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BENGKEL SCORE A+
PHYSICS PAPER 2
SPM 2016
Diagram 1 shows a thermometer is used to
measure the temperature of hot water.
(i) Name one type of liquid
used in the thermometer.
………………………………………
[1 mark]
(ii) Give one reason for the
answer in 1(a)(i).
…………………………………………
[1 mark]
1
Mercury / alcohol
expand uniformly / does
not stick to glass / opaque
/ high boiling point
(i) Complete the following
sentence by ticking (√) the correct
answer.
The temperature of water is taken
when the liquid in the
thermometer
…….. starts to expand.
…….. stops expanding [1 mark]
(ii) Name the physics principle
involved in 1(b)(i).
……………………………………………….
[1 mark]
X
Thermal equilibrium
1
Diagram 2 shows an instrument which is
used to measure atmospheric pressure.
(a) Based on Diagram 2,
(i) Name the instrument which is used
to measure the atmospheric pressure.
………………………………………………………….
(ii) State one reason why mercury is
used in the instrument.
……………………………………………………………
Barometer
Higher density // opaque
// non stick
(b) Based on Diagram 2,
(i) State the atmospheric
pressure in the unit of cm Hg.
………………………………………………
Calculate the atmospheric
pressure in the unit of Pascal.
[Density of mercury = 13.6 x 103
kg m-3]
76 cm Hg
P = ƿgh
= 13600 x 10 x 0.76
= 1.034 x 105 Pa
Diagram 3.2 shows the electromagnetic
spectrum.
(a) State the electromagnetic wave R.
..........................................................................
[1 mark]
Give one reason why microwave is used in
satelite communication.
..........................................................................
[1 mark]
Gamma ray
Higer frequency / higher energy, shorter λ
A radio station emits radio wave at a
frequency of 100 MHz.
(i) State the frequency in the unit of Hz.
(ii) Calculate the wave length of the radio
wave.[speed of radio wave is 3 x 108 m s-1]
[2 marks]
100 x 106 = 1 x 108
v = fλ
λ = 3 x 108 / 1 x 108
= 3 m
• Diagram 4 shows ice cubes are being heated
by 600 W immersion heater for 60 seconds.
The melting ice cubes are collected in a
beaker. The specific latent heat of fusion is
3.3 x 105 Jkg-1
(a)What is the meaning of specific latent
heat of fusion?
The amount of heat required to melt 1 kg of
solid without any change of temperature
(b) Explain why the temperature does not
change when the ice cubes changes to
liquid.
1st : Energy is used to overcome the binding
force between molecules
2nd : The kinetic energy does not change
Calculate
(i) The energy absorbed by the ice cubes.
[1 m]E = Pt = 600 x 60
= 36000 J
(ii) The mass of ice cubes which have melted.
[2 marks]
Pt = mL
m = 36000/3.3 x 105 = 1.09 x 10-1 kg
Diagram 5.1 and Diagram 5.2 show the ray
diagram of a man standing at two different
distances in front of a concave mirror.
5
What is the
characteristic of the
image formed in
Diagram 5.1? Tick
(√) the correct
answer in the box
provided
Real image
(b) Observed Diagram 5.1 and Diagram 5.2.
(i) Compare the object distance
(ii) Compare the image distance
(iii)Compare the size of the image
Object distance in Diagram 5.1 is longer
Image distance in Diagram 5.1 is shorter
Size of image in Diagram 5.1 is smaller
(c) Based on the answer in 5(b),
(i) State the relationship between object
distance and the image distance.
(ii) State the relationship between object
distance and the size of the image.
Object distance larger, image distance
shorter / inversely proportional
Object distance longer, size of the image smaller
/ inversely proportional
(d) Diagram 5.3 shows a parabolic dish that is
used to receive signals from a television
station.
(i) Where should the
receiver be placed to
obtain the strongest
signal?
(i) Give one reason for your
answer in 5(d)(i).
At the focal point / F
The object is at infinity / very far away @ parallel
signal is reflected / converge at focal point
Diagram 6.1 shows the wave pattern when
water wave moves from region A to region B
in a ripple tank.
6
Diagram 6.2 shows the cross-section of a ripple
tank. The wavelength of the water changes as
it moves from region A to region B.
(a) What is the meaning of wavelength?
The distance between two successive points
which are inphase.
@ Distance between two consecutive crests
or trough
Based on Diagram 6.1 and Diagram 6.2,
(i) Compare the wavelength between region A
and region B.
(ii) compare the incident angle, θ1 and refracted
angle, θ2.
(i) compare the depth of water between region
A and region B.
Wavelength in region A is longer
Incident angle is larger than refracted angle
depth of water in region
A is deeper
(c) Based on answers in 6(b),
(i) state the relationship between the depth of
water and the wavelength.
(i) Complete the sentence below.
As the depth increases, the wavelength
increases
When water wave travels from a deep to
a shallow region, the direction of
propagation is refracted towards the
normal.
(d) Explain why most beach resorts are built at
the bay area compared to the headland.
1st : The energy of the wave spread at the
bay /the wave refracted towards the
normal
2nd : calmer sea / smaller amplitude
A student is running a 200 m event. Diagram 7
shows the distance-time graph to illustrate his
running.
7
(a)Tick (√) the correct answer in the box
provided.
Distance is a Scalar quantity
(i) Based on Diagram 7, calculate the speed of
the student at section AB.
7
(ii) Compare the speed of the student at
OA and AB.
(200 – 100)
24 - 14
= 10 ms-1
Speed OA < speed AB
Based on the following aspect, give
suggestions on how the running time for 200
m event can be shortened.
(i) The student’s attire:
Reason:
(ii) The student’s shoe:
Reason:
(iii) The equipment used at the starting line
Reason:
Tight
Reduce air resistance
Spike shoe /stud
Better grip
Starting block
Increase forward force /
momentum
Diagram 8.1 shows a metal coated polystyrene
ball hang between two metal plates, R and S.
The metal plates are connected to an Extra
High Tension, E.H.T. supply. A strong electric
field between metal plates R and S is produced
when the switch is on.
8
(a)What is the meaning of electric field?
(a)When the metal coated polystyrene ball
oscillates between the two plates for 3
minutes, 0.3 A of current flows in the circuit.
Calculate the total charge transferred
between the two plates.
A region where electric charges experience
forces
Q = It = 0.3 x (3 x 60) = 54 C
The frequency of oscillation of the metal coated
polystyrene ball can be increased by using one
of the method listed in Table 8.1.
Based on Table 8.1, state the suitable method to
increase the frequency of oscillation.
(i) Diameter between the two plates:
Reason:
(ii) Mass of the metal coated polystyrene ball:
Reason:
(iii) Voltage of E.H.T. supply:
Reason:
Short distance
Oscillates in short time / faster
Low mass
Increase the acceleration / speed
High voltage
Increase electric field
Based on the answers in (c)(i), (c)(ii) and
(c)(iii), choose the most suitable method to
increase the frequency of oscillation. Z
(e) The nylon thread in Diagram 8.1 is replaced
with a copper thread.
(i) What happen to the motion of the metal
coated polystyrene ball?
(i) Give a reason for your answer in (e)(i).
stationary
No charge on the metal coated
polystrene ball // charge is earthed
Diagram 9.1 and Diagram 9.2 show two toy
boats are separated at two different distances
to each other due to the difference in pressure.
In Diagram 9.1, the end of the rubber hose is
pressed to reduce the size of the hose nozzle.
(a) What is the meaning of pressure?
Force per unit area //
force/area
9
(b)(i) Using Diagram 9.1 and Diagram 9.2,
compare the speed of water spurting out from
the rubber hose and the distance of separation
between the toy boats.
• Speed of water that spurst out in Diagram
9.1 is higher
• The distance of separation between the
two toy boats is Diagram 9.1 is shorter
(b)(ii) State the relationship between the speed
of water spurting out and the distance of
separation between the toy boats to make a
deduction regarding of relationship between
the speed of water and pressure.
.
• The higher the speed of water, the
shorter the distance of separation
• The higher the speed of water, the lower
the pressure
(iii) Name the physics principles involved.
Bernoulli’s principle
(c) Diagram 9.3 shows a cross section of a
Bunsen burner. Using the physics principle,
explain how a complete combustion can be
produced by the Bunsen burner.
[4 marks]• The gas from the gas tank flow in the
bunsen burner
• At the nozzle, the velocity of gas flows is
very high
• A region of low pressure is produced at
the nozzle
• Air is sucked in
• The mixture of gas and air
producing complete combustion of gas
(d) Diagram 9.4 shows a hydrometer which is
used to measure density of a liquid.
You are required to modify the design in Diagram
9.4 so that the hydrometer is more sensitive and
can measure wider range of liquid’s density.
State and explain the modifications based on the
following aspects:
(i) Length of the stem
(ii) Material of the hydrometer
(iii) Diameter of the stem
(iv) Size of the bulb
(v) Number of lead shots
[10 marks]
• longer
• Wide / big range // sensitive // small
scale division
• Plastic // glass
• Avoid corrosion
• Small diameter // narrow
increase sensitivity / detect small change
• Big bulb
• Bouyant force / more weight of water
displaced
• More number of lead shorts
• Stable // balance
Diagram 10.1(a) and Diagram 10.2(a) show two
identical Van de Graaff generators being charged for 1
minute and 5 minutes respectively. Diagram 10.1(b)
and Diagram 10.2(b) show the deflection of the
microammeter pointer when the metal dome is
connected to the microammeter and a metal tap.
What is the physical quantity that can be measured
by a microammeter? [1 mark]
Current
10
(i) Using Diagram 10.1 and 10.2, compare the time
taken to charge the Van de Graaff generator, quantity
of charge produced on the dome and the angle of
deflection of the microammeter pointer.
The time taken to charge the Van de Graaff generator in
Diagram 10.2(b) is longer (vice versa)
√2 The quantity of charge produced on the dome in
Diagram 10.2(b) is greater (vice versa)
√3 The angle of deflection of the micrometer pointer in
Diagram 10.2(b) is greater (vice versa)
10
(ii) State the relationship between:
*The time taken to charge the Van de Graaff generator
and the quantity of charge produced on the dome.
*The quantity of charge produced on the dome and
the current produced. [2 marks]
√4 Time increase, charge increase // time α charge // Q
α t // q α t // Q = It //graph
√5 charge increase, current increase
10
(c) Diagram 10.3 shows a filament lamp. Explain why
the filament in coiled shape produces more light.
√1 Length high / long / increase
√2 high resistance / resistivity / R / ƿ
√3 (produce / release) heat /energy / power //
E = I2Rt / (V2/R)t // P = I2R / P = (V2/R)
√4 heat to light // Electric → light // Electrical →
light // heat → light
10
(d) Diagram 10.4 shows the design of a wire-wrapped variable
resistor made by a student to control the amount of current
flowing through a circuit. The resistance of the variable resistor
can be varied to a maximum of 10 Ω.
You are required to modify the design in Diagram 10.4 so that the
maximum resistance is greater than 10 Ω. State and explain the
modification based on following aspects:
(i) Cross-sectional area of wire used.
(ii) Length of wire used
(iii) Number of turns of the wire
(iv) Conductivity of the slider
(v) Type of wire used.
[10 marks]
10
Small cross sectional
area
High resistance
Longer wire To increase number of turns
wrapped / High resistance
5 Higher number of
turns of wrapped wire
6 To increase the maximum
resistance // increase resistance
High conductivity
To allow current flow from the
terminal to the coil
Brass / nichrome /
constantan
High resistance
10
Induced current
• The strength of
magnetic field of the
bar magnet is same
• The number of turns of
the coil in 10.2 is
greater
• The deflection of the
galvanometer pointer
in 10.2 is greater
• The number of turns of the
coil is directly proportional
to the size of deflection of
the galvanometer pointer
• The number of turns of the
coil is directly proportional
with the rate of change of
magnetic flux.
• The rate of change of magnetic
flux is directly proportional to
the magnitude of induced
current
• Rotate the coil
• Magnetic flux is cut by the
solenoid
• Induced current is
produced
copper Low resistance / good
conductor
Thick wire Low resistance
5 soft iron core
6 easy to magnetized and
demagnetized // reduce
hysterisis
Laminated core
Reduce eddy current
Closer
Wind secondary coil on
top of the primary coil
Reduce leakage of magnetic
flux
10
Distance/time
360 x 103 / 3600 = 100
(100 – 0)/10 = 10 ms-2
0(10) + ½ (10)(10)2 = 500 m
1. Low density of material
2. Light / smaller mass / small inertia
3. aerodynamic
4. Less air frictional force
5. superconductor
6. Zero resistance / no energy loss
7. 8 short coaches
8. Reduce the effect of inertia / can easily make a
turn at the sharp end
9. Choose L
10.Low density material, aerodynamic shape,
superconductor is used to make the magnet
and 8 short coaches of fast train.
Explain how to move with
a constant velocity:
1. Drag = engine thrust
2. Resultant force = 0
Explain how to move with
an acceleration
1. Engine thrust > Drag
2. Resultant force is not
equal zero / F = ma
Diagram 11.1 shows a man standing infront of a
curve mirror with his image shown in the mirror.
(a)(i) State a light phenomenon involved in the
formation of the image.
Reflection of light
(b) Draw a ray diagram on Diagram 7.1
to show how the image is formed.
[3 marks]
Image
1. A ray from object parallel to
its principal axis, reflects to F
2. A ray passing through C, will
reflect at the same path, C
3.Extrapolation
of both rays to
form image
(ii) Based on Diagram 11.1 explain how a
magnified image of the man is formed by the
curved mirror.
• Concave mirror is used
• u < f
• Reflection of light formed a virtual image
• v > u
• m = v/u > 1
• Height of image is bigger than height of
object
Curved mirrors are always used as security mirror
in shops to watch our for shop-lifter.
You are required to investigate the characteristics
of curved mirrors as shown in Table 11.
Explain the suitability of each characteristic of the
curved mirror to be used as an effective security
mirror. Determine the most suitable curved mirror
that can be used as a security mirror. Give reasons
for your choice.
• Convex mirror
• Larger view of vision / wide field of view
• Big diameter
• more light / brighter image formed
• High position
• Wider coverage / wide view / no obstacle
• Strong reflector
• good reflection / clear image / sharp image
• Choose S
• Because it is convex mirror, big diameter,
high position and strong reflector
Diagram 11.2 shows the formation of an
image by a convex lens. The focal length of
the lens is 6 cm and the height of the object
is 2 cm. Calculate
(i) The power of the lens.
(ii) The image distance.
(iii)The height of the image.
P = 1/f = 1/0.06 = 16.67 D
(ii) 1/f = 1/u + 1/v
1/v = 1/6 – 1/9 = 9 – 6
54
v = 18 cm
(iii) m = 18/9 = h/2 = 4

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Bright Minds Teknik Menjawab SPM Fizik 2016

  • 1. BENGKEL SCORE A+ PHYSICS PAPER 2 SPM 2016
  • 2. Diagram 1 shows a thermometer is used to measure the temperature of hot water. (i) Name one type of liquid used in the thermometer. ……………………………………… [1 mark] (ii) Give one reason for the answer in 1(a)(i). ………………………………………… [1 mark] 1 Mercury / alcohol expand uniformly / does not stick to glass / opaque / high boiling point
  • 3. (i) Complete the following sentence by ticking (√) the correct answer. The temperature of water is taken when the liquid in the thermometer …….. starts to expand. …….. stops expanding [1 mark] (ii) Name the physics principle involved in 1(b)(i). ………………………………………………. [1 mark] X Thermal equilibrium 1
  • 4. Diagram 2 shows an instrument which is used to measure atmospheric pressure. (a) Based on Diagram 2, (i) Name the instrument which is used to measure the atmospheric pressure. …………………………………………………………. (ii) State one reason why mercury is used in the instrument. …………………………………………………………… Barometer Higher density // opaque // non stick
  • 5. (b) Based on Diagram 2, (i) State the atmospheric pressure in the unit of cm Hg. ……………………………………………… Calculate the atmospheric pressure in the unit of Pascal. [Density of mercury = 13.6 x 103 kg m-3] 76 cm Hg P = ƿgh = 13600 x 10 x 0.76 = 1.034 x 105 Pa
  • 6. Diagram 3.2 shows the electromagnetic spectrum. (a) State the electromagnetic wave R. .......................................................................... [1 mark] Give one reason why microwave is used in satelite communication. .......................................................................... [1 mark] Gamma ray Higer frequency / higher energy, shorter λ
  • 7. A radio station emits radio wave at a frequency of 100 MHz. (i) State the frequency in the unit of Hz. (ii) Calculate the wave length of the radio wave.[speed of radio wave is 3 x 108 m s-1] [2 marks] 100 x 106 = 1 x 108 v = fλ λ = 3 x 108 / 1 x 108 = 3 m
  • 8.
  • 9. • Diagram 4 shows ice cubes are being heated by 600 W immersion heater for 60 seconds. The melting ice cubes are collected in a beaker. The specific latent heat of fusion is 3.3 x 105 Jkg-1
  • 10. (a)What is the meaning of specific latent heat of fusion? The amount of heat required to melt 1 kg of solid without any change of temperature (b) Explain why the temperature does not change when the ice cubes changes to liquid. 1st : Energy is used to overcome the binding force between molecules 2nd : The kinetic energy does not change
  • 11. Calculate (i) The energy absorbed by the ice cubes. [1 m]E = Pt = 600 x 60 = 36000 J (ii) The mass of ice cubes which have melted. [2 marks] Pt = mL m = 36000/3.3 x 105 = 1.09 x 10-1 kg
  • 12. Diagram 5.1 and Diagram 5.2 show the ray diagram of a man standing at two different distances in front of a concave mirror. 5 What is the characteristic of the image formed in Diagram 5.1? Tick (√) the correct answer in the box provided Real image
  • 13. (b) Observed Diagram 5.1 and Diagram 5.2. (i) Compare the object distance (ii) Compare the image distance (iii)Compare the size of the image Object distance in Diagram 5.1 is longer Image distance in Diagram 5.1 is shorter Size of image in Diagram 5.1 is smaller
  • 14. (c) Based on the answer in 5(b), (i) State the relationship between object distance and the image distance. (ii) State the relationship between object distance and the size of the image. Object distance larger, image distance shorter / inversely proportional Object distance longer, size of the image smaller / inversely proportional
  • 15. (d) Diagram 5.3 shows a parabolic dish that is used to receive signals from a television station. (i) Where should the receiver be placed to obtain the strongest signal? (i) Give one reason for your answer in 5(d)(i). At the focal point / F The object is at infinity / very far away @ parallel signal is reflected / converge at focal point
  • 16. Diagram 6.1 shows the wave pattern when water wave moves from region A to region B in a ripple tank. 6 Diagram 6.2 shows the cross-section of a ripple tank. The wavelength of the water changes as it moves from region A to region B.
  • 17. (a) What is the meaning of wavelength? The distance between two successive points which are inphase. @ Distance between two consecutive crests or trough
  • 18. Based on Diagram 6.1 and Diagram 6.2, (i) Compare the wavelength between region A and region B. (ii) compare the incident angle, θ1 and refracted angle, θ2. (i) compare the depth of water between region A and region B. Wavelength in region A is longer Incident angle is larger than refracted angle depth of water in region A is deeper
  • 19. (c) Based on answers in 6(b), (i) state the relationship between the depth of water and the wavelength. (i) Complete the sentence below. As the depth increases, the wavelength increases When water wave travels from a deep to a shallow region, the direction of propagation is refracted towards the normal.
  • 20. (d) Explain why most beach resorts are built at the bay area compared to the headland. 1st : The energy of the wave spread at the bay /the wave refracted towards the normal 2nd : calmer sea / smaller amplitude
  • 21. A student is running a 200 m event. Diagram 7 shows the distance-time graph to illustrate his running. 7 (a)Tick (√) the correct answer in the box provided. Distance is a Scalar quantity
  • 22. (i) Based on Diagram 7, calculate the speed of the student at section AB. 7 (ii) Compare the speed of the student at OA and AB. (200 – 100) 24 - 14 = 10 ms-1 Speed OA < speed AB
  • 23. Based on the following aspect, give suggestions on how the running time for 200 m event can be shortened. (i) The student’s attire: Reason: (ii) The student’s shoe: Reason: (iii) The equipment used at the starting line Reason: Tight Reduce air resistance Spike shoe /stud Better grip Starting block Increase forward force / momentum
  • 24. Diagram 8.1 shows a metal coated polystyrene ball hang between two metal plates, R and S. The metal plates are connected to an Extra High Tension, E.H.T. supply. A strong electric field between metal plates R and S is produced when the switch is on. 8
  • 25. (a)What is the meaning of electric field? (a)When the metal coated polystyrene ball oscillates between the two plates for 3 minutes, 0.3 A of current flows in the circuit. Calculate the total charge transferred between the two plates. A region where electric charges experience forces Q = It = 0.3 x (3 x 60) = 54 C
  • 26. The frequency of oscillation of the metal coated polystyrene ball can be increased by using one of the method listed in Table 8.1.
  • 27. Based on Table 8.1, state the suitable method to increase the frequency of oscillation. (i) Diameter between the two plates: Reason: (ii) Mass of the metal coated polystyrene ball: Reason: (iii) Voltage of E.H.T. supply: Reason: Short distance Oscillates in short time / faster Low mass Increase the acceleration / speed High voltage Increase electric field Based on the answers in (c)(i), (c)(ii) and (c)(iii), choose the most suitable method to increase the frequency of oscillation. Z
  • 28. (e) The nylon thread in Diagram 8.1 is replaced with a copper thread. (i) What happen to the motion of the metal coated polystyrene ball? (i) Give a reason for your answer in (e)(i). stationary No charge on the metal coated polystrene ball // charge is earthed
  • 29. Diagram 9.1 and Diagram 9.2 show two toy boats are separated at two different distances to each other due to the difference in pressure. In Diagram 9.1, the end of the rubber hose is pressed to reduce the size of the hose nozzle. (a) What is the meaning of pressure? Force per unit area // force/area 9
  • 30. (b)(i) Using Diagram 9.1 and Diagram 9.2, compare the speed of water spurting out from the rubber hose and the distance of separation between the toy boats. • Speed of water that spurst out in Diagram 9.1 is higher • The distance of separation between the two toy boats is Diagram 9.1 is shorter
  • 31. (b)(ii) State the relationship between the speed of water spurting out and the distance of separation between the toy boats to make a deduction regarding of relationship between the speed of water and pressure. . • The higher the speed of water, the shorter the distance of separation • The higher the speed of water, the lower the pressure (iii) Name the physics principles involved. Bernoulli’s principle
  • 32. (c) Diagram 9.3 shows a cross section of a Bunsen burner. Using the physics principle, explain how a complete combustion can be produced by the Bunsen burner. [4 marks]• The gas from the gas tank flow in the bunsen burner • At the nozzle, the velocity of gas flows is very high • A region of low pressure is produced at the nozzle • Air is sucked in • The mixture of gas and air producing complete combustion of gas
  • 33. (d) Diagram 9.4 shows a hydrometer which is used to measure density of a liquid. You are required to modify the design in Diagram 9.4 so that the hydrometer is more sensitive and can measure wider range of liquid’s density. State and explain the modifications based on the following aspects: (i) Length of the stem (ii) Material of the hydrometer (iii) Diameter of the stem (iv) Size of the bulb (v) Number of lead shots [10 marks]
  • 34. • longer • Wide / big range // sensitive // small scale division • Plastic // glass • Avoid corrosion • Small diameter // narrow increase sensitivity / detect small change • Big bulb • Bouyant force / more weight of water displaced • More number of lead shorts • Stable // balance
  • 35. Diagram 10.1(a) and Diagram 10.2(a) show two identical Van de Graaff generators being charged for 1 minute and 5 minutes respectively. Diagram 10.1(b) and Diagram 10.2(b) show the deflection of the microammeter pointer when the metal dome is connected to the microammeter and a metal tap. What is the physical quantity that can be measured by a microammeter? [1 mark] Current 10
  • 36. (i) Using Diagram 10.1 and 10.2, compare the time taken to charge the Van de Graaff generator, quantity of charge produced on the dome and the angle of deflection of the microammeter pointer. The time taken to charge the Van de Graaff generator in Diagram 10.2(b) is longer (vice versa) √2 The quantity of charge produced on the dome in Diagram 10.2(b) is greater (vice versa) √3 The angle of deflection of the micrometer pointer in Diagram 10.2(b) is greater (vice versa) 10
  • 37. (ii) State the relationship between: *The time taken to charge the Van de Graaff generator and the quantity of charge produced on the dome. *The quantity of charge produced on the dome and the current produced. [2 marks] √4 Time increase, charge increase // time α charge // Q α t // q α t // Q = It //graph √5 charge increase, current increase 10
  • 38. (c) Diagram 10.3 shows a filament lamp. Explain why the filament in coiled shape produces more light. √1 Length high / long / increase √2 high resistance / resistivity / R / ƿ √3 (produce / release) heat /energy / power // E = I2Rt / (V2/R)t // P = I2R / P = (V2/R) √4 heat to light // Electric → light // Electrical → light // heat → light 10
  • 39. (d) Diagram 10.4 shows the design of a wire-wrapped variable resistor made by a student to control the amount of current flowing through a circuit. The resistance of the variable resistor can be varied to a maximum of 10 Ω. You are required to modify the design in Diagram 10.4 so that the maximum resistance is greater than 10 Ω. State and explain the modification based on following aspects: (i) Cross-sectional area of wire used. (ii) Length of wire used (iii) Number of turns of the wire (iv) Conductivity of the slider (v) Type of wire used. [10 marks] 10
  • 40. Small cross sectional area High resistance Longer wire To increase number of turns wrapped / High resistance 5 Higher number of turns of wrapped wire 6 To increase the maximum resistance // increase resistance High conductivity To allow current flow from the terminal to the coil Brass / nichrome / constantan High resistance 10
  • 42. • The strength of magnetic field of the bar magnet is same • The number of turns of the coil in 10.2 is greater • The deflection of the galvanometer pointer in 10.2 is greater
  • 43. • The number of turns of the coil is directly proportional to the size of deflection of the galvanometer pointer • The number of turns of the coil is directly proportional with the rate of change of magnetic flux. • The rate of change of magnetic flux is directly proportional to the magnitude of induced current
  • 44. • Rotate the coil • Magnetic flux is cut by the solenoid • Induced current is produced
  • 45.
  • 46. copper Low resistance / good conductor Thick wire Low resistance 5 soft iron core 6 easy to magnetized and demagnetized // reduce hysterisis Laminated core Reduce eddy current Closer Wind secondary coil on top of the primary coil Reduce leakage of magnetic flux 10
  • 47.
  • 48. Distance/time 360 x 103 / 3600 = 100 (100 – 0)/10 = 10 ms-2 0(10) + ½ (10)(10)2 = 500 m
  • 49.
  • 50.
  • 51. 1. Low density of material 2. Light / smaller mass / small inertia 3. aerodynamic 4. Less air frictional force 5. superconductor 6. Zero resistance / no energy loss 7. 8 short coaches 8. Reduce the effect of inertia / can easily make a turn at the sharp end 9. Choose L 10.Low density material, aerodynamic shape, superconductor is used to make the magnet and 8 short coaches of fast train.
  • 52. Explain how to move with a constant velocity: 1. Drag = engine thrust 2. Resultant force = 0 Explain how to move with an acceleration 1. Engine thrust > Drag 2. Resultant force is not equal zero / F = ma
  • 53. Diagram 11.1 shows a man standing infront of a curve mirror with his image shown in the mirror. (a)(i) State a light phenomenon involved in the formation of the image. Reflection of light
  • 54. (b) Draw a ray diagram on Diagram 7.1 to show how the image is formed. [3 marks] Image 1. A ray from object parallel to its principal axis, reflects to F 2. A ray passing through C, will reflect at the same path, C 3.Extrapolation of both rays to form image
  • 55. (ii) Based on Diagram 11.1 explain how a magnified image of the man is formed by the curved mirror. • Concave mirror is used • u < f • Reflection of light formed a virtual image • v > u • m = v/u > 1 • Height of image is bigger than height of object
  • 56. Curved mirrors are always used as security mirror in shops to watch our for shop-lifter. You are required to investigate the characteristics of curved mirrors as shown in Table 11. Explain the suitability of each characteristic of the curved mirror to be used as an effective security mirror. Determine the most suitable curved mirror that can be used as a security mirror. Give reasons for your choice.
  • 57.
  • 58. • Convex mirror • Larger view of vision / wide field of view • Big diameter • more light / brighter image formed • High position • Wider coverage / wide view / no obstacle • Strong reflector • good reflection / clear image / sharp image • Choose S • Because it is convex mirror, big diameter, high position and strong reflector
  • 59. Diagram 11.2 shows the formation of an image by a convex lens. The focal length of the lens is 6 cm and the height of the object is 2 cm. Calculate (i) The power of the lens. (ii) The image distance. (iii)The height of the image. P = 1/f = 1/0.06 = 16.67 D (ii) 1/f = 1/u + 1/v 1/v = 1/6 – 1/9 = 9 – 6 54 v = 18 cm (iii) m = 18/9 = h/2 = 4