The document summarizes key information about an elliptical orbit: 1) A planet travels in an elliptical orbit around the sun, with a minimum distance of 50,000km and one focal point located 20,000km from the center. 2) The length of the minor axis is 100,000km and the major axis is calculated to be 53851.6481km using the Pythagorean theorem. 3) The standard equation x2/a2 + y2/b2 = 1 is used to represent the ellipse, with a being the semi-major axis and b the semi-minor axis.

1. ELLIPSE
Source: http://www.librarising.com/space/images/darkstar.jpg

2. A planet travels on an elliptical orbit and the sun as
its centre has a minimum distance of 50000km.
(one focus has a distance of 20000km from the
center)
(-@ origin)
(horizontal)
Identify the length of the major and minor axis foci
and vertices. Find the equation of the ellipse.
Sketch the ellipse.

3. Length of the minor axis
Semi minor =50000km minor axis
(2)50000km = 100000km
(c) or the
semi major
Length of the major axis axis
Semi minor(a) = 50000km
Focus(b) =20000km
c2 = a2+b2
c= (a2+b2)
*Semi major axis is equal
C= (500002 + 200002) to the (c) and using the
Pythagorean
C = 53851.6481 Theorem, we can solve
for it.

4. x + y = 1 *Because our ellipse is in the
origin, we will just use this
a2 b2 formula.
We ,then input the values of the
x + y = 1 semi minor and major axis.
2.5 x 109 2.9 x 109

5. Semi minor axis
Graph at the origin
Semi major axis
Focal distance