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How to evaluate
?
EVALUATING FUNCTIONS
General Math
Week 1, LC Code: (M11GM - Ia – 1)
Learning Competency
The learner evaluates a function.
(M11GM - Ia – 1)
Learning Objectives
At the end of this video, you are able to:
1. Recall the difference between function and relation;
2. Recall on the four ways to represent a function; and
3. Evaluate a function.
What is the difference between
function and relation?
Function
β€’ A function is a relation that is for each
input there is only one output.
β€’ A function is a set of ordered pairs
(x,y) such that no two ordered pairs
have the same x-element (abscissa).
β€’ A function can be a one-to-one or
many-to-one correspondence but can
not be a one-to-many
correspondence.
Relation
β€’ A relation is a set of inputs and
outputs.
β€’ A relation is a set of ordered pairs
(x,y).
β€’ A relation can be one-to-one, one-to-
many and/or many-to-one
correspondence.
Fact or Bluff
1. All functions are relations.
Answer: Fact
2. All relations are functions.
Answer: Bluff
3. A function is a set of ordered pairs
(x,y) such that no two ordered pairs
have the same y-element.
Answer: Bluff
4. A student with a unique
identification number is an
example of a function.
Answer: Fact
5. Not all functions are relations.
Answer: Bluff
Four Ways to represent a FUNCTION
Sets of Ordered Pairs
Table of Values
Graphs
Equation
Which of the following sets of ordered pairs are functions?
Answer: The sets in a and b are functions.
Multiple Choice
a. h = {(0,0),(1,1),(2,2),(3,3),(4,4),...}
d. H = {(0,0),(0,1),(2,2),(3,3),(4,4),...}
b. g = {(0,0),(1,0),(2,0),(3,0),(4,0),...}
c. f = {(-2,0),(-2,1),(-2,2),(-2,3),(-2,4),...}
Which of the following tables below represent a
function?
x 0 1 2 3
y 0 1 2 3
x 1 1 1 1
y -4 -2 0 2
x -1 0 1 2
y 2 2 2 2
x 2 4 2 4
y -2 0 2 6
Answer: A and C
A
B
C
D
Which of the following graphs can be graphs of
functions?
Answer: a, b and c
Which of the following equations represent a
function?
Answer: a, c and d
𝒃. π’™πŸ
+ π’šπŸ
= 𝟏 d. π’š = πŸπŸŽπŸŽπ’™
𝒂. π’š = πŸπ’™πŸ βˆ’ πŸπ’™ + 𝟐 c. π’š = πŸπ’™ + 𝟏
Evaluating a function means replacing the variable x in the function
with a given number or expression.
For example, evaluate the function 𝑓 π‘₯ = 2π‘₯ + 4 π‘“π‘œπ‘Ÿ π‘₯ = 5.
Just replace the variable β€œx” with β€œ5”:
𝑓 5 = 2 5 + 4 = 14
Answer: f(5)=14
Evaluating Functions
The function f is define on the real numbers by
𝑓 π‘₯ = 2 + π‘₯ βˆ’ π‘₯2
. What is the value of 𝑓 βˆ’3 ?
Solution:
𝑓 π‘₯ = 2 + π‘₯ βˆ’ π‘₯2, 𝑓 βˆ’3 =?
𝑓 βˆ’3 = 2 + (βˆ’3) βˆ’ (βˆ’3)2 substitute x with -3
𝑓 βˆ’3 = 2 + βˆ’3 βˆ’ 9 simplify (βˆ’32)
𝑓 βˆ’3 = βˆ’10
The value of 𝑓 βˆ’3 is βˆ’ 10.
The function 𝑔 is define on the real numbers by
g π‘₯ = (π‘₯2
+ 1)(3π‘₯ βˆ’ 5). What is the value of g 4 ?
Solution:
g π‘₯ = (π‘₯2 + 1)(3π‘₯ βˆ’ 5), g 4 =?
g 4 = 42 + 1 [3(4) βˆ’ 5], substitute x with 4
g 4 = (16 + 1)(12 βˆ’ 5), simplify 42 , multiply 3(4)
g 4 = (17)(7), add (16 + 1), subtract (12 - 5)
g 4 = 119
The value of 𝑔 4 is 119.
Quiz
Evaluate the following functions at π‘₯ = 2.
1. 𝑓 π‘₯ = 2π‘₯ + 1
2. π‘ž π‘₯ = π‘₯2 βˆ’ 2π‘₯ + 2
3. 𝑔 π‘₯ = π‘₯ + 7
4. π‘Ÿ π‘₯ =
6π‘₯βˆ’2
π‘₯+3
5. π‘Ÿ π‘₯ = 4π‘₯ βˆ’ 1
Answer:
1. 𝑓 2 = 2π‘₯ + 1= 2(2)+1 = 4 + 1 = 5
2. π‘ž 2 = π‘₯2
βˆ’ 2π‘₯ + 2 = 22
βˆ’ 2 2 + 2 = 4 βˆ’ 4 + 2 = 2
3. 𝑔 2 = π‘₯ + 7 = 2 + 7 = 9 = Β±3
4. π‘Ÿ 2 =
6π‘₯βˆ’2
π‘₯+3
=
6 2 βˆ’2
2+3
=
12βˆ’2
5
=
10
5
= 2
5. π‘Ÿ π‘₯ = 4π‘₯ βˆ’ 1 = 42 βˆ’ 1 = 16 βˆ’ 1 = 15

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How to evaluate functions in four steps

  • 2. EVALUATING FUNCTIONS General Math Week 1, LC Code: (M11GM - Ia – 1)
  • 3. Learning Competency The learner evaluates a function. (M11GM - Ia – 1)
  • 4. Learning Objectives At the end of this video, you are able to: 1. Recall the difference between function and relation; 2. Recall on the four ways to represent a function; and 3. Evaluate a function.
  • 5. What is the difference between function and relation? Function β€’ A function is a relation that is for each input there is only one output. β€’ A function is a set of ordered pairs (x,y) such that no two ordered pairs have the same x-element (abscissa). β€’ A function can be a one-to-one or many-to-one correspondence but can not be a one-to-many correspondence. Relation β€’ A relation is a set of inputs and outputs. β€’ A relation is a set of ordered pairs (x,y). β€’ A relation can be one-to-one, one-to- many and/or many-to-one correspondence.
  • 6. Fact or Bluff 1. All functions are relations. Answer: Fact 2. All relations are functions. Answer: Bluff 3. A function is a set of ordered pairs (x,y) such that no two ordered pairs have the same y-element. Answer: Bluff 4. A student with a unique identification number is an example of a function. Answer: Fact 5. Not all functions are relations. Answer: Bluff
  • 7. Four Ways to represent a FUNCTION Sets of Ordered Pairs Table of Values Graphs Equation
  • 8. Which of the following sets of ordered pairs are functions? Answer: The sets in a and b are functions. Multiple Choice a. h = {(0,0),(1,1),(2,2),(3,3),(4,4),...} d. H = {(0,0),(0,1),(2,2),(3,3),(4,4),...} b. g = {(0,0),(1,0),(2,0),(3,0),(4,0),...} c. f = {(-2,0),(-2,1),(-2,2),(-2,3),(-2,4),...}
  • 9. Which of the following tables below represent a function? x 0 1 2 3 y 0 1 2 3 x 1 1 1 1 y -4 -2 0 2 x -1 0 1 2 y 2 2 2 2 x 2 4 2 4 y -2 0 2 6 Answer: A and C A B C D
  • 10. Which of the following graphs can be graphs of functions? Answer: a, b and c
  • 11. Which of the following equations represent a function? Answer: a, c and d 𝒃. π’™πŸ + π’šπŸ = 𝟏 d. π’š = πŸπŸŽπŸŽπ’™ 𝒂. π’š = πŸπ’™πŸ βˆ’ πŸπ’™ + 𝟐 c. π’š = πŸπ’™ + 𝟏
  • 12. Evaluating a function means replacing the variable x in the function with a given number or expression. For example, evaluate the function 𝑓 π‘₯ = 2π‘₯ + 4 π‘“π‘œπ‘Ÿ π‘₯ = 5. Just replace the variable β€œx” with β€œ5”: 𝑓 5 = 2 5 + 4 = 14 Answer: f(5)=14 Evaluating Functions
  • 13. The function f is define on the real numbers by 𝑓 π‘₯ = 2 + π‘₯ βˆ’ π‘₯2 . What is the value of 𝑓 βˆ’3 ? Solution: 𝑓 π‘₯ = 2 + π‘₯ βˆ’ π‘₯2, 𝑓 βˆ’3 =? 𝑓 βˆ’3 = 2 + (βˆ’3) βˆ’ (βˆ’3)2 substitute x with -3 𝑓 βˆ’3 = 2 + βˆ’3 βˆ’ 9 simplify (βˆ’32) 𝑓 βˆ’3 = βˆ’10 The value of 𝑓 βˆ’3 is βˆ’ 10.
  • 14. The function 𝑔 is define on the real numbers by g π‘₯ = (π‘₯2 + 1)(3π‘₯ βˆ’ 5). What is the value of g 4 ? Solution: g π‘₯ = (π‘₯2 + 1)(3π‘₯ βˆ’ 5), g 4 =? g 4 = 42 + 1 [3(4) βˆ’ 5], substitute x with 4 g 4 = (16 + 1)(12 βˆ’ 5), simplify 42 , multiply 3(4) g 4 = (17)(7), add (16 + 1), subtract (12 - 5) g 4 = 119 The value of 𝑔 4 is 119.
  • 15. Quiz Evaluate the following functions at π‘₯ = 2. 1. 𝑓 π‘₯ = 2π‘₯ + 1 2. π‘ž π‘₯ = π‘₯2 βˆ’ 2π‘₯ + 2 3. 𝑔 π‘₯ = π‘₯ + 7 4. π‘Ÿ π‘₯ = 6π‘₯βˆ’2 π‘₯+3 5. π‘Ÿ π‘₯ = 4π‘₯ βˆ’ 1 Answer: 1. 𝑓 2 = 2π‘₯ + 1= 2(2)+1 = 4 + 1 = 5 2. π‘ž 2 = π‘₯2 βˆ’ 2π‘₯ + 2 = 22 βˆ’ 2 2 + 2 = 4 βˆ’ 4 + 2 = 2 3. 𝑔 2 = π‘₯ + 7 = 2 + 7 = 9 = Β±3 4. π‘Ÿ 2 = 6π‘₯βˆ’2 π‘₯+3 = 6 2 βˆ’2 2+3 = 12βˆ’2 5 = 10 5 = 2 5. π‘Ÿ π‘₯ = 4π‘₯ βˆ’ 1 = 42 βˆ’ 1 = 16 βˆ’ 1 = 15