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International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4461
UNMANNED AERIAL SURVEILLANCE VEHICLE
Prof Dr Subash Gadhave1, Trisham Patil2, Ranveer Singh3, Nikhil Marwaha4, Prashant Chavan5
1Associate Professor, Dr. D. Y. Patil Institute of Technology, Pune, India.
2Student & Pune, pune
3Student & Pimpri, pune
4Student & Sangvi, pune
5Student & Pune, pune
---------------------------------------------------------------***----------------------------------------------------------------
Abstract - UAV is defined as an aerial vehicle that does not
carry a human operator, uses aerodynamic forcestoprovide
vehicle lift, can fly autonomously or be piloted remotely,can
be expandable or recoverable, and can carry a lethal or
nonlethal payload. It is controlled either autonomously by
on-board computers or by remote control of a pilot on the
ground. Its usage is currently limited by difficulties such as
satellite communication and cost. A Drone has been built
that can be operated by radio frequency controller and send
live audio-visual feedback.
The developed Drone issimulated inANSYStodetermine the
forces and the stresses induced in the drone and whether it
will hold up in various environments. The simulation shows
a very stable operation and control of the developed Drone.
Microcontroller based drone control system has also been
developed where a RF transmitter and receiver operatingin
the frequency of 2.4 GHz are used for remote operation for
the Drone.
Key Words: UASV, Aerofoil, Wing Loading, Aspect Ratio,
Empennage
1. INTRODUCTION
An UNMANNED AERIALVEHICLE (UAV),commonlyknown
as a DRONE, is an aircraft without a human pilot onboard.
UAVs are a component of an unmanned aircraft system
(UAS); which include a UAV, a ground-based controller, and
a system of communications between the two. The flight of
UAVs may operate with various degrees of autonomy:either
under remote control by a humanoperatororautonomously
by onboard computers. Compared to manned aircraft, UAVs
were originally used for missions too "dull, dirty or
dangerous" for humans. While they originated mostly in
military applications, their use is rapidly expanding to
commercial, scientific, recreational, agricultural, and other
applications, such as policing, peacekeeping and
surveillance, product deliveries, aerial photography,
smuggling, and drone racing.
In our project we are going to construct a drone (aircraft)
from scratch without copying or modifying any previously
known or existing design. In this firstly we are going to
calculate the dimensions of the drone using theoretical
formulae’s available, then according to the values obtained
from the formulae we are going to construct prototypes to
validate the calculations and modify the dimensions
accordingly after performing basic trials on the prototypes.
After performing trials on the prototypes we are going to
modify the dimensions and construct a final structurewhich
gives the most optimal performance, thethingtonotehereis
that theoretical values obtained just serve as a base for
designing the drone and that the final dimensions may vary
from the values calculated.
Lastly after constructing the drone we will perform trials
using a camera on board and then validate the structural
stability of the drone using simulation software (ANSYS).
India’s present development of Unmanned Aerial Vehicle
(UAVs) and Smaller Drones locally is pathetically low to
meet a large number of requirements felt by the Indian
Armed forces, with technology trajectory of UAV’s and
Drones moving to next level in the usage of their military
applications.
Fig.1 A Hand launched UASV.
2. METHODOLOGY
India is one of the fastest developing countries in the world
and its need for advanced technologies is on the rise to
counter the various problems that it faces, internationally
and domestically. These problems range from military
surveillance to traffic managementandforestsurveys.In our
project we are attempting to design and construct a drone
which will help tackling the above mentioned problems.
In our project we are going to design and construct a drone
from scratch. At first we finalised the span of the wings and
then depending on the approximatetotal weightofthedrone
we designed the air foil of the shape to achieve the desired
lift for a given speed.
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4462
Then we designed the fuselage, the shapeofthefuselage was
chosen as a square, but the edges would be made round to
prevent excessive drag. The length of the fuselage and the
position of the tail, rudder and wings was finalised
depending upon the size of the wings, as the wings are
ultimately responsible for the lift of the drone. Then on
calculating the actual weight of the drone the type of motor
and the propeller dimensions were finalised and calculated.
At the end we are going to create a 3D model of the drone
and simulate it in ANSYS software to find out the stresses
and load acting in various conditions.Variousvelocitiessuch
as the stall velocity, maximum velocity will be calculated.
Then the size of the batteries will be finalised depending
upon the range of the drone, and the mechatronics system
which includes the remote receivers will be attached to
match with the functionality of the drone.
Fig. 2: Project Methodology
3. DESIGN PROCEDURE AND CALCULATION
1. Wing Design- To estimate the wing parameters, a value
for wing loading (W/S) needstobechosen.Afterconsidering
similar airplanes, an initial estimate for (W/S) is taken as 6
kg/ .
S= Wing surface area ( )
Wl=Wing loading (kg/ ) =6 kg/
Wing span (b) can be calculated from S and A (Aspect Ratio).
A= 7 (for a glider)
b= = =3.8 m
But, one of the important aspect of our droneisthatitshould
be easily accommodated in a backpack and readily
assembled, keeping this in mindandtheapproximateweight
of our drone we decided on the wing span accordingly.
Wing Span (b) =120cm=1.2m
According to the new wing span which we have selected, we
get
The root chord (r) and tip chord (t) of the wing can be
obtained using the following equations.
Ω=taper ratio=0.8 (for high wing gliders)
r=
Similarly
t=0.23m
2. Wing Planform- We have used a combination of
rectangular and elliptical wings because an elliptical wing is
a wing planform shape that minimizes induced drag.
3. Aspect Ratio-
Aspect Ratio=
Mean Chord=
Tip Chord=20cm=0.2m
Root Chord=17.5cm=0.175m
Mean Chord= 18.75cm=0.1875m
Aspect Ratio (AR) = 6.5:1
4. Wing Loading- Wing Loading (Approximate) = Total
weight of the aircraft/ wing area
Total Approximate weight of the drone= 1.25 kg=1250gm
Wing area=wing span*mean chord=120*18.75=2250 cm
sq=0.2250
Wing Loading=5.55kg/
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4463
5. Air Foil Design- The airfoil which we have selected is
Selig S7055 low Reynolds number airfoil or S7055
airfoil.
6. Spar Design Spar Thickness= 2cm
7. Sizing the Stabilizer Surfaces (Analytical Calculation)
 Horizontal Tail Volume Ratio
Cht= Horizontal Tail Volume Coefficient=0.5(fromtheabove
table)
Sht= Horizontal Tail Surface Area
Lht= Length between the aerodynamic centers of the wing
and horizontal tail plane=0.55m (approximated)
Sw= Wing Surface Area= 0.225
MAC= Mean Air Chord= 0.185m
t
bh= width of the horizontal tail
Ah= aspect ratio of horizontal tail surface=3.5 (taken as half
of aspect ratio of the wing)
So we have,
 Vertical Tail Volume Ratio
We get Shv=0.01665
8. Design of control surfaces:
 Aileron Design
Type of Aileron used= Strip Aileron
Length of the aileron= 60cm on each wing=0.6m
Breadth of the aileron= 5cm=0.05m
Thickness of the aileron=0.2cm=0.002m
Design of rudder and elevator
 Rudder
Length=0.175m
Width=0.065m
 Elevator
Length=0.145m
Width=0.06m
9. Fuselage Design: Length of the fuselage (LF) = 0.85m
Centre of gravity position from the start of the fuselage
is=0.275m
Total Surface Area of fuselage=0.2975
Width of the fuselage (Wf) = 10cm=0.1m
Thickness of the fuselage=4mm=0.004m
Distance between elevator and center of gravity=0.575m
Distance between the propeller and centerof gravity=0.33m
10. Avionics: Motor, Receiver, Transmitter, Battery,
Electronic Speed Control, Propeller, Servo Motors
11. Performance Analysis of the plane:
a. Obtaining the minimum, maximum and operating
velocity
As the maximum Reynolds number is 500,000(because
above this the flow of air becomes turbulentoverthewings),
the formula for Reynolds number is
Re =
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4464
Density of air = 1.225kg/cc
Chord Length = 0.1875m
Dynamic viscosity of air = 0.0000179kg/m/s
Re = 500,000, calculating the velocity we get v=140.4kmph,
At this high velocity it is impossible to control the aircraft,
hence the maximum Reynolds number is selected as
250,000, which gives a maximum velocity of 71kmph,
The Reynolds number for operational velocity was selected
as 200,000 which gives operational velocity as 56kmph,
b. Analytically proving the values calculated are correct
(for steady level flight)
To prove that at the given Reynolds number we get the
appropriate amount of lift,
a) Re = 250,000
Coefficient of lift = 1.423
Lift
= N
Lift = 74.11N
Weight of the aircraft= N
= 1.25 9.81
=12N
As we observe that the lift generated by the aircraft is more
than the weight of the plane the plane will rise and not stall.
b) Re=200,000
Coefficient of lift=1.383
Lift= N
Lift=45.7N
Weight of the aircraft= N
= 1.25 9.81
=12N
As we observe that the lift generated by the aircraft is more
than the weight of the plane the plane will rise and not stall.
c) Re=100,000
Coefficient of lift=1.316
Lift= N
Lift=11.8N
Weight of the aircraft= N
= 1.25 9.81
=12N
As we observe that the lift generated by the aircraft
approximately equal to the weight of the aircraft the aircraft
will start to loose height which gives the minimum speed of
the aircraft i.e. 26kmph
c. Determining the maximum angle of attack
At Re=200,000 the coefficient of lift is=1.383 and the
Maximum angle of attack (AOA) =12.815 degrees
For Re= 25000 Coefficient of lift= 1.423
Maximum angle of attack (AOA) = 12.815 degrees,
From the graphs we found out the maximum angle of attack
for the aircraft which is 12.85 degrees as above this angle of
attack the plane will stall.
 AOA max=12.85˚
d. Thrust Calculations
In this section below we have calculatedtheminimumthrust
required to get the plane of the ground.
Prerequisite formulae and values-
1) L(Lift)
(N)
2) W(Weight of the plane)= Mass×9.81(N)
3) T=Thrust(N)
4) D(Drag)=
5) Coefficient of lift=1.4
6) Density of air=1.225 kg/
7) Wing surface area=0.225
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4465
8) Coefficient of drag=0.05
9) Total surface area= wing area+fuselage
area+empennage area=2.0025
Now for achieving lift, the Lift force should be greater than
the weight of the plane,
So L W, from this equation we will calculate the minimum
velocity required for take-off, so converting the greaterthan
sign to equality sign we get,
L
W=1.225 =12.01725N
So, =12.01725N
V=7.971 m/s or 28.7 kmph (Minimum Velocity required for
take-off)
This velocity will be generated due to the thrust provided,
now for the plane to move forward and generate enough lift,
thrust should be greater than drag force,
So we have, T
Removing the greater than symbol and converting it into
equality
T= 4N
e. The minimum thrust required for lift is 4N.
f. Endurance of the aircraft- Endurance of the aircraft is
the maximum time the aircraft can stay in the air.
Case 1- The motor is operating at full capacity drawing 35A
current.
Using a 2200 mah battery we have the endurance as
=3.77min
 The endurance of the aircraft at maximum power is
3.77min
Case 2- The motor is operating at minimum capacity of 16A
current
 Using a 2200 mah battery we havetheenduranceas
8.25 min.
Case 3- The motor is used at an optimal current of 26A (mid
throttle position)
 We have endurance of the aircraft as 5min.
g. Range of the aircraft is 1.5 km and can be varied using
a different set of transmitter and receivers.
h. Rate of climb
In order to increase altitude, we must add energy to the
aircraft. We can do this by increasing the thrust or power
available. If we do that, one of three things can happen:
1. We will increase kinetic energy (accelerate).
2. We will increase potential energy (climb).
3. We will do both, accelerate and climb.
If we desire to climb, we should hold the airspeed constant
and use all excess power to increase our potential energy.
Consequently, if we assume that we keep the airspeed
approximately constant (called the quasi-steady
assumption), then the governing equations become:
T-D-WsinΩ=mv=0
L-WcosΩ=0=mvΩ …… (1)
H=VsinΩ
Where,
T- Thrust available
D- Total drag of the aircraft
W- Weight of the aircraft
L- Lift of the aircraft
Ω- Climb angle
H-Rate of climb
The first equation gives us the result:
sinΩ= ………… (2)
Hence angle of climb is related to the excess of thrust
available over the thrust required. The rate of climb can be
obtained by substituting Eq. (2) for the sine term in the rate
of climb equation:
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4466
H=
So let us find the rate of climb for the optimum speed of
71kmph, the other values we have are
Tmax=330W=16.75N for 71kmph
W=1.25×9.81=12.265N
D=9.726N for speed of 71kmph
 So we have H=11.28 m/s.
Fig- 3D Representation of the drone.
Fig- Velocity distribution over the plane
Fig-Pressure distribution over the plane.
5. CONCLUSIONS
We have presented a model and control methodology to
construct an unmanned aerial vehicle using the standard
design procedures. By characterizing the forces and torques
experienced by the UAV during bothflight andmanipulation,
we have designed the structure to handle the before
mentioned forces and also to compensate for reactionary
forces.
Our simulation and test results indicate that the UAV is
stable and satisfies the prerequisitefunctionsthatitneedsto
without any difficulties. Motion capture using a camera does
not disrupt aircraft stability and enables us to capture High
Resolution videos and photos.
REFERENCES
1. Design and Development of Unmanned Aerial
Vehicle (Drone) for Civil Applications, A Thesis
submitted to the Dept. of Electrical & Electronic
Engineering, BRAC University in partial fulfillment
of the requirements for the Bachelor of Science
degree in Electrical & Electronic Engineering by
Pran Kanai Saha(2014).
2. GATE PATHSHALA Educational Services Llp.
(www.gatepathshala.com), Concept of Tail Volume
to size Horizontal and Vertical tails.
3. Design of a low cost powered r/c combat airplane
and manufacturing plan by jonathan n. bailey,
California Polytechnic State University San Luis
Obispo (2016).
4. Journal of Communications Vol. 11, No. 2, February
2016, Introduction of Real-Time Video Surveillance
System Using UAV, Hwan-Chul Kim, Choong-Soo
Lim, Chang-Seok Lee, and Jeong-Hun Choi.
5. IJERT Issue 12, Vol 3, December 2014, Systematic
approach for building, analyzing and designing a
model RC plane, Shreyas Hegde, Sandeep Nayak.
6. IJSRD - International Journal for Scientific Research
& Development| Vol. 3, Issue 02, 2015, Radio
Controlled Airplane, Omkar Bhosle, Rohit Varpe,
Mahesh Pula.
7. The pilot's handbook of aeronautical knowledge,
Paul E Illman, December 1990, Page no 1-200
8. Radio Controlled Airplane, Department of
Electronics Engineering, Omkar Bhosle, Rohit
Varpe,Mahesh Phula, MH Saboo Siddik College of
Engineering, IJSRD - International Journal for
Scientific Research & Development| Vol. 3, Issue02,
2015 | ISSN (online): 2321-0613

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IRJET- Unmanned Aerial Surveillance Vehicle

  • 1. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4461 UNMANNED AERIAL SURVEILLANCE VEHICLE Prof Dr Subash Gadhave1, Trisham Patil2, Ranveer Singh3, Nikhil Marwaha4, Prashant Chavan5 1Associate Professor, Dr. D. Y. Patil Institute of Technology, Pune, India. 2Student & Pune, pune 3Student & Pimpri, pune 4Student & Sangvi, pune 5Student & Pune, pune ---------------------------------------------------------------***---------------------------------------------------------------- Abstract - UAV is defined as an aerial vehicle that does not carry a human operator, uses aerodynamic forcestoprovide vehicle lift, can fly autonomously or be piloted remotely,can be expandable or recoverable, and can carry a lethal or nonlethal payload. It is controlled either autonomously by on-board computers or by remote control of a pilot on the ground. Its usage is currently limited by difficulties such as satellite communication and cost. A Drone has been built that can be operated by radio frequency controller and send live audio-visual feedback. The developed Drone issimulated inANSYStodetermine the forces and the stresses induced in the drone and whether it will hold up in various environments. The simulation shows a very stable operation and control of the developed Drone. Microcontroller based drone control system has also been developed where a RF transmitter and receiver operatingin the frequency of 2.4 GHz are used for remote operation for the Drone. Key Words: UASV, Aerofoil, Wing Loading, Aspect Ratio, Empennage 1. INTRODUCTION An UNMANNED AERIALVEHICLE (UAV),commonlyknown as a DRONE, is an aircraft without a human pilot onboard. UAVs are a component of an unmanned aircraft system (UAS); which include a UAV, a ground-based controller, and a system of communications between the two. The flight of UAVs may operate with various degrees of autonomy:either under remote control by a humanoperatororautonomously by onboard computers. Compared to manned aircraft, UAVs were originally used for missions too "dull, dirty or dangerous" for humans. While they originated mostly in military applications, their use is rapidly expanding to commercial, scientific, recreational, agricultural, and other applications, such as policing, peacekeeping and surveillance, product deliveries, aerial photography, smuggling, and drone racing. In our project we are going to construct a drone (aircraft) from scratch without copying or modifying any previously known or existing design. In this firstly we are going to calculate the dimensions of the drone using theoretical formulae’s available, then according to the values obtained from the formulae we are going to construct prototypes to validate the calculations and modify the dimensions accordingly after performing basic trials on the prototypes. After performing trials on the prototypes we are going to modify the dimensions and construct a final structurewhich gives the most optimal performance, thethingtonotehereis that theoretical values obtained just serve as a base for designing the drone and that the final dimensions may vary from the values calculated. Lastly after constructing the drone we will perform trials using a camera on board and then validate the structural stability of the drone using simulation software (ANSYS). India’s present development of Unmanned Aerial Vehicle (UAVs) and Smaller Drones locally is pathetically low to meet a large number of requirements felt by the Indian Armed forces, with technology trajectory of UAV’s and Drones moving to next level in the usage of their military applications. Fig.1 A Hand launched UASV. 2. METHODOLOGY India is one of the fastest developing countries in the world and its need for advanced technologies is on the rise to counter the various problems that it faces, internationally and domestically. These problems range from military surveillance to traffic managementandforestsurveys.In our project we are attempting to design and construct a drone which will help tackling the above mentioned problems. In our project we are going to design and construct a drone from scratch. At first we finalised the span of the wings and then depending on the approximatetotal weightofthedrone we designed the air foil of the shape to achieve the desired lift for a given speed.
  • 2. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4462 Then we designed the fuselage, the shapeofthefuselage was chosen as a square, but the edges would be made round to prevent excessive drag. The length of the fuselage and the position of the tail, rudder and wings was finalised depending upon the size of the wings, as the wings are ultimately responsible for the lift of the drone. Then on calculating the actual weight of the drone the type of motor and the propeller dimensions were finalised and calculated. At the end we are going to create a 3D model of the drone and simulate it in ANSYS software to find out the stresses and load acting in various conditions.Variousvelocitiessuch as the stall velocity, maximum velocity will be calculated. Then the size of the batteries will be finalised depending upon the range of the drone, and the mechatronics system which includes the remote receivers will be attached to match with the functionality of the drone. Fig. 2: Project Methodology 3. DESIGN PROCEDURE AND CALCULATION 1. Wing Design- To estimate the wing parameters, a value for wing loading (W/S) needstobechosen.Afterconsidering similar airplanes, an initial estimate for (W/S) is taken as 6 kg/ . S= Wing surface area ( ) Wl=Wing loading (kg/ ) =6 kg/ Wing span (b) can be calculated from S and A (Aspect Ratio). A= 7 (for a glider) b= = =3.8 m But, one of the important aspect of our droneisthatitshould be easily accommodated in a backpack and readily assembled, keeping this in mindandtheapproximateweight of our drone we decided on the wing span accordingly. Wing Span (b) =120cm=1.2m According to the new wing span which we have selected, we get The root chord (r) and tip chord (t) of the wing can be obtained using the following equations. Ω=taper ratio=0.8 (for high wing gliders) r= Similarly t=0.23m 2. Wing Planform- We have used a combination of rectangular and elliptical wings because an elliptical wing is a wing planform shape that minimizes induced drag. 3. Aspect Ratio- Aspect Ratio= Mean Chord= Tip Chord=20cm=0.2m Root Chord=17.5cm=0.175m Mean Chord= 18.75cm=0.1875m Aspect Ratio (AR) = 6.5:1 4. Wing Loading- Wing Loading (Approximate) = Total weight of the aircraft/ wing area Total Approximate weight of the drone= 1.25 kg=1250gm Wing area=wing span*mean chord=120*18.75=2250 cm sq=0.2250 Wing Loading=5.55kg/
  • 3. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4463 5. Air Foil Design- The airfoil which we have selected is Selig S7055 low Reynolds number airfoil or S7055 airfoil. 6. Spar Design Spar Thickness= 2cm 7. Sizing the Stabilizer Surfaces (Analytical Calculation)  Horizontal Tail Volume Ratio Cht= Horizontal Tail Volume Coefficient=0.5(fromtheabove table) Sht= Horizontal Tail Surface Area Lht= Length between the aerodynamic centers of the wing and horizontal tail plane=0.55m (approximated) Sw= Wing Surface Area= 0.225 MAC= Mean Air Chord= 0.185m t bh= width of the horizontal tail Ah= aspect ratio of horizontal tail surface=3.5 (taken as half of aspect ratio of the wing) So we have,  Vertical Tail Volume Ratio We get Shv=0.01665 8. Design of control surfaces:  Aileron Design Type of Aileron used= Strip Aileron Length of the aileron= 60cm on each wing=0.6m Breadth of the aileron= 5cm=0.05m Thickness of the aileron=0.2cm=0.002m Design of rudder and elevator  Rudder Length=0.175m Width=0.065m  Elevator Length=0.145m Width=0.06m 9. Fuselage Design: Length of the fuselage (LF) = 0.85m Centre of gravity position from the start of the fuselage is=0.275m Total Surface Area of fuselage=0.2975 Width of the fuselage (Wf) = 10cm=0.1m Thickness of the fuselage=4mm=0.004m Distance between elevator and center of gravity=0.575m Distance between the propeller and centerof gravity=0.33m 10. Avionics: Motor, Receiver, Transmitter, Battery, Electronic Speed Control, Propeller, Servo Motors 11. Performance Analysis of the plane: a. Obtaining the minimum, maximum and operating velocity As the maximum Reynolds number is 500,000(because above this the flow of air becomes turbulentoverthewings), the formula for Reynolds number is Re =
  • 4. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4464 Density of air = 1.225kg/cc Chord Length = 0.1875m Dynamic viscosity of air = 0.0000179kg/m/s Re = 500,000, calculating the velocity we get v=140.4kmph, At this high velocity it is impossible to control the aircraft, hence the maximum Reynolds number is selected as 250,000, which gives a maximum velocity of 71kmph, The Reynolds number for operational velocity was selected as 200,000 which gives operational velocity as 56kmph, b. Analytically proving the values calculated are correct (for steady level flight) To prove that at the given Reynolds number we get the appropriate amount of lift, a) Re = 250,000 Coefficient of lift = 1.423 Lift = N Lift = 74.11N Weight of the aircraft= N = 1.25 9.81 =12N As we observe that the lift generated by the aircraft is more than the weight of the plane the plane will rise and not stall. b) Re=200,000 Coefficient of lift=1.383 Lift= N Lift=45.7N Weight of the aircraft= N = 1.25 9.81 =12N As we observe that the lift generated by the aircraft is more than the weight of the plane the plane will rise and not stall. c) Re=100,000 Coefficient of lift=1.316 Lift= N Lift=11.8N Weight of the aircraft= N = 1.25 9.81 =12N As we observe that the lift generated by the aircraft approximately equal to the weight of the aircraft the aircraft will start to loose height which gives the minimum speed of the aircraft i.e. 26kmph c. Determining the maximum angle of attack At Re=200,000 the coefficient of lift is=1.383 and the Maximum angle of attack (AOA) =12.815 degrees For Re= 25000 Coefficient of lift= 1.423 Maximum angle of attack (AOA) = 12.815 degrees, From the graphs we found out the maximum angle of attack for the aircraft which is 12.85 degrees as above this angle of attack the plane will stall.  AOA max=12.85˚ d. Thrust Calculations In this section below we have calculatedtheminimumthrust required to get the plane of the ground. Prerequisite formulae and values- 1) L(Lift) (N) 2) W(Weight of the plane)= Mass×9.81(N) 3) T=Thrust(N) 4) D(Drag)= 5) Coefficient of lift=1.4 6) Density of air=1.225 kg/ 7) Wing surface area=0.225
  • 5. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4465 8) Coefficient of drag=0.05 9) Total surface area= wing area+fuselage area+empennage area=2.0025 Now for achieving lift, the Lift force should be greater than the weight of the plane, So L W, from this equation we will calculate the minimum velocity required for take-off, so converting the greaterthan sign to equality sign we get, L W=1.225 =12.01725N So, =12.01725N V=7.971 m/s or 28.7 kmph (Minimum Velocity required for take-off) This velocity will be generated due to the thrust provided, now for the plane to move forward and generate enough lift, thrust should be greater than drag force, So we have, T Removing the greater than symbol and converting it into equality T= 4N e. The minimum thrust required for lift is 4N. f. Endurance of the aircraft- Endurance of the aircraft is the maximum time the aircraft can stay in the air. Case 1- The motor is operating at full capacity drawing 35A current. Using a 2200 mah battery we have the endurance as =3.77min  The endurance of the aircraft at maximum power is 3.77min Case 2- The motor is operating at minimum capacity of 16A current  Using a 2200 mah battery we havetheenduranceas 8.25 min. Case 3- The motor is used at an optimal current of 26A (mid throttle position)  We have endurance of the aircraft as 5min. g. Range of the aircraft is 1.5 km and can be varied using a different set of transmitter and receivers. h. Rate of climb In order to increase altitude, we must add energy to the aircraft. We can do this by increasing the thrust or power available. If we do that, one of three things can happen: 1. We will increase kinetic energy (accelerate). 2. We will increase potential energy (climb). 3. We will do both, accelerate and climb. If we desire to climb, we should hold the airspeed constant and use all excess power to increase our potential energy. Consequently, if we assume that we keep the airspeed approximately constant (called the quasi-steady assumption), then the governing equations become: T-D-WsinΩ=mv=0 L-WcosΩ=0=mvΩ …… (1) H=VsinΩ Where, T- Thrust available D- Total drag of the aircraft W- Weight of the aircraft L- Lift of the aircraft Ω- Climb angle H-Rate of climb The first equation gives us the result: sinΩ= ………… (2) Hence angle of climb is related to the excess of thrust available over the thrust required. The rate of climb can be obtained by substituting Eq. (2) for the sine term in the rate of climb equation:
  • 6. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 4466 H= So let us find the rate of climb for the optimum speed of 71kmph, the other values we have are Tmax=330W=16.75N for 71kmph W=1.25×9.81=12.265N D=9.726N for speed of 71kmph  So we have H=11.28 m/s. Fig- 3D Representation of the drone. Fig- Velocity distribution over the plane Fig-Pressure distribution over the plane. 5. CONCLUSIONS We have presented a model and control methodology to construct an unmanned aerial vehicle using the standard design procedures. By characterizing the forces and torques experienced by the UAV during bothflight andmanipulation, we have designed the structure to handle the before mentioned forces and also to compensate for reactionary forces. Our simulation and test results indicate that the UAV is stable and satisfies the prerequisitefunctionsthatitneedsto without any difficulties. Motion capture using a camera does not disrupt aircraft stability and enables us to capture High Resolution videos and photos. REFERENCES 1. Design and Development of Unmanned Aerial Vehicle (Drone) for Civil Applications, A Thesis submitted to the Dept. of Electrical & Electronic Engineering, BRAC University in partial fulfillment of the requirements for the Bachelor of Science degree in Electrical & Electronic Engineering by Pran Kanai Saha(2014). 2. GATE PATHSHALA Educational Services Llp. (www.gatepathshala.com), Concept of Tail Volume to size Horizontal and Vertical tails. 3. Design of a low cost powered r/c combat airplane and manufacturing plan by jonathan n. bailey, California Polytechnic State University San Luis Obispo (2016). 4. Journal of Communications Vol. 11, No. 2, February 2016, Introduction of Real-Time Video Surveillance System Using UAV, Hwan-Chul Kim, Choong-Soo Lim, Chang-Seok Lee, and Jeong-Hun Choi. 5. IJERT Issue 12, Vol 3, December 2014, Systematic approach for building, analyzing and designing a model RC plane, Shreyas Hegde, Sandeep Nayak. 6. IJSRD - International Journal for Scientific Research & Development| Vol. 3, Issue 02, 2015, Radio Controlled Airplane, Omkar Bhosle, Rohit Varpe, Mahesh Pula. 7. The pilot's handbook of aeronautical knowledge, Paul E Illman, December 1990, Page no 1-200 8. Radio Controlled Airplane, Department of Electronics Engineering, Omkar Bhosle, Rohit Varpe,Mahesh Phula, MH Saboo Siddik College of Engineering, IJSRD - International Journal for Scientific Research & Development| Vol. 3, Issue02, 2015 | ISSN (online): 2321-0613