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Diffusions in
Solids
Group 2
By: Belamide, Rannelle O.
Dela Cruz, Mary Adela L.
SOLID RECORDS
What is
Diffusion in
Solids?
• The process of molecules moving
from one area of a solid to
another due to differences in
concentration.
• It is a type of transport
phenomenon that is driven by a
concentration gradient and is
affected by temperature and
pressure.
• It is used to explain the
behavior of materials under
certain conditions, such as the
movement of heat, mass, and
electric charge.
SOLID RECORDS
Types of
Diffusions
• Three main types of diffusion in solids
• Self-diffusion - occurs for pure metals, but
all atoms exchanging positions are of the
same type
• Inter-diffusion/ Impurity Diffusion - The
process by which atoms of one metal diffuse
into another.
• Surface diffusion - the movement of atoms
or molecules along the surface of a solid due
to differences in concentration. It is driven
by an energy gradient and is affected by
temperature and pressure.
SOLID RECORDS
Diffusion
Mechanism
• For an atom to move, it must meet two
conditions:
• an empty adjacent site must be
available,
• the atom must have enough energy to
disrupt its neighboring atoms and
cause lattice distortion during
displacement.
SOLID RECORDS
Vacancy Diffusion- the process by which
atoms or molecules move within a material through
vacancies or empty spaces in its crystal lattice.
• occurs when atoms or molecules leave or enter
these vacancies through thermal motion or heat
energy.
• Interstitial Diffusion-refers to the
process wherein atoms or molecules move through
the spaces between the atoms or molecules of a
crystalline material
• occurs when atoms or molecules move into these
interstitial spaces.
Fick’s Law
How do we quantify the rate of
Diffusion?
• J = Flux =
𝑚𝑜𝑙𝑒𝑠 𝑚𝑎𝑠𝑠 𝑑𝑖𝑓𝑓𝑢𝑠𝑖𝑛𝑔
(𝑎𝑟𝑒𝑎)(𝑡𝑖𝑚𝑒(𝑡𝑖𝑚𝑒)
=
𝑚𝑜𝑙
𝑐𝑚2𝑠
𝑜𝑟
𝑘𝑔
𝑚2𝑠
• Measured empirically
• Make thin film (membrane) of known cross-sectional area
• Impose concentration gradien
• Measure how fast atoms or molecules diffuse through the membrane
Fick’s First Law / Steady State Diffusion
• Diffusion condition for which the flux is independent of time
• Flux proportional to concentration gradient =
𝑑𝑐
𝑑𝑥
• Fick’s First Law of Diffusion
J= -D
𝒅𝒄
𝒅𝒙
D = diffusion coefficient
Sample Problem
A glass beaker contains a solution of salt in water. The
concentration of salt in the beaker is 0.02 g/cm^3. The
beaker is left uncovered, and over time, salt diffuses into
the air above the solution. After 5 hours, the
concentration of salt in the air above the solution is
measured to be 0.001 g/cm^3. The diffusion coefficient
of salt in air is 0.1 cm^2/hour. Calculate the rate of mass
transfer (flux) of salt from the solution into the air using
Fick's First Law.
Answer
C1 = 0.02 g/cm^3 C2 = 0.001 g/cm^3
t = 5 hours
𝑑𝐶
𝑑𝑥
=
0.001𝑔/𝑐𝑚^3− 0.02𝑔/𝑐𝑚^3
5 ℎ𝑟
𝑑𝐶
𝑑𝑥
= −0.0038
𝑔
𝑐𝑚3∗ ℎ𝑟
J = −𝐷 ∗
𝑑𝐶
𝑑𝑥
J = -0.1
𝑐𝑚^2
ℎ𝑟
∗ (−0.0038
𝑔
𝑐𝑚3∗ ℎ𝑟
)
J = 0.00038
𝑔
𝑐𝑚2∗ ℎ𝑟
Fick’s Law
Fick’s Second
Law
• The concentration of diffusing species is a function of both time and position C = C(x,t)
• In this case Fick’s Second Law is used
• Fick’s Second Law of Diffusion
∂𝑪
∂𝒕
=
∂𝟐
𝑪
∂𝒙𝟐
• This is a partial differential equation and it has been assumed here that the diffusivity
is independent of composition
To Solve a PDE, we need boundary and initial
conditions
• Boundary conditions
At t=0, C=𝑪𝒐 for 0 ≤ x ≤ ∞ (initial conditions)
At t › 0, C= 𝑪𝒔 for x = 0 (constant surface conc.)
C = 𝑪𝒐 for x = ∞ (con. At infinity)
With increasing time
concentration increases
further into the Al bar
Semi-infinite solid diffusion: Cu diffusing into
aluminum bar
Pre-existing
conc., 𝐂𝐨 𝐨𝐟 𝐜𝐨𝐩𝐩𝐞𝐫
Solution to PDE for semi-infinite solid diffusion
As a result, the right side is constant and
also the term inside the error function
For Specific concentration, left side of equation
is constant
For a constant D and C, increasing depth
will require a longer time
Effective penetration depth, 𝑥𝑒𝑓𝑓 is where C is in
the middle
erf(): Gaussian error function and is normally
tabulated
Note that there are 3 columns of z-values. Make sure to match the correct value of z with the
appropriate value of erf(z)
Sample Problem
A thin sheet of paper with a thickness of 0.2 cm is
initially coated with a dye on one side. The
concentration of the dye on the coated side is 1.5
g/cm^3, and the concentration on the uncoated side is
0.2 g/cm^3. The diffusion coefficient of the dye in paper
is 0.01 cm^2/hour. After 3 hours, the concentration of
the dye at a distance of 0.1 cm from the coated side is
measured to be 0.8 g/cm^3. Calculate the rate of
change of concentration with respect to time (dc/dt) at
that location using Fick's Second Law.
Answer
C = 0.8 𝑔/𝑐𝑚^3 D = 0.01 cm^2/hour
C2 = 0.2 g/cm^3
𝑑𝑐
𝑑𝑥
= 6 g/(cm^3 * cm)
x = 0.1 cm
𝑑𝑐
𝑑𝑡
= 0.01 cm^2/hour * (6 g/(cm^3 * cm))
𝑑𝑐
𝑑𝑥
= (0.8 - 0.2) / 0.1
𝑑𝑐
𝑑𝑡
= 0.06 g/(cm^3 * hour)
𝑑𝑐
𝑑𝑥
= 6 g/(cm^3 * cm)
Ready For the Quiz!!
THANK YOU

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Diffusion in Solids.pptx

  • 2. Group 2 By: Belamide, Rannelle O. Dela Cruz, Mary Adela L.
  • 3. SOLID RECORDS What is Diffusion in Solids? • The process of molecules moving from one area of a solid to another due to differences in concentration. • It is a type of transport phenomenon that is driven by a concentration gradient and is affected by temperature and pressure. • It is used to explain the behavior of materials under certain conditions, such as the movement of heat, mass, and electric charge.
  • 4. SOLID RECORDS Types of Diffusions • Three main types of diffusion in solids • Self-diffusion - occurs for pure metals, but all atoms exchanging positions are of the same type • Inter-diffusion/ Impurity Diffusion - The process by which atoms of one metal diffuse into another. • Surface diffusion - the movement of atoms or molecules along the surface of a solid due to differences in concentration. It is driven by an energy gradient and is affected by temperature and pressure.
  • 5.
  • 6. SOLID RECORDS Diffusion Mechanism • For an atom to move, it must meet two conditions: • an empty adjacent site must be available, • the atom must have enough energy to disrupt its neighboring atoms and cause lattice distortion during displacement.
  • 7. SOLID RECORDS Vacancy Diffusion- the process by which atoms or molecules move within a material through vacancies or empty spaces in its crystal lattice. • occurs when atoms or molecules leave or enter these vacancies through thermal motion or heat energy. • Interstitial Diffusion-refers to the process wherein atoms or molecules move through the spaces between the atoms or molecules of a crystalline material • occurs when atoms or molecules move into these interstitial spaces.
  • 8.
  • 10. How do we quantify the rate of Diffusion? • J = Flux = 𝑚𝑜𝑙𝑒𝑠 𝑚𝑎𝑠𝑠 𝑑𝑖𝑓𝑓𝑢𝑠𝑖𝑛𝑔 (𝑎𝑟𝑒𝑎)(𝑡𝑖𝑚𝑒(𝑡𝑖𝑚𝑒) = 𝑚𝑜𝑙 𝑐𝑚2𝑠 𝑜𝑟 𝑘𝑔 𝑚2𝑠 • Measured empirically • Make thin film (membrane) of known cross-sectional area • Impose concentration gradien • Measure how fast atoms or molecules diffuse through the membrane
  • 11. Fick’s First Law / Steady State Diffusion • Diffusion condition for which the flux is independent of time • Flux proportional to concentration gradient = 𝑑𝑐 𝑑𝑥 • Fick’s First Law of Diffusion J= -D 𝒅𝒄 𝒅𝒙 D = diffusion coefficient
  • 13. A glass beaker contains a solution of salt in water. The concentration of salt in the beaker is 0.02 g/cm^3. The beaker is left uncovered, and over time, salt diffuses into the air above the solution. After 5 hours, the concentration of salt in the air above the solution is measured to be 0.001 g/cm^3. The diffusion coefficient of salt in air is 0.1 cm^2/hour. Calculate the rate of mass transfer (flux) of salt from the solution into the air using Fick's First Law.
  • 14. Answer C1 = 0.02 g/cm^3 C2 = 0.001 g/cm^3 t = 5 hours 𝑑𝐶 𝑑𝑥 = 0.001𝑔/𝑐𝑚^3− 0.02𝑔/𝑐𝑚^3 5 ℎ𝑟 𝑑𝐶 𝑑𝑥 = −0.0038 𝑔 𝑐𝑚3∗ ℎ𝑟 J = −𝐷 ∗ 𝑑𝐶 𝑑𝑥 J = -0.1 𝑐𝑚^2 ℎ𝑟 ∗ (−0.0038 𝑔 𝑐𝑚3∗ ℎ𝑟 ) J = 0.00038 𝑔 𝑐𝑚2∗ ℎ𝑟
  • 16. Fick’s Second Law • The concentration of diffusing species is a function of both time and position C = C(x,t) • In this case Fick’s Second Law is used • Fick’s Second Law of Diffusion ∂𝑪 ∂𝒕 = ∂𝟐 𝑪 ∂𝒙𝟐 • This is a partial differential equation and it has been assumed here that the diffusivity is independent of composition
  • 17. To Solve a PDE, we need boundary and initial conditions • Boundary conditions At t=0, C=𝑪𝒐 for 0 ≤ x ≤ ∞ (initial conditions) At t › 0, C= 𝑪𝒔 for x = 0 (constant surface conc.) C = 𝑪𝒐 for x = ∞ (con. At infinity)
  • 18. With increasing time concentration increases further into the Al bar Semi-infinite solid diffusion: Cu diffusing into aluminum bar Pre-existing conc., 𝐂𝐨 𝐨𝐟 𝐜𝐨𝐩𝐩𝐞𝐫
  • 19. Solution to PDE for semi-infinite solid diffusion
  • 20. As a result, the right side is constant and also the term inside the error function For Specific concentration, left side of equation is constant For a constant D and C, increasing depth will require a longer time
  • 21. Effective penetration depth, 𝑥𝑒𝑓𝑓 is where C is in the middle
  • 22. erf(): Gaussian error function and is normally tabulated Note that there are 3 columns of z-values. Make sure to match the correct value of z with the appropriate value of erf(z)
  • 24. A thin sheet of paper with a thickness of 0.2 cm is initially coated with a dye on one side. The concentration of the dye on the coated side is 1.5 g/cm^3, and the concentration on the uncoated side is 0.2 g/cm^3. The diffusion coefficient of the dye in paper is 0.01 cm^2/hour. After 3 hours, the concentration of the dye at a distance of 0.1 cm from the coated side is measured to be 0.8 g/cm^3. Calculate the rate of change of concentration with respect to time (dc/dt) at that location using Fick's Second Law.
  • 25. Answer C = 0.8 𝑔/𝑐𝑚^3 D = 0.01 cm^2/hour C2 = 0.2 g/cm^3 𝑑𝑐 𝑑𝑥 = 6 g/(cm^3 * cm) x = 0.1 cm 𝑑𝑐 𝑑𝑡 = 0.01 cm^2/hour * (6 g/(cm^3 * cm)) 𝑑𝑐 𝑑𝑥 = (0.8 - 0.2) / 0.1 𝑑𝑐 𝑑𝑡 = 0.06 g/(cm^3 * hour) 𝑑𝑐 𝑑𝑥 = 6 g/(cm^3 * cm)
  • 26. Ready For the Quiz!!

Editor's Notes

  1. This energy is in the form of vibrations, and at a specific temperature, a small fraction of atoms can move due to the magnitude of their vibrational energies.
  2. states that the rate of diffusion of a substance (J) is directly proportional to the concentration gradient (dc/dx) of that substance in the medium, and is also proportional to the diffusion coefficient (D) of the substance in that medium
  3. it describes how the concentration of a substance changes over time in a medium due to diffusion, taking into account the diffusion coefficient and the curvature of the concentration profile states that the rate of change of concentration with respect to time (∂C/∂t) is proportional to the curvature of the concentration profile (∂^2C/∂x^2), and the proportionality constant is given by the diffusion coefficient (D).
  4. it describes how the concentration of a substance changes over time in a medium due to diffusion, taking into account the diffusion coefficient and the curvature of the concentration profile states that the rate of change of concentration with respect to time (∂C/∂t) is proportional to the curvature of the concentration profile (∂^2C/∂x^2), and the proportionality constant is given by the diffusion coefficient (D).
  5. it describes how the concentration of a substance changes over time in a medium due to diffusion, taking into account the diffusion coefficient and the curvature of the concentration profile states that the rate of change of concentration with respect to time (∂C/∂t) is proportional to the curvature of the concentration profile (∂^2C/∂x^2), and the proportionality constant is given by the diffusion coefficient (D).
  6. it describes how the concentration of a substance changes over time in a medium due to diffusion, taking into account the diffusion coefficient and the curvature of the concentration profile states that the rate of change of concentration with respect to time (∂C/∂t) is proportional to the curvature of the concentration profile (∂^2C/∂x^2), and the proportionality constant is given by the diffusion coefficient (D).