In 1986 a nuclear plant in Chernobyl (former Soviet Union) had a bre.pdf

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In 1986 a nuclear plant in Chernobyl (former Soviet Union) had a breakdown and spilled radioactive elements into the environment. In particular, it sent the radioisotope Iodine-131, denoted I131, over a large area of Eastern Europe. Suppose that in your hometown of Western Poland the levels of this isotope increased to 12 times the levels considered safe for living organisms. To avoid big doses of radiation, you leave your home and move to, say, South America. If the half-life of I131 is 8 days, when will the radioactivity levels drop enough for you to return safely home? Solution 12 times the levels considered safe for living organisms ---- 12x Now the levels to be dropped to x to be safe for return home safely -- x half life = 8 dsy decay constant = 0.693/8 = 0.086625 per day N(t) = Noe^(-kt) x = 12xe^(-0.086625t) (1/12) =e^(-0.086625t) ln(1/12) = -0.086625t t = 28.68 days.

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When a planetary nebula forms around a star you see gas emitting light and a white dwarf present at the center. Below is a detailed image of M 57, the Ring Nebula. In this image it looks very much like a flower, with different layers of gas clearly seen. What does this image tell us about the conditions inside the star that created the nebula? The layers are the various shells of gas from inside the star. Before the star exploded, there were shells burning around the core. When it exploded, it reveals these layers in the expansion of the gas. Each layer of gas was previously a shell inside the star. Measurements of the Doppler velocity for the gas shows that it is expanding outward from the white dwarf. This means that the outer most gas layer must have been accelerated more rapidly than the inner layers, when the star exploded. The outer most layer is made of hydrogen, which is the lightest element and would be accelerated the most. As you move inward the layers are made of helium, carbon, oxygen, etc. Moving inward, each layer is composed of a heavier element which isn\'t accelerated as much due to its larger mass. So the nebula formed from a single explosion. Measurements of the Doppler velocity for the inner most layer of gas shows that it is expanding outward. This is the outer layer of the star which is moving outward when the star exploded. The other layers farther out are gas from the molecular cloud that is colliding with the expanding gas of the planetary nebula. The molecular cloud gas is surrounding the planetary nebula, because a low mass star doesn\'t live long enough to move very far from where it is formed. The planetary nebula is compressing the molecular cloud, setting off star formation. Measurements of the Doppler velocity for the gas snows that it is expanding outward from the white dwarf. This means that the outer most gas was ejected from the star first since it is the farthest from the white dwarf. Layers that are in closer must have been ejected at a later time. This suggests that the planetary nebula formed from multiple eruptions inside the star and not one single explosion. Solution a) First of all, one should know how a planetary nebula is formed. When an aging star is unable to sustain further fusion reaction to keep its core stable it has many ways to give away - either turn into a supernova, become a black hole or neutron star, or shed its outer envelopes and then the core turns into a white dwarf. this later stage is known as planetary nebulae. The M 57, commonly goes by the name of Ring Nebula, has a bipolar morphology where the core primarily contains carbon and oxygen and other lighter elements. The strong concentration of matter around the equator makes it look like a prolate spheroid. Option d..

When a planetary nebula forms around a star you see gas emitting ligh.pdf

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Which of the following is consistent with a history of positibe selection but not genetic drift a. common haplotype exhibiting weak linkage disequilibrium b a rare haplotype showing strong linkage disequilibrium c. a common haplotype in a region of high recombination d. a rare haplotype in a region of low recombination e. higher frequency and higher linkage disequilibrum that other alleles at the same locus Solution c. a common haplotype in a region of high recombination is consistent with positive selection Genetic drift is usually one of the reasons of linkage disequilibrium, so linkage disequilibrium could be thought to be asociated with Genetic drift. If a common haplotype is ina region on of high recombination, there are greater chances of being it to transmitted to the next generations and thus positively selected..

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What are the reasons for joining management development programs? What are the benefits of these programs? Solution Management development programs (MDP): Management development programs are the training module which helps to enhance the organization performance through training programs. There are so many reasons for joining the management development programs are listed below: Benefits of the MDP:.

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Using C++ I keep getting message: \'head does not name a type\' \'teal does not name a type\' Where do I place this code in my program: /*search and delete with respect to location as current, head and tail //define below 2 lines in LinkedList() function head = new NodeType; tail = new NodeType; void UnsorderedType::DeleteItem(ItemType item) { NodeType *tempLocation, *location; bool stop = false; if(!isEmpty()) { location = head; tempLocation = head->link; while (templocation != tail && !stop) { if (templocation->info == item) stop = true; else { location = templocation; templocation = templocation->link; } } if (!stop) cout << \"The node to delete is not in the list!\" << endl; else { location->link = templocation->link; delete templocation; count--; } } else { cout << \"The list is empty!\" << endl; } }*/ /Problem and code: Implement the UnsortedList class to store a list of strings that are input into the list from data2.txt. - create a main.cpp file that gets the numbers from the file - insert the word \"cat\" into the list - insert another word \"antibacterial\" into the list - delete the word \"letter\" from the list - print out the following: --the entire list - the greatest - the least 2. Attach the main.cpp, UnsortedList.cpp, the ItemType.h, and the output file one called outfile1.txt - Yes you need to make your program output an \"outfile1.txt\" 3. Implement the UnsortedList class to store a list of numbers that are input into the list from data.txt. - create a main.cpp file that gets the numbers from the file - insert the number 7 into the list - insert another number 300 into the list - delete the number 6 from the list - print out the following: --the entire list - the greatest - the least 2. Attach the main.cpp, UnsortedList.cpp, the ItemType.h, and the output file two called outfile2.txt - Yes you need to make your program output an \"outfile2.txt\" data.txt super formula travel free thick Josephine Clara education data2.txt super formula travel free thick Josephine Clara education //My main.cpp //-------------------------------------------------------------- // Test driver for Linked List UnsortedType list // Navarr Barnier // Your class CS3350 TTh 1:00 // Due date: Thursday, September 13, 2012 // // Compile command: g++ hw2.cpp ch03-UnsortedType.cpp ch03-ItemType.cpp // Input file name: hw2.txt // Contains list of commands to add items to list, split original // list into two lists, print each list and get the length of // each list. // Output: The result of each command is displayed on the screen. // Filename: hw2.cpp //-------------------------------------------------------------- #include #include #include #include #include #include \"ItemType.h\" using namespace std; void PrintList(UnsortedType&); void SplitList(UnsortedType&, ItemType); ItemType GetItem(ItemType& item, bool& found); int main() { ifstream inFile; // file containing operations ofstream outFS; // Output file stream string data; // operation to be executed s.

Using C++I keep getting messagehead does not name a type.pdf

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true or false A primary sources tend to be firsthand observations of an event. B an example of a primary source would be a book review. Solution A> primary sources tend to be firsthand observations of an event. TRUE Explanation: A primary source provides direct or firsthand evidence about an event, object, person, or work of art. B> an example of a primary source would be a book review. FALSE Explanation: Book review is the secondary sources which describe, analyze, summarize, evaluate, discuss, interpret, comment upon and process primary sources..

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There are n couples invited to a banquet. Suppose there are some number of speeches given during the banquet, so that at most one member of each couple gives a talk. How many different sets of speakers could the evening have? Solution n couple would mean we have n men and n women. Lets assume that this fact holds( universal fact) Now, at most 1 member of each couple gives a talk. This would mean that we will have at most 1 from each couple giving a sppech during banquet. We can have no people talking , 1 person talking from the whole n couple group, 2 people,................ or each of n couples pair giving a speech = Hence, the difference sets one can have : nC0 +nC1 +nC2 + ....... n Cn = 2^n Please note that if we neccesarily got to have speech then the first term( nC0 = 1) will yeild to 0 and therefore come to the RHS. Hence, nC1 +nC2 + ....... n Cn = 2^n -1 Therefore, 2^n ways when atmost 1 from each couple pair, or 2^n -1 when we need atleast 1 speech from the group, will leave it to you to decide on this one..

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The Northwest Ordinance inclmsted all of the following EXCEPT: a. Nominal prohibition of slavery. b. Guarantee of freedom of religion for settlers. c. The process by which western territories could become states. d. Land reserved for Indians. Hide Feedback Solution Option d. The Northwest Ordinance provided a method for admitting new states to the Union and spelled out a plan which would result in the taking of lands from hundreds of Indian tribes..

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the initiation phase of eukaryotic transcription via RNA polymerase ll is considered an assembly and disassembly C24. The initiation phase of eukaryotic transcription via RNA polymerase II is considered an assembly and disassembly process. Which types of biochemical interactions- hydrogen bonding, ionic bonding, covalent bonding, and/or hydrophobic interactions would you expect to drive the assembly and disassembly process? How would temperature and salt concentration affect assembly and disassembly? Solution During the assembly and disassembly the Hydrogen bond between the DNA strand and the RNA polymerase II is predominantly involved. The ionic and hydrophobic interactions may occur depending on the sequence and the supercoiling of the template DNA. Since assembly and disassembly are dynamic process, the stronger covalent bonds are not involved, which are difficult to break. The hydrogen bonds are broken down easily in high temperature and high salt concentrations. Hence these conditions would inhibit the process of RNApol assembly and disassembly..

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Suppose you were asked to recommend changes to the UN Security Council (especially in permanent membership and veto power). What changes would you recommend, if any? What is your logic for this recommendation? Please give THREE distinct, concise and logical reasons for your recommendation. Your recommendation should be “Yes, I recommend changes” or “No, I do not recommend changes” and then provide your three reasons. (Note: It is very important that you keep in mind what you have learned thus far this semester: the very nature of the international system and nation-states themselves, distribution of power and capabilities, and the existence of relevant norms and institutions. These notions will be important as you evaluate the question and craft an acceptable response.) Solution Yes I recommend changes due to following reasons 1 in security council is not representative of all people of world. It represents only some countries without any rational justification. E. G India which has worlds 2nd largest population is neglected 2 world conditions have changed since then. Now Un bodies like security council do not represent nations as per their importance E G Germany which is an economic power has been neglected 3 security council etc has served interests of only few countries. These countries are often against one another. Hence no meaningful resolution is formed. Large number of members will reduce influence of one or two members and make decision making much better.

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