Balancing Equations
Yay, balancing equations! The law of conservation of matter tells us that during a chemical change no material is created or destroyed. This means that all of the atoms that appear on the reactant side of the equation must also appear on the products side. Now that we are using symbols the equations must be  balanced . Let us see what balancing involves. Consider the following equation: NaOH  +  Pb(NO3)2     Pb(OH)2  +  NaNO3 1 sodium  1 lead   1 lead 1 sodium 1 oxygen  2 nitrogen  2 oxygen 1 nitrogen 1 hydrogen  6 oxygen   2 hydrogen 3 oxygen
You must NEVER try to change a formula in order to balance an equation. 2NaOH  +  Pb(NO3)2    Pb(OH)2  + NaNO3 2 sodium  1 lead   1 lead   2 sodium 2 oxygen  2 nitrogen   2 oxygen   2nitrogen 2 hydrogen 6 oxygen   2 hydrogen  6 oxygen
Try to balance these equations Mg  +  HCl     MgCl 2   +  H 2 Mg  +  O 2      MgO SO 2   +  O 2      SO 3 KClO 3      KCl  +  O 2
All we need now is plenty of practice. NO  +  O 2      NO 2 Fe  +  HCl     FeCl 2   +  H 2 NaHCO 3      Na 2 CO 3   +  CO 2   +  H 2 O Al  +  O 2      Al 2 O 3 FeS  +  HCl     FeCl 2   +  H 2 S
More? C 2 H 6   +  O 2      CO 2   +  H 2 O Mg  +  CO 2      MgO  +  C Ca(OH) 2   +  CH 3 COOH     Ca(CH 3 COO) 2   + H 2 O KOH  +  H 2 SO 4      K 2 SO 4   +  H 2 O Pb(NO 3 ) 2   +  ZnCl 2      Zn(NO 3 ) 2   +  PbCl 2
And some more! AlCl 3   +  NaOH     Al(OH) 3   +  NaCl Ca  +  H 2 O     Ca(OH) 2   +  H 2 Ca(NO 3 ) 2   + (NH 4 ) 2 CO 3      CaCO 3   +  NH 4 NO 3 K 3 PO 4   +  Fe(NO 3 ) 2     Fe 3 (PO 4 ) 2   +  KNO 3
More challenging ones C 12 H 22 O 11   +  O 2      CO 2   +  H 2 O Mg(HCO 3 ) 2      MgO  +  CO 2   +  H 2 O MgCO 3   + H 3 PO 4      Mg 3 (PO 4 ) 2   +H 2 O  + CO 2 S  +  Fe 2 O 3      Fe  +  SO 2 Cu  +  HNO 3      Cu(NO 3 ) 2   +NO 2  +  H 2 O
MnO 2   +  HCl     MnCl 2   +  H 2 O  +  Cl 2 FeS  +  O 2      Fe 2 O 3   +  SO 2 CH 3 OH  +  O 2      H 2 O  +  CO 2 NH 3   +  O 2      N 2   +  H 2 O NO 2   +  H 2 O     HNO 3   +  NO

Balancing equations

  • 1.
  • 2.
    Yay, balancing equations!The law of conservation of matter tells us that during a chemical change no material is created or destroyed. This means that all of the atoms that appear on the reactant side of the equation must also appear on the products side. Now that we are using symbols the equations must be balanced . Let us see what balancing involves. Consider the following equation: NaOH + Pb(NO3)2  Pb(OH)2 + NaNO3 1 sodium 1 lead 1 lead 1 sodium 1 oxygen 2 nitrogen 2 oxygen 1 nitrogen 1 hydrogen 6 oxygen 2 hydrogen 3 oxygen
  • 3.
    You must NEVERtry to change a formula in order to balance an equation. 2NaOH + Pb(NO3)2  Pb(OH)2 + NaNO3 2 sodium 1 lead 1 lead 2 sodium 2 oxygen 2 nitrogen 2 oxygen 2nitrogen 2 hydrogen 6 oxygen 2 hydrogen 6 oxygen
  • 4.
    Try to balancethese equations Mg + HCl  MgCl 2 + H 2 Mg + O 2  MgO SO 2 + O 2  SO 3 KClO 3  KCl + O 2
  • 5.
    All we neednow is plenty of practice. NO + O 2  NO 2 Fe + HCl  FeCl 2 + H 2 NaHCO 3  Na 2 CO 3 + CO 2 + H 2 O Al + O 2  Al 2 O 3 FeS + HCl  FeCl 2 + H 2 S
  • 6.
    More? C 2H 6 + O 2  CO 2 + H 2 O Mg + CO 2  MgO + C Ca(OH) 2 + CH 3 COOH  Ca(CH 3 COO) 2 + H 2 O KOH + H 2 SO 4  K 2 SO 4 + H 2 O Pb(NO 3 ) 2 + ZnCl 2  Zn(NO 3 ) 2 + PbCl 2
  • 7.
    And some more!AlCl 3 + NaOH  Al(OH) 3 + NaCl Ca + H 2 O  Ca(OH) 2 + H 2 Ca(NO 3 ) 2 + (NH 4 ) 2 CO 3  CaCO 3 + NH 4 NO 3 K 3 PO 4 + Fe(NO 3 ) 2  Fe 3 (PO 4 ) 2 + KNO 3
  • 8.
    More challenging onesC 12 H 22 O 11 + O 2  CO 2 + H 2 O Mg(HCO 3 ) 2  MgO + CO 2 + H 2 O MgCO 3 + H 3 PO 4  Mg 3 (PO 4 ) 2 +H 2 O + CO 2 S + Fe 2 O 3  Fe + SO 2 Cu + HNO 3  Cu(NO 3 ) 2 +NO 2 + H 2 O
  • 9.
    MnO 2 + HCl  MnCl 2 + H 2 O + Cl 2 FeS + O 2  Fe 2 O 3 + SO 2 CH 3 OH + O 2  H 2 O + CO 2 NH 3 + O 2  N 2 + H 2 O NO 2 + H 2 O  HNO 3 + NO