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S U R FA C E A R E A S O F
P Y R A M I D S A N D C O N E S
S E C T I O N 1 2 - 3
E S S E N T I A L Q U E S T I O N S
• How do you find lateral areas and surface areas of
pyramids?
• How do you find lateral areas and surface areas of
cones?
V O C A B U L A RY
1. Regular Pyramid:
2. Slant Height:
3. Right Cone:
4. Oblique Cone:
V O C A B U L A RY
1. Regular Pyramid:
2. Slant Height:
3. Right Cone:
4. Oblique Cone:
Has a base that is a regular
polygon, and the altitude has an endpoint at
the center of the base
V O C A B U L A RY
1. Regular Pyramid:
2. Slant Height:
3. Right Cone:
4. Oblique Cone:
Has a base that is a regular
polygon, and the altitude has an endpoint at
the center of the base
The height of the lateral face
V O C A B U L A RY
1. Regular Pyramid:
2. Slant Height:
3. Right Cone:
4. Oblique Cone:
Has a base that is a regular
polygon, and the altitude has an endpoint at
the center of the base
The height of the lateral face
A cone whose axis is also the
altitude (perpendicular to the base)
V O C A B U L A RY
1. Regular Pyramid:
2. Slant Height:
3. Right Cone:
4. Oblique Cone:
Has a base that is a regular
polygon, and the altitude has an endpoint at
the center of the base
The height of the lateral face
A cone whose axis is also the
altitude (perpendicular to the base)
A cone whose axis is not an
altitude
PA R T S O F A P Y R A M I D
PA R T S O F A P Y R A M I D
Vertex
PA R T S O F A P Y R A M I D
Vertex
PA R T S O F A P Y R A M I D
Vertex
Altitude
PA R T S O F A P Y R A M I D
Vertex
Altitude
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
Base
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
Base
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
Base
Base Edge
PA R T S O F A P Y R A M I D
Vertex
Altitude
Lateral Face
Lateral Edge
Slant Height
Base
Base Edge
F O R M U L A S F O R R E G U L A R P Y R A M I D S
F O R M U L A S F O R R E G U L A R P Y R A M I D S
Lateral Area of a Regular Pyramid
F O R M U L A S F O R R E G U L A R P Y R A M I D S
Lateral Area of a Regular Pyramid
L =
1
2
Pl
F O R M U L A S F O R R E G U L A R P Y R A M I D S
Lateral Area of a Regular Pyramid
L =
1
2
Pl
Surface Area of a Regular Pyramid
F O R M U L A S F O R R E G U L A R P Y R A M I D S
Lateral Area of a Regular Pyramid
L =
1
2
Pl
Surface Area of a Regular Pyramid
SA =
1
2
Pl +B
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
L =
1
2
Pl
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
L =
1
2
Pl
L =
1
2
(2.5)(4)(5)
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
L =
1
2
Pl
L =
1
2
(2.5)(4)(5)
L = 25 cm2
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
SA =
1
2
Pl +B
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
SA =
1
2
Pl +B
SA =
1
2
(2.5)(4)(5)+ 2.52
E X A M P L E 1
Find the lateral area and the surface area of the
square pyramid. The base has a side length of 2.5
cm and a slant height of 5 cm.
SA =
1
2
Pl +B
SA =
1
2
(2.5)(4)(5)+ 2.52
SA = 31.25 cm2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
42
+ 62
= l2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
42
+ 62
= l2
16 + 36 = l2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
42
+ 62
= l2
16 + 36 = l2
52 = l2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
42
+ 62
= l2
16 + 36 = l2
52 = l2
52 = l2
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
a2
+b2
= c2
42
+ 62
= l2
16 + 36 = l2
52 = l2
52 = l2
l = 52
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
SA =
1
2
Pl +B
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
SA =
1
2
Pl +B
SA =
1
2
(4)(8)( 52)+ 82
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
SA =
1
2
Pl +B
SA =
1
2
(4)(8)( 52)+ 82
SA = 16 52 + 64
E X A M P L E 2
Find the surface area of the square pyramid to the
nearest hundredth.
SA =
1
2
Pl +B
SA =
1
2
(4)(8)( 52)+ 82
SA = 16 52 + 64
SA ≈ 179.38 m2
PA R T S O F A C O N E
PA R T S O F A C O N E
Vertex
PA R T S O F A C O N E
Vertex
PA R T S O F A C O N E
Vertex
Altitude
PA R T S O F A C O N E
Vertex
Altitude
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
Base
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
Base
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
Base
Radius
PA R T S O F A C O N E
Vertex
Altitude
Slant Height
Base
Radius
F O R M U L A S F O R C O N E S
F O R M U L A S F O R C O N E S
Lateral Area of a Cone
F O R M U L A S F O R C O N E S
Lateral Area of a Cone
L = πrl
F O R M U L A S F O R C O N E S
Lateral Area of a Cone
L = πrl
Surface Area of a Cone
F O R M U L A S F O R C O N E S
Lateral Area of a Cone
L = πrl
Surface Area of a Cone
SA = πrl +πr2
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
a2
+b2
= c2
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
a2
+b2
= c2
82
+1.252
= l2
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
a2
+b2
= c2
82
+1.252
= l2
64 +1.5625 = l2
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
a2
+b2
= c2
82
+1.252
= l2
64 +1.5625 = l2
65.5625 = l2
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1
2
d
r = 1
2
(2.5)
r = 1.25 in.
a2
+b2
= c2
82
+1.252
= l2
64 +1.5625 = l2
65.5625 = l2
l = 65.5625
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1.25 in.
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1.25 in. l = 65.5625
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1.25 in. l = 65.5625
L = π1.25 65.5625
E X A M P L E 3
An ice cream cone has an altitude of 8 inches and a
diameter of 2.5 inches. Find the lateral area of the cone
to the nearest hundredth.
L = πrl
r = 1.25 in. l = 65.5625
L = π1.25 65.5625
L ≈ 31.80 in2
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
SA = πrl +πr2
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
SA = πrl +πr2
SA = π(1.4)(3.2)+π(1.4)2
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
SA = πrl +πr2
SA = π(1.4)(3.2)+π(1.4)2
SA = 4.48π +1.96π
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
SA = πrl +πr2
SA = π(1.4)(3.2)+π(1.4)2
SA = 4.48π +1.96π
SA = 6.44π
E X A M P L E 4
Find the surface area of the cone. Round to the nearest
hundredth.
SA = πrl +πr2
SA = π(1.4)(3.2)+π(1.4)2
SA = 4.48π +1.96π
SA = 6.44π
SA ≈ 20.23 in2
S O L I D M O D E L
L AT E R A L
A R E A
S U R FA C E A R E A
P R I S M
C Y L I N D E R
P Y R A M I D
C O N E
L = Ph
L = 2πrh
L =
1
2
Pl
L = πrl
SA = Ph + 2B
SA = 2πrh + 2πr2
SA =
1
2
Pl +B
SA = πrl +πr2
– R O N A L D R E A G A N
“We can’t help everyone, but everyone can help someone.”
P R O B L E M S E T
p. 843 #1-19 odd, skip #3

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Geometry Section 12-3

  • 1. S U R FA C E A R E A S O F P Y R A M I D S A N D C O N E S S E C T I O N 1 2 - 3
  • 2. E S S E N T I A L Q U E S T I O N S • How do you find lateral areas and surface areas of pyramids? • How do you find lateral areas and surface areas of cones?
  • 3. V O C A B U L A RY 1. Regular Pyramid: 2. Slant Height: 3. Right Cone: 4. Oblique Cone:
  • 4. V O C A B U L A RY 1. Regular Pyramid: 2. Slant Height: 3. Right Cone: 4. Oblique Cone: Has a base that is a regular polygon, and the altitude has an endpoint at the center of the base
  • 5. V O C A B U L A RY 1. Regular Pyramid: 2. Slant Height: 3. Right Cone: 4. Oblique Cone: Has a base that is a regular polygon, and the altitude has an endpoint at the center of the base The height of the lateral face
  • 6. V O C A B U L A RY 1. Regular Pyramid: 2. Slant Height: 3. Right Cone: 4. Oblique Cone: Has a base that is a regular polygon, and the altitude has an endpoint at the center of the base The height of the lateral face A cone whose axis is also the altitude (perpendicular to the base)
  • 7. V O C A B U L A RY 1. Regular Pyramid: 2. Slant Height: 3. Right Cone: 4. Oblique Cone: Has a base that is a regular polygon, and the altitude has an endpoint at the center of the base The height of the lateral face A cone whose axis is also the altitude (perpendicular to the base) A cone whose axis is not an altitude
  • 8. PA R T S O F A P Y R A M I D
  • 9. PA R T S O F A P Y R A M I D Vertex
  • 10. PA R T S O F A P Y R A M I D Vertex
  • 11. PA R T S O F A P Y R A M I D Vertex Altitude
  • 12. PA R T S O F A P Y R A M I D Vertex Altitude
  • 13. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face
  • 14. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face
  • 15. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge
  • 16. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge
  • 17. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height
  • 18. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height
  • 19. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height Base
  • 20. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height Base
  • 21. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height Base Base Edge
  • 22. PA R T S O F A P Y R A M I D Vertex Altitude Lateral Face Lateral Edge Slant Height Base Base Edge
  • 23. F O R M U L A S F O R R E G U L A R P Y R A M I D S
  • 24. F O R M U L A S F O R R E G U L A R P Y R A M I D S Lateral Area of a Regular Pyramid
  • 25. F O R M U L A S F O R R E G U L A R P Y R A M I D S Lateral Area of a Regular Pyramid L = 1 2 Pl
  • 26. F O R M U L A S F O R R E G U L A R P Y R A M I D S Lateral Area of a Regular Pyramid L = 1 2 Pl Surface Area of a Regular Pyramid
  • 27. F O R M U L A S F O R R E G U L A R P Y R A M I D S Lateral Area of a Regular Pyramid L = 1 2 Pl Surface Area of a Regular Pyramid SA = 1 2 Pl +B
  • 28. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm.
  • 29. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. L = 1 2 Pl
  • 30. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. L = 1 2 Pl L = 1 2 (2.5)(4)(5)
  • 31. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. L = 1 2 Pl L = 1 2 (2.5)(4)(5) L = 25 cm2
  • 32. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm.
  • 33. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. SA = 1 2 Pl +B
  • 34. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. SA = 1 2 Pl +B SA = 1 2 (2.5)(4)(5)+ 2.52
  • 35. E X A M P L E 1 Find the lateral area and the surface area of the square pyramid. The base has a side length of 2.5 cm and a slant height of 5 cm. SA = 1 2 Pl +B SA = 1 2 (2.5)(4)(5)+ 2.52 SA = 31.25 cm2
  • 36. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth.
  • 37. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2
  • 38. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2 42 + 62 = l2
  • 39. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2 42 + 62 = l2 16 + 36 = l2
  • 40. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2 42 + 62 = l2 16 + 36 = l2 52 = l2
  • 41. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2 42 + 62 = l2 16 + 36 = l2 52 = l2 52 = l2
  • 42. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. a2 +b2 = c2 42 + 62 = l2 16 + 36 = l2 52 = l2 52 = l2 l = 52
  • 43. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth.
  • 44. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. SA = 1 2 Pl +B
  • 45. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. SA = 1 2 Pl +B SA = 1 2 (4)(8)( 52)+ 82
  • 46. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. SA = 1 2 Pl +B SA = 1 2 (4)(8)( 52)+ 82 SA = 16 52 + 64
  • 47. E X A M P L E 2 Find the surface area of the square pyramid to the nearest hundredth. SA = 1 2 Pl +B SA = 1 2 (4)(8)( 52)+ 82 SA = 16 52 + 64 SA ≈ 179.38 m2
  • 48. PA R T S O F A C O N E
  • 49. PA R T S O F A C O N E Vertex
  • 50. PA R T S O F A C O N E Vertex
  • 51. PA R T S O F A C O N E Vertex Altitude
  • 52. PA R T S O F A C O N E Vertex Altitude
  • 53. PA R T S O F A C O N E Vertex Altitude Slant Height
  • 54. PA R T S O F A C O N E Vertex Altitude Slant Height
  • 55. PA R T S O F A C O N E Vertex Altitude Slant Height Base
  • 56. PA R T S O F A C O N E Vertex Altitude Slant Height Base
  • 57. PA R T S O F A C O N E Vertex Altitude Slant Height Base Radius
  • 58. PA R T S O F A C O N E Vertex Altitude Slant Height Base Radius
  • 59. F O R M U L A S F O R C O N E S
  • 60. F O R M U L A S F O R C O N E S Lateral Area of a Cone
  • 61. F O R M U L A S F O R C O N E S Lateral Area of a Cone L = πrl
  • 62. F O R M U L A S F O R C O N E S Lateral Area of a Cone L = πrl Surface Area of a Cone
  • 63. F O R M U L A S F O R C O N E S Lateral Area of a Cone L = πrl Surface Area of a Cone SA = πrl +πr2
  • 64. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth.
  • 65. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl
  • 66. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d
  • 67. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5)
  • 68. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in.
  • 69. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in.
  • 70. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in. a2 +b2 = c2
  • 71. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in. a2 +b2 = c2 82 +1.252 = l2
  • 72. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in. a2 +b2 = c2 82 +1.252 = l2 64 +1.5625 = l2
  • 73. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in. a2 +b2 = c2 82 +1.252 = l2 64 +1.5625 = l2 65.5625 = l2
  • 74. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1 2 d r = 1 2 (2.5) r = 1.25 in. a2 +b2 = c2 82 +1.252 = l2 64 +1.5625 = l2 65.5625 = l2 l = 65.5625
  • 75. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth.
  • 76. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl
  • 77. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1.25 in.
  • 78. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1.25 in. l = 65.5625
  • 79. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1.25 in. l = 65.5625 L = π1.25 65.5625
  • 80. E X A M P L E 3 An ice cream cone has an altitude of 8 inches and a diameter of 2.5 inches. Find the lateral area of the cone to the nearest hundredth. L = πrl r = 1.25 in. l = 65.5625 L = π1.25 65.5625 L ≈ 31.80 in2
  • 81. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth.
  • 82. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth. SA = πrl +πr2
  • 83. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth. SA = πrl +πr2 SA = π(1.4)(3.2)+π(1.4)2
  • 84. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth. SA = πrl +πr2 SA = π(1.4)(3.2)+π(1.4)2 SA = 4.48π +1.96π
  • 85. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth. SA = πrl +πr2 SA = π(1.4)(3.2)+π(1.4)2 SA = 4.48π +1.96π SA = 6.44π
  • 86. E X A M P L E 4 Find the surface area of the cone. Round to the nearest hundredth. SA = πrl +πr2 SA = π(1.4)(3.2)+π(1.4)2 SA = 4.48π +1.96π SA = 6.44π SA ≈ 20.23 in2
  • 87. S O L I D M O D E L L AT E R A L A R E A S U R FA C E A R E A P R I S M C Y L I N D E R P Y R A M I D C O N E L = Ph L = 2πrh L = 1 2 Pl L = πrl SA = Ph + 2B SA = 2πrh + 2πr2 SA = 1 2 Pl +B SA = πrl +πr2
  • 88. – R O N A L D R E A G A N “We can’t help everyone, but everyone can help someone.” P R O B L E M S E T p. 843 #1-19 odd, skip #3