The Solar Group is A Clock (VIII)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar Group is A Clock (VIII)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –30th
April 2021
Abstract
Paper hypothesis
- 2 Planets Velocities Rate expresses the rate of time between these 2 planets
The hypothesis explanation
- The hypotheses tells,
- Where (Earth Velocity / Pluto Velocity) =6.34, because of that, 1 hour of Earth
motion be equivalent to 6.34 hours of Pluto Motion.
- By that the hypothesis shows the used rule for planet motion rate of time definition
- This hypothesis is required to answer the question (Can the 1 second period of
time for any planet be = the 1 second period of time of another planet?)
- The idea tells us, where the (1 second period of time) is defined based on planet
motion features, that may cause the (1 second period) to be different from a planet
to another. (otherwise we need to answer, Why the period of 1 second of Earth
day = the period of 1 second of Venus day?!)
- The paper hypothesis solves the question and gives us the rule by which the
planets motions rates of time are defined….
- But
- This rule isn't used for all planets! Why?
- Theoretically, the rule restricts the rates of time to the planets velocity, that means,
where Mercury Velocity (47.4 km/s) is the greatest and Pluto velocity (4.7 km/s) is

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the smallest, that means, the maximum rate of time be that, 1 hour of Mercury be
=10.08 hours of Pluto, that causes the solar group works by so limited ability
- The 2nd
reason is that, some rate of time (1 hour =24 hours) is found in the solar
group by some planets motions interaction, and this interaction disturbs the rule
which is defined by the paper hypothesis
- This interaction is the paper point of discussion, because it hurts the discovered
rule

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1- Introduction
- Let's provide a word about this interaction in following:
o The velocities total of (Mercury 47.4 + Venus 35 + Earth 29.8) =112.2 km/s
o Pluto velocity = 4.7 km /s
o The rate is (112.2/4.7) =23.9 (suppose the rate to be 24 for simplicity)
o i.e.
o Each 1 hour of (the 3 planets velocities total) motion be equivalent to 24
hours of Pluto motion
o The rate (1 h = 24 h) is a basic rate in the solar system
o But this interaction effect on the planets motions cause change in the basic
rule – for example
o Mars velocity (24.1 km/s) / (Pluto velocity 4.7 km/s) =5.12
o But
o 1 hour of Mars Motion = 4.61 hours of Pluto motion
o The rate which was 5.12 became 4.61 because 24 =5.12 x 4.61 and that
means this planets interaction rate (1 hour =24 hours) causes this change
o Because of this interaction we have lost the discovered rule and can't define
the rates of time among the planets.
o For example 1hour of Mercury motion = 9.23 hours of Pluto motion (instead
of their velocities rate 10.08)
o What's this interaction? Why is it found and how does effect on the solar
system motion?
o The basic question is that, how can these 3 planets create one unified total
for their velocities and relative to one point?
o By what geometrical mechanism this interaction be done? The paper tries to
discover it

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2- Planet Motion Rate Of Time Definition
2-1 The new discovered planets motions rates of time
2-2 The planets motions interaction to cause (1 hour =24 hours)
2-3 The planets motions interaction discussion

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2-1 The new discovered planets motions rates of time
(1) –The rate of time between Mercury motion and the moon displacement
I- Data
(1)
742 mkm = 88000 km (the moon daily displacement) x 8432 solar days
(2)
8432 hours = 2 x 175.94 days x 23.96 hours
(3)
742 mkm x 2 = 4.095 mkm (Mercury velocity per solar day) x 365.25 solar days
II- Discussion
Equations No. (1 and 2) tell that
o The moon displacements total during 8432 solar days be = 742 mkm
o 8432 solar days of the moon motion
o But
o Let's suppose each 2 days of this (8432 days) = 1 hour of Mercury motion
o 8432 hours = 2 x 175.94 days x 23.96 hours
o 175.94 solar days = Mercury Day Period
o 23.9 hours = Earth rotation period
o Where (23.96/23.9) = (361 degrees /360 degrees)
o Based on that, 48 Hours Of The Moon Motion Be Equivalent To One
Hour Of Mercury Motion
o That shows the rate of time is (1 hour is equivalent to 48 hours)
Equation No. (3)
742 mkm x 2 = 4.095 mkm (Mercury velocity per solar day) x 365.25 solar days
- Equation no (3) tells that,
- Mercury moves during 365.25 solar days a distance = 742 mkm x 2
- Let's divide the discussion into basic points as following

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o (1st
Point)
o We have to suppose that the periods 365.25 days and (2 x 175.94 days) are
equivalent. Based on that, 1 hour of Mercury motion be equivalent to 48
hours of the moon motion
o (Why the periods 365.25 days and (2 x 175.94 days) are equivalent? The
question is answered in the point (3-4)
o (2nd
Point)
o The rule which controls this process tells (Equal Distances Create
Different Rates Of Time) – that means – If Mercury moves 742 mkm and
not 2 x 742 mkm – that will cause the rate of time to be 1 hour of Mercury
motion is equivalent to 24 hours of the moon motion – but because Mercury
moves 2 x 742 mkm that causes the rate to be 1 hour of Mercury motion be
equivalent to 48 hours of the moon motion.
o (3rd
Point)
o The question is
o Why these 2 planets (mercury and the moon) are required to be
interacted in their motions?
o Because the moon daily displacement = 88000 km where it's necessary to
make this displacement equal (176000 km = 2 x 88000 km) – (in the moon
orbital motion description (Point No. 4) of the current paper we review why
this distance 176000 km is required)
o So, The 2 Gears (Mercury and the moon use the moon displacement 88000
km daily to produce the required distance 176000 km)
o So, the moon motion distance = 742 mkm and Mercury motion distance = 2
x 742 mkm – similar to that – the moon daily displacement be 88000 km
and be = 176000 km by The Interaction Between Mercury And The Moon
Motion –

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o (Because of that, Mercury orbital period =88 days and its day period
=175.95 days, If this data is used through the rate 1000 km = 1 solar day,
these 2 values will be equal the 2 distances of the moon motion)
o (5th
Point)
o Where (23.96/23.9) = (361 degrees /360 degrees)
o Why we need this rate
o The very small error between (23.96 h and 23.9 h) is rated to the rate
(361/360) and what's this rate
o 360 degrees is the cycle degrees
o 361 degrees is the moon orbit regression degrees – because the moon orbit
regresses during a year (365.25 days) 19 degrees which causes change for
the eclipse calendar with 19 days– so during 19 years – the complete
revolution will be 361 degrees –
o Because of that many data is rated by this rate (361/360) and that means this
small error isn't an error but it's found for a geometrical necessity because
the revolution degrees is not 360 degrees but 361 degrees and that
necessitates geometrical modifications for different data

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(2) –The rate of time between Mars motion and the moon displacement
I- Data
(4)
24.1 (km/s) (Mars Velocity) x 29.53 hours = 2562074.856
(5)
The moon displacement total during 29.53 solar days = 2598693km
The difference between both = 1.4%
II- Discussion
- Equations no. (4 and 5) tell that
- Mars moves during 29.53 hours a distance equal (approximately) the moon
displacements total during 29.53 solar days
- From this data we conclude that
- 1 hour of Mars Motion be equivalent to 24 hours of the moon motion
- We use the same rule (Equal Distances Create Different Rates Of Time)
- But
- There's error 1.4% between the 2 distances, that tells the rate (1 hour = 24 hours) is
correct but in the detailed discussion the accuracy needs to take into consideration
this error 1.4%
- The rule is still solid and correct.
Notice
- 1 hour of Mercury Motion be equivalent to 48 hours of the moon motion
- And
- 1 hour of Mars Motion be equivalent to 24 hours of the moon motion
- So
- 2 hours of Mars Motion must be equivalent to 1 hour of Mercury Motion, Is it
true? Let's answer in following

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I-Data
(6)
Mercury (47.4 km/s) moves during its rotation period (1407.6 hours) = 240.2 mkm
Mars (24.1 km/s) moves during Venus day period (2802 hours) = 243.1 mkm
II-Discussion
Equation no. (6)
Mercury (47.4 km/s) moves during its rotation period (1407.6 hours) = 240.2 mkm
Mars (24.1 km/s) moves during Venus day period (2802 hours) = 243.1 mkm
- The difference between the distance 240.2 mkm and 243.1 mkm is around (1%)
- Equation no. (6) tells that both distances are equal (approximately)
- Let's remember the rule (Equal distances create different rates of time) means, the
periods of time are equal, so the mercury period (1407.6 hours) is equal Mars
period (2802 hours)
- By that 2 hours of Mars Motion is equivalent to 1 hour of Mercury Motion
- This same rate we have concluded from the moon motion (supposed) interaction
with these 2 planets – that means – we have 2 different data prove this same rate of
time which may show that it's a fact
Notice
- Mercury velocity (47.4 km/s) = 2 x Mars velocity (24.1 km/s) (error 1.6%)
- The rate of time (2: 1) depends on the rate of velocities
- But why Mars moves 243 mkm during Venus day period? This question should be
answer in point no. (3-4) of this current paper.

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(3) –The rate of time between Mars motion and Pluto motion
I-Data
(7)
Mars velocity (24.1 km/s) = Pluto velocity (4.7 km/s) x 5.12
(8)
(112.2 km/s) = 24 x (4.7 km/s)
II-Discussion
Equation no. (7)
Mars velocity (24.1 km/s) = Pluto velocity (4.7 km/s) x 5.12
- We remember that
- The moon day period 708.7 hours = 4.61 x 153.3 h (Pluto day period)
- And
- 1 hour of Mars motion = 24 hours of the moon motion
- Based on that,
- 1 hour of Mars motion should be = 5.12 hours of Pluto motion
- But, it's not true!!
- 1 hour of Mars motion should be = 4.61 hours of Pluto motion,
- Why?
Equation no. (8)
(112.2 km/s) = 24 x (4.7 km/s) = 4.61 x (24.1 km/s) Where 24 = 5.2 x 4.61
- The velocity 112.2 km/s = the velocities total of (Mercury + Venus + Earth)
- The equation tells, we have 2 gears, the 3 planets motions together form one gear
and Pluto motion alone form the other gear between both gears the rate of time (1
hour =24 hours) is created
- The 3 planets motions total effect on Pluto (4.7 km/s) and Mars (24.1 km/s)
motions and because of that the rate 4.61 is used with the 2 planets.

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- 1 hour of the 3 planets motions total = 4.61 hours of Mars motion
- And
- 1 hour of Mars motion = 4.61 hours of Pluto motion
- And
- 1 hour of Pluto motion = 4.61 hours of the Earth moon motion
- The data tells that there's a geometrical necessity to use the same with 3 planets
- It's a transportation of motion is done from point to another point through the solar
group.
- The secret is in the equation ((24 hours/ 4.61) = 5.2), also because Mars velocity
=24.1 km/s, this all (similar data) doesn't tell about pure coincidence of numbers
but tells about a motion transportation mentioned to create the data values similar
to one another for geometrical necessities
- What's This Geometrical Necessity?
The Velocities Total 112.2 km/s
- How to create this velocity 112.2 km/s ?
- It's the total of (Mercury 47.4 + Venus 35+Earth) velocities =112.2 km/s
- But
- How to create this velocity geometrically? Relative to what point this velocity
(112.2 km/s) can be defined?
- This velocity (112.2 km/s) is defined relative to the sun point, it's the only possible
method, because the 3 planets revolve around the sun in the same direction and
theoretically their velocities can be added to each other relative to the sun point.
- Imagine these 3 planets as 3 gears, how to create their total velocities? Their
velocities total can be defined relative to their center
- Let's see the following equation

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Equation no. (9)
1392000 km = 112.2 km/s x 12430 seconds
- Where
- 1392000 km = The Sun Diameter
- 12430 seconds =we have discussed deeply in the current paper Methodology
- Even if the geometrical mechanism is still absent but the data shows that our
expectation is correct, the velocity 112.2 km/s is used for the sun data
- That tells there's a geometrical necessity for this using – and this velocity (112.2
km/s) is a real one
Notice
- Earth motion distance during its day period = 2574720 km
- The velocity (112.2 km/s) passes this same distance in 6.374 hours
- This is the rate between Earth and Pluto velocities (and also their days periods)
- That tells this velocity (112.2 km/s) is a basic player in the solar system geometry,
how this velocity (112.2 km/s) effect on the other planets motions data? In point
no. 3-3 we should discuss this question
Notice
- 113.4 km x 0.99 = 112.2 km
- But
- 113.4 degrees = 90 degrees + 23.4 degrees (Earth Axial Tilt)
- That tells this velocities total (112.2 km/s) effect on Earth Axial Tilt creation

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(4) –The general rate of time between the 4 planets
I-Data
(10)
48 hours of the moon motion =1 hour of Mercury Motion = 2 hours of Mars
Motion = 9.23 hours of Pluto Motion
(11)
9.23 x 153.3 hours = 1415 hours
Equation no. (11)
9.23 x 153.3 hours = 1415 hours
- Where
- 153.3 hours = Pluto Rotation Period
- 1407.6 hours = Mercury Rotation Period (the error 0.5% with 1415)
- So, both 2 planets rotation periods depends on this same rate 9.23
- We have a reason to consider that, this data is created based on a geometrical
machine and that tells the different rates of time is almost a fact tool used in the
solar system geometry.
Notice
- But the rate 4.61 doesn't define Mars motion with Mercury motion
- Where
- 4.61 x 24.6 hours (Mars rotation period) = 113.4 hours
- And
- Mercury rotation period =1407.6 hours?

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(5) –The rates among other planets
- 24 hours of Uranus Motion = 1 hour of Mercury Motion = 1.35 hour of Venus
Motion = 1.6 hours of Earth Motion= 2 hours of Mars Motion = 48 hours of
the moon motion = 4.61 hours of Pluto Motion
I- Data
(12)
Earth (29.8 km/s) moves during its day period (24 h) a distance = 2574720 km
(13)
Pluto (4.7 km/s) moves during its day period (153.3 h) a distance = 2593836 km
(14)
The Earth moon displacements total during 29.53 days be = 2598693 km
(15)
Mars (24.1 km/s) moves during (29.53 h) a distance = 2562075 km
(16)
Uranus (6.8 km/s) moves during 6 Uranus days (103.2h) a distance =2526336 km
II- Discussion
- let's remember the rule
- Equal Distances Cause To Create A Different Rate Of Time
o (Point No. A)
o The moon displacement daily =88000 km, and its total during 29.53 days =
Earth motion distance during its day period (the difference =1%)
o Based on this data
o 29.53 solar days of the moon motion =1 solar day of Earth motion
o i.e.
o 29.53 hours of the moon motion =1 hours of Earth motion.

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o (Point No. B)
o Earth (29.8 km/s) moves during its day period (24h) a distance= the distance
passed by Pluto (4.7 km/s) during its day period (153.3 h) (error 1%)
o So
o 153.3 hours of Pluto Motion = 24 hours of Earth Motion
o i.e.
o 1 hour of Earth motion = 6.3875 hours of Pluto Motion
o Also
o The moon displacements total during 29.53 days = Pluto motion distance
during its day period (153.3 h)
o So
o 153.3 hours of Pluto motion = 29.53 days of the moon motion
o i.e.
o 1 hour of Pluto motion = 4.61 hours of the Earth moon motion
o (Point No. C)
o Mars (24.1 km/s) moves during (29.53 h) a distance = the distance passed
by Earth during its day period (24 h) = the moon displacements total
distance during 29.53 solar days = the distance passed by Pluto during its
day period (153.3 h)
o Based on that
o 29.53 hours of Mars motion = 29.53 solar days of the moon displacement
motion = 1 solar day of Earth motion = 153.3 hours of Pluto motion
o i.e.
o 1 hour of Mars motion = 24 hours of the moon motion
o 1.23 hour of Mars motion = 1 hour of the Earth motion
o 1 hour of Mars motion should be equal 5.2 hours of Pluto motion (But this
rate isn't correct, instead 1 hour of Mars motion =4.62 hours of Pluto
motion) (Why? we have discussed that)

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o (Point No. D)
o Earth (29.8 km/s) moves during its day period (24 h) a distance = the
distance passed by Pluto during its day period (153.3 h) = The moon
displacements total during 29.53 days be = the distance passed by Mars
during (29.53 h) = the distance passed by Uranus during 6 Uranus days
(103.2h)
o So
o 24 hours of Earth motion = 153.3 hours of Pluto motion = 29.53 solar days
of the moon motion = 29.53 hours of Mars motion = 103.2 hours of Uranus
Motion
o i.e.
o 1 hour of Earth motion = 6.3875 hours of Pluto motion = 1.23 solar days of
the moon motion = 1.23 hours of Mars motion = 4.3 hours of Uranus
Motion
o But, not
o (1 hour of Uranus Motion = 2 hours of the moon motion) why? we need
to answer this question later
Shortly
Pluto & Uranus rates of time are different from the defined rates based on the used
rule
Let's discuss why both rates should be different in following

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Pluto and Uranus Motions Rates Of Time
- (1st
Pluto Rate of time) (Revision)
- Equations no. (13 and 15) tell that, Pluto motion distance during its day period
(153.3 hours) = Mars motion distance during (29.53 hours)
- Based on that
- (153.3 hours /29.53 hours) = 5.2
- Means
- 1 hour of Mars Motion should be = 5.2 hours of Pluto motion
- But
- The fact is that
- 1 hour of Mars Motion should be = 4.61 hours of Pluto motion
- And
- 1 hour of Mercury Motion = 2 hours of Mars motion ,
- So
- 1 hour of Mercury Motion = 9.23 hours of Pluto motion.
- Why Pluto rate is 4.62 hours and not 5.2 hours?
- Because
- The total velocities of (Mercury + Venus +Earth)=112.2 km/s
- These velocities total work together as one gear in opposite to Pluto (4.7km/s) as
another gear
- 112.2 km/s = 24 x 4.7 km/s = 24.1 x 4.61
- And
- 24 = 5.2 x 4.62
- That means, Pluto works as a common gears between 2 sides, on the first side the
three planets velocities total and on the second side Mars velocity
- For that, the rate (5.2) changed to be (4.62) because of the rate 24 effect which is
found between the 3 planets velocities total on one side and Pluto on the other side.

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(2nd
Uranus Rate of time)
- Let's suppose Uranus rate of time as following
- 1 hour of Mercury Motion = 24 hours of Uranus Motion =9.23 of Pluto
Motion
- Based on that
- 1 hour Pluto motion =2.6 h Uranus Motion
- Uranus rate of time is changed (from the rule suppose result) because of Pluto rate
change from 5.2 to 4.62
- The rate 2.6 = (5.2/2)
- And the rate 5.2 connects Uranus and Pluto motion with the moon motion (because
5.1 degrees = the moon orbital inclination)
- Also
- 97.8 deg (Uranus axial tilt) = 19 x 5.14 deg (the moon orbital inclination)
- 17.2 deg (Pluto orbital inclination) = 5.1 deg x 3.37 deg (Venus orbital inclination
3.4 deg)
Notice
- Because 1 hour Mercury Motion = 24 hours of Uranus Motion
- 2815 mkm (Mercury Uranus Distance), this distance is used as a period of time
with the rate 1 mkm =1 hour
- And by that
- 2815 mkm = 2815 hours = 2 x 1407.6 hours (Mercury Rotation period)
Notice
- Mercury (47.4 km/s) moves during its rotation period (1407.6 hours) a distance =
240.2 mkm
- It different 1% from the distance 243 mkm
- If this distance is used as a period of time with the rate 1 mkm = 1 solar day
- It will be =243 solar days = Venus Rotation Period

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- Also
- Venus (35 km/s) moves during 365.25 solar days a distance = 1106 mkm = 2π x
175.94 mkm
- If this distance is used as a period of time with the rate 1 mkm =11 solar day
- It will be =175.94 solar days (Mercury Day period)
Notice
- 153.3 hours/ 29.53 (hours) = 5.2 =2 x 2.6
- That shows Uranus motion effects on the earth moon and Pluto motions to create
their days periods
- That tells this geometrical mechanism is effected basically by Uranus motion
which cause a unification for the whole process
Notice (please remember)
- 1 hour Mercury Motion = 9.23 hours Pluto Motion
- Because of that
- 153.3 h (Pluto rotation period) x 9.23 = 1415 hours
- (where 1407.6 hours = Mercury rotation period ) (error 0.5%)
- Based On Uranus Rate Of Time
- 1 hour of Mercury Motion = 24 hours of Uranus Motion =9.23 of Pluto
Motion
- Let's define the rest planets rates of time in following
- 1 hour of Earth Motion = 1.235 hours of Mars Motion
- But
- 1 hour of Mercury Motion =2 hours of Mars Motion
- Based on that
- 1 hour of Mercury Motion =1.6 hours of Earth Motion
- This is true because (Mercury velocity 47.4) / (Earth velocity 29.8) =1.6

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- 1 hour of Mercury Motion = 1.354 hours of Venus Motion
- Based on that
- 1 hour of Venus Motion = 17.7 hours of Uranus Motion
Notice
17.2 hours = Uranus day period
And
17.7 hours = 17.2hours = 0.5 hours = 1800 seconds
Uranus (6.8 km/s) moves during 1800 seconds a distance = 12104 km (error 1%)
Where
12104 km = Venus Diameter.
Notice
2 x 2815 hours (2 Mercury rotation periods) = 17.2 hours (Uranus day) x 327.6
Where
327.6 solar days = the moon sidereal year
- But the rate 4.61 doesn't define Mars motion with Mercury motion
- Where
- 4.61 x 24.6 hours (Mars rotation period) = 113.4 hours
- And
- 113.4 deg = 90 deg +23.4 deg (Earth Axial Tilt)

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2-2 The Planets Motions Interaction To Cause (1 Hour =24 Hours)
- How do we know this interaction between the 3 planets velocities total (112.2 km)
and Pluto velocity (4.7km)?!
- We have only the rate (24) between both velocities and this rate (24) is attractive
for us to suppose the interesting rate (1 hour =24 hours)
- But
- The conclusion is neither strong nor supported
- For that we have to search in these 4 planets motions data to find some help

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Question (no.1)
How To Create The Velocities Total (112.2 Km/S)?
- How to unify the 3 planets velocities to create one unified velocity =112.2 km/s?
- The planet isn't a gear, and we don't how this velocity is created? the planets
revolve around the sun and by that their velocities total can be created relative to
the sun point.
- How? And why these specific planets?
- How, we don't know
- Why these 3 planets (Mercury, Venus and Earth)? Because these 3 planets orbital
circumferences = their distances to Jupiter (that creates for them on point of effect)
- Let's review this data in following:
- Mercury (47.4 km/s) moves during its day period (4222.6 h) a distance = 720.7
mkm = Mercury Jupiter distance
- Venus (35 km/s) moves during its orbital period (224.7 solar days) a distance
=680 mkm =Venus Jupiter distance (670.4 mkm error 1.4%)
- Earth (29.8 km/s) moves during its orbital period (365.25 solar days) a distance
=940 mkm =Earth Jupiter distance (928 mkm error 1.3%)
- (Notice, in this case, Earth and Jupiter be on 2 different sides from the sun and by
that the distance between them be =778.6 mkm +149.6 mkm =928 mkm)
A Comment
- The previous data shows that the three (specific) planets use similar behaviors with
Jupiter
- The data gives a central point for the 3 planets motions, telling that, These 3
Planets Velocities Total Effect On Pluto Through Jupiter
- But, the velocities total can be performed geometrically relative to the sun point,
but the data shows it effect on Jupiter! How to understand?

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Question (no.2)
Can the velocities Total (112.2 km/s) effect on Jupiter data?
I- Data
(a)
The velocity (112.2 km/s) passes during (12104 hours) a distance = 4900 mkm =
Jupiter orbital circumference
(b)
The velocity (112.2 km/s) passes during (4879 hours) a distance = 1970 mkm = the 3
planets orbital circumferences total (=360+680 +940= 1980 mkm error 0.5%)
(c)
The velocity (112.2 km/s) passes during (4222.6 hours) a distance = 3413 mkm = the
4 inner planets orbital circumferences total (=360+680 +940+1433= 3413 mkm)
(d)
The velocity (112.2 km/s) passes during (12104 second) a distance = 3 x 449197 km
= 3 Jupiter Circumferences
Where
12104 km = Venus Diameter
4879 km = Mercury Diameter
4222.6 hours = Mercury Day Period
II- Discussion
- The data shows that the velocities total (112.2 km/s) has some clear effect on
Jupiter motion data,
- That tells the value (112.2 km/s) is a real velocity used in the solar system
geometrical design and gas clear effect on Jupiter motion data

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Question (no.3)
Can an interaction be found between the velocities Total (112.2 km/s) and
Jupiter velocity?
I- Data
(e)
2 x (112.2 km/s) = 13.1 (km/s) x 17.2 (error 0.4%)
II- Discussion
Equation no. (e)
2 x (112.2 km/s) = 13.1 (km/s) x 17.2 (seconds)
Where
13.1 km/s = Jupiter velocity
17.2 hours = Uranus Day Period
- Equation no. (e) tells that, Jupiter during 17.2 seconds moves a distance be passed
by the velocities total (112.2 km/s) in 2 seconds
- Equation no. (e) tells that, some interaction is found with Uranus day period, why
that should be?
Notice
- 2 Jupiter days (19.8 hours = 17.2 hours Uranus day + 2 x 1.3 hours)
- Where
- 1.3 degrees = Jupiter orbital inclination
- Similar data (Mars orbital period 687 days + (6.2 days) = 2 x 364.6 days (the
nodal year)
- Where 6.2 = 2 x 3.1 (Jupiter axial tilt =3.1 degrees)

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Question (no.4)
Why does Uranus day period =17.2 hours but Pluto orbital inclination =17.2
degrees?
- And
- Does Uranus motion effect on Pluto motion cause Pluto day period to be so long
(153.3 hours) in comparison with the outer planets days periods?
I- Data
(f)
(112.2 km/s) / (6.8 km/s) = 16.5
(g)
5060 = 153.3 x 33
II- Discussion
Equation no. (f)
(112.2 km/s) / (6.8 km/s) = 16.5
Where
112.2 km /s = the 3 planets velocities total
6.8 km/s = Uranus velocity
Equation no. (g)
5060 = 153.3 hours x 33
Where
153.3 hours = Pluto day period
33 =16.5 x 2
What's 5060??
The only known number is 5040 seconds ( a period required for mercury day period
to be 176 sole days)
Equations (f and g) tell Mercury day period be less than 176 solar days with 5040
seconds to enable Pluto day to be 153.3 hours by Uranus effect.
Why?

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To enable Pluto to move during its day period a distance = Earth motion distance
during its day period.
That means
The velocities total (112.2 km/) interaction with Pluto velocity (4.7 km/s) caused
Pluto day period to be 153.3 hours
A Comment
- The interaction between the 3 planets velocities total (112.2 km/s) with Pluto
velocity causes many results which are:
- The creation of the rate of time (1 hour =24 hours)
- Causes Pluto day period to be =153.3 hours
- Causes Mercury day to be =176 solar days minus 5040 seconds
- The moon orbital apogee circumference to be 2550973 km decreased from the
moon displacements total during 29.53 solar days (2598693 km).

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Question (no.5)
Why the rate (1 hour = 24 hours) is used by Mars and the moon motions?
- 1 hour of Mars Motion = 24 hours of the moon motion
- The data is interesting because
o 112.2 km/s (the velocities total) = 24.1 km/s (Mars Velocity) x 4.65
o Pluto motion distance during a solar day (406000km) =88000 km x 4.61
o 1 hour of Mars motion = 4.61 hours of Pluto motion
o Perhaps these 3 rates depend on the same effect – means – these 3 rates are
one rate but be seen in 3 different positions
o This idea tells that Uranus day period (17.2 hours) and Pluto orbital
inclination (17.2 degrees), these 2 values are only one value be seen in
different positions….

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Question (no.6)
Can the dependency between Mercury and Pluto days period be proved?
I- Data
(h)
4222.6 h = 153.3 h x 27.55
(i)
5906 mkm = 1.4 x 4222.6 mkm
(j)
5040 mkm = 0.406 mkm x 12430
II- Discussion
Equation (h)
4222.6 h = 153.3 h x 27.55
Where
4222.6 h = Mercury day period
153.3 h = Pluto day period
27.55 days = Anomalistic Month
Equation no. (h) tells that, the rate (1 hour =24 hours) is used in this equation,
showing that the moon motion data depends on this rate
Equation (i)
5906 mkm = 1.4 x 4222.6 mkm
Where
5906 mkm = Pluto orbital distance
4222.6 h = Mercury day period (here is used as a distance 4222.6 mkm)
1.4 hour = Mercury day period needs 1.4 hours to be 176 solar days
Equation (i) tells that, Mercury and Pluto motions data are created depends on one
another
Equation (j)
5040 mkm = 0.406 mkm x 12430

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Where
0.406 mkm = Pluto motion distance per a solar day
12430 days
Equation (j) tells that, Pluto needs 12430 days to pass the distance 5040 mkm
(Note , Mercury day period needs 5040 seconds to be 176 solar days)
Notice
- The velocities total (112.2 km/s) during 12430 second pass a distance =1392000
km = The Sun Diameter
- Mars (24.1 km/s) during 12430 second pass a distance =300000 km = light motion
distance during 1 second
- Saturn (9.7 km/s) during 12430 second pass a distance =120536 km = Saturn
diameter

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2-3 The planets motions interaction discussion
- Why the 3 planets velocities interaction be done?
- Pluto was the Mercury moon and Mars was the planet between Mercury an Venus
- Because of some earthquake, Mars had migrated from its original orbital distance
(84mkm) to its currant orbital distance (227.9 mkm). In its motion Mars had
collided Venus and then Earth, and from these collisions debris the Earth moon is
created
- Pluto, because of its small mass, the earthquake pushed it to the end of the solar
group with orbital distance =5906 mkm
- In that time Neptune occupied the orbital distance 5906 mkm and Pluto had
collided with Neptune pushed it out of its orbital distance forces it to be more near
to the sun but without orbit (for that reason the distance between Pluto and
Neptune = Pluto eccentricity distance)
- This migration of the 2 planets effected negatively on the solar system geometrical
structure
- Jupiter and Uranus unified their powers to save the solar group
- Their effect cause the 3 inner planets velocities to be added to each other –
creating a total (=112.2 km/s)
- By this process, the solar group gives a chance for Saturn Creation, Where Saturn
is created after the planets migration
- Saturn creation depended on the 3 planets velocities total (112.2 km/s)
- The value 12430 seconds show the harmony between Saturn data and the 3 planets
data
- Later we should add more data to support this claim
- But why Saturn is required to be created?
- Uranus power saves Pluto inside the solar group, but Mars needed help to save its
motion in its new orbital distance – also Neptune was removed from its orbit and
needed to built a new orbit

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- Saturn saves Mercury and Jupiter provided an orbit for Neptune – so – the machine
which was in serious risk – at end- be in safe (approximately)
- Let's summarize the general idea in following:
o Saturn is born by Uranus effect depends on the 3 inner planets to save Mars
o Jupiter provided the required energy to build an orbit to Neptune after Pluto
pushed it out its orbit
o Uranus controls Pluto migration and prevented it to move out of the solar
group.
Notice
- We see the solar planets as rigid bodies but their creation and motion data are
found based on geometrical calculations
- Even planets collisions are done based on geometrical calculations
- That because light motion is a player in the planet motion
- For that reason Saturn (9.7 km/s) moves during (17.2 hours) (Uranus day period) a
distance = 2 x 300000 km (light motion distance during 1 second)
- Also Saturn (9.7 km/s) moves during (30589 second) a distance = 300000 km
(light motion distance during 1 second) (error1%)
- Where (30589 solar days = Uranus orbital period)

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Saturn Creation
I- Data
(k)
4879 km x 1092
= 57.9 mkm
12756 km x 1092
= 149.6 mkm
120536 km x 1092
= 1433 mkm
(l)
10747 days =365.25 days x 29.53
(m)
1433 mkm = Saturn orbital distance = Mars orbital circumference = (Venus
Circumference)2
(n)
112.2 km/s x 2 =9.7 km/s x 23.2
(p)
86400 seconds x 112.2 km/s =9.7 mkm
(q)
9.7 mkm x 2 x 1461 = 28255 mkm (Neptune orbital circumference)
II- Discussion
- Equations (k), (l) and (m) show that Saturn motion data is created depends on the
3 inner planets motions data
- Also these equations shows that Saturn data is in harmony with Mars, because
Saturn saves Mars (even mars velocity =2.5 Saturn velocity but 2.5 degrees=
Saturn orbital inclination)

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Equation no. (n)
112.2 km/s x 2 =9.7 km/s x 23.2
Where
112.2 km/s = the 3 planets velocities total
9.7 km/s = Saturn velocity
23.4 deg = Earth axial tilt
We notice that, always the velocity (112.2 km/s) is used in (2 values), with Jupiter,
Uranus and Saturn – some reason must be found behind
Equation no (p)
86400 seconds x 112.2 km/s =9.7 mkm
The 3 planets move during a solar day a distance = 9.7 mkm
Equation no (q)
9.7 mkm x 2 x 1461 = 28255 mkm (Neptune orbital circumference)
So, the velocities total (112.2 km/s) during 1461 days x2 moves a distance = Neptune
orbital circumference
Notice
Because the period 5040 seconds (which is required for Mercury day period to be 176
solar days) be produced by the interaction of the 3 planets (112.2 km/s) and Pluto
And based on this interaction Saturn is created
Mercury (47.4 km/s) moves during 5040 seconds a distance = 2 Saturn diameters
(error 1%)
Mars (24.1 km/s) moves during 5040 seconds a distance = Saturn diameter

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Solar Group is A Clock (VIII)

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