1. THEORY 4 TWINS
All prime numbers, except for 2 and 3, are located, or to 6n-1, 6n + 1, for designating
the specified rank without +1 or -1, I would use the notation 6n + -1.
All the numbers, which are not of the form 6n + -1 is divisible by 2 or by 3.
The 6n + -1, are of two kinds:
there are those who are prime numbers and those who are not prime numbers because
they are the product of
multiplying two 6n + -1:
list of 6n + -1 prime numbers, less than 100:
5-7-11-13-17-19-23-29-31-37-41-43-47-53-59-61-71-73-79-83-89-97
List of 6n + -1, which are not prime numbers, less than 100:
25-35-49-55-65-77-85-91-95
Decomposition of 6n + -1, which are not prime:
25 = 5 x 5
35 = 5 x 7
49 = 7 x 7
55 = 5 x 11
65 = 5 x 13
77 = 7 x 11
85 = 5 x 17
91 = 7 x 13
95 = 5 x 19
We can see that the not prime numbers 6n + -1, are the products of multiplying two 6n +
-1
There are only twins, which can take four different forms, I
designated VFAB:
V = The real twins or if both numbers are prime.
F = Fraternal twins: case both numbers are multiples.
A: half-twins A: the first number is the first and the second multiple
B: Half-twins B: the first number is the first and second multiple.
5 -7 = V
11 -13 = V
17 -19 = V
23 -25 = A
29 -31 = V
35 -37 = B
41 - 43 = V
47 - 49 = A
53 - 55 = A
2. 59 - 61 = V
65 - 67 = B
71 - 73 = V
77 - 79 = B
83 - 85 = A
89 - 91 = A
95 - 97 = B
This explains the differences variables, separating pairs of twins, we still do not know how
to calculate 6n + -1 first by against-we know how to calculate 6n + -1, which are not
prime.
Now determine how many of the 6n + -1, located at 6n + -1, which is what we'll see.
To simplify, I would designate a prime number with the letter P and 6n + -1, which are not
first with the letters PP,
Pou identify its multiple of 6n + -1, located 6n + -1, it suffices to apply P + (Px4) + (Px2)
if the number is prime or Pp + (Ppx4) + (Ppx2) when is a multiple.
Example 5:
5+ (5 × 4) + (5 × 2) = 5 + 20 + 10,
This gives us the following:
5 + 20 + 10 + 20 + 10 + 20 + 10 + 20 + 10 .. ...... (n + -1) + 20 + 10 ... ..∞
the results:
25; 35; 55; 65; 85; 95; 115; 125; 145; 155; 175 ...... ..∞
You can see that by dividing the results by 5 we fall on 6n + -1
25: 5 = 5
35: 5 = 7
55: 5 = 11
65: 5 = 13
85: 5 = 17
95: 5 = 19
115: 5 = 23
125: 5 = 25
145: 5 = 29
155: 5 = 31
175: 5 = 35