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Sal College of Engineering
In geometry, we have learnt formulae to calculate 
areas of various geometrical figures including 
triangles, rectangles, trapezias and circle. Such 
formulae are fundamental in the application of 
mathematics to many real life problems. The 
formulae of elementary geometry allow us to 
calculate areas of many simple figures, However, 
they are inadequate for calculating the areas 
enclosed by curves. For that we shall need some 
concept of Integral Calculus. 
In the previous chapter, we have studied to 
find the area bounded by the curve y = f(x), the 
ordinates x = a, x=b and x-axis, while calculating 
definite integral as the limit of a sum. Here, in 
this chapter, we shall study a specific application 
of integrals to find the area under simple curves, 
area between lines and arcs of circles , parabolas 
and ellipses(standard forms only).We shall also 
deal with finding the area bounded by the above 
said curves. 
A.L. Cauchy 
(1789-1857) 
INTRODUCTION
 Integration is the inverse process of differentiation. In the differential 
calculus, we are given a function and we have to find the derivative or 
differential of this function, but in the integral calculus, we are to find a 
function whose differential is given. Thus, integration is a process which is 
the inverse of differentiation. 
Let d/ dx F(x)= f(x) . ∫f(x) dx=F (x) + C. These integrals are called 
indefinite integrals or general integrals, C is called constant of 
integration. All these integrals differ by a constant. 
 From the geometric point of view, an indefinite integral is collection of 
family of curves, each of which is obtained by translating one of the curves 
parallel to itself upwards or downwards along along the y-axis. 
 Some properties of indefinite integrals are as follows: 
1. ∫[ f(x) + g (x)] dx =∫ f (x) dx + ∫ g (x) dx 
2. For any real number k, ∫k f(x)dx = k ∫ f (x) dx 
More generally, if f1,f2,f3, ….. , fn are function and k1,k2,…. , kn are real 
numbers. Then 
∫[k1 f1(x)+ k2f2(x)+..+kn fn(x)]dx = k1∫f1(x)dx+k2∫f2(x)dx+…+kn∫ fn(x) dx
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Akshay

  • 1. Sal College of Engineering
  • 2.
  • 3. In geometry, we have learnt formulae to calculate areas of various geometrical figures including triangles, rectangles, trapezias and circle. Such formulae are fundamental in the application of mathematics to many real life problems. The formulae of elementary geometry allow us to calculate areas of many simple figures, However, they are inadequate for calculating the areas enclosed by curves. For that we shall need some concept of Integral Calculus. In the previous chapter, we have studied to find the area bounded by the curve y = f(x), the ordinates x = a, x=b and x-axis, while calculating definite integral as the limit of a sum. Here, in this chapter, we shall study a specific application of integrals to find the area under simple curves, area between lines and arcs of circles , parabolas and ellipses(standard forms only).We shall also deal with finding the area bounded by the above said curves. A.L. Cauchy (1789-1857) INTRODUCTION
  • 4.  Integration is the inverse process of differentiation. In the differential calculus, we are given a function and we have to find the derivative or differential of this function, but in the integral calculus, we are to find a function whose differential is given. Thus, integration is a process which is the inverse of differentiation. Let d/ dx F(x)= f(x) . ∫f(x) dx=F (x) + C. These integrals are called indefinite integrals or general integrals, C is called constant of integration. All these integrals differ by a constant.  From the geometric point of view, an indefinite integral is collection of family of curves, each of which is obtained by translating one of the curves parallel to itself upwards or downwards along along the y-axis.  Some properties of indefinite integrals are as follows: 1. ∫[ f(x) + g (x)] dx =∫ f (x) dx + ∫ g (x) dx 2. For any real number k, ∫k f(x)dx = k ∫ f (x) dx More generally, if f1,f2,f3, ….. , fn are function and k1,k2,…. , kn are real numbers. Then ∫[k1 f1(x)+ k2f2(x)+..+kn fn(x)]dx = k1∫f1(x)dx+k2∫f2(x)dx+…+kn∫ fn(x) dx