2. There are more steps you have to following to do design
for any building. Up to have we finished eight steps to
design structure of building:
1. Select a plan of building
2. Draw the plan of a building in AUTOCAD program and
show columns position.
3. Calculate the slab load, wall load, beam self weight and
total load for each beam in the building.
4. Make a staad model.
5. Do the columns and beam size and enter it in staad
program.
6. Enter the total loads in staad program.
7. By using staad program select the grade of concrete and
steel for the full structure of building.
8. Do design of columns, beams and slabs of building.
7. Assume the load of slab
•Overall of slab=??
Lx/d=32
7500/32=d
D=234.375mm
h= Ø/2+c+d
=12/2+20+234.375
=260.375mm
*Loading on 1m of slab
Dl of concrete = vol x uw
=1 x 1 x 0.260 x 24
=6.24kn/m2
Dl finishing=1KN/m2
Imposed load live(Qk)=2.5kn/m2
Ultimate load
=1.4 x 7.24 x 1.6 x 2.5
Wu=14.136kn/m2
LX = 7.5m
LY = 10.6m
8. Distribution of slab
S1
Ly/lx = 10604.5/7500=1.4
1.4 < 2 two way slab
Long beam =
((Wu x lx)/6) x (3-(Lx/Ly)2)
= ((14.136 x 7.5)/6) x {3-
(7.5/10.6)2} = 44.15kN/m2
Short beam =(Wu x lx)/3
= (14.136 x 7.5)/3 = 35.34 KN/m2
S2
Ly/lx = 7500/7203=1.4
1.4 < 2 two way slab
Long beam =((Wu x lx)/6) x (3-
(Lx/Ly)2)
= ((14.136 x 7.203)/6) x (3-
(7.203/10.6)2) = 43 KN/m2
Short beam =(Wu x lx)/3
= (14.136 x 7.203)/3
= 34kn/m2
S3
Ly/lx = 7500/5353=1.4
1.4 < 2 two way slab
Long beam
=((Wu x lx)/6) x {3-(Lx/Ly)2)
= ((14.136 x 5.353)/6) x (3-(5.353/7.5)2) =
31.4 kn/m2
Short beam =(Wu x lx)/3 = (14.136 x
5.353)/3 = 25.22kn/m2
S4
Ly/lx = 8804.5/7500=1.4
1.1< 2 two way slab
Long beam=((Wu x lx)/6) x (3-(Lx/Ly)2) =
((14.136 x 7.5)/6) x (3-(7.5/8.8)2) = 40.17
kn/m2
Short beam=(Wu x lx)/3 = (14.136 x 7.5)/3
= 35.34 kn/m2
S5
Ly/lx = 45771/3251=14
14> 2 one way slab
(Wu x lx)/2 = (14.136 x 3)/2 =21.204kn/m2
9. Slab load for staircase
Dl of waist slab 1m2
=1.16 x 0.260 x 24 = 6.2 kn/m2
Dl of steps = 4 (0.5 x .25 x .15) x 24
=108 kn/m2
Floor finish = 1kn/m2
Total DI load = 10 x 1.4 = 14 kn/m2
Live load = 3 kn/m2
= 3 x 1.6 =4.8 kn/m2
Wu = 14+ 4.8 = 18.8 kn/m2
For staircase design one way slab
(Wu x lx)/2 = (18.8 x 5.25)/2 =
49.35 kn/m2
250mm
1m
150mm
Ø
Tan Ø=150/250
Ø =30.9°
Cos 30.9° =1/x
X= 1.16m
10. Sunken slab load
Dl of filling material
= 1 x 1 x .3 x 12
=3.6 x 1.4 = 5 KN/m2
Wu = 14.13 + 5 = 19.136 KN/m2
Ly/lx = 525/325=1.6
1.6< 2 two way slab
short beam=(Wu x lx)/3
= (19.136 x 3.251)/3
= 20.7 KN/m2
Long beam
=((Wu x lx)/6) x (3-(lx/ly)2)
= ((19.136 x 3.251)/6) x (3-
(3.251/5.35)2)
= 27.129 KN/m2
Filling material
SLAB
11. Self weight of beam
= 1 x 0.25 x 0.6 x 24
= 3.6 x 1.4
= 5.04 kn/m2
250mm
600mm
Load of wall
= 1x 0.200 x 3 x 15
= 9 x 1.4
=12.6 kn/m2
0.2m
3m
36. .
Table : bars of steel for beam
Beam
Size Top Bars
Bottom
Top Extra
Bottom Extra Links
Name
mm
Bars
0.25L
0.7L
AB 600X250 2 T 32 2 T 16 2 T 25 1 T 16 8Ø@150 C/c
BC 600X250 2 T 25 2 T 16 2 T 20 1 T 16 8Ø@171C/c
CD 600X250 2 T 32 2 T 12 2 T 25 1 T 16 8Ø@166C/c
DE 800X250 2 T 32 2 T 16 2 T 25 1 T 25 10Ø@150C/c
EF 800X250 2 T 32 2 T 16 2 T 25 1 T 20 8Ø@146C/c
FG 600X250 2 T 16 2 T 8 2 T 12 1 T 8 8Ø@223C/c
GH 450X250 2 T 10 2 T 8 2 T 8 1 T 10 8Ø@216C/c
IJ 600X250 2 T 32 2 T 16 2 T 25 1 T 16 10Ø@150C/c
JK 600X250 2 T 25 2 T 16 2 T 20 1 T 16 10Ø@120C/c
KL 600X250 2 T 32 2 T 16 2 T 25 1 T 16 8Ø@100 C/c
LM 800X250 2 T 32 2 T 32 2 T 25 1 T 40 10Ø@120C/c
MN 800X250 2 T 32 2 T 20 2 T 25 1 T 20 8Ø@163C/c
NN1
OP 600X250 2 T 25 2 T 16 2 T 20 1 T 25 8Ø@109C/c
PQ 800X250 2 T 32 2 T 32 2 T 25 1 T 40 10Ø@120C/c
QR 800X250 2 T 32 2 T 25 2 T 25 1 T 25 8Ø@66C/c
RS 800X250 2 T 32 2 T 25 2 T 25 1 T 32 10Ø@120C/c
ST 600X250 2 T 25 2 T 20 2 T 20 1 T 20 10Ø@120C/c
TT1 450X250 2 T 25 2 T 10 2 T 20 1 T 12 10Ø@120C/c
UV 600X250 2 T 32 2 T 16 2 T 25 1 T 16 8Ø@160C/c
VW 800X250 2 T 32 2 T 25 2 T 25 1 T 25 8Ø@110C/c
WX 800X250 2 T 32 2 T 20 2 T 25 1 T 20 8Ø@103C/c
XY 800X250 2 T 32 2 T 20 2 T 25 1 T 20 8Ø@103C/c
37. .
Beam
Size Top Bars
Bottom
Top Extra
Bottom Extra Links
Name
Mm
Bars
0.25L
0.7L
AI 600X250 2 T 25 2 T 25 2 T 20 1 T 25 8Ø@104C/c
IO 450X250 2T25 2T20 2T20 1T16 10Ø@120 C/c
OU 600X250 2 T 25 2 T 25 2 T 20 1 T 25 10Ø@120C/c
G G1 450X250 2 T 25 2 T 16 2 T 20 1 T 16 8Ø@168C/c
H H1 450X250 2 T 16 2 T 12 2 T 12 1 T 16 8Ø@116C/c
G1 H1 450X250 2 T 10 2 T 12 2 T 10 1 T 12 8Ø@218C/c
H1 T 450X250 2 T 16 2 T 8 2 T 16 1 T 10 10Ø@120C/c
TZ 600X250 2 T 20 2 T 20 2 T 16 1 T 25 10Ø@120C/c
G1 T1 600X250 2 T 25 2 T 16 2 T 20 1 T 16 10Ø@120C/c
BJ 600X250 2 T 32 2 T 32 2 T 25 1 T 40 10Ø@120C/c
CK 600X250 2 T 32 2 T 32 2 T 25 1 T 40 10Ø@120C/c
DL 600X250 2 T 32 2 T 25 2 T 25 1 T 25 10Ø@120C/c
EM 600X250 2 T 32 2 T 25 2 T 25 1 T 25 10Ø@120C/c
FN 600X250 2 T 32 2 T 25 2 T 25 1 T 25 10Ø@120C/c
PV 600X250 2 T 32 2 T 25 2 T 25 1 T 32 8Ø@120 C/c
QW 600X250 2 T 32 2 T 25 2 T 25 1 T 25 8Ø@64C/c
RX 600X250 2 T 32 2 T 25 2 T 25 1 T 25 10Ø@120C/c
SY 600X250 2 T 32 2 T 25 2 T 25 1 T 25 10Ø@120C/c
44. Table : bars of steel for column
NO. of Links
Bars
Size
MM
Column
Name
A 600mm X 250mm T 16 6 8T @ 150 c/c
B 250mm X 600mm T 16 8 8T @ 150 c/c
C 250mm X 600mm T 16 4 8T @ 150 c/c
D 250mm X 600mm T 16 8 8T @ 150 c/c
E 250mm X 600mm T 16 8 8T @ 150 c/c
F 250mm X 600mm T 16 4 8T @ 150 c/c
G 250mm X 600mm T 16 4 8T @ 150 c/c
G1 250mm X 600mm T 16 4 8T @ 150 c/c
H 250mm X 600mm T 16 4 8T @ 150 c/c
H1 250mm X 600mm T 16 4 8T @ 150 c/c
I 600mm X 250mm T 16 4 8T @ 150 c/c
J 600mm X 250mm T 25 6 8T @ 150 c/c
K 250mm X 600mm T 20 4 8T @ 150 c/c
L 250mm X 600mm T 20 8 8T @ 150 c/c
M 250mm X 600mm T 20 8 8T @ 150 c/c
N 250mm X 600mm T 20 4 8T @ 150 c/c
O 600mm X 250mm T 16 4 8T @ 150 c/c
P 250mm X 600mm T 20 8 8T @ 150 c/c
45. NO. of Links
bars
Size
MM
Column
Name
Q 250mm X 600mm T 20 8 8T @ 150 c/c
R 250mm X 600mm T 20 8 8T @ 150 c/c
S 250mm X 600mm T 16 4 8T @ 150 c/c
T 600mm X 250mm T 16 4 8T @ 150 c/c
T1 250mm X 600mm T 16 4 8T @ 150 c/c
U 250mm X 600mm T 16 4 8T @ 150 c/c
V 250mm X 600mm T 20 6 8T @ 150 c/c
W 250mm X 600mm T 20 6 8T @ 150 c/c
X 250mm X 600mm T 25 4 8T @ 150 c/c
Y 250mm X 600mm T 20 6 8T @ 150 c/c
Z 600mm X 250mm T 16 8 8T @ 150 c/c
46.
47. STEP 1
Assume overall depth
Lx/d =32
7500/d=32
d= 234 mm
h=d+dia/2+c
h=234+12/12+20=260 mm
STEP 2: LOADS
DL=GK=1x1x0.26x24+1=7.24 KN/m2
L.L=QK=2.5 KN/m2
Design load =1.4GK+1.6QK
Wu =1.4x7.24+1.6x2.5=14.13 KN
STEP3: bending moment max
Msx=B Wu Lx
= -0.068x14.13x7.22
= -54 KNm
Msy= -0.037x14.13x7.22
= -29.4 KNm
STEP 4: moment of resistance of
c/r
Mu=0.156fcu b d2
=0.156x30x2342
= 256.2x106 Nmm
=256.2 KNm
STEP 5
Mu > M
256.2 > 54 yes ok S.R slab
48. STEP 6 Equation of Design
For shorten Direction
K=M/fcubd2
=54x106/30x1000x2342
= 0.03
Z=d(0.5+Squroot 0.25+k/0.9)
=234(0.5+Squroot 0.25+0.03/0.9)
=225.9 mm < 0.95d = 0.95x234
=222 mm NOT OK
Z=222 mm
As=M/0.95fyZ
=54x106/0.95x460x222
=556 mm2 provide 12 T@200 c/c _ 566
mm2
Check for As min and As max
As max = 4/100 x b x h
= 4/100 x 1000 x 260 = 10400 mm2
As min = 0.4/100 x b x h
= 0.13/100 x 1000 x 260 =338 mm2
For longer Direction
K=M/fcubd2
=29.4x106/30x1000x2342= 0.017
Z=d(0.5+Squroot 0.25+k/0.9)
=234(0.5+Squroot 0.25+0.017/0.9)
=229 mm < 0.95d = 0.95x234
=222 mm NOT OK
Z=222 mm
As=M/0.95fyZ
=29.4x10^6/0.95x460x222
=303 mm2 provide 10 T@200 c/c _ 393
mm2
Check for As min and As max
As max = 4/100 x b x h
= 4/100 x 1000 x 260 = 10400 mm2
As min = 0.4/100 x b x h
= 0.13/100 x 1000 x 260 =338 mm2
51. Long side
reinforceme
nt
Short side
reinforceme
nt
Overall
depth
mm
Slab size
mm
Slab name
S1 1O604 X 7500 234 12T@200 C/C 10T@200C/C
S2 7203 x7500 234 10T@200C/C 8T@175C/C
S3 7203 x7500 234 10T@200C/C 10T@200C/C
S4 10604 x 7500 234 12T@175C/C 10T@200C/C
S5 8804 x 7500 234 12T@200C/C 10T@200C/C