This document discusses analyzing a hauled container collection system. It defines key terms like pickup time (Phcs), haul time (h), and at-site time (s). The total time per trip (Thcs) is calculated as the sum of Phcs, s, and h. An example problem is worked through to determine the pickup time, time per trip, number of trips per day, and actual workday length for a given hauled container collection system scenario.

1. Analyzing a hauled
container collection
system

2. Pickup (Phcs)
Phcs is the time spent in
 driving to the next container after an empty container has been
deposited.
 the time spent pickup the loaded container.
 the time required to redeposit the container after it has been emptied.
Pscs: Refers to the time spent loading the vehicle, beginning with the
stop to load the first container and ending when the last container has
been loaded.
Analysis of Collection Systems

3. Haul (h)
Does not include actually picking up the loaded container or
redepositing the empty container nor the time spent at the
location where the waste is unloaded.
HCS- The time required to reach the location where the waste
will be emptied, starting when the container has been loaded on
the truck and continuing through unloading until the truck
arrives at the location where the empty container is to be
redeposited.

4. At-Site (s)
The time spent at the site (landfill, MRF, transfer station)
where the system is unloaded including waiting time.
Off-Route (W)
Non-productive activities
- Necessary - Check in, check out, meeting, breaks.
- Unnecessary - Personal errands, extended coffee breaks

5. Hauled Container System
The time required per trip , is sum of pick-up , at-site and haul times , given by the following
equation
Thcs = (Phcs + s + h) (eqn 11.1)
The haul time may be expressed as:
h = a + bx (Table 11.7)
And is essentially a function of the distance traveled.
Where ,
Phcs = pick up time per trip for hauled container system
s = at-site time per trip , h/trip
a and b = emperical haul const. h/km
x = round trip haul distance , km/trip

6. The pickup time is the sum required to pickup the container, to unload the
container and drive between containers (p+u+d).
Phcs = pc + uc + dbc (eqn 11.2 )
Where,
pc = Time required to pick up loaded container, h/trip
uc = Time required to unload empty container , h/trip
dbc = average time spent driving between container locations , h/trip
Pick up time

7. Number of trips per day
The number of trips that can be made per vehicle per day with a hauled container system
including a factor to account for off-route activities is determined using eqn.
Nd = [ (1-W)H - (t1-t2) ] / ( Phcs + s + a + bx )
(eqn 11.3 )
Where,
W = off-route factor
H = length of workday, h/d
T1 = time from garage to first container location, h
T2 = time from last container location to garage, h

9. Example 11-1 : Analysing a hauled container collection system

10. Solution :
Part 1. Determine the Pick-up time :
Phcs = pc + uc + dbc (eqn 11.2 )
pc + uc = 0.4 h/trip ( Table 11.8 )
dbc = 0.1 h/trip
=>
phcs = 0.4 + 0.1
= 0.5 h/trip

11. Part 2. Determine the time per trip
Thcs = (Phcs + s + a + bx) (eqn 11.1)
Phcs = 0.5h/trip
s = 0.133 ( Table 11-8 )
a = 0.016 ( Table 11-7 )
b = 0.011 ( Table 11-7 )
=>
thcs = [0.5 + 0.133 + 0.016 + 0.011 (50) ]
= 1.20 h/trip

12. Part 3. Determine the number of trips per day
Nd = [(1 – W)H – (t1 + t2)]/(Phcs + s + a + bx)
(eqn 11.3 )
W = 0.15 ( Assumed )
H = 8 ( given )
t1 = 0.25 h ( given )
t2 = 0.33 h ( given )
=>
Nd = [ ( 1 – 0.15 ) 8 – ( 0.25 + 0.33 ) ] /1.20 h/trip
= (6.8 – 0.58)/1.20
= 5.18trips/d
Nd = 5 trips/d

13. Part 4 . Determine the actual length of the
workday
5 trips = (1 – 0.15)H - 0.58 / 1.2
H = [ (5 * 1.2) + 0.58] / 0.85
= 7.74 h

14. Thankyou