A sample survey by the Pew internet and American Life Project asked .pdf

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A sample survey by the Pew internet and American Life Project asked a random sample of adults whether they had a brodband internet connection at home, with the following results by type of community: Have broadband No broadband Urban 320 276 Suburban 521 542 Rural 254 327 Test the hypotesis that there is a relationship between community type (urban, suburban, or rural) and whether the residents have broadband. Solution Set up null and alternate as H0: There is no relation between community type and having broadband Ha: There is relation between them Two tailed chi square test Prepare contingency table chi-square = 11.7 degrees of freedom = 2 probability = 0.003 As p <0.01, reject null hypothesis. There is relation between the two..

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Which of the following is not a property of a normal curve A. Bell .pdf

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What tissue type has polarity and is avascular What tissue type has polarity and is avascular Solution The epithelial tissue do not receive vascular supply, so they are avascular. It is polar because it contains apical, lateral and basal membrane domains. The epithelial tissues form the sheet like outer covering of the body surfaces and provide protection to the organs. One surface of this epithelial tissue is not bound to anything and produces glandular secretions, also involved in absorption process. The characteristics of the epithelial tissues include the following: 1). Cells undergo frequent cell division 2). Lack of blood vessels 3). Cells are tightly packed by cell junctions..

What tissue type has polarity and is avascular What tissue.pdf

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What organizations are involved in Internet2? How is this development similar to the beginnings of our present Internet? Does your school or employer participate in Internet2? Solution Answer: Internet2 developing network capabilities . The organizations in involved in the internet2 are mostly the US institutions of higher education , government agencies , and corporations. Internet brought the world into new stage. Even we are seeing change in almost everything. Bussinesses are changing to E-business , banking to e-banking all because of the internet. Internet2 brought the higher capabilities of networking systems. Like before , we were using Class A IP addresses . But now a days we are using the class C IP addresses due to increse of the users. Yes first when the internet 2 introduced, the US institutions of higher education participated with full bhoom..

What organizations are involved in Internet2How is this developme.pdf

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What is meant by modular software and why is it important? How can the modularity of a program code be quantifiably measured? Solution 1) What is ment by modular software and why is it important? Answer:- How important is modularization of software projects: Modularization is obviously important in software projects, but I want to know people\'s opinions on how important and for what reasons it is important. I\'ve obviously got my own ideas since I\'m asking this, but think of it like a \"common brainstorm\" of the reasons one should modularize one\'s software projects.. Techopedia explains Modular Programming: 1) Modules in modular programming enforce logical boundaries between components and improve maintainability. They are incorporated through interfaces. They are designed in such a way as to minimize dependencies between different modules. Teams can develop modules separately and do not require knowledge of all modules in the system. 2) Each and every modular application has a version number associated with it. This provides developers flexibility in module maintenance. If any changes have to be applied to a module, only the affected subroutines have to be changed. This makes the program easier to read and understand. 3) Modular programming has a main module and many auxiliary modules. The main module is compiled as an executable (EXE), which calls the auxiliary module functions. 2) How can the modularity of a program code be quantifiably measured? Answer:- A Software Metric is a standard of measure of a degree to which a software system or process possesses some property. Even if a metric is not a measurement (metrics are functions, while measurements are the numbers obtained by the application of metrics), often the two terms are used as synonymous. A Software development goal is obtaining objective, reproducible and quantifiable measurements, which may have numerous valuable applications in schedule and budget planning, cost estimation, quality assurance testing, software debugging, software performance optimization, and optimal personnel task assignments..

What is meant by modular software and why is it important How can t.pdf

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What are the two major steps in biological classification? What did Linnaeus contribute to taxonomy? are scientific names derived? want to identify the various Solution Answers: 1. Two major steps in biological classification are: a) Defining and describing organisms b) Arranging organisms into a logical classification scheme 2. The binomial nomenclature system was introduced by Carolus Linnaeus. It is used to assign each organism a two part scientific name - genus and species. 3. Scientific names are derived following the universal rules of nomenclature: a) These are in Latin and written in italics. b) The first word represents the genus while the second word is the species epithet c) The first word (genus) is written in capital letter while second word (species) is written in small letter. d) If hand written, they are separately underlined, or printed in italics to denote their Latin origin..

What are the two major steps in biological classification What .pdf

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Tissue transplant rejection is primarily a type I reaction. type II reaction. type III reaction. type IV reaction. type V reaction. Solution Organ transplantation is the replacement of a host\'s dysfunctional tissue with a healthy tissue from another organism (host). Since the transplanted organ is from another (foreign) organism, the host\'s immune system reacts to the foreign antigens. This immunological response is a hypersensitivity response called Transplant Rejection. During a Tissue Transplant, the transplant rejection is a T-Cell mediated response against foreign Major Histocompatibility Complex in the donated organ. The Major Histocompatibility Complex are a group of genes that code for proteins found on the surfaces of the donated tissue that helps the immune system to recognize the foreign substances. It usualy takes around weeks to months. Therefore, a tissue transplant rejection is a Type IV hypersensitivity reaction..

Tissue transplant rejection is primarily atype I reaction.type I.pdf

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The members of the UN peace committee, must choose, from among themselves, a presiding officer of their committee. For each member x, let f(x) designate that member\'s choice for officer. If no two members vote alike, what is the range of f? Solution Since each member can vote only for one person and no two members vote alike the mapping f: x to f(x) is one to one and onto. Hence f is a bijective function So order of x = order of f(x) Or Range of f = No of members of the UN Peace committee.

The members of the UN peace committee, must choose, from among thems.pdf

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NetWork Design Question 1a.) In writing a letter to a Friend, what do you hace to do to get the letter to your friend. List all the steps and ways. 1b.) Relate the stages of letter transaction to the layers of the internet. Solution In writing a letter to a Friend, the following 5 steps do you face to get the letter to your friend. 1) Application layer: TCP/IP: A user retrieves a Web page from a server in somewhere by typing a URL into a browser and clicking the enter key. The server receives the request, finds the page on its hard drive and sends it back to the user. Neither the user nor the client or server software is aware of the way the messages were delivered. There are many application layer protocols. 2) Transport layer: TCP/IP: Transport layer software establishes a connection between a client and server then monitors that connection for errors. It also slows transmission if it gets too fast to handle at the other end. Transport layer software is not concerned with how the data is actually moved from one point to the other that is the responsibility of lower level software. There are two transport layer protocols TCP (reliable) and UDP (unreliable, but fast). If TCP tries repeatedly and errors persist, it informs its \"boss,\" the application program. 3) Internet layer: TCP/IP:Internet layer programs move data between networks. IP is the internet layer protocol. IP software ignores the data, and it does the same thing with a packet whether it comes from the friend or your mother. Once the data gets to its destination local area network (LAN), it is handed over to data link layer software or firmware for delivery to the proper computer. 4) Data link layer: TCP/IP:Data Link layer programs move (incoming and outgoing) data within LANs. Ethernet is the most common data link protocol. A data link program is not concerned with how outgoing data will be handled once it leaves the LAN or how incoming data got there. That is the responsibility of the internet layer software. 5) Physical layer: TCP/IP:Physical layer protocols specify the means of representing ones and zeros (bits). The method of transmitting them between two points using wire, radio, fiber, etc. is also specified. There are many ways to make ones and zeros and many ways to transmit them so there are many physical layer protocols..

NetWork Design Question1a.) In writing a letter to a Friend, what .pdf

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Please help me with thisLet x denote a single observation of a no.pdf

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Numerical Methods yi + 1 = y_i + Phi (x_i, y_i, h) Consider the equation given above. The function phi (x, y, h) is an incremental function. It can be interpreted as the average of the slope at the initial and end points. a function of the initial x value only. an incremental function. It can be interpreted as the slope at the mid-point. an incremental function. It can be interpreted as a representative slope over the interval. Solution Option D.

Numerical Methods yi + 1 = y_i + Phi (x_i, y_i, h) Consider the equ.pdf

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My question is pretty simple, I just want to know how to call my operator== function in Stack.cpp using a list function. Here is what I meant. This is my Stack.h file: class Stack { public: /**constructors and destructors*/ Stack(); Stack(const Stack &S); ~Stack(); void pop(); void push(int data); bool operator==(const Stack &S); [ .......] private: List stack; }; Here is my List.h file: template class List { private: struct Node { listitem data; Node* next; Node* previous; Node(listitem data) : next(NULL), previous(NULL), data(data) { } }; typedef struct Node* NodePtr; NodePtr start; NodePtr end; NodePtr cursor; int length; public: ........ bool operator==(const List &list); [.......] } [........] template bool List::operator==(const List& list) { if (length != list.length) return false; NodePtr temp1 = start; NodePtr temp2 = list.start; while (temp1 != NULL) { if (temp1->data != temp2->data) return false; temp1 = temp1->next; temp2 = temp2->next; } return true; } [......] So I already define my functions in List.h and I only need to call my function from List again in my Stack.cpp file. For example from my Stack.cpp: Stack::Stack(const Stack &S) : stack(S.stack) { } void Stack::pop() { stack.remove_start(); } [......] And I don\'t know how to call my operator== function in Stack.cpp from the List.h like the way above. This is what my guess so far but did not work: bool Stack::operator==(const Stack &S) { stack.operator==(S.stack); } Thank you Solution When we wish to make a comparison, such as in an if statement, we use the double equals sign (==). 1)bool operator==(const Stack &S); [ .......] It means whatever the boolean operator it should be belongs to stack or equal to. 2) bool operator==(const List &list); Likewise link list also compare with the constructor link list. and constructor need not to call explicitly. it will call itself when program called first..

My question is pretty simple, I just want to know how to call my ope.pdf

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Java Assignment Convert infix to postfix. Solution To convert infix expressions to postfix, we can use the stack data structure. The stack is used to store the operators and parenthesis to apply the precedence. For example if the input is a%b is ab% class Stack { char c[]=new char[100]; int top=-1; void push(char a) { try { c[++top]=a; } catch(StringIndexOutOfBoundsException e) { System.out.println(\"Stack full\"); System.exit(0); } } char pop() {return c[top--]; } boolean isEmpty() { return (top==-1)?true:false; } char peak() { return c[top]; } } public class InfixToPostfix { static Stack expression= new Stack; public static void main(String argv[]) throws IOException { String infix; BufferedReader keyboard= new BufferedReader(new InputStreamReader(System.in)); System.out.print(\"enter the expression in infix notation\"); infix=keyboard.readLine(); System.out.println(\"The resultant postfix expression is \"+ toPostfix(infix)); } private static String toPostfix(String infix) { char sym; string postfix=\"\"; for(int i=0;i.

Java AssignmentConvert infix to postfix.SolutionTo convert i.pdf

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Irreducible polynomials over a field F play a similar, in a certain sense, role in F[x] to the role the prime numbers play for Z. Using your favorite proof of the existence of an infinite number of primes as inspiration, please prove that there are infinitely many irreducible polynomials over a field F. Solution if there were finite such polynomials.... p1.p2.p3.........pn then p1 * p2 * p3 * ......pn +1 (multiplicative unity) is a polynomial which is either irreducible or can be written as a product of irreducible polynomials. It cannot be irreducible since it is different from the set of irreducibles. Also it cannot be divisible by any irreducible . Say it does pi divides this new polynomial fr some i , then pi divides p1*p2*......pn + 1 and also pi is one of p1,p2....pn so divides p1*p2*....pn hence it divides 1 contradiction.

Irreducible polynomials over a field F play a similar, in a certain .pdf

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Inferential statistics is more than descriptive statistics. direct .pdf

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If an organism produces two different alleles for a gene, that organism is ___________ with respect to that gene. Question 13 options: dioecious homozygous haploid heterozygous diallelic dioecious homozygous haploid heterozygous diallelic Solution Dioecious - dioecious species has the different male and female reproductive structures. Homozygous - Homozygous species are those ones having identical pair of genes for a given pair. Haploid - haploid cell contain only one complete set of chromosomes. Heterozygous - They carry dissimilar alleles, different genotype and having both dominant and recessive alleles. Diallellic- It is applied to those where two different alleles are present at particular gene. Hence most perfect answer for above question is DIALLELLIC..

If an organism produces two different alleles for a gene, that organ.pdf

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I apologize: this 1 question has numerous parts. I didn\'t want to split it up in to separate questions and confuse others. Selected year-end financial statements of Cabot Corporation follow. (All sales were on credit; selected balanoe sheet amounts at December 31, 2014, were inventory, S53,900; total assets, $199,400; common stock, 588,000; and retained earnings, 344,392.) CABOT CORPORATION Income Statement For Year Ended December 31, 2015 Sales Cost of goods sold S453,600 298,850 Gross profit Operating expenses Interest expense 158,750 98,800 4,600 Income before taxes Income taxes 53,350 21,492 Net income S 31,858 CABOT CORPORATION Balance Sheet December 31, 2015 Assets Cash Short-term investments Accounts receivable, net Notes receivable (trade) S 18,000 9,200 32,200 000 38,150 2,800 151,300 Liabilities and Equity Accounts payable Accrued Income taxes payable Long- term note payable, secured S 17,500 4,800 4,700 wages payable 5, Prepaid expenses Plant assets, net by mortgage on plant assets Common stod Retained earnings 83,400 88,000 76,250 Total assets S254,650 Total liabilities and equity S254,650 These are short-term notes receivable arising from customer (trade) sales. Required: Compute the following: (1) current ratio, (2) acid- test ratio, (3) days sales uncollected, (4) inventory turnover, (5) days\' sales in inventory, (8) debt-to-equity ratio, (7) times interest earned, (8) profit margin ratio, (9) total asset turnover, (10) return on total assets, and (11) return on common stockholders\' equity Do not round intermediate calculations.) Choose Numerator: | Choose Denominator: | = Current Ratio Current ratio 2015 to 1 Solution Answer to Part 1. Current Ratio = Current Assets / Current Liabilities Current Assets = Cash + Short Term Investments + Accounts Receivable, net + Notes Receivable (Trade) + Merchandise Inventory + Prepaid Expenses Current Assets = $16,000 + $9,200 + $32,200 + $5,000 + $38,150 + $2,800 Current Assets = $103,350 Current Liabilities = Accounts Payable + Accrued Wages Payable + Income Taxes Payable Current Liabilities = $17,500 + $4,800 + $4,700 Current Liabilities = $27,000 Current Ratio = 103,350 / 27,000 Current Ratio = 3.83 to 1 Answer to Part 2. Acid-Test Ratio = Quick Assets / Current Liabilities Quick Assets = Current Assets – Merchandise Inventory – Prepaid Expenses Quick Assets = $103,350 - $38,150 - $2,800 Quick Assets = $62,400 Acid-Test Ratio = 62,400 /27,000 Acid-Test Ratio = 2.31 to 1 Answer to Part 3. Days Collected Sales = Current Receivable / Net Sales * 365 Current Receivable = $32,200 + $5,000 = $37,200 Days Collected Sales = 37,200 / 453,600 * 100 Days Collected Sales = 29.93 days Answer to Part 4. Inventory Turnover Ratio = Cost of goods sold / Average Inventory Average Inventory = (38,150 + 53,900) / 2 Average Inventory = $46,025 Inventory Turnover Ratio = 296,850 / 46,025 Inventory Turnover Ratio = 6.45 times Answer to Part 5. Days’ Sales in Inventory = Average Inventory / Cost of Goods Sol.

I apologize this 1 question has numerous parts. I didnt want to s.pdf

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8. On January 1, Wismer Corporation declared a $1.50 per share cash dividend on its common stock (18,000 shares) for stockholders on record as of January 15. Wismer paid the dividend on January 31. Journalize the entries declaring the cash dividend and paying the dividend. (Record debits first, then credits. Select the explanation on the last line of the journal entry table.) Journalize the entry declaring the cash dividend. Date Accounts and Explanation Debit Credit Jan. 1 Journalize the entry paying the dividend. Date Accounts and Explanation Debit Credit Jan. 31 Solution 1-Jan Cash dividends 27000 =18000*1.5 Dividends payable 27000 31-Jan Dividends payable 27000 Cash 27000 2 Interest expense for 2019 = 59000*7%/12*5= 1721.

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Graph one cycle of the following function. y = 5 sin(-2pi x + pi) St.pdf

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explain why these three properties of water are important? melting and freezing cohesive and adhesive An excellent solvent Solution Water melting and freezing properties are important because these properties are main colligative properties useful to prepare polar biological & pharmaceutical products suitable to the internal human body environment The cohesive forces (cohesion) & adhesive forces of water molecules enable to acquire elastic tendency with considerable surface area promote solubility. This tendency is referred as surface tension. Surface tension of any fluid decreases with increasing temperature. This is due to existence of cohesive intermolecular forces between molecules of the fluid is reduced and it is based on the surrounding environment with adhesive intermolecular forces & viscosity of the fluid, molecular thermal activity at the liquid interface For example, water is a universal solvent and it has both polar because it has both positive charge (H+ or H3O+) and negative charge (OH-). This polarity enables water to make substances to dissolve in it as charged species. On the other hand, water molecules possess a higher attractive power to each other so that these forces are referred as cohesive forces responsible for “surface tension” phenomenon” and these attractions are predominantly due to hydrogen bonding. For instance, 2 to 3 drops of water between the cover slip is imparted adhesive forces (another example is capillary rise due to forces between glass and water in capillary tube) between the two glass cover slips result in adhesion instead of cohesion that potentially differentiate intermolecular forces between two different substances namely water and silicon. These intermolecular forces render glass surface as hydrophilic. These intermolecular forces are decreased as the temperature increases due to increase in molecular thermal activity of the fluid molecules ate the interface of water molecules. An excellent solvent Water is a universal polar solvent and it has hydrogen bonding associated with highest heat capacity and is referred as “specific heat capacity”. This specific heat is predominantly due to intermolecular and intermolecular hydrogen bonding. In nature on land when heat is absorbed result in breaking of hydrogen bonds specifically followed by production of heat. Normally ocean water cool little bit slower when compared to the land water because of more heat capacity. This sterile solvent has ability to dissolve a majority of biological products to prepare pharmaceutical products finally used as diluents in saline, injectables etc. Water properties and the biological importance of water: 1). Due of the presence of hydrogen bonds and strong intermolecular forces, water has high specific heat index. Specific heat capacity of water is defined as; the amount of heat (energy in joules) required for raise of temperature of water per unit mass by 10C. Our body temperature is maintained higher than the surroundin.

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Drosophila melanogaster has one pair of sex chromosomes (XX or XY) and three pairs of autosomes, referred to as chromosomes II, III, and IV. A genetics student discovered a male fly with very short (sh) legs. Using this male, the student was able to establish a pure breeding stock of this mutant and found that it was recessive. She then incorporated the mutant into a stock containing the recessive gene black (b, body color located on chromosome II) and the recessive gene pink (p, eye color located on chromosome III). A female from the homozygous black, pink, short stock was then mated to a wild-type male. The F1 males of this cross were all wild type and were then backcrossed to the homozygous b, p, sh females. The F2 results appeared as shown in the following table. No other phenotypes were observed. Based on these results, the student was able to assign short to a linkage group (a chromosome). Which one was it? a. X chromosome b. chromosome II c. chromosome III d. chromosome IV Solution Image is not loading... upload the image in dropbox or google drive and paste the link in comment. I will answer the question.Categoryfemalesmaleswild6359122pink5865123black short5551106black pink short6960129.

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