The decay rate of a certain chemical is 9 4 per year. What is its ha.pdf

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The decay rate of a certain chemical is 9 4% per year. What is its half-life? Use the exponential decay model P(t) = P_0e^-kt where kt is the decay rate, and P_o is the original amount of chemical. The half-life of the chemical is years. (Round to the nearest integer) Solution k = 9.4% = 0.094 P(t) = Poe^(-kt) 0.5Po = Poe^(-0.094t) 0.5 = e^(-0.094t) take natural log on both sides: ln0.5 = -0.094t t = 7.37 = 7 years is the half life.

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When a planetary nebula forms around a star you see gas emitting light and a white dwarf present at the center. Below is a detailed image of M 57, the Ring Nebula. In this image it looks very much like a flower, with different layers of gas clearly seen. What does this image tell us about the conditions inside the star that created the nebula? The layers are the various shells of gas from inside the star. Before the star exploded, there were shells burning around the core. When it exploded, it reveals these layers in the expansion of the gas. Each layer of gas was previously a shell inside the star. Measurements of the Doppler velocity for the gas shows that it is expanding outward from the white dwarf. This means that the outer most gas layer must have been accelerated more rapidly than the inner layers, when the star exploded. The outer most layer is made of hydrogen, which is the lightest element and would be accelerated the most. As you move inward the layers are made of helium, carbon, oxygen, etc. Moving inward, each layer is composed of a heavier element which isn\'t accelerated as much due to its larger mass. So the nebula formed from a single explosion. Measurements of the Doppler velocity for the inner most layer of gas shows that it is expanding outward. This is the outer layer of the star which is moving outward when the star exploded. The other layers farther out are gas from the molecular cloud that is colliding with the expanding gas of the planetary nebula. The molecular cloud gas is surrounding the planetary nebula, because a low mass star doesn\'t live long enough to move very far from where it is formed. The planetary nebula is compressing the molecular cloud, setting off star formation. Measurements of the Doppler velocity for the gas snows that it is expanding outward from the white dwarf. This means that the outer most gas was ejected from the star first since it is the farthest from the white dwarf. Layers that are in closer must have been ejected at a later time. This suggests that the planetary nebula formed from multiple eruptions inside the star and not one single explosion. Solution a) First of all, one should know how a planetary nebula is formed. When an aging star is unable to sustain further fusion reaction to keep its core stable it has many ways to give away - either turn into a supernova, become a black hole or neutron star, or shed its outer envelopes and then the core turns into a white dwarf. this later stage is known as planetary nebulae. The M 57, commonly goes by the name of Ring Nebula, has a bipolar morphology where the core primarily contains carbon and oxygen and other lighter elements. The strong concentration of matter around the equator makes it look like a prolate spheroid. Option d..

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Which of the following is consistent with a history of positibe selection but not genetic drift a. common haplotype exhibiting weak linkage disequilibrium b a rare haplotype showing strong linkage disequilibrium c. a common haplotype in a region of high recombination d. a rare haplotype in a region of low recombination e. higher frequency and higher linkage disequilibrum that other alleles at the same locus Solution c. a common haplotype in a region of high recombination is consistent with positive selection Genetic drift is usually one of the reasons of linkage disequilibrium, so linkage disequilibrium could be thought to be asociated with Genetic drift. If a common haplotype is ina region on of high recombination, there are greater chances of being it to transmitted to the next generations and thus positively selected..

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What are the reasons for joining management development programs? What are the benefits of these programs? Solution Management development programs (MDP): Management development programs are the training module which helps to enhance the organization performance through training programs. There are so many reasons for joining the management development programs are listed below: Benefits of the MDP:.

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Using C++ I keep getting message: \'head does not name a type\' \'teal does not name a type\' Where do I place this code in my program: /*search and delete with respect to location as current, head and tail //define below 2 lines in LinkedList() function head = new NodeType; tail = new NodeType; void UnsorderedType::DeleteItem(ItemType item) { NodeType *tempLocation, *location; bool stop = false; if(!isEmpty()) { location = head; tempLocation = head->link; while (templocation != tail && !stop) { if (templocation->info == item) stop = true; else { location = templocation; templocation = templocation->link; } } if (!stop) cout << \"The node to delete is not in the list!\" << endl; else { location->link = templocation->link; delete templocation; count--; } } else { cout << \"The list is empty!\" << endl; } }*/ /Problem and code: Implement the UnsortedList class to store a list of strings that are input into the list from data2.txt. - create a main.cpp file that gets the numbers from the file - insert the word \"cat\" into the list - insert another word \"antibacterial\" into the list - delete the word \"letter\" from the list - print out the following: --the entire list - the greatest - the least 2. Attach the main.cpp, UnsortedList.cpp, the ItemType.h, and the output file one called outfile1.txt - Yes you need to make your program output an \"outfile1.txt\" 3. Implement the UnsortedList class to store a list of numbers that are input into the list from data.txt. - create a main.cpp file that gets the numbers from the file - insert the number 7 into the list - insert another number 300 into the list - delete the number 6 from the list - print out the following: --the entire list - the greatest - the least 2. Attach the main.cpp, UnsortedList.cpp, the ItemType.h, and the output file two called outfile2.txt - Yes you need to make your program output an \"outfile2.txt\" data.txt super formula travel free thick Josephine Clara education data2.txt super formula travel free thick Josephine Clara education //My main.cpp //-------------------------------------------------------------- // Test driver for Linked List UnsortedType list // Navarr Barnier // Your class CS3350 TTh 1:00 // Due date: Thursday, September 13, 2012 // // Compile command: g++ hw2.cpp ch03-UnsortedType.cpp ch03-ItemType.cpp // Input file name: hw2.txt // Contains list of commands to add items to list, split original // list into two lists, print each list and get the length of // each list. // Output: The result of each command is displayed on the screen. // Filename: hw2.cpp //-------------------------------------------------------------- #include #include #include #include #include #include \"ItemType.h\" using namespace std; void PrintList(UnsortedType&); void SplitList(UnsortedType&, ItemType); ItemType GetItem(ItemType& item, bool& found); int main() { ifstream inFile; // file containing operations ofstream outFS; // Output file stream string data; // operation to be executed s.

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true or false A primary sources tend to be firsthand observations of an event. B an example of a primary source would be a book review. Solution A> primary sources tend to be firsthand observations of an event. TRUE Explanation: A primary source provides direct or firsthand evidence about an event, object, person, or work of art. B> an example of a primary source would be a book review. FALSE Explanation: Book review is the secondary sources which describe, analyze, summarize, evaluate, discuss, interpret, comment upon and process primary sources..

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