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05. operational amplifier
- 1. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan DASAR RANGKAIAN LISTRIK Ali Sadiyoko, S.T., M.T. Faisal Wahab, S.Pd., M.T. FAKULTAS TEKNOLOGI INDUSTRI PROGRAM STUDI TEKNIK ELEKTRO KONSENTRASI MEKATRONIKA 2016
- 2. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Topik 5 Operational Amplifier β’ Gelombang Sinusoidal β’ Pengantar β’ Ideal Op-Amp β’ Inverter Op-Amp β’ Non-Inverter Op-Amp β’ Summing Op-Amp β’ Diferensial Op-Amp β’ Cascade Op-Amp
- 3. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Gelombang Sinusoidal Dimana : A = Amplituda π = 2ππ = πππππ’πππ π π π’ππ’π‘ π = 1 π = πππππ’πππ π π‘ = π ππ‘π’ππ πππ‘ππ T A π π π‘2ππ 2 3π 2 ) 2 (sin t T Ay ο° ο½ )(sin tAy ο·ο½ )2(sin tfAy ο°ο½ A
- 4. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Gambarkan Sinyal sinusoidal y= 2 sin (6280t) Jawab : Amplitudo A = 2 perioda π = 2π π π = 2π π = 2π₯3,14 6280 = 0.001 π frekuensi π = 2ππ π = π 2π = 6280 2π₯3.14 = 1000 π»π§/1ππ»π§
- 5. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Gain (A) ππ π π ππ + β Op-Amp π½π = π¨π½ π Tegangan output ππ adalah penguatan dari Tegangan sumber ππ Amplifier LoadSource
- 6. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan + - π£π π π π ππ π΄ π£ ππ π ππ’π‘ + β π£ππ π£ππ = π ππ π π + π ππ π£π π£π = π π π ππ’π‘ + π π π΄ π£ ππ + β π£π πππ = π π Idealnya ππ = π¨ π ππ ππ = π¨ π π π π π ππ= β (open loop) π ππ’π‘ = 0 (close loop)
- 7. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan + - π ππ π΄ π£ ππ π ππ’π‘ + β π£ππ π£ π π£ π Karakteristik Ideal Op-Amp 1. π ππ= β, (open circuit) 2. π π = 0, (short circuit) 3. π΄ = β, π£ π = π£ π π π = π π = 0 π π π π Circuit Model π£ππ = π£ π β π£ π Dengan gain π΄ = β, sedangkan π£ππ dibatasi 24 V, Maka, π£ ππ π΄ = 0 Pada Op-Amp ideal π ππ= β sehingga arus yang masuk π£ π dan π£ π dianggap nol π£ π
- 8. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan + - π£π π π π π + β π£ ππ£ π π£ π Inverting Amplifier Circuit Model π£π π π π π + β π£ π π£ π π£ π Tentukan close loop voltage gain π΄ = ππ ππ ! π΄ π£ ππ + β π£ππ π ππ π ππ’π‘
- 9. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan + - Terminal non-inversi dihubungkan ke ground, sehingga π£ π = 0 maka π£ π = π£ π = 0 dan π£π π π π π + β π£ π π£ π π£ π π£π β π£ π π π β π£ π β π£ π π π β π π = 0 π£π β π£ π π π = π£ π β π£ π π π π£π π π β π£ π π π = π£ π π π β π£ π π π π£π π π = π£ π(π π + π π) β π£ π π π karena π£ π = 0 π£π π π = β π£ π π π π£ π π£π = β π π π π π΄ = π£ π π£π = β π π π π Tentukan close loop voltage gain π΄ = π£ π π£ π ! Inverting Amplifier KCL di node π£ π: π1 β π2 β π π = 0 π π = π π = 0 π π π π π΄ π£ ππ + β π1 + β π2
- 10. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan π£π = 0.5 10β¦ + β π£ ππ£ π π£ π Contoh Inverting Amplifier 25β¦ 1. Tentukan π£ π 2. Tentukan arus i π£ π = β π π π π π£π π£ π = β 25 10 0.5 π£ π = β1.25 + β π π = π£π β π£ π π π π = 0.5 β 0 10 π = 0.05 π΄
- 11. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan π£π π π π π + β π£ π π£ π π£ π Tentukan close loop voltage gain π΄ = π£ π π£ π ! 0 β π£ π π π β π£ π β π£ π π π β π π = 0 β π£ π π π = π£ π β π£ π π π βπ£π π π = π£π π π β π£ π π π π£ π π£π = π π + π π π π π£π (π π + π π ) = π£ π π π Non-Inverting Amplifier Terminal non-inversi dihubungkan ke sumber, sehingga π£ π = π£π maka π£ π = π£ π = π£π Op-amp ideal π π = π π = 0 β π£π π π = π£π β π£ π π π dan π£ π = π£ π = π£π π π π1 π2
- 12. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Tentukan close loop voltage gain π΄ = π£ π π£ π ! 0 β π£ π π π β π£ π β π£ π π π β π π = 0 β π£ π π π = π£ π β π£ π π π βπ£π π π = π£π π π β π£ π π π π£ π π£π = π π + π π π π π£π (π π + π π ) = π£ π π π Non-Inverting Amplifier Terminal non-inversi dihubungkan ke sumber, sehingga π£ π = π£π maka π£ π = π£ π = π£π Op-amp ideal π π = π π = 0 β π£π π π = π£π β π£ π π π dan π£ π = π£ π = π£π π π π π π£ π π£ π + β π£ π
- 13. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Contoh non-Inverting Amplifier 6π 4β¦ 10β¦ + β π£ ππ£ π π£ π 4π 6 β π£ π π π β π£ π β π£ π π π β π π = 0 Karena π£ π = π£ π = π£π dan π π = π π = 0 6 β 4 4 β 4 β π£ π 10 β 0 = 0 6 β 4 4 = 4 β π£ π 10 2 4 = 4 β π£ π 10 5 = 4 β π£ π π£ π = β1 1. Tentukan π£ π KCL di node π£ π
- 14. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan π£π + β π£ π π£ π π£ π Buffer Amplifier Terminal non-inversi (π£ π) dihubungkan ke sumber, sehingga π π= π π maka π π = π π = π π Dan terminal π£ π terhubung langsung dengan π£π π£ π = π£π Sehingga π π = π π = π π = π π Jadi gain loop tertutupnya adalah 1.
- 15. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Summing Amplifier π£1 π 1 π π + β π£ ππ£ π π£ ππ£2 π£3 π 2 π 3 π1 + π2 + π3 β π = 0 π1 π2 π3 π π£1 β π£ π π 1 + π£2 β π£ π π 2 + π£3 β π£ π π 3 = π£ π β π£ π π π π£1 π 1 + π£2 π 2 + π£3 π 3 = βπ£ π π π β π π π 1 π£1 + π π π 2 π£2 + π π π 3 π£3 = π£ π Terminal non-inversi dihubungkan ke ground, sehingga π£ π = 0 maka π£ π = π£ π = 0 KCL di node π£ π
- 16. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan 2 π 5β¦ 10 β¦ + β π£ π π£ π π£ π 1 π 2.5β¦ π1 π2 Contoh Summing Amplifier 2 β¦ β 10 5 2 + 10 2,5 1 = π£ π β 4 + 4 = π£ π 1. Tentukan π£ π 2. Tentukan π π β8 = π£ π π π = π£ π β 0 10 + π£ π β 0 2 π π = β 8 10 β 8 2 π π = β0.8 β 4 π π = β4.8 π΄ 1. Mentukan π£ π 1. Mentukan π π π0
- 17. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Difference Amplifier π1 π 1 π 4 + β ππππ ππ π2 π 2 π 3 π1 π2
- 18. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan ππ = π 2 + π 1 π 1 ππ β π 2 π 1 π1 karena ππ = ππ ππ = π 2 + π 1 π 1 π 4 π 3 + π 4 π2 β π 2 π 1 π1 ππ = π 4 π 3 + π 4 π2 π2 β ππ π 3 = ππ π 4 π2 π 4 β ππ π 4 = ππ π 3 π2 π 4 = ππ π 3 + ππ π 4 π2 π 4 = ππ(π 3 + π 4) ππ = π 4 π 3 + π 4 π2 KCL di node π£ π π1 β ππ π 1 = ππ β ππ π 2 π1 π 2 β ππ π 2 = ππ π 1 β ππ π 1 ππ π 1 = ππ π 2 + π 1 β π1 π 2 ππ = π 2 + π 1 π 1 ππ β π 2 π 1 π1 KCL di node π£ π
- 19. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan Cascaded Op Amp Circuits ππ π π π π + β ππ ππ ππ ππ ππ π π π π ππ π π π π + β ππ ππ ππ ππ ππ π π π π Inverting Amplifier Non-Inverting Amplifier
- 20. Program Studi Teknik Elektro Konsentrasi Mekatronika Universitas Katolik Parahyangan 20mV 3 12 + β ππ ππ ππ ππ ππ 4 10 Op-amp pertama Op-amp kedua π£ π = 12 + 3 3 20 π£ π = 100ππ π£ π = 10 + 4 4 100 π£ π = 350ππ