Gymnosperms differ from both extinct and extant (living) ferns becaus.pdf

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Gymnosperms differ from both extinct and extant (living) ferns because they A) are woody. B) have macrophylls. C) have pollen. D) have sporophylls. E) have spores Which of the following statements is true of the pine life cycle? A) Cones are homologous to the capsules of moss plants. B) The pine tree is a gametophyte. C) Male and female gametophytes are in close proximity during gamete synthesis. D) Conifer pollen grains contain male gametophytes. E) Double fertilization is a relatively common phenomenon. Which structure is common to both gymnosperms and angiosperms? A) stigma B) carpel C) ovule D) ovary E) anthers What is true of stamens, sepals, petals, carpels, and pine cone scales? A) They are female reproductive pans. B) None are capable of photosynthesis. C) They are modified leaves. D) They are found on flowers. E) They are found on angiosperms. Which of the following is a characteristic of all angiosperms? A) complete reliance on wind as the pollinating agent B) double internal fertilization C) free-living gametophytes D) carpels that contain microsporangia E) ovules that are not contained within ovaries Which of the following statements is true of monocots? A) They are currently thought to be polyphyletic. B) The veins of their leaves form a netlike pattern C) They, along with the eudicots, magnoliids, and basal angiosperms, are currently placed in the phylum Anthophyta D) Each possesses multiple cotyledons. E) They are in the clade that includes most of our crops, except the cereal grains. Solution Ans 7 C have pollen Gametophytes produce seeds whereas fern reproduce through spores. Female plant gets fertilised with sperm containing sperm to produce seeds..

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QUESTION 1 All of the following are parts of a flower except the A. carpel. B. ovary. C. fruit. D. stamen. E. cuticle. QUESTION 2 The segmented worms of the phylum Annelida A. have an open circulatory system. B. possess setae on each segment. C. are acoelomate. D. display radial symmetry. E. move by use of flagella. QUESTION 3 In bryophytes, the rhizoids A. obtain nutrients. B. are involved in reproduction. C. obtain water. D. lure possible prey. E. serve as attachment structures. QUESTION 4 Which of the following is not a characteristic differentiating Neanderthals from modern humans? A. Neanderthals had smaller brains. B. Neanderthals had larger noses. C. Neanderthals had projecting brow ridges. D. Neanderthals were shorter. E. Neanderthals were stronger. QUESTION 5 Fungi exhibit certain characteristics. One of these characteristics is that they A. are capable of carrying on photosynthesis. B. lack cell nuclei. C. reproduce using seeds and pollen. D. reproduce using spores. E. are prokaryotes. QUESTION 6 In plants, the secondary metabolites are primarily responsible for A. food gathering. B. nutrition. C. defense. D. protection against ultraviolet radiation. E. overcoming air pollutants. QUESTION 7 In cnidarians, nematocysts are important in A. obtaining oxygen from the water. B. obtaining prey. C. movement. D. excretion of wastes. E. food digestion. QUESTION 8 Cnidarians and ctenophores are similar in that they both have A. a pseudocoel. B. a digestive tract with two openings. C. radial symmetry. D. mesoderm. E. nematocysts. QUESTION 9 All members of the phylum Chordata share A. exoskeletons. B. gills present throughout their lives. C. tails present throughout their lives. D. a vertebral column. E. a notochord present sometime in their lives. QUESTION 10 It is generally thought that animals have undergone four major physiological and anatomical innovations during their evolution. These are (in no particular order) A. development of tissues, photosynthesis, bilateral symmetry, multicellularity. B. development of the versatile forelimb, multicellularity, origin of patterns of embryonic development, development of tissues. C. multicellularity, bilateral symmetry, origin of patterns of embryonic development, development of tissues. D. bilateral symmetry, development of tissues, origin of the multichambered heart, origin of patterns of embryonic development. E. origin of patterns of embryonic development, development of the versatile forelimb, origin of the multichambered heart, multicellularity. QUESTION 11 Mammals have two traits that set them apart from all other animals. These are A. body hair or fur, and being homeothermic. B. four-chambered heart and milk production. C. amniotic eggs and milk production. D. body hair or fur, and milk production. E. four-chambered heart and body hair or fur. QUESTION 12 Which of the following characteristics is not shared by typical birds and mammals? A. four limbs B. insulating skin ...

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Bryophytes are mostly terrestrial plants. They are found in moist shady places. But they need water for fertilization and completion of their life cycle. Hence they are called ‘amphibious plants’. They include approximately 960 genera and about 25,000 species. Life cycle of Bryophytes shows sporophytic and gametophytic stages.. Bryophytes have root-like structures called rhizoids. Rhizoids are unicellular in liverworts while multicellular in mosses.

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Be able to give an example of each category of plants (angiosperm, gymnosperm, etc.) Solution Gymnosperms means naked seed.gymnosoerms are mostly found in trees,shrubs and climbers.mostly they remain evergreen..example__fir trees,spruce trees,pine trees,cykafs and ginkgo trees. Angiosperms evolve from gymnosperms.Their flowers are their reproductive organs.Examples of angiosperms include oak trees,forsythias,daisies,birches,lilies,lilac bushes,maples,roses ,sunflowersetc... Angiosperms are further classified into monocots and eudicots... Monocots are known for having one original leaf from their seed,parallel veins in their leaves,flower parts in multiple of three, and a fibrous root system.examples of monocots aregarlic ,onions,wheat,rice, asparagus,lilies,orchids,grasses, potatoes, cauliflower, tomatoes,peas,beans,etc Eudicots vary from monocots by having two original leaves from their seed,branched veins,flower parts in multiples of four or five.examples of eudicots are maples,forget me not, cabbage,buttercup etc. Others category of plants include ferns.it is seedless vascular plant and reproduce by use of spores..Examples of ferns are holly fern which grows best inUS department of agriculture plant,, cinnamon fern,fishbone fern,bracken etc.

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3. Ant mutualists defend some species of plants by clearing neighboring plants and removing pest insects. What services does the plant provide in return?: a. Extrafloral nectaries, which are primarily rich in amino acids. b. Protein rich Beltian bodies. c. A protected enclosure to call home. d. B and C . e. All of the above 4. You're rummaging in the leaf litter and come across an interesting caterpillar-like larva, but you're unsure whether it's a member of the Symphyta or the Lepidoptera. To tell them apart you look for: a. Three pairs of true legs. b. A well-defined sclerotized head capsule. c. Prolegs that do not have crochets. d. Chewing mandibles versus sucking mouthparts. e. Who isn't vibing. 5. You come across a winged male insect and being a world-renowned myrmecologist, you immediately know it is an ant because of the following character(s) (circle any): a. The antennae are elbowed. b. The insect lacks a stinger. c. Only male ants have wings. d. It is not married to your uncle e. The mesosoma is separated from the gaster by a humped pedicel. 6. Which statements about insect symbionts are correct?: a. Alimentary tract symbionts are frequently transferred vertically, via eggs of the host. b. Endosymbionts are most commonly transferred horizontally, for instance by anal feeding by the host. c. Primary endosymbionts frequently evolve in parallel with their insect hosts. d. Secondary endosymbionts are typically obligate mutualists with their insect hosts. e. All of the above. 7. The Lepidopteran family a. Gracillaridae; particularly rapid metamorphosis. b. Sphingidae; when the pupa is able to move around. c. Agromyzidae; dramatic morphological changes between instars. d. Gracillaridae; dramatic morphological changes between instars. .

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The _________ is the protective chamber that houses the ovule and Later matures to become the fruit. A. Petal B. Ovary C. Carpel D. Stigma E. Sepals. What adaptation enhances bird\'s flying ability? A. hollow bones B. sternum. C. air sacs D. homeothermy E. all of the above. What plant characteristics are adaptations to land? A. internal fertilizations B. vascular tissues. C. seeds with waterproof coats. D. waxy leaves. E. all of the above. Which of which is characteristic of alternation of generation in land plants? A. haploid sporophytes make haploid spores. B. gametophytes produce spores that develop into gametes C. sporophytes and gametophytes are typically similar in appearance. D. meiosis in sporophytes produces haploid spores. E. either the gametophyte or the sporophyte is unicellular. The haploid stage in a plant life in a plant life cycle is called A. embryo B. zygote C. gametophyte D. sporophyte E. conspicuous Animals in which the blastopo Solution 31. ovary is the protective chamber that houses the ovule and later matures the fruit 32. tha hollow bones, air sacs , the sternum and homeothermy helps the birds to fly. the hollow bones helps in reducing the body weight which helps in flying. the air sacs are responsible for extracting more oxygen which hepls them to frly high. the sternum bones are present in the wings which are strong and flexible for the movement of the wings 33. all of the above are the plants characteristics for the plant to adapt land 34. 35. the haploid stage of plant life in plant life cycle is known as gametophyte. 36.in protostomes the blastopore becomes the mouth.

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ABSTRACT: Anoverview of the habit and habitat of Podostemaceae is briefly discussed. Then,the paper attempts to review the past and present female gametophyte studies in the Podostemaceae. It trace the course and major achievements during the megasporogenesis, megagametogenesis and embryogenesis studies in the Podostemaceae. The evolutionary and functional significance of polarity during two-nucleate stage division of the megagametogenesis is discussed. Antipodal cell in the organized female gametophyte is discussed. Possible courses and causes of single fertilization and nucellar plasmodium organization are suggested. Then, provides and points out areas of special attention and limitations in the study of female gametophyte in future. Attempts are made to relate the ontogenies found in the family to plants with similar single fertilization phenomenon, for example Spinacia and Oenothera. Their embryological significances in the development of the female gametophyte in the angiosperms and gymnosperms are discussed

A Critical Review of the Female Gametophyte in the Podostemaceae - Past, Pres...

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A three-phase induction motor has the following name plate data: Using the data given in the nameplate. determine the following and justify fully your answers a) Explain the meaning of \"Design B\" b) explain the marking S.F. 115 and what it indicates c) Explain what NEMA NOM Efficiency means d) What is the synchronous speed of this motor? e) What a the slip at rated load for this motor? f) What is the expected maximum starting current (inrush) for this motor? g) What is the input power supplied if it is assumed that the motor is operating at its nominal efficiency with rated nameplate values? h) What is the rated output torque for this motor? i) How much reactive power is drawn under rated conditions? Solution c) Nema Nominal efficiency is defined as the ratio of output power to input power, which is expressed as , (output/input)*100 d)synchronous speed ns = 120f/p ns=120(60hZ)/3 ns=2400rpm e)slip s(=n1-n)/n1 where s= a normal value of slip n1=synchronous speed n=asynchronous speed as we know synchronous speed =2400rpm.

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You are to write a C++ program to produce an inventory repor.pdf

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Working with Layout Managers. Notes: 1. In part 2, note that the Game class inherits from JPanel. Therefore, the panel you are asked to add to the center of the content pane is the \"game\" object. 2. In part 4, at the end of the function, call validate(). This is not mentioned in the book, but it is mentioned in the framework comments. import javax.swing.*; import java.awt.*; import java.awt.event.*; public class Game extends JPanel { private JButton [][] squares; private TilePuzzle game; public Game( int newSide ) { game = new TilePuzzle( newSide ); setUpGameGUI( ); } public void setUpGame( int newSide ) { game.setUpGame( newSide ); setUpGameGUI( ); } public void setUpGameGUI( ) { removeAll( ); // remove all components setLayout( new GridLayout( game.getSide( ), game.getSide( ) ) ); squares = new JButton[game.getSide( )][game.getSide( )]; ButtonHandler bh = new ButtonHandler( ); // for each button: generate button label, // instantiate button, add to container, // and register listener for ( int i = 0; i < game.getSide( ); i++ ) { for ( int j = 0; j < game.getSide( ); j++ ) { squares[i][j] = new JButton( game.getTiles( )[i][j] ); add( squares[i][j] ); squares[i][j].addActionListener( bh ); } } setSize( 300, 300 ); setVisible( true ); } private void update( int row, int col ) { for ( int i = 0; i < game.getSide( ); i++ ) { for ( int j = 0; j < game.getSide( ); j++ ) { squares[i][j].setText( game.getTiles( )[i][j] ); } } if ( game.won( ) ) { JOptionPane.showMessageDialog( Game.this, \"Congratulations! You won!\ Setting up new game\" ); // int sideOfPuzzle = 3 + (int) ( 4 * Math.random( ) ); // setUpGameGUI( ); } } private class ButtonHandler implements ActionListener { public void actionPerformed( ActionEvent ae ) { for( int i = 0; i < game.getSide( ); i++ ) { for( int j = 0; j < game.getSide( ); j++ ) { if ( ae.getSource( ) == squares[i][j] ) { if ( game.tryToPlay( i, j ) ) update( i, j ); return; } // end if } // end inner for loop } // outer for loop } // end actionPerformed method } // end ButtonHandler class } // end Game class import javax.swing.*; import java.awt.*; import java.awt.event.*; public class NestedLayoutPractice extends JFrame { private Container contents; private Game game; private BorderLayout bl; private JLabel bottom; // ***** Task 1: declare a JPanel named top // also declare three JButton instance variables // that will be added to the JPanel top // these buttons will determine the grid size of the game: // 3-by-3, 4-by-4, or 5-by-5 // Part 1 student code starts here: // Part 1 student code ends here. public NestedLayoutPractice() { super(\"Practicing layout managers\"); contents = getContentPane(); // ***** Task 2: // instantiate the BorderLayout manager bl // Part 2 student code starts here: // set the layout manager of the content pane contents to bl: game = new Game(3); // instantiating the GamePanel object // add panel (game) to the center of the content pane // Part 2 student code ends here. bottom = new JLabel(.

Working with Layout Managers. Notes 1. In part 2, note that the Gam.pdf

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Write a java program that would ask the user to enter an input file name, and an output file name. Then the program reads the content of the input file, and then writes the content of the input file to the output file with each line proceeded with a line number followed by a colon. The line numbering should start at 1. should be used the following technique (a) while loop should be used to complete the program. (b)Scanner classisused (c) PrintWriter class is used (d) The files are closed before the program terminates. ExampleOriginal Input fileOutput file with line number added1341: 1341252: 1251123: 1121894: 189 Solution FileCopier.java:- import java.io.File; import java.io.FileInputStream; import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; import java.util.Scanner; public class FileCopier { public static void main(String[] args) throws IOException{ Scanner in=new Scanner(System.in); System.out.println(\"Enter input file\"); File inputFile=new File(in.nextLine()); if(!inputFile.exists()){ System.out.println(\"Source file doesn\'t exist\"); System.exit(0); } FileInputStream fis=new FileInputStream(inputFile); System.out.println(\"Enter output file\"); FileWriter fw=new FileWriter(in.nextLine()); PrintWriter pw=new PrintWriter(fw); in=new Scanner(inputFile); int i=1; while(in.hasNextLine()){ String s=in.nextLine(); pw.write(i++ + \": \" + s + \"\ \"); } pw.flush();pw.close(); } } Console output: Enter input file test.txt Enter output file output.txt Sample run 1:- test.txt: hey 123 . howdy output.txt: 1: hey 2: 123 3: . 4: howdy Sample run 2:- test.txt: 123 345 567 789 output.txt 1: 123 2: 345 3: 567 4: 789.

Write a java program that would ask the user to enter an input file .pdf

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Which of the following defines a method doubleEach that returns an ar.pdf

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When the Fed provides more reserves toprovides more reserves to.pdf

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What is a common infrastructure and what does it provide? Solution Ans. Common Infrastructure is the definition of service providers or users of Information and Communications Technologies which share the systems used to distribute electronic communication signals and services. It provides services which are required by the larger sections of the society such as airports, stations, large databases etc...

What is a common infrastructure and what does it provideSolutio.pdf

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What are the eukaryotic kingdoms? Question 4 options: Bacteria, Archae Phylum, Class, Order Eukarya, Archaea, Bacteria Protists, Fungi, Plants, Animals Bacteria, Archae Phylum, Class, Order Eukarya, Archaea, Bacteria Protists, Fungi, Plants, Animals Solution Ans d protista fungi planta animalia All other options have one or more prokaryote. Organisms are divided into 3 major domains, archae, bacteria and eukaryota. Eukaryota is then divided into 4 kingdoms.

What are the eukaryotic kingdomsQuestion 4 optionsBacteria, Ar.pdf

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What are some of the commonly seen WLAN devices? What role does each of them play in creating the WLAN network infrastructure? Solution What are some of the commonly seen WLAN devices? Ans:Access Point(AP),Bridges,Switch,Router,Gateway,Hub Access Point(AP):It connects wireless devices.It allows to user to have an access of network for communication. Bridege:It is used to connect network of different types.E.g.Ethernet bridge connects wired Ethernet network to wireless network. Switch:It allows to connect devices among each other using method of packet switching for send,receive and process of data. Router:It allows to forward packets from one computer to another.It does job of traffic management of network. Gateway:It is used to coonect to another network which uses another protocol.It routes traffic from inside of network to outside. Hub:It is common point where all devices are connected.In this hub,frame of data is broadcasted to each device.It doesnt matter whether frame is for particular computer or device.It just broadcasts..

What are some of the commonly seen WLAN devices What role does each.pdf

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Using the header(dlist) and mainline file (dlistapp) below You are going to write public functions for a doubly linked list class. The dlist class is declared in the file dlist.h as follows: struct dlist_node { char contents; // contents in the node dlist_node *back, // pointer to previous node in the list *next; // pointer to the next node in the list }; typedef dlist_node* dptr; class dlist { private: dptr front, // pointer to the front of the list current; // pointer to current node in the list public: dlist (); // constructor creates an empty list void insert (char ch); // inserts a new node void remove (); // removes a node void Move_Right(int distance); // moves current right void Move_Left(int distance); // moves current left void print (); // prints the list }; The public functions that you need to define are: dlist (): Constructor that initializes the list to be empty. voidinsert (char ch): Adds a new node to the right of current containing ch and points current at the new node. Should insert first node correctly. void remove (): Removes the node from the list pointed to by current. Points current at the node after the deleted node (if present) else points current at the node before the deleted node (if present). Should remove last node correctly and recycle nodes. Should not fail if list is empty. void Move_Right (int distance): Moves current to the right distance nodes. If the given distance will move current off the end of the list, current should be set to point at the rightmost node. Should not fail if list is empty. void Move_Left (int distance): Moves current to the left distance nodes. If the given distance will move current off the end of the list, current should be set to point at the leftmost node. Should not fail if list is empty. void print (): Prints all the nodes in the list. The value pointed to by current should be printed in braces.print does not output any spaces or linefeeds. For example, if the data in the linklist represents CIS 361, the output would be : CIS 3{6}1 The dlistapp.cpp application file is coded except for the calls to the public functions. Add the calls as directed by the comments in the file. dlist.h dlistapp.cpp Sample run Select p (print), i (insert), d (delete), r (right), l (left) or q (quit): d Select p (print), i (insert), d (delete), r (right), l (left) or q (quit): r Enter the distance to move right: 10 Select p (print), i (insert), d (delete), r (right), l (left) or q (quit): l Enter the distance to move left: 2 Select p (print), i (insert), d (delete), r (right), l (left) or q (quit): p The list is: Select p (print), i (insert), d (delete), r (right), l (left) or q (quit): i Enter the character to insert: h front current Solution #include using namespace std; struct dlist_node { char contents; // contents in the node dlist_node *back, // pointer to previous node in the list *next; // pointer to the next node in the list }; typedef dlist_node* dptr; class dlist { private: dptr front, // po.

Using the header(dlist) and mainline file (dlistapp) belowYou are .pdf

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Virology. Explain the make up and role of different complexes: for example the components of the spliceosome made up and its role. Solution Answer=1] components of spliceosome made up &its roles Spliceosome is large & compex molecular machine assembled from snRNAs & protein complexes 1] sn RNAs = it is composed of 5 small nuclear RNAs are U1,U2,U4,U5 ,U6 Roles - they participate in most RNA -RNA & RNA -Protein interactions 2] associated protein factors = snRNPs or small nuclear ribonucleoproteins are RNA protein complexes that combine with unmodified mRNA & various other proteins to form spliceosome 2] Multiprotein complex = is a group of 2 or more associated polypeptide chains example -proteasome - important for molecular degradation 3] Major histocompatibility compex (MHC )=set of cell surface proteins role- to bind antigen derived from pathogens & display them on the call surface for recognition by appropriate T cells.

Virology.Explain the make up and role of different complexes for .pdf

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TOPOLOGY 541 Let M be a set with two members a and b. Define the function D : M × M as follows: D(a,a) = D(b,b) = 0,D(a,b) = D(b,a) = r where r is a positive real number. Prove that (M, D) is a metric space. Solution Definition 1.1 (Metric). A metric, or distance function, on a set X is a mapping d : X × X R such that • d(x, y) 0 for all x, y X, and d(x, y) = 0 if and only if x = y. • d(x, y) = d(y, x) for all x, y X. • d(x, z) d(x, y) + d(y, z) for all x, y, z X. We call (X, d) a metric space. Definition 1.2 (Open ball). Let (X, d) be a metric space. For x X and > 0, the set Bd(x, ) defined by Bd(x, ) = {y X | d(x, y) < } is callen an open ball in the set X. Definition 1.3 (Open sets in metric spaces). Let (X, d) be a metric space and let U be any subset of X. Then U is called an open set in X if every point of U is an interior point of U; that is, for any a U, there is an open ball B(a, ) such that B(a, ) U. Definition 1.4 (Properties of open sets). Let (X, d) be a metric space. • and X are open. • The union of an arbitrary collection of open sets is open. • The intersection of a finite number of open sets is open. Definition 1.5 (Closed set). A subset A of a metric space (X, d) is closed if it’s complement X\\A is open in X. Definition 1.6 (Properties of closed sets). Let (X, d) be a metric space. • and X are closed. • The union of an finite collection of closed sets is closed. • The intersection of an arbitrary number of closed sets is closed. Definition 1.7 (Limit point of a subset). Let (X, d) be a metric space and let A be a subset of X. Then a point x in X is a limit point of A if every open ball B(x, ) contains at least one point of A. The set of all limit points of A is called the derived set A . Definition 1.8 (Closure of a set). Let (X, d) be a metric space and let A X. Then the set consisting of A and its limit points is called the closure of A, denoted A. A = A A Corollary 1.19. We note that A is dense in X if and only if for any x X and > 0, there is a point a A such that d(x, a) < . 1.2. Subspaces. Definition 1.20 (Open sets in a subspace). Let (X, d) be a metric space and (Y, dY ) be a metric subspace of (X, d). Let G be a subset of Y . Then G is open in Y if and only if, for any x G, there is an open ball B(x, ) in X such that B(x, ) Y G A subset H of Y is closed in Y if its complement G = Y \\H of H is open in Y . Theorem 1.21 (Open sets in a metric subspace). Let (Y, dY ) be a metric subspace of a metric space (X, d), and let G Y . Then G is open in Y if and only if there exists an open subset U in X such that G = U Y . 1.3. Convergence in a Metric Space. Definition 1.22 (Convergence). A sequence (xn) in a metric space (X, d) is said to converge to a point x X if for any > 0, there exists N such that n > N implies d(xn, x) < The point x is called a limit of the sequence (xn) Corollary 1.23. A sequence (xn) in a metric space (X, d) is said to converge to a point x X if any open ball B(x, ) contains almost all xn. Theorem 1..

TOPOLOGY 541Let M be a set with two members a and b. Define the fu.pdf

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These are the outputs which should match they are 4 of them :- output 1 - output 2 - output 3 - output 4 - Here is the Assingment5.java file can make changes to it :- You are required, but not limited, to turn in the following source files: Assignment5.java (Download this file and use it as your driver program for this assignment. You need to add more codes to complete it.) Soup.java SoupInBox.java SoupInCylinder.java SoupParser.java Requirements to get full credits in Documentation The assignment number, your name, StudentID, Lecture number/time, and a class description need to be included at the top of each class/file. A description of each method is also needed. Some additional comments inside of methods (especially for a \"main\" method) to explain code that are hard to follow should be written. You can look at Java programs in the text book to see how comments are added to programs. Skills to be Applied In addition to what has been covered in previous assignments, the use of the following items, discussed in class, will probably be needed: Inheritance The protected modifier The super Reference Abstract class NumberFormat/DecimalFormat Wrapper classes ArrayList Program Description Class Diagram: In Assignment #5, you will need to make use of inheritance by creating a class hierarchy for vehicles. Soup is an abstract class, which represents the basic attributes of any soup in a container to be sold. It is used as the root of the soup hierarchy. It has the following attributes (should be protected): Attribute name Attribute type Description volume int The volume of the soup unitPrice double The price per unit of the soup totalPrice double The total price of the soup soupId String The Id of the soup The following constructor method should be provided to initialize the instance variables. publicSoup(String id, double someUnitPrice) The instance variable volume is initialized to 0, totalPrice is initialized to 0.0, unitPrice is initialized to the value of the second parameter, and soupId is initialized to the string value of the first parameter. The following accessor method should be provided for soupId : publicString getSoupId() The Class Soup also has an abstract method (which should be implemented by its child classes, SoupInCylinder and SoupInBox) to compute the volume of the soup: publicabstract void computeTotalPrice(); The following public method should be provided: publicString toString() toString method returns a string of the following format: \ The SoupId:\\t\\ttomatosoup591\ The Volume:\\t\\t150\ The Unit Price:\\t\\t0.0015\ The Total Price:\\t$330.00\ \ You should make use of the NumberFormat class and DecimalFormat (in java.text package) to format the total price in the dollar format (NumberFormat) and the unit price using 4 digits after their decimal point (DecimalFormat using \"0.0000\"). SoupInCylinder class SoupInCylinder is a subclass of Soup class. It represents a soup in a can (cylinder). It has the following attribute in.

These are the outputs which should match they are 4 of them -outp.pdf

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The test solution is made basic and drops of 0.1 M Ca(NO3)2 are adde.pdf

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The selection of officials in which of the following branches of the national government is least consistent with the ideal of democracy, or popular sovereignty? The The The The d A. the judiciary B. The executive C. The legislature d. The federalaa. TheB. TheC. The The d A. the judiciary B. The executive C. The legislature d. The federal Solution WHAT ARE THE ESSENTIAL CHARACTERISTICS AND PRINCIPLES OF CONSTITUTIONAL DEMOCRACY? CONSTITUTIONAL DEMOCRACY is the antithesis of arbitrary rule. It is democracy characterized by: A. POPULAR SOVEREIGNTY. The people are the ultimate source of the authority of the government which derives its right to govern from their consent. B. MAJORITY RULE AND MINORITY RIGHTS. Although \"the majority rules,\" the fundamental rights of individuals in the minority are protected. C. LIMITED GOVERNMENT. The powers of government are limited by law and a written or unwritten constitution which those in power obey. D. INSTITUTIONAL AND PROCEDURAL LIMITATIONS ON POWERS. There are certain institutional and procedural devices which limit the powers of government. These may include: 1. SEPARATED AND SHARED POWERS. Powers are separated among different agencies or branches of government. Each agency or branch has primary responsibility for certain functions such as legislative, executive, and judicial functions. However, each branch also shares these functions with the other branches. 2. CHECKS AND BALANCES. Different agencies or branches of government have adequate power to check the powers of other branches. Checks and balances may include the power of judicial reviewÀ\"Àthe power of courts to declare actions of other branches of government to be contrary to the constitution and therefore null and void. 3. DUE PROCESS OF LAW. Individual rights to life, liberty, and property are protected by the guarantee of due process of law. 4. LEADERSHIP SUCCESSION THROUGH ELECTIONS. Elections insure that key positions in government will be contested at periodic intervals and that the transfer of governmental authority is accomplished in a peaceful and orderly process. C. The legislature.

The selection of officials in which of the following branches of the.pdf

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