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IOSR Journal of Mathematics (IOSR-JM)
e-ISSN: 2278-5728,p-ISSN: 2319-765X, Volume 6, Issue 3 (May. - Jun. 2013), PP 25-29
www.iosrjournals.org
www.iosrjournals.org 25 | Page
Notions via β*-open sets in topological spaces
J.Antony Rex Rodgio , Jessie Theodore And Hanaselvi Jansi.J
Department of mathematics,V.O.Chidambaram College,Tuticorin-62800Tamil Nadu,INDIA
Ph.D. Scholar ,Department of mathematics,Sarah Tucker college,Tirunelveli- 627007,Tamil Nadu,INDIA .
Ph.D. Scholar ,Department of mathematics,Sarah Tucker college,Tirunelveli- 627007,Tamil Nadu,INDIA .
Abstract: In this paper, first we define β*-open sets and β*-interior in topological spaces.J.Antony Rex
Rodrigo[3] has studied the topological properties of 𝜂* -derived, 𝜂* -border, 𝜂* -frontier and 𝜂* exterior of a
set using the concept of 𝜂* -open following M.Caldas,S.Jafari and T.Noiri[5]. By the same technique the
concept of β*-derived, β*-border, β*-frontier and β*exterior of a set using the concept of β*-open sets are
introduced.Some interesting results that shows the relationships between these concepts are brought about.
Key words: 𝜂* -border, 𝜂* -frontier and 𝜂* exterior, β*-derived, β*-border, β*-frontier and β*exterior
I. Introduction:
For the first time the concept of generalized closed sets was considered by Levine in 1970 [7]. After
the works of Levine on semi-open sets, various mathematicians turned their attention to the generalizations of
topology by considering semi open sets instead of open sets. In 2002, M. Sheik John [8] introduced a class of
sets namely ω-closed set which is properly placed between the class of semi closed sets and the class of
generalized closed sets. The complement of an ω-closed set is called an ω-open set.The concept of semi pre
open sets was defined by Andrijevic[2] in 1986 and are also known under the name β sets.
We have already introduced a class of generalized closed sets called β*-closed sets using semipreopen
sets and ω-open sets. The complement of a β*-closed set is called β*-open set.In this paper the concept of of
β*-kernel, β*-derived, β*-border, β*-frontier and β*exterior of a set using the concept of β*-open sets are
introduced.
II. Preliminaries:
Throughout the paper (X, τ), (Y, σ) and (Z, η) or simply X, Y and Z denote topological spaces on
which no separation axioms are assumed unless otherwise mentioned explicitly.
We recall some of the definitions and results which are used in the sequel.
Definition 2.1
A subset A of a topological space (X, τ) is called
(i) A semi-open set [7] if Acl(int(A)) and a semi-closed set if int(cl(A))A,
(ii) A semipre open set [6] (= β-open set [1]) if Acl(int(cl(A))) and a semi-pre closed set(=β closed) if
int(cl(int(A)))A
(iii) ω-open [8] if cl(A)⊂ U whenever A⊂ U and U is semi open.
(iv) A β*-closed set [4] if spcl(A) int(U) whenever AU and U is ω-open
Theorem 2.2:[4] Every closed(resp.open) set is β*- closed(resp.β*open).
3.1. β*-Open sets
Definition 3.1.1: A subset A in X is called β*-open in X if Ac
is β*-closed in X. We denote the family of all
β*-open sets in X by β*O(τ).
Definition 3.1.2:For every set E⊂ X, we define the β*-closure of E to be the intersection of all β*-closed sets
containing E. In symbols, β*cl(E) = ∩ {A:E⊂ A, A∈ β*c(τ)}.
Lemma 3.1.3: For any E⊂ X, E⊂ β*cl(E)⊂ cl(E).
Proof: Follows from Theorem 2.2.
Proposition 3.1.4: Let A be a subset of a topological space X.For any x∈ X, x∈ β*cl(A) if and only if U∩A≠∅
for every β*-open set U containing x.
Proof: Necessity: Suppose that x∈ β*cl(A). Let U be a β*-open set containing x such that A∩ U = ∅ and so
A⊂Uc
. But Uc
is a β* closed set and hence β*cl(A) ⊆Uc
. Since x∉Uc
we obtain x∉ β*cl(A) which is contrary to
the hypothesis.
Sufficiency:
Suppose that every β*-open set of X containing x intersects A. If x∉ β*cl(A), then there exist a β*
closed set F of X such that A⊂ F and x∉ F. Therefore x∈ Fc
and Fc
is and β*-open set containing x. But Fc
∩A=
∅. This is contrary to the hypothesis.
Notions via β*-open sets in topological spaces
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Definition 3.1.5: For any A⊂ X, β*int(A) is defined as the union of all β*-open set contained in A. That is
β*int(A) =∪ {U:U⊂Aand U∈ β*O(τ)}.
Proposition 3.1.6: For any A⊂ X, int(A)⊂β*int(A).
Proof: Follows from Theorem 2..2.
Proposition 3.1.7: For any two subsets A1 and A2 of X.
(i) If A1⊂ A2, then β*int(Ai)⊂ β*int(A2).
(ii)β*int(A1∪ A2)β*int(A1)∪ β*int(A2).
Proposition 3.1.8: If A is β*-open then A=β*int(A).
Remark 3.1.9: Converse of Proposition 3.1.8 is not true. It can be seen by the following example.
Example 3.1.10: Let X={a, b, c} and τ = {∅, {a}, X} then for the set A={b, c}, β*int(A) = A but {b, c} is not
β* closed.
Proposition 3.1.11: Let A be a subset of a space X. Then the following are true
(i) (β*int(A))c
= β*cl(Ac
)
(ii) (β*int(A)) = (β*cl(Ac
))c
(iii) β*cl(A)= (β*int(Ac
))c
Proof:
(i) Let x∈ (β*int(A))c
. Then x∉ β*int(A). That is every β* open set U containing x is such that U∉A. Thus
every β*-open set U containing x is such that U∩Ac
≠∅. By proposition 3.1.4, x∈ β*cl(Ac
) and therefore
(β*int(A))c
⊂ β*cl(Ac
). Conversely, let x∈ β*cl(Ac
). Then by proposition 3.1.4, every β* open set U containing x
is such that U∩Ac
≠ ∅. By definition 3.1.5, x∉ β*int(A). Hence x∈ (β*int(A))c
and so β*cl(Ac
)⊂ (β*int(A))c
.
Hence (β*int(A))c
= β*cl(Ac
).
(ii) Follows by taking complements in (i).
(iii) Follows by replacing A by Ac
in (i).
Proposition 3.1.12: For a subset A of a topological space X, the following conditions are equivalent.
(i) β*O(τ) is closed under any union.
(ii) A is β* closed if and only if β*cl(A) = A.
(iii) A is β* open if and only if β*int(A) = A.
Proof: (i) ⇒ (ii): Let A be a β* closed set. Then by the definition of β*-closure we get β*cl(A) = A.
Conversely, assume β*cl(A) = A. For each x∈ Ac
, x∉ β*cl(A), by proposition 3.1.4, there exists a β* open set
Gxcontaining x such that Gx∩A=∅ and hence x∈Gx⊂ Ac
. Therefore we obtain Ac
=⋃ 𝐺𝑥𝑥∈𝐴 𝑐 . By (i) Ac
is β*-
open and hence A is β* closed.
(ii)⇒ (iii): Follows by (ii) and proposition 3.1.11.
(iii)⇒ (i): Let {Uα /α ∈∧ } be a family of β*-open sets of X. Put U=⋃ U 𝛼𝛼 . For each x∈ U, there exists α(x)∈⋁
such that x∈ Uα(x)⊂ U. Since Uα(x) is β*-open, x∈ β*int(U) and so U=β*int(U). By (iii), U is β*-open. Thus
β*O(τ) is closed under any union.
Proposition 3.1.13: In a topological space X, assume that β*O(τ) is closed under any union. Then β*cl(A) is a
β*closed set for every subset A of X.
Proof: Since β*cl(A) = β*cl(β*cl(A)) and by proposition 3.1.12, we get β*cl(A) is a β*closed set.
3.2. β-*Kernel
Definition 3.2.1: For any A⊂ X, β*ker(A) is defined as the intersection of all β*-open sets containing A. In
notation, β*ker(A) = ∩{U/A⊂ U, U∈ β*O(τ)}.
Example 3.2.2: Let X= {a, b, c}, τ = {∅, {a}, {a, c}, X}. Here β*O(τ) = P(X) –{{b}, {b, c}}. Let A= {b, c}then
kerA=X and B={a}, then kerB={a}.
Definition 3.2.3: A subset A of a topological space X is a U-set if A=β*ker(A).
Example 3.2.4: Let X={a, b, c} and τ ={∅, {a}, {a, c}, X}. Here {a}, {c}, {a, b}, {a, c} are U-sets. The set {b,
c} is not a U-set.
Lemma 3.2.5:For subsets A, B and Aα(α∈∧ ) of a topological space X, the following hold,
(i) A⊂ β*ker(A).
(ii) If A⊂ B, then β*ker(A)⊂ β*ker(B).
(iii) β*ker(β*ker(A)) = β*ker(A).
(iv) If A is β*-open then A=β*ker(A).
(v) β*ker(∪ {Aα/α ∈∧ })⊂∪ {β*ker(Aα)/α ∈∧ }
(vi) β *ker(∩ {Aα /α ∈∧ })⊂ ∩ {β*ker(Aα )/α ∈∧ }.
Proof:
(i) Clearly follows from Definition 3.2.1.
(ii) Suppose x∉ β*ker(B), then there exists a subset U∈ β*O(τ) such that UB with x∉ U. since A⊂ B, x∉
β*ker(A). Thus β*ker(A)⊂ β*ker(B).
Notions via β*-open sets in topological spaces
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(iii) Follows from (i) and Definition 3.2.1.
(iv) By definition 3.2.1 and A∈ β*O(τ), we have β*ker(A)⊂ A. By (i) we get A = β*ker(A).
(v) For each α ∈∧ , β*ker(Aα)⊂ β*ker(⋃ 𝐴 𝛼𝛼∈∧ ). Therefore we ⋃ β ∗ ker⁡(Aα)α∈∧ ⊂β*ker(⋃ 𝐴 𝛼𝛼∈⋁ ).
(vi) Suppose that x∉∩{β*ker(Aα)/α ∈} then there exists an α0∈∧ , such that x∉β*ker( A𝛼0) and there exists
a β*-open set U such that x∉ U and A𝛼0⊂ U. We have ⋂ 𝐴 𝛼𝛼∈∧ ⊂A𝛼0⊂ U and x∉ U. Therefore x∉ β*ker{∩ Aα
/α ∈∧ }. Hence ∩{β*ker(Aα)/α ∈∧ }β*ker(∩ {Aα /α ∈∧ }.
Remark 3.2.6: In (v) and (vi) of Lemma 3.2.5, the equality does not necessarily hold as shown by the following
example.
Example 3.2.7: Let X={a, b, c, d} and τ = {∅, {a}, X}. Let A = {b} and B = {c, d}. Hereβ*kerA = {b} and
β*ker(B)={c, d}. β*ker(A)∪ β*kerB = {b}∪ {b}∪ {c, d} = {b, c, d}. β*ker(A∪ B) = β*ker({b, c, d}) = X.
Let X= {a, b, c} and τ= {∅, {a}, X}. Let P= {a, b} and Q= {b, c}. Here β*ker(P∩Q) = β*ker({b}) =
{b}. But β*ker(P)∩ β*ker(Q) = {a, b}∩ X = {a, b}.
Remark 3.2.8: From (iii) of Lemma 3.2.5 it is clear that β*ker(A) is a U-set and every open set is a U-set.
Lemma 3.2.9: Let Aα(α ∈⋀) be a subset of a topological space X. If Aα is a U-set then (⋂ 𝐴 𝛼𝛼∈⋀ ) is a U-set.
Proof: β*ker(⋂ 𝐴 𝛼𝛼∈⋀ ) ⊂⋂ β∗
ker⁡(Aα)α∈⋀ , by lemma 3.2.5. Since Aα is a U-set, we
getβ*ker(⋂ 𝐴 𝛼𝛼∈⋀ )⊂(⋂ 𝐴 𝛼𝛼∈⋀ ). Again by (i) of lemma 2.4.28, (⋂ 𝐴 𝛼𝛼∈⋀ )⊂β*ker(⋂ 𝐴 𝛼𝛼∈⋀ ). Thus
β*ker(⋂ 𝐴 𝛼𝛼∈⋀ )= (⋂ 𝐴 𝛼𝛼∈⋀ ) which implies (⋂ 𝐴 𝛼𝛼∈⋀ ) is U-set.
Definition 3.2.10: A subset A of a topological space X is said to be U-closed if A= L∩ F where L is an U-set
and F is a closed set of X.
Remark 3.2.11: It is clear that every U-set and closed sets are U-closed.
Theorem 3.2.12: For a subset A of a topological space X, the following conditions are equivalent.
(i) A is U-closed
(ii) A = L∩cl(A) where L is a U-set.
(iii) A = β*ker(A)∩ cl(A).
Proof:
(i)⇒(ii): Let A = L∩F where L is a U-set and F is a closed set. Since A⊂ F, we have cl(A)⊂ F and A⊂ L∩
cl(A)⊂ L∩ F = A. Therefore, we obtain L∩cl(A) = A.
(ii)⇒ (iii): Let A = L∩cl(A) where L is a U-set. Since A⊂ L, we have β*ker(A)⊂β*ker(L) = L. Therefore
β*ker(A)∩ cl(A)⊂ L∩ cl(A) = A. Hence A = β*ker(A)∩ cl(A).
(iii)⇒ (i): Since β*ker(A) is a U-set, the proof follows.
3.3. β*-Derived set
Definition 3.3.1: Let A be a subset of a space X. A point x∈ X is said to be a β* limit point of A, if for each β*-
open set U containing x, U∩ (A-{x}) ≠∅. The set of all β* limit point of A is called a β*-derived set of A and is
denoted by Dβ*(A).
Theorem 3.3.2.: For subsets A, B of a space X, the following statements hold
(i) Dβ*(A) ⊂D(A) where D(A) is the derived set of A.
(ii) If A⊂ B, then Dβ*(A)⊂ Dβ*(B).
(iii) Dβ*(A)∪ Dβ*(B)⊂ Dβ*(A∪B) and Dβ*(A∩B)⊂ Dβ*(A)∩ Dβ*(B).
(iv) Dβ*(Dβ*(A))-A⊂ Dβ*(A).
(v) Dβ*(A∪Dβ*(A))⊂ A∪Dβ*(A).
Proof:
(i) Since every open set is β*-open, the proof follows.
(ii) Follows from definition 3.3.1.
(iii) Follows by (i).
(iv) If x∈ Dβ*(Dβ*(A))-A and U is a β*-open set containing x, then U∩(Dβ*(A)-{x})≠∅. Let y∈ U∩(Dβ*(A)-
{x}). Then since y∈ Dβ*(A) and y∈ U, U∩ (A-{y})≠∅. Let z∈ U∩{A-{y}}. Then z≠x for z∈ A and x∉ A.
Hence U∩(A-{x})≠∅. Therefore, x∈ Dβ*(A).
(v) Let x∈ Dβ*(A∪Dβ*(A)). If x∈ A, the result is obvious. So let x∈ Dβ*(A∪Dβ*(A))-A, then for an β*-open
set U containing x. U∩((A∪Dβ*(A))-{x})≠∅. Thus U∩(A-{x})≠∅ or U∩(Dβ*(A)-{x})≠∅. By the same argument
in (iv), it follows that U∩ (A-{x}) ≠∅. Hence x∈ Dβ*(A). Therefore in either caseDβ*(A∪Dβ*(A))⊂ A∪Dβ*(A).
Remark 3.3.3: In general, the converse of (i) is not true. For example, Let X={a, b, c} and τ = {∅, {a, b}, X}.
Then β*O(τ)={∅, {a}, {b}, {a, b}, X}. Let A = {a, b} then D(A) = X and Dβ*(A) = c. Therefore D(A)  Dβ*(A).
Proposition 3.3.4: Dβ*(A∪B) ≠Dβ*(A)∪Dβ*(B).
Example 3.3.5: Let X = {a, b, c. d} and τ = {∅, {a, b}, X}. Then β*O(τ) = P(X) – [a}, {b}, {a, b}. Let A = {a,
b, d} and B ={c}. Then Dβ*(A∪ B) = {a, b} and Dβ*(A) = ∅, Dβ*(B)=∅.
Theorem 3.3.6: For any subset A of a space X, β*cl(A)= A∪Dβ*(A).
Notions via β*-open sets in topological spaces
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Proof: Since Dβ*(A)⊂ β*cl(A), A∪Dβ*(A)⊂ β*cl(A). On the other hand, let x∈ β*cl(A). If x∈ A, then the proof
is complete. If x∉A, each β*-open set U containing x intersects A at a point distinct from x, so x∈ Dβ*(A). Thus
β*cl(A)⊂ Dβ*(A) ∪ A and hence the theorem.
3. 4. β-*Border
Definition 3.4.1: Let A be a subset of a space X. Then the β* border of A is defined as bβ*(A) = A-β*int(A).
Theorem.3.4.2: For a subset A of a space X, the following statements hold.
(i) bβ*(A)⊂ b(A) where b(A) denote the border of A.
(ii) A = β*int(A) ∪bβ*(A).
(iii) β*int(A)∩ bβ*(A)=∅.
(iv) If A is β*-open then bβ*(A) =∅.
(v) β*int(bβ*(A))=∅.
(vi) bβ* (bβ*(A))=bβ*(A).
(vii) bβ*(A)=A∩ β*cl(Ac
).
Proof: (i),(ii) and (iii) are obvious from the definitions of β*interior of A and β*-border of A where A is any
subset of X.
vi) If A is β*-open, then A=β*int(A). Hence the result follows.
v) If x∈ β*int(bβ*(A)), then x∈ bβ*(A). Now bβ*(A)⊂ A implies β*int(bβ*(A))⊂ β*int(A). Hence x∈ β*int(A)
which is a contradiction to x∈ bβ*(A). Thus β*int(bβ*(A)) = ∅.
vi) bβ*(bβ*(A)) = bβ*(A-β*int(A)) = (A-β*int(A))-β*int(A-β*int(A)) which is bβ*(A)-∅, by (iv). Hence
bβ*(bβ*(A)) = bβ*(A).
vii) bβ*(A) = A-β*int(A) = A-(β*cl(Ac
))c
= A∩ β*cl(Ac
).
Remark 3.4.3.: In general, the converse of (i) is not true. For example, let X = {a, b, c} and τ = {∅, {a}, {a, b},
X}. Then β*O(τ) = {∅, {a}, {b}, {a, b}, {a, c}, X}. Let A = {a, c}, then bβ*(A) = {a, c} – {a, c} = ∅ and b(A) =
{a, c}-{a} = {c}. Therefore b(A)bβ*(A).
3.5 β-*Frontier
Definition 3.5.1: Let A be a subset of a space X. Then β*-frontier of A is defined as Frβ*(A)-β*int(A).
Theorem 3.5.2: For a subset A of a space X, the following statements hold
i) Frβ*(A) ⊂Fr(A), where Fr(A) denotes the frontier of A.
ii) β*cl(A)= β*int(A)∪Frβ*(A)
iii) β*int(A)∩Frβ*(A) = ∅.
iv) bβ*(A)⊂Frβ*(A)
v) Frβ*(A) = bβ*(A)∪ Dβ*(A)
vi) If A is β*-open, then Frβ*(A) =Dβ*(A)
vii) Frβ*(A) =β*cl(A)∩ β*cl(Ac
)
viii) Frβ*(A) =Frβ*(Ac
)
ix) Frβ*(β*int(A))⊂Frβ*(A).
x) Frβ*(β*cl(A)) ⊂Frβ*(A).
Proof:
i) Since every open set is β*-open we get the proof.
ii) β*int(A)∪Frβ*(A)= β*int(A)∪ (β*cl(A)-β*int(A)) = β*cl(A).
iii) β*int(A)∩Frβ*(A)=β*int(A)∩(β*cl(A)-β*int(A))=∅.
iv) Obvious from the definition.
v) β*int(A)∪Frβ*(A)=β*int(A)∪bβ*(A)∪ Dβ*(A), is obvious from the definition. Therefore we get Frβ*(A)
= bβ*(A)∪ Dβ*(A).
vi) If A is β*-open, then bβ*(A) = ∅, then by (V)Frβ*(A) =Dβ*(A).
vii) Frβ*(A) =β*cl(A)-β*int(A) = β*cl(A)-(β*cl(Ac
))c
= β*cl(A)∩ β*cl(Ac
).
viii) Follows from (vii).
ix) Obvious.
x) Frβ*(β*cl(A))=β*cl(β*cl(A))-β*int(β*cl(A))= β*cl(A)-β*int(A) =Frβ*(A).
In general the converse of (i) of theorem 3.5.2 is not true.
Example 3.5.3: Let X={a, b, c} and τ = {∅, {a}, {a, b}, X}. Then β*cl(τ) = {∅, {b}, {c}, {b, c}, {a, c}, X}. Let
A = {a, b}. Then β*cl(A)-β*int(A) = Frβ*(A)=X-{a, b} = {c}. But cl(A)-int(A) = Fr(A) = X-{a} = {b,c}.
Therefore Fr(A)Frβ*(A).
3.6.β-*Exterior
Definition 3.6.1: β*Ext(A) = β*int(Ac
) is said to be the β* exterior of A.
Theorem 3.6.2: For a subset A of a space X, the following statements hold
Notions via β*-open sets in topological spaces
www.iosrjournals.org 29 | Page
(i) Ext(A) ⊂ β*Ext(A) where Ext(A) denote the exterior of A.
(ii) β*Ext(As) = β*int(Ac
) = (β*cl(A))c
.
(iii) β*Ext(β*Ext(A)) = β*int(β*cl(A))
(iv) If A⊂ B, then β*Ext(A) β*Ext(B).
(v) β*Ext(A∪B)⊂ β*Ext(A)∪ β*Ext(B).
(vi) β*Ext(A∩B)β*Ext(A)∩ β*Ext(B).
(vii) β*Ext(X)= ∅.
(viii) β*Ext(∅)= X.
(ix) β*int(A)⊂ β*Ext(β*Ext(A)).
Proof: (i) & (ii) follows from definition 3.6.1.
iii) β*Ext(β*Ext(A)) = β*Ext(β*int(Ac
)) = β*Ext(β*cl(A)c
) = β*int(β*cl(A)).
iv)If A⊂ B, then Ac
Bc
. Hence β*int(Ac
)β*int(Bc
) and so β*Ext(A)β*Ext(B).
v) and (vi) follows from (iv).
(vii) and (viii) follows from 3.6.1.
ix) β*int(A)⊂ β*int(β*cl(A)) = β*int(β*int(Ac
)) = β*int(β*Ext(A))c
= β*Ext(β*Ext(A)).
Proposition 3.6.3: In general equality does not hold in (i), (v) and (vi) of Theorem 2.4.49.
Example 3.6.4: Let X= {a, b, c} and τ = {∅, {a, b}, X}. Then β*O(τ) = {∅, {a}, {b},{a, b}, X}. If A= {a},
B={b} and C={c} then β*Ext(A) ={b},β*Ext(B) ={a} and Ext(A) = ∅. Therefore β*Ext(A)Ext(A),
β*Ext(A)∪ β*Ext(B)β*Ext(A∪B) and β*Ext(A∩B) β*Ext(A)∩ β*Ext(B).
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[7]. . Levine N., Semi-open sets and semi-continuity in topological spaces, Amer. Math. Monthly, 70(1963)
[8]. .Sheik John M., A Study on generalizations of closed sets and continuous maps in topological and bitopological spaces, Ph.D., Thesis,
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Notions via β*-open sets in topological spaces

  • 1. IOSR Journal of Mathematics (IOSR-JM) e-ISSN: 2278-5728,p-ISSN: 2319-765X, Volume 6, Issue 3 (May. - Jun. 2013), PP 25-29 www.iosrjournals.org www.iosrjournals.org 25 | Page Notions via β*-open sets in topological spaces J.Antony Rex Rodgio , Jessie Theodore And Hanaselvi Jansi.J Department of mathematics,V.O.Chidambaram College,Tuticorin-62800Tamil Nadu,INDIA Ph.D. Scholar ,Department of mathematics,Sarah Tucker college,Tirunelveli- 627007,Tamil Nadu,INDIA . Ph.D. Scholar ,Department of mathematics,Sarah Tucker college,Tirunelveli- 627007,Tamil Nadu,INDIA . Abstract: In this paper, first we define β*-open sets and β*-interior in topological spaces.J.Antony Rex Rodrigo[3] has studied the topological properties of 𝜂* -derived, 𝜂* -border, 𝜂* -frontier and 𝜂* exterior of a set using the concept of 𝜂* -open following M.Caldas,S.Jafari and T.Noiri[5]. By the same technique the concept of β*-derived, β*-border, β*-frontier and β*exterior of a set using the concept of β*-open sets are introduced.Some interesting results that shows the relationships between these concepts are brought about. Key words: 𝜂* -border, 𝜂* -frontier and 𝜂* exterior, β*-derived, β*-border, β*-frontier and β*exterior I. Introduction: For the first time the concept of generalized closed sets was considered by Levine in 1970 [7]. After the works of Levine on semi-open sets, various mathematicians turned their attention to the generalizations of topology by considering semi open sets instead of open sets. In 2002, M. Sheik John [8] introduced a class of sets namely ω-closed set which is properly placed between the class of semi closed sets and the class of generalized closed sets. The complement of an ω-closed set is called an ω-open set.The concept of semi pre open sets was defined by Andrijevic[2] in 1986 and are also known under the name β sets. We have already introduced a class of generalized closed sets called β*-closed sets using semipreopen sets and ω-open sets. The complement of a β*-closed set is called β*-open set.In this paper the concept of of β*-kernel, β*-derived, β*-border, β*-frontier and β*exterior of a set using the concept of β*-open sets are introduced. II. Preliminaries: Throughout the paper (X, τ), (Y, σ) and (Z, η) or simply X, Y and Z denote topological spaces on which no separation axioms are assumed unless otherwise mentioned explicitly. We recall some of the definitions and results which are used in the sequel. Definition 2.1 A subset A of a topological space (X, τ) is called (i) A semi-open set [7] if Acl(int(A)) and a semi-closed set if int(cl(A))A, (ii) A semipre open set [6] (= β-open set [1]) if Acl(int(cl(A))) and a semi-pre closed set(=β closed) if int(cl(int(A)))A (iii) ω-open [8] if cl(A)⊂ U whenever A⊂ U and U is semi open. (iv) A β*-closed set [4] if spcl(A) int(U) whenever AU and U is ω-open Theorem 2.2:[4] Every closed(resp.open) set is β*- closed(resp.β*open). 3.1. β*-Open sets Definition 3.1.1: A subset A in X is called β*-open in X if Ac is β*-closed in X. We denote the family of all β*-open sets in X by β*O(τ). Definition 3.1.2:For every set E⊂ X, we define the β*-closure of E to be the intersection of all β*-closed sets containing E. In symbols, β*cl(E) = ∩ {A:E⊂ A, A∈ β*c(τ)}. Lemma 3.1.3: For any E⊂ X, E⊂ β*cl(E)⊂ cl(E). Proof: Follows from Theorem 2.2. Proposition 3.1.4: Let A be a subset of a topological space X.For any x∈ X, x∈ β*cl(A) if and only if U∩A≠∅ for every β*-open set U containing x. Proof: Necessity: Suppose that x∈ β*cl(A). Let U be a β*-open set containing x such that A∩ U = ∅ and so A⊂Uc . But Uc is a β* closed set and hence β*cl(A) ⊆Uc . Since x∉Uc we obtain x∉ β*cl(A) which is contrary to the hypothesis. Sufficiency: Suppose that every β*-open set of X containing x intersects A. If x∉ β*cl(A), then there exist a β* closed set F of X such that A⊂ F and x∉ F. Therefore x∈ Fc and Fc is and β*-open set containing x. But Fc ∩A= ∅. This is contrary to the hypothesis.
  • 2. Notions via β*-open sets in topological spaces www.iosrjournals.org 26 | Page Definition 3.1.5: For any A⊂ X, β*int(A) is defined as the union of all β*-open set contained in A. That is β*int(A) =∪ {U:U⊂Aand U∈ β*O(τ)}. Proposition 3.1.6: For any A⊂ X, int(A)⊂β*int(A). Proof: Follows from Theorem 2..2. Proposition 3.1.7: For any two subsets A1 and A2 of X. (i) If A1⊂ A2, then β*int(Ai)⊂ β*int(A2). (ii)β*int(A1∪ A2)β*int(A1)∪ β*int(A2). Proposition 3.1.8: If A is β*-open then A=β*int(A). Remark 3.1.9: Converse of Proposition 3.1.8 is not true. It can be seen by the following example. Example 3.1.10: Let X={a, b, c} and τ = {∅, {a}, X} then for the set A={b, c}, β*int(A) = A but {b, c} is not β* closed. Proposition 3.1.11: Let A be a subset of a space X. Then the following are true (i) (β*int(A))c = β*cl(Ac ) (ii) (β*int(A)) = (β*cl(Ac ))c (iii) β*cl(A)= (β*int(Ac ))c Proof: (i) Let x∈ (β*int(A))c . Then x∉ β*int(A). That is every β* open set U containing x is such that U∉A. Thus every β*-open set U containing x is such that U∩Ac ≠∅. By proposition 3.1.4, x∈ β*cl(Ac ) and therefore (β*int(A))c ⊂ β*cl(Ac ). Conversely, let x∈ β*cl(Ac ). Then by proposition 3.1.4, every β* open set U containing x is such that U∩Ac ≠ ∅. By definition 3.1.5, x∉ β*int(A). Hence x∈ (β*int(A))c and so β*cl(Ac )⊂ (β*int(A))c . Hence (β*int(A))c = β*cl(Ac ). (ii) Follows by taking complements in (i). (iii) Follows by replacing A by Ac in (i). Proposition 3.1.12: For a subset A of a topological space X, the following conditions are equivalent. (i) β*O(τ) is closed under any union. (ii) A is β* closed if and only if β*cl(A) = A. (iii) A is β* open if and only if β*int(A) = A. Proof: (i) ⇒ (ii): Let A be a β* closed set. Then by the definition of β*-closure we get β*cl(A) = A. Conversely, assume β*cl(A) = A. For each x∈ Ac , x∉ β*cl(A), by proposition 3.1.4, there exists a β* open set Gxcontaining x such that Gx∩A=∅ and hence x∈Gx⊂ Ac . Therefore we obtain Ac =⋃ 𝐺𝑥𝑥∈𝐴 𝑐 . By (i) Ac is β*- open and hence A is β* closed. (ii)⇒ (iii): Follows by (ii) and proposition 3.1.11. (iii)⇒ (i): Let {Uα /α ∈∧ } be a family of β*-open sets of X. Put U=⋃ U 𝛼𝛼 . For each x∈ U, there exists α(x)∈⋁ such that x∈ Uα(x)⊂ U. Since Uα(x) is β*-open, x∈ β*int(U) and so U=β*int(U). By (iii), U is β*-open. Thus β*O(τ) is closed under any union. Proposition 3.1.13: In a topological space X, assume that β*O(τ) is closed under any union. Then β*cl(A) is a β*closed set for every subset A of X. Proof: Since β*cl(A) = β*cl(β*cl(A)) and by proposition 3.1.12, we get β*cl(A) is a β*closed set. 3.2. β-*Kernel Definition 3.2.1: For any A⊂ X, β*ker(A) is defined as the intersection of all β*-open sets containing A. In notation, β*ker(A) = ∩{U/A⊂ U, U∈ β*O(τ)}. Example 3.2.2: Let X= {a, b, c}, τ = {∅, {a}, {a, c}, X}. Here β*O(τ) = P(X) –{{b}, {b, c}}. Let A= {b, c}then kerA=X and B={a}, then kerB={a}. Definition 3.2.3: A subset A of a topological space X is a U-set if A=β*ker(A). Example 3.2.4: Let X={a, b, c} and τ ={∅, {a}, {a, c}, X}. Here {a}, {c}, {a, b}, {a, c} are U-sets. The set {b, c} is not a U-set. Lemma 3.2.5:For subsets A, B and Aα(α∈∧ ) of a topological space X, the following hold, (i) A⊂ β*ker(A). (ii) If A⊂ B, then β*ker(A)⊂ β*ker(B). (iii) β*ker(β*ker(A)) = β*ker(A). (iv) If A is β*-open then A=β*ker(A). (v) β*ker(∪ {Aα/α ∈∧ })⊂∪ {β*ker(Aα)/α ∈∧ } (vi) β *ker(∩ {Aα /α ∈∧ })⊂ ∩ {β*ker(Aα )/α ∈∧ }. Proof: (i) Clearly follows from Definition 3.2.1. (ii) Suppose x∉ β*ker(B), then there exists a subset U∈ β*O(τ) such that UB with x∉ U. since A⊂ B, x∉ β*ker(A). Thus β*ker(A)⊂ β*ker(B).
  • 3. Notions via β*-open sets in topological spaces www.iosrjournals.org 27 | Page (iii) Follows from (i) and Definition 3.2.1. (iv) By definition 3.2.1 and A∈ β*O(τ), we have β*ker(A)⊂ A. By (i) we get A = β*ker(A). (v) For each α ∈∧ , β*ker(Aα)⊂ β*ker(⋃ 𝐴 𝛼𝛼∈∧ ). Therefore we ⋃ β ∗ ker⁡(Aα)α∈∧ ⊂β*ker(⋃ 𝐴 𝛼𝛼∈⋁ ). (vi) Suppose that x∉∩{β*ker(Aα)/α ∈} then there exists an α0∈∧ , such that x∉β*ker( A𝛼0) and there exists a β*-open set U such that x∉ U and A𝛼0⊂ U. We have ⋂ 𝐴 𝛼𝛼∈∧ ⊂A𝛼0⊂ U and x∉ U. Therefore x∉ β*ker{∩ Aα /α ∈∧ }. Hence ∩{β*ker(Aα)/α ∈∧ }β*ker(∩ {Aα /α ∈∧ }. Remark 3.2.6: In (v) and (vi) of Lemma 3.2.5, the equality does not necessarily hold as shown by the following example. Example 3.2.7: Let X={a, b, c, d} and τ = {∅, {a}, X}. Let A = {b} and B = {c, d}. Hereβ*kerA = {b} and β*ker(B)={c, d}. β*ker(A)∪ β*kerB = {b}∪ {b}∪ {c, d} = {b, c, d}. β*ker(A∪ B) = β*ker({b, c, d}) = X. Let X= {a, b, c} and τ= {∅, {a}, X}. Let P= {a, b} and Q= {b, c}. Here β*ker(P∩Q) = β*ker({b}) = {b}. But β*ker(P)∩ β*ker(Q) = {a, b}∩ X = {a, b}. Remark 3.2.8: From (iii) of Lemma 3.2.5 it is clear that β*ker(A) is a U-set and every open set is a U-set. Lemma 3.2.9: Let Aα(α ∈⋀) be a subset of a topological space X. If Aα is a U-set then (⋂ 𝐴 𝛼𝛼∈⋀ ) is a U-set. Proof: β*ker(⋂ 𝐴 𝛼𝛼∈⋀ ) ⊂⋂ β∗ ker⁡(Aα)α∈⋀ , by lemma 3.2.5. Since Aα is a U-set, we getβ*ker(⋂ 𝐴 𝛼𝛼∈⋀ )⊂(⋂ 𝐴 𝛼𝛼∈⋀ ). Again by (i) of lemma 2.4.28, (⋂ 𝐴 𝛼𝛼∈⋀ )⊂β*ker(⋂ 𝐴 𝛼𝛼∈⋀ ). Thus β*ker(⋂ 𝐴 𝛼𝛼∈⋀ )= (⋂ 𝐴 𝛼𝛼∈⋀ ) which implies (⋂ 𝐴 𝛼𝛼∈⋀ ) is U-set. Definition 3.2.10: A subset A of a topological space X is said to be U-closed if A= L∩ F where L is an U-set and F is a closed set of X. Remark 3.2.11: It is clear that every U-set and closed sets are U-closed. Theorem 3.2.12: For a subset A of a topological space X, the following conditions are equivalent. (i) A is U-closed (ii) A = L∩cl(A) where L is a U-set. (iii) A = β*ker(A)∩ cl(A). Proof: (i)⇒(ii): Let A = L∩F where L is a U-set and F is a closed set. Since A⊂ F, we have cl(A)⊂ F and A⊂ L∩ cl(A)⊂ L∩ F = A. Therefore, we obtain L∩cl(A) = A. (ii)⇒ (iii): Let A = L∩cl(A) where L is a U-set. Since A⊂ L, we have β*ker(A)⊂β*ker(L) = L. Therefore β*ker(A)∩ cl(A)⊂ L∩ cl(A) = A. Hence A = β*ker(A)∩ cl(A). (iii)⇒ (i): Since β*ker(A) is a U-set, the proof follows. 3.3. β*-Derived set Definition 3.3.1: Let A be a subset of a space X. A point x∈ X is said to be a β* limit point of A, if for each β*- open set U containing x, U∩ (A-{x}) ≠∅. The set of all β* limit point of A is called a β*-derived set of A and is denoted by Dβ*(A). Theorem 3.3.2.: For subsets A, B of a space X, the following statements hold (i) Dβ*(A) ⊂D(A) where D(A) is the derived set of A. (ii) If A⊂ B, then Dβ*(A)⊂ Dβ*(B). (iii) Dβ*(A)∪ Dβ*(B)⊂ Dβ*(A∪B) and Dβ*(A∩B)⊂ Dβ*(A)∩ Dβ*(B). (iv) Dβ*(Dβ*(A))-A⊂ Dβ*(A). (v) Dβ*(A∪Dβ*(A))⊂ A∪Dβ*(A). Proof: (i) Since every open set is β*-open, the proof follows. (ii) Follows from definition 3.3.1. (iii) Follows by (i). (iv) If x∈ Dβ*(Dβ*(A))-A and U is a β*-open set containing x, then U∩(Dβ*(A)-{x})≠∅. Let y∈ U∩(Dβ*(A)- {x}). Then since y∈ Dβ*(A) and y∈ U, U∩ (A-{y})≠∅. Let z∈ U∩{A-{y}}. Then z≠x for z∈ A and x∉ A. Hence U∩(A-{x})≠∅. Therefore, x∈ Dβ*(A). (v) Let x∈ Dβ*(A∪Dβ*(A)). If x∈ A, the result is obvious. So let x∈ Dβ*(A∪Dβ*(A))-A, then for an β*-open set U containing x. U∩((A∪Dβ*(A))-{x})≠∅. Thus U∩(A-{x})≠∅ or U∩(Dβ*(A)-{x})≠∅. By the same argument in (iv), it follows that U∩ (A-{x}) ≠∅. Hence x∈ Dβ*(A). Therefore in either caseDβ*(A∪Dβ*(A))⊂ A∪Dβ*(A). Remark 3.3.3: In general, the converse of (i) is not true. For example, Let X={a, b, c} and τ = {∅, {a, b}, X}. Then β*O(τ)={∅, {a}, {b}, {a, b}, X}. Let A = {a, b} then D(A) = X and Dβ*(A) = c. Therefore D(A)  Dβ*(A). Proposition 3.3.4: Dβ*(A∪B) ≠Dβ*(A)∪Dβ*(B). Example 3.3.5: Let X = {a, b, c. d} and τ = {∅, {a, b}, X}. Then β*O(τ) = P(X) – [a}, {b}, {a, b}. Let A = {a, b, d} and B ={c}. Then Dβ*(A∪ B) = {a, b} and Dβ*(A) = ∅, Dβ*(B)=∅. Theorem 3.3.6: For any subset A of a space X, β*cl(A)= A∪Dβ*(A).
  • 4. Notions via β*-open sets in topological spaces www.iosrjournals.org 28 | Page Proof: Since Dβ*(A)⊂ β*cl(A), A∪Dβ*(A)⊂ β*cl(A). On the other hand, let x∈ β*cl(A). If x∈ A, then the proof is complete. If x∉A, each β*-open set U containing x intersects A at a point distinct from x, so x∈ Dβ*(A). Thus β*cl(A)⊂ Dβ*(A) ∪ A and hence the theorem. 3. 4. β-*Border Definition 3.4.1: Let A be a subset of a space X. Then the β* border of A is defined as bβ*(A) = A-β*int(A). Theorem.3.4.2: For a subset A of a space X, the following statements hold. (i) bβ*(A)⊂ b(A) where b(A) denote the border of A. (ii) A = β*int(A) ∪bβ*(A). (iii) β*int(A)∩ bβ*(A)=∅. (iv) If A is β*-open then bβ*(A) =∅. (v) β*int(bβ*(A))=∅. (vi) bβ* (bβ*(A))=bβ*(A). (vii) bβ*(A)=A∩ β*cl(Ac ). Proof: (i),(ii) and (iii) are obvious from the definitions of β*interior of A and β*-border of A where A is any subset of X. vi) If A is β*-open, then A=β*int(A). Hence the result follows. v) If x∈ β*int(bβ*(A)), then x∈ bβ*(A). Now bβ*(A)⊂ A implies β*int(bβ*(A))⊂ β*int(A). Hence x∈ β*int(A) which is a contradiction to x∈ bβ*(A). Thus β*int(bβ*(A)) = ∅. vi) bβ*(bβ*(A)) = bβ*(A-β*int(A)) = (A-β*int(A))-β*int(A-β*int(A)) which is bβ*(A)-∅, by (iv). Hence bβ*(bβ*(A)) = bβ*(A). vii) bβ*(A) = A-β*int(A) = A-(β*cl(Ac ))c = A∩ β*cl(Ac ). Remark 3.4.3.: In general, the converse of (i) is not true. For example, let X = {a, b, c} and τ = {∅, {a}, {a, b}, X}. Then β*O(τ) = {∅, {a}, {b}, {a, b}, {a, c}, X}. Let A = {a, c}, then bβ*(A) = {a, c} – {a, c} = ∅ and b(A) = {a, c}-{a} = {c}. Therefore b(A)bβ*(A). 3.5 β-*Frontier Definition 3.5.1: Let A be a subset of a space X. Then β*-frontier of A is defined as Frβ*(A)-β*int(A). Theorem 3.5.2: For a subset A of a space X, the following statements hold i) Frβ*(A) ⊂Fr(A), where Fr(A) denotes the frontier of A. ii) β*cl(A)= β*int(A)∪Frβ*(A) iii) β*int(A)∩Frβ*(A) = ∅. iv) bβ*(A)⊂Frβ*(A) v) Frβ*(A) = bβ*(A)∪ Dβ*(A) vi) If A is β*-open, then Frβ*(A) =Dβ*(A) vii) Frβ*(A) =β*cl(A)∩ β*cl(Ac ) viii) Frβ*(A) =Frβ*(Ac ) ix) Frβ*(β*int(A))⊂Frβ*(A). x) Frβ*(β*cl(A)) ⊂Frβ*(A). Proof: i) Since every open set is β*-open we get the proof. ii) β*int(A)∪Frβ*(A)= β*int(A)∪ (β*cl(A)-β*int(A)) = β*cl(A). iii) β*int(A)∩Frβ*(A)=β*int(A)∩(β*cl(A)-β*int(A))=∅. iv) Obvious from the definition. v) β*int(A)∪Frβ*(A)=β*int(A)∪bβ*(A)∪ Dβ*(A), is obvious from the definition. Therefore we get Frβ*(A) = bβ*(A)∪ Dβ*(A). vi) If A is β*-open, then bβ*(A) = ∅, then by (V)Frβ*(A) =Dβ*(A). vii) Frβ*(A) =β*cl(A)-β*int(A) = β*cl(A)-(β*cl(Ac ))c = β*cl(A)∩ β*cl(Ac ). viii) Follows from (vii). ix) Obvious. x) Frβ*(β*cl(A))=β*cl(β*cl(A))-β*int(β*cl(A))= β*cl(A)-β*int(A) =Frβ*(A). In general the converse of (i) of theorem 3.5.2 is not true. Example 3.5.3: Let X={a, b, c} and τ = {∅, {a}, {a, b}, X}. Then β*cl(τ) = {∅, {b}, {c}, {b, c}, {a, c}, X}. Let A = {a, b}. Then β*cl(A)-β*int(A) = Frβ*(A)=X-{a, b} = {c}. But cl(A)-int(A) = Fr(A) = X-{a} = {b,c}. Therefore Fr(A)Frβ*(A). 3.6.β-*Exterior Definition 3.6.1: β*Ext(A) = β*int(Ac ) is said to be the β* exterior of A. Theorem 3.6.2: For a subset A of a space X, the following statements hold
  • 5. Notions via β*-open sets in topological spaces www.iosrjournals.org 29 | Page (i) Ext(A) ⊂ β*Ext(A) where Ext(A) denote the exterior of A. (ii) β*Ext(As) = β*int(Ac ) = (β*cl(A))c . (iii) β*Ext(β*Ext(A)) = β*int(β*cl(A)) (iv) If A⊂ B, then β*Ext(A) β*Ext(B). (v) β*Ext(A∪B)⊂ β*Ext(A)∪ β*Ext(B). (vi) β*Ext(A∩B)β*Ext(A)∩ β*Ext(B). (vii) β*Ext(X)= ∅. (viii) β*Ext(∅)= X. (ix) β*int(A)⊂ β*Ext(β*Ext(A)). Proof: (i) & (ii) follows from definition 3.6.1. iii) β*Ext(β*Ext(A)) = β*Ext(β*int(Ac )) = β*Ext(β*cl(A)c ) = β*int(β*cl(A)). iv)If A⊂ B, then Ac Bc . Hence β*int(Ac )β*int(Bc ) and so β*Ext(A)β*Ext(B). v) and (vi) follows from (iv). (vii) and (viii) follows from 3.6.1. ix) β*int(A)⊂ β*int(β*cl(A)) = β*int(β*int(Ac )) = β*int(β*Ext(A))c = β*Ext(β*Ext(A)). Proposition 3.6.3: In general equality does not hold in (i), (v) and (vi) of Theorem 2.4.49. Example 3.6.4: Let X= {a, b, c} and τ = {∅, {a, b}, X}. Then β*O(τ) = {∅, {a}, {b},{a, b}, X}. If A= {a}, B={b} and C={c} then β*Ext(A) ={b},β*Ext(B) ={a} and Ext(A) = ∅. Therefore β*Ext(A)Ext(A), β*Ext(A)∪ β*Ext(B)β*Ext(A∪B) and β*Ext(A∩B) β*Ext(A)∩ β*Ext(B). References: [1]. Abd EI-Mobsef M.E,EI-Deeb S.N and Mahmoud R.A., β-open sets and β-continuous mappings, Bull.Fac.Sci.Assiut Univ., 12(1983), 77-90. [2]. Andrijevic D., Semi-preopen sets, Mat. Vesnik, 38(1986), 24-32. [3]. Antony Rex Rodrigo. J. Some Characterizations of η* closed sets and η* -continuous maps in Topological and bitopological spaces, Ph.D., Thesis, Alagappa university, Karaikudi(2007) [4]. Antony Rex Rodrigo J,Jessie Theodore and Hana selvi Jansi,β* -Closed sets in topological spaces,International journal of mathematical Archive-3(3),2012,1065-1070 [5]. Caldas M Jafari S., and Noiri,T., Notions via g-open sets,Kochi J. of maths (accepted) [6]. Dontchev. J, On generalizing semi-preopen sets. Mem. Fac. Sci. Kochi Uni. Ser. A Math., (1995), 35-48. [7]. . Levine N., Semi-open sets and semi-continuity in topological spaces, Amer. Math. Monthly, 70(1963) [8]. .Sheik John M., A Study on generalizations of closed sets and continuous maps in topological and bitopological spaces, Ph.D., Thesis, Bharathiar University, Coimbatore(2002). .