Question paper and its solution of supplementary on line test on synthesis
1. SEM-IV Paper-C10T Organic Chemistry 17th
May-2020
TAMRALIPTA MAHAVIDYALAYA
Semester IV Chemistry (H): Jan.,â20âJune,â20
Supplementary online Test on Organic Chemistry: 17-05-2020
Topic: Synthesis :: Paper: C10T :: Full Marks: 30 :: Time: 2 hr.
Name of Teacher: Dr. Satyajit Dey
Name of Examinee: College Roll No. Whatsapp No.
University Roll No. Regn. No. of
Please copy the RED COLOURED portion of this question paper with complete filling up of the
blanks. Always use a BLACK INK PEN and do not jumble the answer sequence.
Answer all questions.
1. Define the terms âLogical synthonâ and âillogical synthonâ with suitable example. Write their
corresponding synthetic equivalents. 3
2. Propose all possible disconnection/retro-synthesis for the following 1,4-dicarbonyl molecule.
Consider the pattern of functional groups when determining the best site for a disconnection.
Write forward syntheses also. 8
3. Synthetic target of the following compound by the adapted method fails to give the desired
product. What is the actual product? Why is that product formed? Suggest a suitable synthetic
route that will give the desired product as shown below. 4
4. Propose a possible retro-synthesis for the following target molecules. Show forward synthesis
also (any three). 6
5. Show two retrosynthetic pathways differing in the position of disconnection for the following
compound. Which pathway will lead to efficient synthesis and why? 3
6. Provide missing structure of products for each of the steps of the following multistep synthesis.
Give mechanism for conversion of A into B. 6
2. ___________________________________________________________________________
SEM-IV Paper-C10T Organic Chemistry 17th
May-2020
TAMRALIPTA MAHAVIDYALAYA
Semester IV Chemistry (H): Jan.,â20âJune,â20
Supplementary online Test on Organic Chemistry: 17-05-2020
Topic: Synthesis :: Paper: C10T :: Full Marks: 30 :: Time: 2 hr.
Name of Teacher: Dr. Satyajit Dey
Solution to Supplementary online Test on Organic Chemistry
1. Define the terms âLogical synthonâ and âillogical synthonâ with suitable example. Write their
corresponding synthetic equivalents. 3
Answer:
Definition of logical synthon and illogical synthon:
If, disconnection of a bond in a target molecule leads to a synthon which has natural polarity that can be
demonstrated from the latent polarity of the molecule, such synthons are called logical synthons or
natural synthons. Disconnection of a bond in a target molecule sometimes leads to a synthon which has
polarity that is reversed to its normal latent polarity. Such synthons are called illogical synthons or
unnatural synthons.
According to the concept of latent polarity, the polarity of the carbon atom next to the hydroxyl group
bearing carbon should be negative. But, disconnection of Îł-hydroxy carbonyl compound leads to a
synthon which has positive polarity on that carbon. Therefore, this synthon is illogical synthon.
However, the α-carbon with respect to carbonyl group should be negative, and the disconnection leads
to a carbonyl synthon that acquires the same polarity as exhibited by latent polarity. Therefore, this
synthon is logical synthon.
2. Propose all possible disconnection/retro-synthesis for the following 1,4-dicarbonyl molecule.
Consider the pattern of functional groups when determining the best site for a disconnection.
Write forward syntheses also. 8
3. ___________________________________________________________________________
SEM-IV Paper-C10T Organic Chemistry 17th
May-2020
Answer:
Write forward synthesis accordingly.
3. Synthetic target of the following compound by the adapted method fails to give the desired
product. What is the actual product? Why is that product formed? Suggest a suitable synthetic
route that will give the desired product as shown below. 4
Answer:
Synthetic target by the given method fails to give the desired product. This is because the α-protons of
α-bromo ethyl acetate is more acidic than the α-protons of acetone due to resonance stabilization by
ester carbonyl as well as electron withdrawing inductive effect of bromine atom. Consequently, the
carbanion derived from acetone undergoes proton exchange with α-bromo ethyl acetate faster than α-
alkylation reaction which could provide the desired product. The new carbanion resulting from α-bromo
ethyl acetate reacts with acetone to undergo Darzenâs reaction as depicted below.
4. ___________________________________________________________________________
SEM-IV Paper-C10T Organic Chemistry 17th
May-2020
To get the desired product, either pre-formed enolate can be used or activating group at ïĄ-position of
acetone can be introduced to increase its acidity compared to bromo ethyl acetate.
Using pre-formed enolate:
Introducing Activation group:
4. Propose a possible retro-synthesis for the following target molecules. Show forward synthesis
also (any three). 6
i) Retro-synthesis:
Synthesis:
6. ___________________________________________________________________________
SEM-IV Paper-C10T Organic Chemistry 17th
May-2020
iv) Retro-synthesis:
Synthesis:
5. Show two retrosynthetic pathways differing in the position of disconnection for the following
compound. Which pathway will lead to efficient synthesis and why? 3
Answer:
Proposed Retro-synthetic Paths:
The path âaâ would lead to the efficient synthesis because: i) path âaâ involves only a single substrate,
ethyl phenylacetate, which is inexpensive and readily available; ii) path âaâ demonstrates to a single step
synthesis; iii) dibenzyl ketone, one of the starting materials of retro-synthetic path âbâ would probably
have to be synthesized in a three-step synthesis involving Grignard reaction. So, path âaâ would lead to
a single step synthesis, whereas path âbâ would lead to a three-step synthesis.