1. Welcome to
Classes
BYJU’S
Alternating Current
What you already know
What you will learn
S8: Resonance
1 . Pure AC circuits
2 . RC and L R AC circuits
3 . Impedance
4. Powe r in AC circuits
5 . Se rie s L CR circuits
1 . Condition for re sonance
2 . Graphical representation
3 . Num e ricals on re sonance
2. Apparent power
Total power flowing in a circuit is known as apparent power.
𝑆 = E𝑟𝑚𝑠 𝑖𝑟𝑚𝑠
Reactive power is product of voltage and current off phase by
𝜋
2
with the voltage
𝑄 = E𝑟𝑚𝑠 𝑖𝑟𝑚𝑠 sin 𝜙
Reactive power Current out
of phase
Current in
phase
E
𝐼
𝐼 sin 𝜙
𝜙
𝐼 cos 𝜙
𝑃 = E𝑟𝑚𝑠 𝑖𝑟𝑚𝑠 cos 𝜙
Active power is product of voltage and current in phase with the voltage.
Active power
3. Power factor
The ratio of Active power to Apparent power is the power factor.
𝑃
𝑆
= cos 𝜙
Relationship between apparent, reactive and active power
E
𝑆
𝑄 = E𝐼 sin 𝜙
𝜙
𝑃 = E𝐼 cos 𝜙
E
𝐼
𝐼 sin 𝜙
𝜙
𝐼 cos 𝜙
Where,
𝑆 = Apparent power
𝑄 = Reactive power
𝑃 = Active power 𝑆 = 𝑃2 + 𝑄2
7. In series LCR circuit, resistance 𝑅 = 10 Ω and impedance 𝑍 = 20 Ω. The phase
difference between the current and the voltage is:
a b c
30° 45° 60° 90°
d
8. 𝜙
𝑅
|𝑋𝐿 − 𝑋𝐶 |
𝑅 = 10 Ω
𝐶
𝐿
𝐴
cos 𝜙 =
𝑅
𝑍
=
10
20
=
1
2
𝑍 = 20 Ω
𝜙 = cos−1 0.5 = 60°
c
a b
30° 45° 60° 90°
d
9. In a circuit, 𝐿, 𝐶 and 𝑅 are connected in series with an alternating voltage source
of frequency 𝑓. The current leads the voltage by 45°
. The value of 𝐶 is
a b c
1
2ߨ݂(2ߨ݂ܮ+ܴ)
1
2𝜋𝑓(2𝜋𝑓𝐿 − 𝑅)
1
𝜋𝑓(2𝜋𝑓𝐿 − 𝑅)
1
𝜋𝑓 2𝜋𝑓𝐿 + 𝑅
d
10. tan 𝜙 =
𝑋𝐶 − 𝑋𝐿
𝑅
(∵ Current leads the source voltage)
tan 45∘ =
1
2𝜋𝑓𝐶
− 2𝜋𝑓𝐿
𝑅
𝑅 =
1
2𝜋𝑓𝐶
− 2𝜋𝑓𝐿 ⇒ 2𝜋𝑓𝐶 =
1
2𝜋𝑓𝐿 + 𝑅
∴ 𝐶 =
1
2𝜋𝑓 2𝜋𝑓𝐿 + 𝑅
𝑅
𝑓 𝐻𝑧
𝐶
𝐿
b c d
a
1
2ߨ݂(2ߨ݂ܮ+ܴ)
1
2𝜋𝑓(2𝜋𝑓𝐿 − 𝑅)
1
𝜋𝑓(2𝜋𝑓𝐿 − 𝑅)
1
𝜋𝑓 2𝜋𝑓𝐿 + 𝑅
11. CASE 2
If 𝑋𝐶 < 𝑋𝐿 , 𝜙 ≠ 0
Circuit is predominantly
inductive
Current lags the source
voltage
CASE 1
If 𝑋𝐶 > 𝑋𝐿 , 𝜙 ≠ 0
Circuit is predominantly
capacitive
Current leads the source
voltage
CASE 3
if 𝑋𝐶 = 𝑋𝐿 , 𝜙 = 0
𝒕𝒂𝒏 𝝓 =
𝑿𝑳 − 𝑿𝑪
𝑹
𝜙
𝑅
|𝑋𝐿 − 𝑋𝐶 |
12. 𝑅
𝐶
𝐿
𝑖𝑚 =
𝑉𝑚
𝑅2 + 𝑋𝐶 − 𝑋𝐿
2
𝑋𝐶 =
1
𝜔𝐶
𝑋𝐿 = 𝜔𝐿
If 𝜔 is varied, then at a particular frequency (𝜔0), 𝑋𝐶 = 𝑋𝐿
𝑉 = 𝑉𝑚 sin(𝜔𝑡)
13. 𝑖𝑚 =
𝑉𝑚
𝑅2 + 𝑋𝐶 − 𝑋𝐿
2
𝑋𝐶 =
1
𝜔𝐶
𝑋𝐿 = 𝜔𝐿
𝜔0 is resonant angular frequency
Impedance is minimum (𝑍 = 𝑅2 + 02 = 𝑅)
and purely resistive circuit
Current is maximum (𝑖𝑚 = 𝑉𝑚 /𝑅)
If 𝜔 is varied, then at a particular frequency (𝜔0), 𝑋𝐶 = 𝑋𝐿
18. What is the value of inductance 𝐿 for which the current is maximum in a series LCR
circuit with 𝐶 = 10 𝜇𝐹 and 𝜔 = 1000 𝑠−1?
a b c
1 𝑚𝐻 10 𝑚𝐻 100 𝑚𝐻 Cannot be calculated
unless 𝑅 is known
d
19. 𝑋𝐿 = 𝑋𝐶 ⇒ 𝜔𝐿 =
1
𝜔𝐶
𝐿 =
1
𝜔2𝐶
=
1
1000 2 × 10 × 10−6
𝐿 =
1
10
= 0.1 𝐻 = 100 𝑚𝐻
For maximum current in series 𝐿𝐶𝑅 circuit,
a b d
c
1 𝑚𝐻 10 𝑚𝐻 100 𝑚𝐻 Cannot be calculated
unless 𝑅 is known
20. a b c
𝜋 𝑍𝑒𝑟𝑜 𝜋/4 𝜋/2
d
A LCR circuit is connected to a source of alternating current. At resonance, find
the phase difference between the applied voltage and the current in the circuit.
21. 𝐼
𝑉𝑅
𝜔𝑡 + 𝜙
𝑉𝐿
𝑉𝐶
In resonance condition,
𝑉𝐿 = 𝑉𝐶
∴ Phase difference between applied voltage
and current = 0
a c d
b
𝜋 𝑍𝑒𝑟𝑜 𝜋/4 𝜋/2
22. A transistor-oscillator using a resonant circuit with an inductor 𝐿 (of negligible
resistance) and a capacitor 𝐶 in series produce oscillation of frequency 𝑓. If 𝐿 is
doubled and 𝐶 is changed to 4𝐶, the frequency will be
a b c
𝑓/2 2 𝑓/2 𝑓/4 8𝑓
d