Alice wants to teleport an unknown quantum state ψ to Bob using prior entanglement and classical communication. They share one half of an entangled Bell state β each. Alice combines her half of β with ψ and performs a teleportation circuit involving CNOT and Hadamard gates. She then measures her two qubits and sends the results to Bob. Based on the received classical bits, Bob applies a Pauli operator to reconstruct the state ψ exactly at his location.
4. Bra-Ket Notation Involves
Vector Xn can be represented two
ways
Ket
|n>
z
y
x
w
v
Bra
<n| = |n>t
( )*****
zyxwv
*
m is the complex conjugate of m.
5. Inner Products
An Inner Product is a Bra multiplied by a Ket
<a| |b> can be simplified to <a|b>
=<a|b> =
p
o
n
m
l
( )*****
zyxwv
*****
pzoynxmwlv ++++
6. Outer Products
An Outer Product is a Ket multiplied by a Bra
|a><b| =
p
o
n
m
l
=
*****
*****
*****
*****
*****
pzpypxpwpv
ozoyoxowov
nznynxnwnv
mzmymxmwmv
lzlylxlwlv
( )*****
zyxwv
By Definition ( ) acbcba =
7.
8. • State Space: The inner product space
associated with an isolated quantum system.
•The system at any given time is described by a
“state”, which is a unit vector in V.
n
CV /=
9. • Simplest state space - (Qubit)
If and form a basis for ,
then an arbitrary qubit state has the form
, where a and b in
have .
• Qubit state differs from a bit because
“superpositions” of a qubit state are possible.
2
CV /=
〉0| 〉1| V
〉+〉=〉 1|0|| bax C/
1|||| 22
=+ ba
10. The evolution of an isolated quantum system is
described by a unitary operator on its state
space.
The state is related to the state by a
unitary operator .
i.e.,
〉)(| 2tψ〉)(| 1tψ
2,1 ttU
〉=〉 )(|)(| 1,2 21
tUt tt ψψ
11. Quantum measurements are described by a
finite set of projections, {Pm}, acting on the
state space of the system being measured.
12. • If is the state of the system immediately
before the measurement.
•Then the probability that the result m occurs is
given by .
〉ψ|
〉〈= ψψ ||)( mPmp
13. • If the result m occurs, then the state of the
system immediately after the measurement is
)(
|
||
|
2/1
mp
P
P
P m
m
m 〉
=
〉〈
〉 ψ
ψψ
ψ
14. • The state space of a composite quantum system
is the tensor product of the state of its
components.
• If the systems numbered 1 through n are
prepared in states , i = 1,…, n, then the
joint state of the total composite system is
.
〉)(| itψ
〉⋅⊗⋅⋅⊗〉 nψψ || 1
15. Quantum Uncertainty and
Quantum Circuits
Classical Circuits vs. Quantum Circuits
Hadamard Gates
C-not Gates
Bell States
Other Important Quantum Circuit Items
16. Classical Circuits
vs.
Quantum Circuits
Classical Circuits based upon bits, which are
represented with on and off states. These states
are usually alternatively represented by 1 and 0
respectively.
The medium of transportation of a bit is a
conductive material, usually a copper wire or
something similar. The 1 or 0 is represented with
2 different levels of current through the wire.
17. Circuits Continued…
Quantum circuits use electron “spin” to hold
their information, instead of the conductor
that a classical circuit uses.
While a classical circuit uses transistors to
perform logic, quantum circuits use
“quantum gates” such as the Hadamard
Gates.
18. Hadamard Gates
Hadamard Gates can perform logic and are
usually used to initialize states and to add
random information to a circuit.
Hadamard Gates are represented
mathematically by the Hadamard Matrix which
is below.
−
=
11
11
2
1
H
19. Circuit Diagram of a
Hadamard Gate
Hx y
When represented in a Quantum Circuit
Diagram, a Hadamard Gate looks like this:
Where the x is the input qubit and the y is
the output qubit.
20. C-Not Gates
C-not Gates are one of the basic 2-qubit gates in
quantum computing. C-not is short for controlled
not, which means that one qubit (target qubit) is
flipped if the other qubit (control qubit) is |1>,
otherwise the target qubit is left alone.
The mathematical representation of a C-Not Gate
is below.
=
0100
1000
0010
0001
CNU
21. Circuit Diagram of a C-Not Gate
x
y
x
yx ⊕
When represented in a Quantum Circuit
Diagram, a C-Not Gate looks like this:
Where x is the control qubit and y is the
target qubit.
22. Bell States
Bell States are sets of qubits that are entangled.
They can be created with the following Quantum
Circuit called a Bell State Generator:
With H being a Hadamard Gate and x and y
being the input qubits. is the Bell State.
Hx
y
xyβ
β
23. Bell State Equations
The following equations map the previous Bell State
Generator:
( ) ( ) 001100
2
1
0000
2
1
00 β=+→+→
( ) ( ) 011001
2
1
1101
2
1
01 β=+→+→
( ) ( ) 101100
2
1
1000
2
1
10 β=+→+→
( ) ( ) 111001
2
1
1101
2
1
11 β=+→+→
So we can write: ( )
2
110 yy
x
xy
−+
=β
25. Controlled U-Gate
A Controlled U-Gate is an extension of a C-Not
Gate. Where a C-Not Gate works on one qubit
based upon a control qubit, a U-Gate works on
many qubits based upon a control qubit.
A Controlled U-Gate can be represented with the
following diagram:
U
n n
Where n is the number of qubits the gate is
acting on.
26. Measurement Devices
These devices convert a qubit state into a
probabilistic classical bit.
It can be represented in a diagram with the
following:
Ψ M
x
A measurement with x possible outcomes has x
wires coming from the device that measures it.
28. Cloning
Can copying of an unknown qubit
state really happen?
By copy we mean:
1. Take a quantum state
2. Perform an operation
3. End with an exact copy of
Z
Z
29. Using a Classical Idea
• A classical CNOT gate can be used for an
unknown bit x
• Let x be the control bit and 0 be the target
• Send x0 xx where is a CNOT gate
• Yields an exact copy of x in the classical
setting
30. Move the Logic to Quantum
States
• Given a qubit in an unknown quantum state
such that
• Through a CNOT gate we take
such that
• Note if indeed we copied we would thus
end up with which would equal
Z 1b0aZ +=
Z ZZ0
10b00a0)1b0(a +=+
Z
ZZ
11b²10ab01ab00a² +++
31. Limits on Copying
Note that:
only at ab=0 and for a and b being or
11b²10ab01ab00a²10b00a +++=+
0 1
32. Proving the difficulty of cloning
• Suppose there was a copying machine
• Such that can be copied with a standard
state
• This gives an initial state which when
the unitary operation U is applied yields
SZ
( ) ZZSZU =
Z
S
33. …difficulty cloning
• Let
• By taking inner products of both sides:
• From this we can see that: = 0 or 1
• Therefore this must be true: or
• Thus if the machine can successfully copy it is
highly unlikely that the machine will copy an
arbitrary unknown state unless is
orthogonal to
yy== )syU(&zz)szU(
²yzyz =
yz
yz ⊥ y=z
z
z
y y
34. Final cloning summary
• Cloning is improbable.
• Basically all that can be accomplished is
what we know as a cut-n-paste.
• Original data is lost.
• The process of this will be shown in the
teleportation section soon to follow.
35. Distinguishability
• To determine the state of an element in the
set:
• This must be true:
-
• Finding the probability of observing a
specific state , let be the measurement
such that
n21
y,...,y,y
n21 y...yy ⊥⊥⊥
mmm
yyP =
my mP
36. Distinguishability cont.
• Then the probability that m will be observed is:
-
• Which yields
• Because the set is orthogonal
-
• If the set was not orthogonal we couldn’t know for
certain that m will be observed.
mm
y|P|yP(m) m=
mmmm yyyyP(m) =
111P(m) =×=
37. Cloning and
Distinguishability
• Take some quantum information
• Send it from one place to another
• Original is destroyed because it can’t just be
cloned (copied)
• Basically it must be combined with some
orthogonal group or distinguishing the quantum
state with absolute certainty is impossible.
40. THE CONDITIONS…
• Alice and Bob are a long way from one
another.
• Alice wants to transmit some classical
information in the form of a 2-bit to Bob.
41. HOW IT WORKS…
• Alice and Bob initially share a 2-qubit in the
entangled Bell state
which is just a pair of quantum particles.
( )
2
1100 +
=Ψ
42. HOW IT WORKS…
• is a fixed state and it is not necessary for
Alice to send any qubits to Bob to prepare
this state.
• For example, a third party may prepare the
entangled state ahead of time, sending one of
the qubits to Alice and the other to Bob.
Ψ
43. HOW IT WORKS…
1) Alice keeps the first qubit (particle).
2) Bob keeps the second qubit (particle).
3) Bob moves far away from Alice.
44. HOW IT WORKS…
• The 2-bit that Alice wishes to send to Bob
determines what quantum gate she must
apply to her qubit before she sends it to
Bob.
45. The four resulting states are:
( )
( )
.)(:11
,:10
,)(:01
,:00
11
10
01
00
β
β
β
β
=ΨΙ⊗Υ
=ΨΙ⊗Ζ
=ΨΙ⊗Χ
=Ψ=ΨΙ⊗Ι
i
46. HOW IT WORKS…
• Since Bob is in possession of both qubits,
he can perform a measurement on this Bell
basis and reliably determine which of the
four possible 2-bits Alice sent.
48. TeleportationTeleportation
•Teleportation is sending unknown quantum
information not classical information.
•Teleportation starts just like Superdense coding.
•Alice and Bob each take half of the 2-qubit Bell
state:
•Alice takes the first qubit (particle) and Bob
moves with the other particle to another location.
( ) 2/110000 +=β
49. TeleportationTeleportation
•Alice wants to teleport to Bob:
•She combines the qubit with her half of the
Bell state and sends the resulting 3-qubit (the 2
qubits-Alice & 1 qubit-Bob) through the
Teleportation circuit (shown on the next slide):
ψ
ψ
50. TeleportationTeleportation
CircuitCircuit
Top 2 wires represent Alice's system
Bottom wire represents Bob’s system
43210
2
1
Z
ψψψψψ
ψxy
X
M
MH
•⊕
•ψ
00β {
Single line denotes
quantum information
being transmitted
Double line denotes
classical info being
transmitted
57. ConclusionConclusion
• Brief Review of Quantum Mechanics
• Quantum Circuits/Gates
– Classical Gates vs. Quantum Gates
– Hadamard Gates
– C-not Gates
– Bell States
58. Conclusion, cont.Conclusion, cont.
• No-Cloning
• Distinguishability of Quantum States
• Superdense Coding
- Pauli Matrices
- The Conditions
- How it Works
Reminiscent of the title, not clear if in either. a squared and b squared represent prob of being in either state.
The index m refers to the measurement outcomes that may occur. The projections satisfy the completeness equation If the state of the system is
immediately before the measurement, then the probability that result m occurs is given by ; if the result m occurs, then the state of the system immediately after the measurement is
The index m refers to the measurement outcomes that may occur. The projections satisfy the completeness equation If the state of the system is
immediately before the measurement, then the probability that result m occurs is given by ; if the result m occurs, then the state of the system immediately after the measurement is