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BASICS OF HYDRAULICSBASICS OF HYDRAULICS
BASICS OF HYDRAULICS
1) DEFINITIONS
1.1) HYDRAULICS
1.2) CLASSIFICATION
1.2.1) HYDROSTATICS
1.2.2) HYDRODYNAMICS
1.3) FORCE , PRESSURE , AREA
1.4) PASCAL’S LAW
2) MULTIPLICATION OF FORCES
2.1) BRAMAH’S PRESS
2.2) LAW OF CONSERVATION OF ENERGY
3) HYDRAULIC POWER TRANSMISSION
3.1) LINEAR ACTUATOR
3.2) ROTARY ACTUATOR
BASIC
DEFINITIONS
&
FORMULAE
USES OF
HYDRAULIC
S
BASICS OF HYDRAULICS
4) ADVANTAGES OF HYDRAULICS
4.1) SPEED CONTROL
4.2) DIRECTION CONTROL
4.3) FORCE CONTROL
4.4) OVERLOAD PROTECTION
4.5) COMPACTNESS
5) HOW PRESSURE IS CREATED
ADVANTAGES
OF
HYDRAULICS
PRACTICAL
DETAILS IN
HYDRAULIC
S
 HYDRAULICS
HYDRO AULUS
( meaning Water ) ( meaning Pipe )
HYDRAULICS :
Work done by fluids in pipes.
H Y D R O S T A T I C S H Y D R O D Y N A M I C S
H y d r a u lic s is C la s s ife d a s
HYDROSTATICS
FORCE
F1
AREA
A1
ARE
A
A2
Eg.:-
F1 = 1 Kg
A1 = 1 Cm2
P = F1 = 1 Kg
A1 1 Cm2
= 1 Kg / Cm2
( Same Pressure P
)
A2 = 10 Cm2
F2 = P x A2
= 1 x 10
= 10 Kg
HYDROSTATICS
FORCE
F2
TURBINE
NOZZLE
LIQUID AT
HIGH
VELOCITY
HYDRODYNAMICS
• IN ORDER TO DETERMINE THE TOTAL FORCE EXERTED
ON A SURFACE WE NEED TO KNOW THE PRESSURE OR
FORCE PER UNIT AREA.
• PRESSURE = FORCE FORCE IN → KILOGRAMS ( Kg )
AREA AREA IN → SQ. CM ( Cm2
)
PRESSURE IN → KILOGRAM / SQ.CM
(Kg / Cm2
)
P = F
A
• FORCE = PRESSURE x AREA
• THE ATMOSPHERIC AIR EXERTS UNIFORM PRESSURE
ALL ROUND. THIS PRESSURE IS APPROX. 1 Kg / Cm2
AND
IS DENOTED AS 1 BAR ( BAROMETER )
PRESSURE
F
P A
PASCAL’S LAW
PRESSURE APPLIED ON A CONFINED FLUID IS
TRANSMITTED UNDIMINISHED IN ALL DIRECTIONS AND
ACTS WITH EQUAL FORCE ON EQUAL AREAS AND AT
RIGHT ANGLES TO THEM.
• PRESSURE APPLIED ON A
CONFINED FLUID
IS TRANSMITTED
 UNDIMINISHED
 IN ALL DIRECTIONS
 ACTS WITH EQUAL
FORCE ON EQUAL AREAS
AND
 AT RIGHT ANGLES TO
THEM
• FRENCH SCIENTIST
PASCAL DISCOVERED
THIS LAW IN THE
17th
CENTURY.
• RELATES TO
USE OF CONFINED FLUID
IN
♦ TRANSMITTING
POWER
♦ MODIFYING
MOTION
♦ MULTIPLYING
FORCE.
PASCAL’S LAW
FORCE
F1 SMALL AREA
A1
FORCE
F2
LARGE AREA
A2
P = F1
A1
F2 = P x A2
PRESSURE
P
BRAMAH’S PRESS
HYDRAULIC LEVERAGE
MECHANICAL LEVERAGE
10
kg
1Cm2
10 Cm2
100 kg
INPUT OUTPUT
10 Kg ON A
1Cm2
AREA PRESSURE
DEVELOPED
THROUGHOUT
IS 10 Kg / Cm2
THIS
PRESSURE
SUPPORTS A
WT OF 100 Kg
IF AREA IS
10 Cm2
THE FORCES ARE PROPORTIONAL
TO THE PISTON AREAS
10 Kg
1 Cm2
= 100 Kg
10 Cm2
A LOAD
OF 10 Kg
HERE
WILL
BALANCE A
LOAD OF
100 Kg
HERE
10 Kg
100 Kg
10
1
1Cm
LAW OF CONSERVATION OF ENERGY
1Cm2
10 Cm2
100 kg
10
kg
10Cm
 ENERGY CAN NEITHER BE CREATED NOR DESTROYED.
 WHAT IS GAINED BY FORCE IS SACRIFICED IN THE
DISTANCE MOVED.
WORK DONE = FORCE x DISTANCE MOVED
W = F x d
W = F x d
= 10 Kg x 10 Cm
= 100 Kg-Cm
W = F x d
= 100 Kg x 1 Cm
= 100 Kg-Cm
MOVING THE SMALL PISTON
10 Cm DISPLACES
1 Cm2
x 10 Cm = 10 Cm3
OF LIQUID
10 Cm OF LIQUID WILL
MOVE LARGER PISTON
ONLY 1Cm.
10 Cm2
x 1 Cm = 10 Cm3
Q = A x h
HYDRAULIC POWER TRANSMISSION
LINEAR ACTUATOR
ROTARY ACTUATOR
LOADPUMP
PUMP
PISTON & ROD
TO RESERVOIR
HYDRO MOTOR
ADVANTAGES OF HYDRAULICS
PUMP
10 lpm
10 lpm
PISTON MOVES
“X” Cm IN 1 min.THIS VOL.
IS 10 Lts.
MAXIMUM SPEED
(No speed control )
(Speed control )
RELIEF
VALVE
FLOW
CONTROL
VALVE
Q = A x V
Q  Flow
(Cm3
/min)
A  Area
( Cm2
)
V  Velocity
(Cm/ min )
5 lpm
ACTUATOR GETS ONLY
5 LPM AND TRAVELS
“X/2” Cm IN ONE MIN.
 SPEED CONTROL
PUMP
ADVANTAGES OF HYDRAULICS
PUMP
PUMP
RELIEF
VALVE
RELIEF
VALVE
DIRECTIONA
L
VALVE
DIRECTIONAL
VALVE
DIRECTION CONTROL
THE CYLINDER
ROD EXTENDS
THE CYLINDER
ROD RETRACTS
 HYDRAULIC DRIVES ARE REVERSIBLE
ADVANTAGES OF HYDRAULICS
 RELIEF VALVE PROTECTS THE SYSTEM BY MAINTAINING
THE SYSTEM SET PRESSURE.
 ANY INCREASE IN PRESSURE IN SYSTEM IS RELEAVED
TO TANK . ( MOMENTARILY DIVERTING FLOW TO THE
TANK. )
 THUS OVERLOAD PROTECTION IS ACHIEVED.
 OVER LOAD PROTECTION
PRESSURE HEAD
PUMP INLET LOCATIONS
OIL LEVEL ABOVE PUMP
CHARGES INLET 100 Cm
PUMP
PUMP
OIL LEVEL BELOW PUMP
REQUIRES VACUUM TO
“LIFT “ OIL
INLET OUTLET
PRESSURE HERE IS
0.85 x 100 gm / Cm2
= 0.085 Kg / Cm2
THERE MUST BE A VACUUM
EQUIVALENT TO
0.085 Kg / Cm2
TO LIFT THE
OIL
PUMP MECHANISM CREATES
THE LOWER PRESSURE
CONDITION.
100 Cm
INLET OUTLET
HOW PRESSURE IS DEVELOPED
NO PRESSURE
NO RESTRICTION
WITH RESTRICTION
CLOSING
RELIEF
VALVE
RELIEF
VALVE
PRESSURE
BUILDS UP
PRESSURE BUILDS
UPTO RELIEF VALVE
SETTING (100 Kg / Cm2
)
PUMP
PUMP
Set at 100
Kg/Cm2
Set at 100
Kg/Cm2
RELIEF
VALVE
PUMP
Set at 100
Kg/Cm2
A
B
C
10 BAR OPENS VALVE
A
20 BAR OPENS VALVE
B
30 BAR OPENS VALVE
C
PARALLEL FLOW PATHS
10
PUMP
PUMP
THE OIL CAN CHOOSE
3 PATHS
20
IF FLOW IS
BLOCKED BEYOND “
A”
OIL WILL FLOW
THRO “B” WHEN
PRESSURE
REACHES 20
BAR
OIL TAKES THE
PATH OF LEAST
RESISTANCE
SERIES RESISTANCE ADD PRESSURE
P1 = 0
P2 = ( P1 + 10 )
= 0 + 10
= 10 BAR
P3 = ( P2 + 20 )
= 10 + 20
= 30 BAR
P = ( P3 +
30 )
= 30 + 30
= 60 BAR
A
10 BAR
B
20 BAR
C
30 BAR
PUMP
0
10
30
60
PRINCIPLES OF FLOW
♦ HOW FLOW IS MEASURED ?
 VELOCITY
 FLOW ( FLOW RATE )
♦ FLOW RATE AND SPEED
♦ FLOW AND PRESSURE DROP
♦ LAMINAR AND TURBULENT FLOW
♦ BERNOULLI’S PRINCIPLE
FLOW IS THE ACTION IN THE HYDRAULIC SYSTEM
THAT GIVES THE ACTUATOR ITS MOTION.
PRESSURE GIVES THE ACTUATOR ITS FORCE , BUT
FLOW IS ESSENTIAL TO CAUSE MOVEMENT.
FLOW IN THE HYDRAULIC SYSTEM IS CREATED BY THE
PUMP
PRESSURE INDICATES WORK LOAD.
VELOCITY : IS THE AVERAGE SPEED OF THE FLUID’S
PARTICLES PAST A GIVEN POINT
OR
THE AVERAGE DISTANCE THE PARTICLES
TRAVEL PER UNIT OF TIME.
Unit :m/Sec or m / min ( Metres / Sec or Metres/min )
FLOW RATE : IS THE VOLUME OF FLUID PASSING A POINT
IN A GIVEN TIME.
Unit: Cm3
/ min or l / min ( cc / minute or litres / min )
SPEED OF AN ACTUATOR DEPENDES ON THE ACTUATOR
SIZE AND RATE OF FLOW INTO IT.
Q = A x V
FLOW IN Cm3
/ min : AREA IN Cm 2 :
VELOCITY IN Cm / min
FLOW AND PRESSURE DROPFLOW AND PRESSURE DROP
MAX. PRESSURE
HERE BECAUSE
OF THE HEAD OF
THE FLUID
FRICTION IN PIPE
DROPS PRESSURE
PRESSURE IS
ZERO HERE AS
THE FLUID
FLOWS OUT
UNRESTRICTED
PRESSURE
GRADIENT
SUCEEDINGLY LOWER LEVEL OF LIQUID
SHOWS PRESSURE IS REDUCED AT POINTS
DOWNSTREAM FROM SOURCE.
DUE TO EFFECT OF FRICTION RECOMMENDED VELOCITY RANGES ARE :
1.) PUMP INLET LINE : 0.6 ~ 1.2 metres / Second
2.) WORKING LINE ( PR. LINES) : 2 ~ 6 metres / Second
LAMINAR FLOWLAMINAR FLOW
TURBULENT FLOWTURBULENT FLOW
LOW VELOCITY FLOW IN A
STRAIGHT PIPE IS STREAMLINED.
THE FLUID PARTICLES MOVE
PARALLEL TO FLOW DIRECTION.
NOR DOES A
GRADUAL CHANGE
IN DIRECTION.
THE FLOW MAY START OUT
STREAMLINED.
AN ABRUPT
CHANGE IN CROSS-
SECTION MAKES IT
TURBULENT.
SO DOES AN ABRUPT
CHANGE IN DIRECTION.
NON PARALLEL PATHS OF PARTICLES
INCREASE RESISTANCE TO FLOW.

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Basics hydraulics

  • 2. BASICS OF HYDRAULICS 1) DEFINITIONS 1.1) HYDRAULICS 1.2) CLASSIFICATION 1.2.1) HYDROSTATICS 1.2.2) HYDRODYNAMICS 1.3) FORCE , PRESSURE , AREA 1.4) PASCAL’S LAW 2) MULTIPLICATION OF FORCES 2.1) BRAMAH’S PRESS 2.2) LAW OF CONSERVATION OF ENERGY 3) HYDRAULIC POWER TRANSMISSION 3.1) LINEAR ACTUATOR 3.2) ROTARY ACTUATOR BASIC DEFINITIONS & FORMULAE USES OF HYDRAULIC S
  • 3. BASICS OF HYDRAULICS 4) ADVANTAGES OF HYDRAULICS 4.1) SPEED CONTROL 4.2) DIRECTION CONTROL 4.3) FORCE CONTROL 4.4) OVERLOAD PROTECTION 4.5) COMPACTNESS 5) HOW PRESSURE IS CREATED ADVANTAGES OF HYDRAULICS PRACTICAL DETAILS IN HYDRAULIC S
  • 4.  HYDRAULICS HYDRO AULUS ( meaning Water ) ( meaning Pipe ) HYDRAULICS : Work done by fluids in pipes. H Y D R O S T A T I C S H Y D R O D Y N A M I C S H y d r a u lic s is C la s s ife d a s
  • 5. HYDROSTATICS FORCE F1 AREA A1 ARE A A2 Eg.:- F1 = 1 Kg A1 = 1 Cm2 P = F1 = 1 Kg A1 1 Cm2 = 1 Kg / Cm2 ( Same Pressure P ) A2 = 10 Cm2 F2 = P x A2 = 1 x 10 = 10 Kg HYDROSTATICS FORCE F2
  • 7. • IN ORDER TO DETERMINE THE TOTAL FORCE EXERTED ON A SURFACE WE NEED TO KNOW THE PRESSURE OR FORCE PER UNIT AREA. • PRESSURE = FORCE FORCE IN → KILOGRAMS ( Kg ) AREA AREA IN → SQ. CM ( Cm2 ) PRESSURE IN → KILOGRAM / SQ.CM (Kg / Cm2 ) P = F A • FORCE = PRESSURE x AREA • THE ATMOSPHERIC AIR EXERTS UNIFORM PRESSURE ALL ROUND. THIS PRESSURE IS APPROX. 1 Kg / Cm2 AND IS DENOTED AS 1 BAR ( BAROMETER ) PRESSURE F P A
  • 8. PASCAL’S LAW PRESSURE APPLIED ON A CONFINED FLUID IS TRANSMITTED UNDIMINISHED IN ALL DIRECTIONS AND ACTS WITH EQUAL FORCE ON EQUAL AREAS AND AT RIGHT ANGLES TO THEM. • PRESSURE APPLIED ON A CONFINED FLUID IS TRANSMITTED  UNDIMINISHED  IN ALL DIRECTIONS  ACTS WITH EQUAL FORCE ON EQUAL AREAS AND  AT RIGHT ANGLES TO THEM • FRENCH SCIENTIST PASCAL DISCOVERED THIS LAW IN THE 17th CENTURY. • RELATES TO USE OF CONFINED FLUID IN ♦ TRANSMITTING POWER ♦ MODIFYING MOTION ♦ MULTIPLYING FORCE.
  • 9. PASCAL’S LAW FORCE F1 SMALL AREA A1 FORCE F2 LARGE AREA A2 P = F1 A1 F2 = P x A2 PRESSURE P
  • 10. BRAMAH’S PRESS HYDRAULIC LEVERAGE MECHANICAL LEVERAGE 10 kg 1Cm2 10 Cm2 100 kg INPUT OUTPUT 10 Kg ON A 1Cm2 AREA PRESSURE DEVELOPED THROUGHOUT IS 10 Kg / Cm2 THIS PRESSURE SUPPORTS A WT OF 100 Kg IF AREA IS 10 Cm2 THE FORCES ARE PROPORTIONAL TO THE PISTON AREAS 10 Kg 1 Cm2 = 100 Kg 10 Cm2 A LOAD OF 10 Kg HERE WILL BALANCE A LOAD OF 100 Kg HERE 10 Kg 100 Kg 10 1
  • 11. 1Cm LAW OF CONSERVATION OF ENERGY 1Cm2 10 Cm2 100 kg 10 kg 10Cm  ENERGY CAN NEITHER BE CREATED NOR DESTROYED.  WHAT IS GAINED BY FORCE IS SACRIFICED IN THE DISTANCE MOVED. WORK DONE = FORCE x DISTANCE MOVED W = F x d W = F x d = 10 Kg x 10 Cm = 100 Kg-Cm W = F x d = 100 Kg x 1 Cm = 100 Kg-Cm MOVING THE SMALL PISTON 10 Cm DISPLACES 1 Cm2 x 10 Cm = 10 Cm3 OF LIQUID 10 Cm OF LIQUID WILL MOVE LARGER PISTON ONLY 1Cm. 10 Cm2 x 1 Cm = 10 Cm3 Q = A x h
  • 12. HYDRAULIC POWER TRANSMISSION LINEAR ACTUATOR ROTARY ACTUATOR LOADPUMP PUMP PISTON & ROD TO RESERVOIR HYDRO MOTOR
  • 13. ADVANTAGES OF HYDRAULICS PUMP 10 lpm 10 lpm PISTON MOVES “X” Cm IN 1 min.THIS VOL. IS 10 Lts. MAXIMUM SPEED (No speed control ) (Speed control ) RELIEF VALVE FLOW CONTROL VALVE Q = A x V Q  Flow (Cm3 /min) A  Area ( Cm2 ) V  Velocity (Cm/ min ) 5 lpm ACTUATOR GETS ONLY 5 LPM AND TRAVELS “X/2” Cm IN ONE MIN.  SPEED CONTROL PUMP
  • 14. ADVANTAGES OF HYDRAULICS PUMP PUMP RELIEF VALVE RELIEF VALVE DIRECTIONA L VALVE DIRECTIONAL VALVE DIRECTION CONTROL THE CYLINDER ROD EXTENDS THE CYLINDER ROD RETRACTS  HYDRAULIC DRIVES ARE REVERSIBLE
  • 15. ADVANTAGES OF HYDRAULICS  RELIEF VALVE PROTECTS THE SYSTEM BY MAINTAINING THE SYSTEM SET PRESSURE.  ANY INCREASE IN PRESSURE IN SYSTEM IS RELEAVED TO TANK . ( MOMENTARILY DIVERTING FLOW TO THE TANK. )  THUS OVERLOAD PROTECTION IS ACHIEVED.  OVER LOAD PROTECTION
  • 16. PRESSURE HEAD PUMP INLET LOCATIONS OIL LEVEL ABOVE PUMP CHARGES INLET 100 Cm PUMP PUMP OIL LEVEL BELOW PUMP REQUIRES VACUUM TO “LIFT “ OIL INLET OUTLET PRESSURE HERE IS 0.85 x 100 gm / Cm2 = 0.085 Kg / Cm2 THERE MUST BE A VACUUM EQUIVALENT TO 0.085 Kg / Cm2 TO LIFT THE OIL PUMP MECHANISM CREATES THE LOWER PRESSURE CONDITION. 100 Cm INLET OUTLET
  • 17. HOW PRESSURE IS DEVELOPED NO PRESSURE NO RESTRICTION WITH RESTRICTION CLOSING RELIEF VALVE RELIEF VALVE PRESSURE BUILDS UP PRESSURE BUILDS UPTO RELIEF VALVE SETTING (100 Kg / Cm2 ) PUMP PUMP Set at 100 Kg/Cm2 Set at 100 Kg/Cm2 RELIEF VALVE PUMP Set at 100 Kg/Cm2
  • 18. A B C 10 BAR OPENS VALVE A 20 BAR OPENS VALVE B 30 BAR OPENS VALVE C PARALLEL FLOW PATHS 10 PUMP PUMP THE OIL CAN CHOOSE 3 PATHS 20 IF FLOW IS BLOCKED BEYOND “ A” OIL WILL FLOW THRO “B” WHEN PRESSURE REACHES 20 BAR OIL TAKES THE PATH OF LEAST RESISTANCE
  • 19. SERIES RESISTANCE ADD PRESSURE P1 = 0 P2 = ( P1 + 10 ) = 0 + 10 = 10 BAR P3 = ( P2 + 20 ) = 10 + 20 = 30 BAR P = ( P3 + 30 ) = 30 + 30 = 60 BAR A 10 BAR B 20 BAR C 30 BAR PUMP 0 10 30 60
  • 20. PRINCIPLES OF FLOW ♦ HOW FLOW IS MEASURED ?  VELOCITY  FLOW ( FLOW RATE ) ♦ FLOW RATE AND SPEED ♦ FLOW AND PRESSURE DROP ♦ LAMINAR AND TURBULENT FLOW ♦ BERNOULLI’S PRINCIPLE FLOW IS THE ACTION IN THE HYDRAULIC SYSTEM THAT GIVES THE ACTUATOR ITS MOTION. PRESSURE GIVES THE ACTUATOR ITS FORCE , BUT FLOW IS ESSENTIAL TO CAUSE MOVEMENT. FLOW IN THE HYDRAULIC SYSTEM IS CREATED BY THE PUMP PRESSURE INDICATES WORK LOAD.
  • 21. VELOCITY : IS THE AVERAGE SPEED OF THE FLUID’S PARTICLES PAST A GIVEN POINT OR THE AVERAGE DISTANCE THE PARTICLES TRAVEL PER UNIT OF TIME. Unit :m/Sec or m / min ( Metres / Sec or Metres/min ) FLOW RATE : IS THE VOLUME OF FLUID PASSING A POINT IN A GIVEN TIME. Unit: Cm3 / min or l / min ( cc / minute or litres / min ) SPEED OF AN ACTUATOR DEPENDES ON THE ACTUATOR SIZE AND RATE OF FLOW INTO IT. Q = A x V FLOW IN Cm3 / min : AREA IN Cm 2 : VELOCITY IN Cm / min
  • 22. FLOW AND PRESSURE DROPFLOW AND PRESSURE DROP MAX. PRESSURE HERE BECAUSE OF THE HEAD OF THE FLUID FRICTION IN PIPE DROPS PRESSURE PRESSURE IS ZERO HERE AS THE FLUID FLOWS OUT UNRESTRICTED PRESSURE GRADIENT SUCEEDINGLY LOWER LEVEL OF LIQUID SHOWS PRESSURE IS REDUCED AT POINTS DOWNSTREAM FROM SOURCE. DUE TO EFFECT OF FRICTION RECOMMENDED VELOCITY RANGES ARE : 1.) PUMP INLET LINE : 0.6 ~ 1.2 metres / Second 2.) WORKING LINE ( PR. LINES) : 2 ~ 6 metres / Second
  • 23. LAMINAR FLOWLAMINAR FLOW TURBULENT FLOWTURBULENT FLOW LOW VELOCITY FLOW IN A STRAIGHT PIPE IS STREAMLINED. THE FLUID PARTICLES MOVE PARALLEL TO FLOW DIRECTION. NOR DOES A GRADUAL CHANGE IN DIRECTION. THE FLOW MAY START OUT STREAMLINED. AN ABRUPT CHANGE IN CROSS- SECTION MAKES IT TURBULENT. SO DOES AN ABRUPT CHANGE IN DIRECTION. NON PARALLEL PATHS OF PARTICLES INCREASE RESISTANCE TO FLOW.