The document contains 8 algebra word problems asking to solve for the value of "a". A step-by-step solution is shown for each problem, with the work shown to isolate the variable "a" on one side of the equation. The solutions found are: a = 9, 15, 4, 36, 3, 5, -9, 5, 3, and 4.

1. 3rd
– 4th
Grader Fremont, CA Kids
Introduction to Algebra
Solveall of following questions for thevalueof “a” and show thework.
1) 3 + a = 12 2) a – 3 = 12
3) 3a = 12 4) a/3 = 12
5) 3+ 3a = 12 6) 3a – 3 = 12
7) a + 12 = 3 8) a + 3 ( 5 ) = 20
9) 2 ( 7 + a) = 20 2 (7 – a) = 6

2. 3rd
– 4th
Grader Fremont, CA Kids
STEP BY STEP SOLUTION
Solveall of following questions for thevalueof “a” and show thework.
3 + a = 12
3 + a – 3 = 12 – 3
a = 9
a – 3 = 12
a – 3 + 3 = 12 + 3
a = 15
3a = 12
3a/3 =12/3
a = 4
a/3 = 12
a/3 x 3 = 12 x 3
a = 36
3+ 3a = 12
3 + 3a – 3 = 12 –3
3a = 9
3a/3 =9/3
a = 3
3a – 3 = 12
3a – 3 + 3 = 12 +3
3a = 15
3a/3 =15/3
a = 5
a + 12 = 3
a +12 – 12 =3 – 12
a = - 9
a + 3 ( 5 ) = 20
a + 15 = 20
a + 15 -15 =20 – 15
a = 5
2 ( 7 + a) = 20
14 + 2a = 20
14 + 2a – 14 = 20 –14
2a = 6
2a/2 =6/2
A = 3
2 (7 – a) = 6
14 – 2a = 6
14 – 2a - 14 =6 – 14
-2a = -8
-2a/2 = -8/2
-a = -4  a = 4