4. Vocabulary
1. Great Circle:
2. Pole:
3. Hemisphere:
A circle formed when a plane
intersects a sphere and the circle has the
same center as the sphere
5. Vocabulary
1. Great Circle:
2. Pole:
3. Hemisphere:
A circle formed when a plane
intersects a sphere and the circle has the
same center as the sphere
The endpoints of the diameter of a great
circle
6. Vocabulary
1. Great Circle:
2. Pole:
3. Hemisphere:
A circle formed when a plane
intersects a sphere and the circle has the
same center as the sphere
The endpoints of the diameter of a great
circle
One of the two congruent halves
of a sphere created by a great circle
13. Example 1
Find the surface area of the sphere.
SA = 4πr2
SA = 4π(4.5)2
SA ≈ 254.47 in2
14. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
15. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
16. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
r = 1
2
d
17. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
r = 1
2
d
r = 1
2
(8)
18. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
r = 1
2
d
r = 1
2
(8)
r = 4 mm
19. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
r = 1
2
d
r = 1
2
(8)
r = 4 mm
SA = 2π(4)2
+ π(4)2
20. Example 2
Find the surface area of a hemisphere with a
diameter of 8 mm to the nearest hundredth.
SA = 1
2
i 4πr2
+ πr2
r = 1
2
d
r = 1
2
(8)
r = 4 mm
SA = 2π(4)2
+ π(4)2
SA ≈ 150.8 mm2
21. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
22. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
23. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
24. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
14π = 2πr
25. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
14π = 2πr
2π 2π
26. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
14π = 2πr
2π 2π
r = 7 in.
27. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
14π = 2πr
2π 2π
r = 7 in.
SA = 4π(7)2
28. Example 3
Find the surface area of a sphere if the
circumference of the great circle is 14π inches.
SA = 4πr2
C = 2πr
14π = 2πr
2π 2π
r = 7 in.
SA = 4π(7)2
SA ≈ 615.75 in2
29. Example 4
Find the volume of the sphere rounded to the
nearest hundredth.
30. Example 4
Find the volume of the sphere rounded to the
nearest hundredth.
V =
4
3
πr3
31. Example 4
Find the volume of the sphere rounded to the
nearest hundredth.
V =
4
3
πr3
V =
4
3
π(4.5)3
32. Example 4
Find the volume of the sphere rounded to the
nearest hundredth.
V =
4
3
πr3
V =
4
3
π(4.5)3
V ≈ 381.70 in3
33. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
34. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3
35. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3 r = 1
2
d
36. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3 r = 1
2
d
r = 1
2
(6)
37. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3 r = 1
2
d
r = 1
2
(6)
r = 3 ft
38. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3 r = 1
2
d
r = 1
2
(6)
r = 3 ft
V =
2
3
π(3)3
39. Example 5
Find the volume of a hemisphere with a diameter
of 6 feet to the nearest hundredth.
V =
1
2
i
4
3
πr3 r = 1
2
d
r = 1
2
(6)
r = 3 ft
V =
2
3
π(3)3
V ≈ 56.55 ft3
40. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
41. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
42. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
43. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
44. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
π π
45. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
π π
9 = r2
46. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
π π
r = 3 ft.
9 = r2
47. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
π π
r = 3 ft.
9 = r2
V =
4
3
π(3)3
48. Example 6
Find the volume of a sphere that has a great
circle with an area of 9π square feet.
V =
4
3
πr3
A = πr2
9π = πr2
π π
r = 3 ft.
9 = r2
V =
4
3
π(3)3
V ≈ 113.10 ft3