Diamond is sp3 covalent. It makes for bonds to ne.pdf

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Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up. Solution Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up..

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OBJECTIVE: DESCRIBE THE BONDING OF ETHANE, ETHENE (ETHYLENE) AND ETHYNE(ACETYLENE) AND EXPLAIN THEIR GEOMETRY IN TERMS OF HYBRIDIZATION AND σ AND ¶ CARBON-CARBON BONDS. Hybridization (or hybridization) is the concept of mixing (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electron to form chemical bond is valence bond theory. An orbital of one atom can combine with that of another atom to form a sigma (σ) or pi (∏) bond. A sigma bond is covalent bond resulting from the end-to-end overlap of orbitals. A pi-bond results from the side-to-side overlap of p orbitals along a plane containing a line connecting the nuclei of the atoms

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Carbon being the most versatile element on this earth is also the most important element for mankind. Carbon (from Latin: carbo "coal") is a chemical element with the symbol C and atomic number 6. It is nonmetallic and tetravalent—making four electrons available to form covalent chemical bonds. It belongs to group 14 of the periodic table. Carbon makes up only about 0.025 percent of Earth's crust.

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Carbon can exist in different structural states known as allotropes. Two well-known allotropes are graphite, one of the softest substances, and diamond, the hardest naturally occurring mineral. Graphite has a crystalline structure in which the carbon atoms are arranged in layers of flat sheets. Each sheet consists of a network of hexagonal (six-membered) rings in which each carbon atom is bonded to three other atoms. Diamond, which is formed in the Earth at very high pressures, adopts a different crystalline structure. Each carbon atom is bonded to four others, which together form a tetrahedral shape surrounding the central carbon Diamond is transparent and hard; it acts as an excellent electrical insulator, and can be used as an abrasive. By contrast, graphite is opaque and soft. It conducts electricity, and is a good lubricant. Diamond crystallizes in the cubic system but graphite crystallizes in the hexagonal system. Carbon that lacks an overall crystalline structure is known as amorphous carbon. Although it is possible to produce carbon that is entirely amorphous (non-crystalline), material that is described as amorphous usually includes small crystals of graphite or diamond. Amorphous carbon is the main constituent of charcoal, soot (lampblack or carbon black), and activated carbon. In addition, several exotic allotropes have been synthesized or discovered, including fullerenes, carbon nanotubes, lonsdaleite, carbon nanofoam, and aggregated diamond nanorods. The carbon atoms in these allotropes have different structural arrangements. Fullerene C540. A lattice of five- and six-membered rings of carbon atoms, forming an overall spherical shape.A fullerene is composed of a sheet of carbon atoms linked together in hexagonal and pentagonal rings to take the overall form of a hollow sphere or ellipsoid. A spherical fullerene is also called a buckyball. The most well-known buckyball is Buckminsterfullerene (containing 60 carbon atoms per sphere), named after Richard Buckminster Fuller, the architect who developed the geodesic dome. A carbon nanotube likewise consists of a sheet of carbon atoms linked in hexagonal and pentagonal rings, but the overall shape is that of a hollow cylinder. Sometimes called a buckytube, it is classified as part of the fullerene family of carbon compounds. Lonsdaleite is thought to form when meteoric graphite falls to Earth. The impact\'s heat and stress transform the graphite into a structure similar to diamond, but graphite\'s hexagonal crystal lattice is retained. Also known as hexagonal diamond, lonsdaleite is transparent and brownish yellow in color. Carbon nanofoam was unexpectedly produced by scientists in Australia in 1997*. It consists of low-density clusters of carbon atoms that are bonded in six- and seven-membered rings. Surprisingly, the material is attracted to magnets and can be magnetized at temperatures below - 183°C. Aggregated diamond nanorods (ADNRs) are denser and harder than diamond, and they ap.

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Particulars $Amount Direct materials 64452 Direct Labour (1332 * 14) 18648 Manufacturing Overheads (1490 * 15) 22350 Total cost 105450 Number of units produced 3700 Unit product cost = Total cost / Number of units produced 28.5 Solution Particulars $Amount Direct materials 64452 Direct Labour (1332 * 14) 18648 Manufacturing Overheads (1490 * 15) 22350 Total cost 105450 Number of units produced 3700 Unit product cost = Total cost / Number of units produced 28.5.

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Decrease in inventory Source of cash $ 440 Decrease in accounts payable Use of cash $ (170) Increase in notes payable Source of cash $ 155 Increase in accounys receivables Use of cash $ (185) Cash increased by $ $ 240 Solution Decrease in inventory Source of cash $ 440 Decrease in accounts payable Use of cash $ (170) Increase in notes payable Source of cash $ 155 Increase in accounys receivables Use of cash $ (185) Cash increased by $ $ 240.

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Too low. If you do not dry the sodium thiosulfate the extra water molecules will increase volume while decreasing your actual number of moles of the salt and therefore produce a lower molar concentration. Solution Too low. If you do not dry the sodium thiosulfate the extra water molecules will increase volume while decreasing your actual number of moles of the salt and therefore produce a lower molar concentration..

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1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary storage for IO devices which is used to store sufficient amount of data before it is transferred to CPU. In a system, CPU communicates with the IO devices and vice versa and in order for a system to operate properly the devices must be in synchronization with the CPU. IO devices are usually slower than CPU e:g printer is slower than CPU and when CPU sends some data to be printed this data is stored in the buffer and then transferred to the printer with a speed suitable for printer. Similarly a buffer is used to temporarily store data being entered from a n input device like keyboard, which allows a large block of data to be keyed. held, and then transferred all at once to the CPU and in during the typing period CPU performs some other tasks. Benefits of IO Device Control Unit Buffer are Flow Control. (Modules canbuffer data until the adjacent module is ready to receive it), Better CPU utiization, BetterThroughput etc Solution 1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary .

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1. E) The vapor pressure of a liquid. Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly to each other. Thus it is more difficult for the molecules to escape into the gas phase and the vapor pressure decreases. All the other properties listed should increase in value. 2. A) Ba(OH)2 The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+ and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water and insoluble BaSO4: Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l) The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows and the bulb dims. 3. D) hydration Hydration is the process whereby water molecules form dipole-dipole interactions with the solute ions, releasing energy and causing the salt to fall apart. 4. E)All of these are correct. All the statements about light, matter and energy are true. 5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your question but I have put the correct values here for you) Silicon has electronic configuration 1s2 2s2p6 3s2p2 The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing) ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to the nucleus, so the ionization energy shows a large increase. Solution 1. E) The vapor pressure of a liquid. Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly to each other. Thus it is more difficult for the molecules to escape into the gas phase and the vapor pressure decreases. All the other properties listed should increase in value. 2. A) Ba(OH)2 The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+ and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water and insoluble BaSO4: Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l) The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows and the bulb dims. 3. D) hydration Hydration is the process whereby water molecules form dipole-dipole interactions with the solute ions, releasing energy and causing the salt to fall apart. 4. E)All of these are correct. All the statements about light, matter and energy are true. 5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your question but I have put the correct values here for you) Silicon has electronic configuration 1s2 2s2p6 3s2p2 The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing) ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to the nucleus, so the ionization energy shows a large increase..

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Light is a form of energy that can be released by an atom. It is made up of many small particle-like packets that have energy and momentum but no mass. These particles, called light photons, are the most basic units of light. Atoms release light photons when their electrons become excited. When an atom gains or loses energy, the change is expressed by the movement of electrons. When something passes energy on to an atom, an electron may be temporarily boosted to a higher orbital (farther away from the nucleus). The electron only holds this position for a tiny fraction of a second; almost immediately, it is drawn back toward the nucleus, to its original orbital. As it returns to its original orbital, the electron releases the extra energy in the form of a photon, in some cases a light photon. Solution Light is a form of energy that can be released by an atom. It is made up of many small particle-like packets that have energy and momentum but no mass. These particles, called light photons, are the most basic units of light. Atoms release light photons when their electrons become excited. When an atom gains or loses energy, the change is expressed by the movement of electrons. When something passes energy on to an atom, an electron may be temporarily boosted to a higher orbital (farther away from the nucleus). The electron only holds this position for a tiny fraction of a second; almost immediately, it is drawn back toward the nucleus, to its original orbital. As it returns to its original orbital, the electron releases the extra energy in the form of a photon, in some cases a light photon..

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1) Presence of jaws with paired fins in fish helps to feed them. Fins helps them with increased stability and maneuverability and jaws helps to capture the prey and seize it. 2) Fish with jaws need to regulate their body temperature so they need to feed themselves often. It capture the prey and send it to stomach for digestion and for temporary storage. Jawless fish donot regulate their own body temperature so they don\'t need temporary storage like stomach and also they have sucking mouth and sharp teeth which helps in digestion without the need for pre digestion with gastric juice. So the fish which needs more food has jaw (Capture large prey) with stomach (Temporary storage and pre digestion). The fish which needs less food has no jaw and no stomach but with sucking mouth and also they have no fins. Jawless fish examples : Lampreys and hagfish. Majority of the fishes are with jaws. 3) Two chambered heart have one atrium and one ventricle and three chambered heart have two atrium and one ventricle. There are two types of circulatory system that is single circulation system (fish) and double circulation system (reptiles, mammals) In single circulation system, blood from the parts of the body enters heart through atrium and then ventricle pumps the blood to gills where re-oxygenation takes place. From the gills, blood is sent back to body parts. Blood enters the heart only once that is only deoxygenated blood enters. In double circulation system, blood enters the heart twice that is from parts of the body to heart then from heart to pulmonary circulation (Lungs) and from lungs to heart then heart to parts of the body. Both deoxygenated and oxygenated blood enters the heart. Solution 1) Presence of jaws with paired fins in fish helps to feed them. Fins helps them with increased stability and maneuverability and jaws helps to capture the prey and seize it. 2) Fish with jaws need to regulate their body temperature so they need to feed themselves often. It capture the prey and send it to stomach for digestion and for temporary storage. Jawless fish donot regulate their own body temperature so they don\'t need temporary storage like stomach and also they have sucking mouth and sharp teeth which helps in digestion without the need for pre digestion with gastric juice. So the fish which needs more food has jaw (Capture large prey) with stomach (Temporary storage and pre digestion). The fish which needs less food has no jaw and no stomach but with sucking mouth and also they have no fins. Jawless fish examples : Lampreys and hagfish. Majority of the fishes are with jaws. 3) Two chambered heart have one atrium and one ventricle and three chambered heart have two atrium and one ventricle. There are two types of circulatory system that is single circulation system (fish) and double circulation system (reptiles, mammals) In single circulation system, blood from the parts of the body enters heart through atrium and then ventricle pumps the blood to gills .

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You\'re looking for Ka, the dissociation constant, so you measure this by adding the substance to water. 1. Write the balanced equation HBrO + H2O = BrO- + H30+ 2. the pH is 4.95, so you know its acidic and there has to have hydronium as a product. if the pH was >7.0, there would be OH- instead. the pH is a measure of H ions, and to get the concentration, you simply do 10^(-pH). 10^(-4.95) = 1.12E-5 3. The equation for Ka is concentration of products/concentration of reactants. always look at the coefficients infront of the molecules in the reaction. in this case, it is [BrO-)][H3O+]/[HBrO] *liquids and solids are never included in this, only aqueous solutions and gases are* 4. Your concentration of H3O was found to be 1.12E-5, and because the H30 and BrO are in a 1:1 ration in the equation, the concentration for BrO is also 1.12E-5. The concentration for HBrO as a reactant is given, but the final concentration is 0.063-concentration of hydronium...but since the concentration of the hydronium is so small, it doesnt at all affect the final answer. 5. your equation for Ka=((1.12E- 5)(1.12E-5))/(0.063-1.12E-5). The final answer for your Ka is 2.0E-9 Hope this helps, please rate. Solution You\'re looking for Ka, the dissociation constant, so you measure this by adding the substance to water. 1. Write the balanced equation HBrO + H2O = BrO- + H30+ 2. the pH is 4.95, so you know its acidic and there has to have hydronium as a product. if the pH was >7.0, there would be OH- instead. the pH is a measure of H ions, and to get the concentration, you simply do 10^(-pH). 10^(-4.95) = 1.12E-5 3. The equation for Ka is concentration of products/concentration of reactants. always look at the coefficients infront of the molecules in the reaction. in this case, it is [BrO-)][H3O+]/[HBrO] *liquids and solids are never included in this, only aqueous solutions and gases are* 4. Your concentration of H3O was found to be 1.12E-5, and because the H30 and BrO are in a 1:1 ration in the equation, the concentration for BrO is also 1.12E-5. The concentration for HBrO as a reactant is given, but the final concentration is 0.063-concentration of hydronium...but since the concentration of the hydronium is so small, it doesnt at all affect the final answer. 5. your equation for Ka=((1.12E- 5)(1.12E-5))/(0.063-1.12E-5). The final answer for your Ka is 2.0E-9 Hope this helps, please rate..

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Okay so dipole-dipole interactions would occur between polar molecules such as water. The H has a + charge while O has a - charge. Dipole- induced dipole(or dispersion forces) would be like a molecule that has a polar part to it such as a -COOH group and then a nonpolar part such as a long hydrocarbon chain. The nonpolar part has no charge except the transient charge among the different atoms. I hope that helps Solution Okay so dipole-dipole interactions would occur between polar molecules such as water. The H has a + charge while O has a - charge. Dipole- induced dipole(or dispersion forces) would be like a molecule that has a polar part to it such as a -COOH group and then a nonpolar part such as a long hydrocarbon chain. The nonpolar part has no charge except the transient charge among the different atoms. I hope that helps.

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The answer is A) Pol II, with twelve subunits on its own, is capable of initiating transcription. because it is composed with 12 subunits and due to incapable of specific promoter recognition it can\'t initiate transcription. Solution The answer is A) Pol II, with twelve subunits on its own, is capable of initiating transcription. because it is composed with 12 subunits and due to incapable of specific promoter recognition it can\'t initiate transcription..

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solution: A= 1 1 0 4 3 1 2 0 5 Finding the determinant of the matrix ? det A = -3 The determinant of A is non-zero, hence the inverse matrix A-1 exists. To find the inverse matrix was calculated the minors and cofactors of the matrix ? M1,1 = 3 1 0 5 = 15 C1,1 = (-1)1+1M1,1 = 15 M1,2 = 4 1 2 5 = 18 C1,2 = (-1)1+2M1,2 = -18 M1,3 = 4 3 2 0 = -6 C1,3 = (-1)1+3M1,3 = -6 M2,1 = 1 0 0 5 = 5 C2,1 = (-1)2+1M2,1 = -5 M2,2 = 1 0 2 5 = 5 C2,2 = (-1)2+2M2,2 = 5 M2,3 = 1 1 2 0 = -2 C2,3 = (-1)2+3M2,3 = 2 M3,1 = 1 0 3 1 = 1 C3,1 = (-1)3+1M3,1 = 1 M3,2 = 1 0 4 1 = 1 C3,2 = (-1)3+2M3,2 = -1 M3,3 = 1 1 4 3 = -1 C3,3 = (-1)3+3M3,3 = -1 Matrix of cofactors: C = 15 -18 -6 -5 5 2 1 -1 -1 Transpose of cofactor matrix: CT = 15 -5 1 -18 5 -1 -6 2 -1 Finding the inverse matrix. A-1 = CT = det A -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 B) First, let\'s add the Identity Matrix to the right of our matrix 1 1 0 1 0 0 4 3 1 0 1 0 2 0 5 0 0 1 Now, let\'s do Gauss-Jordan Elimination on our new matrix... Add (-4 * row1) to row2 1 1 0 1 0 0 0 -1 1 -4 1 0 2 0 5 0 0 1 Add (-2 * row1) to row3 1 1 0 1 0 0 0 -1 1 -4 1 0 0 -2 5 -2 0 1 Divide row2 by -1 1 1 0 1 0 0 0 1 -1 4 -1 0 0 -2 5 -2 0 1 Add (2 * row2) to row3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 3 6 -2 1 Divide row3 by 3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 1 2 -2/3 1/3 Add (1 * row3) to row2 1 1 0 1 0 0 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 Add (-1 * row2) to row1 1 0 0 -5 5/3 -1/3 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 The inverse matrix can now be found in the right 3 columns of our reduced row echelon matrix Here is the inverse matrix: -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 A= 1 1 0 4 3 1 2 0 5 Solution solution: A= 1 1 0 4 3 1 2 0 5 Finding the determinant of the matrix ? det A = -3 The determinant of A is non-zero, hence the inverse matrix A-1 exists. To find the inverse matrix was calculated the minors and cofactors of the matrix ? M1,1 = 3 1 0 5 = 15 C1,1 = (-1)1+1M1,1 = 15 M1,2 = 4 1 2 5 = 18 C1,2 = (-1)1+2M1,2 = -18 M1,3 = 4 3 2 0 = -6 C1,3 = (-1)1+3M1,3 = -6 M2,1 = 1 0 0 5 = 5 C2,1 = (-1)2+1M2,1 = -5 M2,2 = 1 0 2 5 = 5 C2,2 = (-1)2+2M2,2 = 5 M2,3 = 1 1 2 0 = -2 C2,3 = (-1)2+3M2,3 = 2 M3,1 = 1 0 3 1 = 1 C3,1 = (-1)3+1M3,1 = 1 M3,2 = 1 0 4 1 = 1 C3,2 = (-1)3+2M3,2 = -1 M3,3 = 1 1 4 3 = -1 C3,3 = (-1)3+3M3,3 = -1 Matrix of cofactors: C = 15 -18 -6 -5 5 2 1 -1 -1 Transpose of cofactor matrix: CT = 15 -5 1 -18 5 -1 -6 2 -1 Finding the inverse matrix. A-1 = CT = det A -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 B) First, let\'s add the Identity Matrix to the right of our matrix 1 1 0 1 0 0 4 3 1 0 1 0 2 0 5 0 0 1 Now, let\'s do Gauss-Jordan Elimination on our new matrix... Add (-4 * row1) to row2 1 1 0 1 0 0 0 -1 1 -4 1 0 2 0 5 0 0 1 Add (-2 * row1) to row3 1 1 0 1 0 0 0 -1 1 -4 1 0 0 -2 5 -2 0 1 Divide row2 by -1 1 1 0 1 0 0 0 1 -1 4 -1 0 0 -2 5 -2 0 1 Add (2 * row2) to row3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 3 6 -2 1 Divide row3 by 3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 1 2 -2/3 1/3 Add (1 * row3) to row2 1 1 0 1 0 0 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 Add (-1 * row2) to row1 1.

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Q1). Gene therapy is an experimental approach to treat the disease by inserting therapeutic genes or changing gene expression levels in the patient’s cells. Genes are nucleic acid polymers; these therapeutic genes used in gene therapy generally encode a functional gene that replaces mutated gene. Potential treatment for single gene genetic disorders such as haemophilia, muscular dystrophy, cystic fibrosis, etc. was demonstrated. Treatment of cancer, AIDS (acquired immune deficiency syndrome), Alzheimer’s disease and rheumatoid arthritis are also under active investigation. All the diseases cannot be cured by gene therapy. Some of hte good targets of the gene therapy include, 1). Diseases with known genetic defects or mutations 2). Diseases with point mutations on one or more genes 3). The possibility of delivering genes to the affected tissues 4). If the substitution of defective gene correct the disease status Solution Q1). Gene therapy is an experimental approach to treat the disease by inserting therapeutic genes or changing gene expression levels in the patient’s cells. Genes are nucleic acid polymers; these therapeutic genes used in gene therapy generally encode a functional gene that replaces mutated gene. Potential treatment for single gene genetic disorders such as haemophilia, muscular dystrophy, cystic fibrosis, etc. was demonstrated. Treatment of cancer, AIDS (acquired immune deficiency syndrome), Alzheimer’s disease and rheumatoid arthritis are also under active investigation. All the diseases cannot be cured by gene therapy. Some of hte good targets of the gene therapy include, 1). Diseases with known genetic defects or mutations 2). Diseases with point mutations on one or more genes 3). The possibility of delivering genes to the affected tissues 4). If the substitution of defective gene correct the disease status.

Q1). Gene therapy is an experimental approach to treat the disease b.pdf

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Solution : Three modes of DNA replication 1) Semi conservative: => Each daughter strand is composed of one old DNA strand and one new DNA strand. 2) Conservative: => The original double helix remains as complete unit. => The new DNA double helix is produced as a single unit. => The old DNA is completly conserved. 3) Dispersive mode: =>Separation of the individual covalent phosphodiester bonds is required for this mode of replication..

Solution Three modes of DNA replication 1) Semi conservative.pdf

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package s3; // Copy paste this Java Template and save it as \"EmergencyRoom.java\" import java.util.*; import java.io.*; // write your matric number here: // write your name here: // write list of collaborators here: // year 2016 hash code: XAbyuzR78fXeaMHBdLan (do NOT delete this line) class patientlist { private String PatientName; private int emergencyLvl; public patientlist(String PatientName, int emergencyLvl) { this.PatientName = PatientName; this.emergencyLvl = emergencyLvl; } public String getPatientName() { return PatientName; } public void setPatientName(String PatientName) { this.PatientName = PatientName; } public int getEmergencyLvl() { return emergencyLvl; } public void setEmergencyLvl(int emergencyLvl) { this.emergencyLvl = emergencyLvl; } } class EmergencyRoom { // if needed, declare a private data structure here that // is accessible to all methods in this class private List patientlist; public EmergencyRoom() { // Write necessary code during construction patientlist = new ArrayList(); } void ArriveAtHospital(String patientName, int emergencyLvl) { // You have to insert the information (patientName, emergencyLvl) // into your chosen data structure if (patientName.length() > 15 || patientName.length() < 1) { System.out.println(\"patient name is either too long or too short.\ Please enter a name between 1 to 15 characters.\"); } else if (emergencyLvl > 100 || emergencyLvl < 30) { System.out.println(\"Emergency level is either too high or too low.\ Please enter a valid level between 30 to 100.\"); } else { int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { System.out.println(\"Patient already admitted\"); break; } } if (i == patientlist.size()) { patientlist p = new patientlist(patientName.toUpperCase(), emergencyLvl); patientlist.add(p); } } } void UpdateEmergencyLvl(String patientName, int incEmergencyLvl) { // You have to update the emergencyLvl of patientName to // emergencyLvl += incEmergencyLvl // and modify your chosen data structure (if needed) int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { //System.out.println(\"Patient already admitted\"); //break; if (incEmergencyLvl > 70 || incEmergencyLvl < 0) { System.out.println(\"Emergency level is either too high or too low.\ Please enter a valid increment between 0 to 70.\"); break; } else { patientlist.get(i).setEmergencyLvl(patientlist.get(i).getEmergencyLvl() + incEmergencyLvl); } } } } void Treat(String patientName) { // This patientName is treated by the doctor // remove him/her from your chosen data structure int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { patientlist.remove(i); } } } String Query() { String ans = \"The emergency room is empty\"; int i; if(patientlist.isEmpty()) return ans; else{ int max=patientlist.get(0).getEme.

package s3; Copy paste this Java Template and save it as Emer.pdf

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Our body is having two line defence system against pathogens.Pathogens are micro-organisms such like virus,bactria,parasite,fungi. First line of defence system:- It is a outside defence system which protect body from the outside ,it includes skin ,tear,mucus,cilia,stomach acid,urine flow. Skin acts as a barrier between pathogens and your body. it stops all microarganisms to enter in to your body unless your skin get brokken.The pathogens can get enter through your nose ,eye,mouth, but through that if pathogen passes .Nose ,eye,mouth contains mucus,tear .they stop pathogen and break down their cell wall because they contain enzyme.those that are not killed immediately are trapped in mucus swallowed. cilia is present in our windpipe.it helps to move mucus and traped pathogens from lungs.Urine flow help to flush out pathogens from the bladder.stomach acid is present in stomach and helps to kill pathogens.this is the fine defence. Second line of defence system :- once pathogen cross your first line of defence second line of defence active for example ,through the cut pathogen enter into body and develope infection then second line defence active .Through a sequence of steps called immune response ,the immune system attacks these pathogens. In the second line of deffence system is a group of cells ,tissues,organs work together to protect the body .This is called immune system. The cells involved in the immune system called white blood cells is helps to destoys the desease causing organisms.there are different types of white blood cells but function is same that protect you from the organisms. They are neutrophiles,T-helper cells,Cytotoxic cells,marcophases,B-cells. These cells work together and kill the micro organism. Tissues and Organs :- This are involved in the immune system are the lymphatic system ,lymph nodes and lymp fluid.This are having specific function. Lymphatic system is a system of thin tube present through out the body .These tubes are called lymph vessels.they contain lymph. Lymph is a fluid that contains white blood cells. lymph helps to protect body form micro organisms. This is a second line of defence system. Solution Our body is having two line defence system against pathogens.Pathogens are micro-organisms such like virus,bactria,parasite,fungi. First line of defence system:- It is a outside defence system which protect body from the outside ,it includes skin ,tear,mucus,cilia,stomach acid,urine flow. Skin acts as a barrier between pathogens and your body. it stops all microarganisms to enter in to your body unless your skin get brokken.The pathogens can get enter through your nose ,eye,mouth, but through that if pathogen passes .Nose ,eye,mouth contains mucus,tear .they stop pathogen and break down their cell wall because they contain enzyme.those that are not killed immediately are trapped in mucus swallowed. cilia is present in our windpipe.it helps to move mucus and traped pathogens from lungs.Urine flow help to flush out.

Our body is having two line defence system against pathogens.Pathoge.pdf

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Once neurons are produced, they migrate and modify to form six layered structure of cortex. The earliest formed neurons form the preplate which is then split into marginal plate and subplate by invading newly formed neurons. The neurons can have two origin: cortical ventricular zone and ganglionic eminences. The corticular neurons exhibit radial migration and form projection neurons while the ganglionic neurons exhibit tangantial migration and form interneurons. Both types arrange in inside out sequence and the early neurons form the deep layers while the late born neuron form the outer layers of cortex. Solution Once neurons are produced, they migrate and modify to form six layered structure of cortex. The earliest formed neurons form the preplate which is then split into marginal plate and subplate by invading newly formed neurons. The neurons can have two origin: cortical ventricular zone and ganglionic eminences. The corticular neurons exhibit radial migration and form projection neurons while the ganglionic neurons exhibit tangantial migration and form interneurons. Both types arrange in inside out sequence and the early neurons form the deep layers while the late born neuron form the outer layers of cortex..

Once neurons are produced, they migrate and modify to form six layer.pdf

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PDU is called Protocol Data Unit.It consists of user data and protoc.pdf

arakalamkah11

1.A hole is the absence of an electron in a particular place in an atom.Electrons and holes do not move as rapidly through the solid materials as electrons do in a vaccum.The holes move more slowly than the electrons.The holes and electrons move in opposite direction. 2.Here if the electric current moving from left to right ,than the holes will be moving in opposite direction that is from right to left. Regardless of the semiconductor type ,with the potencial applied there will be net effect.Both electrons and holes contribute to total current flow,altough they are moving in opposite directions,they are of opposite charge. Solution 1.A hole is the absence of an electron in a particular place in an atom.Electrons and holes do not move as rapidly through the solid materials as electrons do in a vaccum.The holes move more slowly than the electrons.The holes and electrons move in opposite direction. 2.Here if the electric current moving from left to right ,than the holes will be moving in opposite direction that is from right to left. Regardless of the semiconductor type ,with the potencial applied there will be net effect.Both electrons and holes contribute to total current flow,altough they are moving in opposite directions,they are of opposite charge..

1.A hole is the absence of an electron in a particular place in an a.pdf

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1. Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up. Solution Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up.

Diamond is sp3 covalent. It makes for bonds to ne.pdf

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