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By: Gian Gabriel Ibo
Deck Cadet
 First you need the following information
 -Date
 -Time in UTC or GMT
 - Ships Posotion
 -Variation (can be found on charts and ECDIS)
 -Gyro course
 -Gyro Bearing
 -Magnetic Course
 Date: 22 July 1997
 Time: 15h 10m 20s (Philippine Local Time)
 Position: Latitude- 12° 00’N
 Longitude- 121° 30’ E
 Variation: 1.25’W
 Gyro Course: 270°
 Gyro Bearing: 286.1°
Magnetic Course: 265°
 1.) First is to get the GMT
 15h 10m 20s- Local Time (+8 time zone)
 08h 00m 00s(-)
 07h 10m 20s - GMT
 - Get the GHA by the use of the Nautical
Almanac
 - Get also the increments by the use of the
Nautical Amanac
You Have now your GHA and Increments
GHA= 283° 23.9’
INC= 2° 35.0’ + Always plus
GHA= 285° 58.9’
Long= 121° 58.9’E
LHA= 406° 88.9’ E
+1 -60
407° 28.9’
-360°
LHA= 47° 28.9’ W
E (+)
W (-)
-360 if LHA is over 360°
Get Declination
Dec= 20° 15.1’ N
0.1’ (-)
Dec= 20° 15.0’ N
d= 0.5 (bottom part
of the
declination
page)
Minus because Declination
Is Decreasing
Get the True Bearing
Tan Z=
Sin LHA
Tan Dec x Cos lat (+)(-) Cos LHA x sin Lat
(+) Different name
(-) Same name
Lat and Dec
tanZ=
Sin (47° 28.9)
Tan(20°15.0’)xcos(12°) – cos (47°28.9’)x sin(12°)
tanZ= (3.34) Z= tan-1(3.34)
Z= N 73.36 W
N
S
EW
-360 As is
+180 -180
360
Zn= 286.4°
LHA Declination
OR YOU CAN SOLVE IT BY USING
THE ABC METHOD
A= Tan Lat
Tan LHA
B= Tan Dec
Sin LHA
C= A(+,-)B
Change name of latitude
if LHA is not in range
between 90°-270°
Name of Declination
Z= Cx Cos lat= x
1/x= tan-1= Z
A= Tan 12°
Tan 47°28.9’
B= Tan 20°15
Sin LHA
C= A(+,-)B
Z= Cx Cos lat= x
1/x= tan-1= Z
=0.19S
=0.50N
=0.31N
0.31 x cos(12°)= 0.30
1/0.30= 3.33
Tan-1(3.33)= N73.36W
TB=286.4°
GB= 286.1°
TB= 286.4°(-)
GE= 0.3 E
GC=270°
TC= 270.3°
MC=265°
CE= 5.3E
Var= 1.4W (E)
Dev= 6.7 E
Remember the rule
Compass best Error (W)
Compass Least Error (E)
Change the name of the
Variation when solving for
The deviation
Checking:
C- 265°
D- 6.7°E
M- 271.7°
V- 1.4°W
T- 270.3°
Thank you and Godbless

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How to get compass error by sun

  • 1. By: Gian Gabriel Ibo Deck Cadet
  • 2.  First you need the following information  -Date  -Time in UTC or GMT  - Ships Posotion  -Variation (can be found on charts and ECDIS)  -Gyro course  -Gyro Bearing  -Magnetic Course
  • 3.  Date: 22 July 1997  Time: 15h 10m 20s (Philippine Local Time)  Position: Latitude- 12° 00’N  Longitude- 121° 30’ E  Variation: 1.25’W  Gyro Course: 270°  Gyro Bearing: 286.1° Magnetic Course: 265°
  • 4.  1.) First is to get the GMT  15h 10m 20s- Local Time (+8 time zone)  08h 00m 00s(-)  07h 10m 20s - GMT
  • 5.  - Get the GHA by the use of the Nautical Almanac  - Get also the increments by the use of the Nautical Amanac
  • 6.
  • 7.
  • 8. You Have now your GHA and Increments GHA= 283° 23.9’ INC= 2° 35.0’ + Always plus GHA= 285° 58.9’ Long= 121° 58.9’E LHA= 406° 88.9’ E +1 -60 407° 28.9’ -360° LHA= 47° 28.9’ W E (+) W (-) -360 if LHA is over 360°
  • 9.
  • 10. Get Declination Dec= 20° 15.1’ N 0.1’ (-) Dec= 20° 15.0’ N d= 0.5 (bottom part of the declination page) Minus because Declination Is Decreasing
  • 11. Get the True Bearing Tan Z= Sin LHA Tan Dec x Cos lat (+)(-) Cos LHA x sin Lat (+) Different name (-) Same name Lat and Dec
  • 12. tanZ= Sin (47° 28.9) Tan(20°15.0’)xcos(12°) – cos (47°28.9’)x sin(12°) tanZ= (3.34) Z= tan-1(3.34) Z= N 73.36 W N S EW -360 As is +180 -180 360 Zn= 286.4° LHA Declination
  • 13. OR YOU CAN SOLVE IT BY USING THE ABC METHOD
  • 14. A= Tan Lat Tan LHA B= Tan Dec Sin LHA C= A(+,-)B Change name of latitude if LHA is not in range between 90°-270° Name of Declination Z= Cx Cos lat= x 1/x= tan-1= Z
  • 15. A= Tan 12° Tan 47°28.9’ B= Tan 20°15 Sin LHA C= A(+,-)B Z= Cx Cos lat= x 1/x= tan-1= Z =0.19S =0.50N =0.31N 0.31 x cos(12°)= 0.30 1/0.30= 3.33 Tan-1(3.33)= N73.36W TB=286.4°
  • 16. GB= 286.1° TB= 286.4°(-) GE= 0.3 E GC=270° TC= 270.3° MC=265° CE= 5.3E Var= 1.4W (E) Dev= 6.7 E Remember the rule Compass best Error (W) Compass Least Error (E) Change the name of the Variation when solving for The deviation
  • 17. Checking: C- 265° D- 6.7°E M- 271.7° V- 1.4°W T- 270.3°
  • 18. Thank you and Godbless