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Monohybrid and Dihybrid
Cross
Prof Anju
Chaudhary
B.Ed , M.sc , Phd
Monohybrid cross
Monohybrid Cross
 a method of determining the inheritance pattern
of a trait between two single organisms.
 a cross between parents who are true-breeding
for a trait; i.e., both are homozygous for one allele
of the
gene, for example AA x aa, in
which A is the dominant allele
for a trait and a is the recessive
allele for that same trait.
Sample Problem
 In pea plants, spherical seeds (S) are
dominant to dented seeds (s). In a
genetic cross of two plants that are
heterozygous for the seed shape trait,
what fraction of the offspring should
have spherical seeds?
Analysis
 The figure above represents a monohybrid
cross of F1-hybrid plants.
 Both parent plants are heterozygous (Ss) for
an allele that determines seed shape.
 Presence of the dominant allele (S) in
homozygous (SS) or heterozygous (Ss) plants
results in spherical seeds.
 Homozygous recessive (ss) plants have
dented seeds.
Analysis
 To solve the sample problem, you'll
need to set up a Punnett square.
 Punnett square - a diagram that is used
to predict an outcome of a particular
cross or breeding experiment
Steps to Solve the Sample
Problem
 Set up a 2 by 2
Punnett square.
Steps to Solve the Sample
Problem
 Write the alleles for
parent 1 on the left
side of the Punnett
square.
 Each gamete will have
one of the two alleles of
the parent. In this
particular cross, half of
the gametes will have
the dominant (S) allele,
and half will have the
recessive (s) allele. We
will use blue and brown
to keep track of the
alleles of each parent.
S
s
Steps to Solve the Sample
Problem
 Write the alleles
from parent 2 above
the Punnett square.
 For this heterozygous
parent (Ss), half of the
gametes will have the
dominant (S) allele, and
half will have the
recessive (s) allele.
S
S
s
s
Steps to Solve the Sample
Problem
 Fill the squares for
parent 1.
 Fill each square with
the allele from Parent
1 that lines up with
the row.
 Fill the squares for
parent 2.
 Fill each square with
the allele from Parent
2 that lines up with
the column.
S
S
s
s
S S
s sS
S
s
s
Steps to Solve the Sample
Problem
 Interpreting the
results of a Punnett
square
 Genotypes that
resulted from this
monohybrid cross
(Ss x Ss)
 25% homozygous
dominant
 50% heterozygous
 25%
homozygous
recessive
S
S
s
s
S S
s sS
S
s
s
Steps to Solve the Sample
Problem
 Interpreting the
results of a Punnett
square
 Phenotypes that
resulted from this
monohybrid cross
(Ss x Ss)
 75% Spherical
 25% Dented
S
S
s
s
S S
s sS
S
s
s
Dihybrid cross
Dihybrid Cross
 a cross between F1 offspring (first generation
offspring) of two individuals that differ in two traits
of particular interest.
 used to test for dominant and recessive genes in
two separate characteristics
 The rules of meiosis, as they apply to the
dihybrid, are codified in Mendel's First Law and
Mendel's Second Law, which are also called the
Law of Segregation and the Law of Independent
Assortment, respectively
Example Problem
 In summer squash, white fruit color (W) is
dominant over yellow fruit color (w) and disk-
shaped fruit (D) is dominant over sphere-
shaped fruit (d).. If a squash plant true-
breeding for white, disk-shaped fruit is
crossed with a plant true-breeding for yellow,
sphere-shaped fruit, what will the phenotypic
and genotypic ratios be for:
 a. the F1 generation?
 b. the F2 generation?
Steps to Solve the Sample
Problem
 Write down the cross in terms of the
parental (P1) genotypes and
phenotypes:
WWDD (white, disk-shaped
fruit) X wwdd (yellow, sphere-
shaped fruit)
Steps to Solve the Sample
Problem
 Determine the P1 gametes, place
them in a Punnett Square and fill in
the resulting genotypes:
Steps to Solve the Sample
Problem
 Determine the genotypic and
phenotypic ratios for the F1
generation:
All F1 progeny will be
heterozygous for both characters
(WwDd) and will have white, disk-
shaped fruit .
Steps to Solve the Sample
Problem
Write down the cross between
F1 progeny:
WwDd (white, disk-shaped
fruit) X WwDd (white,
disk-shaped fruit)
Steps to Solve the Sample
Problem
 Determine the
F1 gametes,
place them in a
Punnett Square
and fill in the
resulting
genotypes:
Steps to Solve the Sample
Problem
 Determine the genotypic and phenotypic ratios
for the F2 generation:
 Genotypic ratios:
1/16 will be homozygous dominant for both traits
(WWDD)
2/16 will be homozygous dominant for color and
heterozygous for shape (WWDd)
2/16 will be heterozygous for color and homozygous
dominant for shape (WwDD)
1/16 will be homozygous dominant for color and
homozygous recessive for shape (WWdd)
4/16 will be heterozygous for both traits (WwDd)
Steps to Solve the Sample
Problem
2/16 will be heteozygous for color and
homozygous recessive for shape (Wwdd)
1/16 will be homozygous recessive for color
and homozygous dominant for shape
(wwDD)
2/16 will be homozygous recessive for color
and heterozygous for shape (wwDd)
1/16 will be homozygous recessive for both
traits (wwdd)
 This is a 1:2:2:1:4:2:1:2:1 genotypic ratio
Steps to Solve the Sample
Problem
 Determine the genotypic and phenotypic
ratios for the F2 generation:
Phenotypic ratios:
9/16 will have white, disk-shaped fruit
3/16 will have white, sphere-shaped
fruit
3/16 will have yellow, disk-shaped fruit
1/16 will have yellow, sphere-shaped
fruit
This is a 9:3:3:1 phenotypic ratio.
Mono di hybrid cross (p.a.c 2015)

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Mono di hybrid cross (p.a.c 2015)

  • 1. Monohybrid and Dihybrid Cross Prof Anju Chaudhary B.Ed , M.sc , Phd
  • 3. Monohybrid Cross  a method of determining the inheritance pattern of a trait between two single organisms.  a cross between parents who are true-breeding for a trait; i.e., both are homozygous for one allele of the gene, for example AA x aa, in which A is the dominant allele for a trait and a is the recessive allele for that same trait.
  • 4. Sample Problem  In pea plants, spherical seeds (S) are dominant to dented seeds (s). In a genetic cross of two plants that are heterozygous for the seed shape trait, what fraction of the offspring should have spherical seeds?
  • 5. Analysis  The figure above represents a monohybrid cross of F1-hybrid plants.  Both parent plants are heterozygous (Ss) for an allele that determines seed shape.  Presence of the dominant allele (S) in homozygous (SS) or heterozygous (Ss) plants results in spherical seeds.  Homozygous recessive (ss) plants have dented seeds.
  • 6. Analysis  To solve the sample problem, you'll need to set up a Punnett square.  Punnett square - a diagram that is used to predict an outcome of a particular cross or breeding experiment
  • 7. Steps to Solve the Sample Problem  Set up a 2 by 2 Punnett square.
  • 8. Steps to Solve the Sample Problem  Write the alleles for parent 1 on the left side of the Punnett square.  Each gamete will have one of the two alleles of the parent. In this particular cross, half of the gametes will have the dominant (S) allele, and half will have the recessive (s) allele. We will use blue and brown to keep track of the alleles of each parent. S s
  • 9. Steps to Solve the Sample Problem  Write the alleles from parent 2 above the Punnett square.  For this heterozygous parent (Ss), half of the gametes will have the dominant (S) allele, and half will have the recessive (s) allele. S S s s
  • 10. Steps to Solve the Sample Problem  Fill the squares for parent 1.  Fill each square with the allele from Parent 1 that lines up with the row.  Fill the squares for parent 2.  Fill each square with the allele from Parent 2 that lines up with the column. S S s s S S s sS S s s
  • 11. Steps to Solve the Sample Problem  Interpreting the results of a Punnett square  Genotypes that resulted from this monohybrid cross (Ss x Ss)  25% homozygous dominant  50% heterozygous  25% homozygous recessive S S s s S S s sS S s s
  • 12. Steps to Solve the Sample Problem  Interpreting the results of a Punnett square  Phenotypes that resulted from this monohybrid cross (Ss x Ss)  75% Spherical  25% Dented S S s s S S s sS S s s
  • 14. Dihybrid Cross  a cross between F1 offspring (first generation offspring) of two individuals that differ in two traits of particular interest.  used to test for dominant and recessive genes in two separate characteristics  The rules of meiosis, as they apply to the dihybrid, are codified in Mendel's First Law and Mendel's Second Law, which are also called the Law of Segregation and the Law of Independent Assortment, respectively
  • 15. Example Problem  In summer squash, white fruit color (W) is dominant over yellow fruit color (w) and disk- shaped fruit (D) is dominant over sphere- shaped fruit (d).. If a squash plant true- breeding for white, disk-shaped fruit is crossed with a plant true-breeding for yellow, sphere-shaped fruit, what will the phenotypic and genotypic ratios be for:  a. the F1 generation?  b. the F2 generation?
  • 16. Steps to Solve the Sample Problem  Write down the cross in terms of the parental (P1) genotypes and phenotypes: WWDD (white, disk-shaped fruit) X wwdd (yellow, sphere- shaped fruit)
  • 17. Steps to Solve the Sample Problem  Determine the P1 gametes, place them in a Punnett Square and fill in the resulting genotypes:
  • 18. Steps to Solve the Sample Problem  Determine the genotypic and phenotypic ratios for the F1 generation: All F1 progeny will be heterozygous for both characters (WwDd) and will have white, disk- shaped fruit .
  • 19. Steps to Solve the Sample Problem Write down the cross between F1 progeny: WwDd (white, disk-shaped fruit) X WwDd (white, disk-shaped fruit)
  • 20. Steps to Solve the Sample Problem  Determine the F1 gametes, place them in a Punnett Square and fill in the resulting genotypes:
  • 21. Steps to Solve the Sample Problem  Determine the genotypic and phenotypic ratios for the F2 generation:  Genotypic ratios: 1/16 will be homozygous dominant for both traits (WWDD) 2/16 will be homozygous dominant for color and heterozygous for shape (WWDd) 2/16 will be heterozygous for color and homozygous dominant for shape (WwDD) 1/16 will be homozygous dominant for color and homozygous recessive for shape (WWdd) 4/16 will be heterozygous for both traits (WwDd)
  • 22. Steps to Solve the Sample Problem 2/16 will be heteozygous for color and homozygous recessive for shape (Wwdd) 1/16 will be homozygous recessive for color and homozygous dominant for shape (wwDD) 2/16 will be homozygous recessive for color and heterozygous for shape (wwDd) 1/16 will be homozygous recessive for both traits (wwdd)  This is a 1:2:2:1:4:2:1:2:1 genotypic ratio
  • 23. Steps to Solve the Sample Problem  Determine the genotypic and phenotypic ratios for the F2 generation: Phenotypic ratios: 9/16 will have white, disk-shaped fruit 3/16 will have white, sphere-shaped fruit 3/16 will have yellow, disk-shaped fruit 1/16 will have yellow, sphere-shaped fruit This is a 9:3:3:1 phenotypic ratio.