L. x1 and x2 are the Cartesian coordinates of nodes 1 and 2. u1 and u2 are the displacements of nodes 1 and 2. u is the displacement of any point in x-direction. Total DOF = 02 (one at each node) I) Displacement function 1 2 u x     In matrix form     1 2 1 u x               u P   --------------- (1) where, [P] = Parametric matrix
  • 3. II) Displacement function in-terms of nodal displacements Express displacement function in terms of nodal displacements using the coordinates of nodes x1 and x2. 1 1 1 2 2 2 1 1 u x u x                         e x A   where, [A] = Connectivity matrix Obtained from Eq. (2) and put into the Eq. (1), we get    ------------------- (2)        1 e u P A x       e u N x  where [N] = Shape functions      1 N P A  
  • 4. III) Shape functions          1 1 1 2 1 1 1 N P A x N x x           Inverse is obtained by using method of adjoin        1 2 1 1 1 1 1 2 x x N P A x            1 2 2 1 1 2 N x x N x x                2 1 1 2 and x x x x N N L L    
  • 5. Sum of shape functions is always unity Validation of properties of shape functions 2 1 2 1 1 2 1 x x x x x x L N N L L L L          At node 1, x=x1 2 1 1 1 1 2 1 and 0 x x L x x N N L L L        At node 2, x=x2 2 2 2 1 1 2 0 and 1 x x x x L N N L L L        Value of shape function at each node is equal to unity