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ELECTRICITY
LEARNING OBJECTIVE ,[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],Negative charge Positive charge No charge / Neutral -1.6 × 10 -19  C +1.6 × 10 -19  C
Electric charge, Q ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Q = ne e = charged for 1 electron ( -1.6 ×10 -19  C) n = no.of electron
Electric current, I ,[object Object],[object Object],t = time (seconds)
Relationship between electron flow and electric current ,[object Object]
 
Exercise 1  ,[object Object],[object Object],[object Object],Exercise 2  Electric charges flow through a light bulb at the rate of 20 C every 50 seconds.  What is the electric current shown on the ammeter? Exercise 3  When lightning strikes between two charged clouds, an electric current of 400 A flows for 0.05 s.  What is the quantity of charge transferred? 3600 C 2.25×10 22 0.4 A 20 C
Electric Field ,[object Object],[object Object],[object Object],[object Object],[object Object]
 
+ - + + - - - + + + + + + - a) d) c) b) e) f) h)
1.2  Analysing the relationship between electric current and potential difference.
Potential difference, V ,[object Object],[object Object],[object Object],[object Object],OR
What is 1 volt? ,[object Object],[object Object]
Exercises 1  ,[object Object],Exercises 2  If 72 J of work has to be done to carry 6 C of charge across two parallel metal plates, what is the potential difference across the metal plates? 240 J 12 V
Relationship between current and potential difference ,[object Object],[object Object]
Ohm’s Law ,[object Object]
Ohmic conductor and non-ohmic conductor ,[object Object],[object Object],Non-Ohmic conductor Ohmic conductor
Resistance, R ,[object Object],[object Object],[object Object]
Disadvantage of resistance ,[object Object],Advantage of resistance ,[object Object],[object Object],[object Object]
Factors affecting resistance ,[object Object],[object Object],[object Object],[object Object]
a) Length of wire ,[object Object],[object Object],b) Cross-sectional area of wire ,[object Object]
c) Temperature ,[object Object],d) Type of wire ,[object Object]
Superconductor ,[object Object]
 
1.3  Analysing Series and Parallel circuit.
SERIES CIRCUIT PARALLEL CIRCUIT I 1  = I 2  = I 3   I = I 1  +I 2  + I 3 V = V 1  + V 2  + V 3 V = V 1  = V 2  =V 3 R = R 1  + R 2  + R 3 1/R = 1/R 1  + 1/R 2 + 1/R 3
Compare the brightness
SERIES CIRCUIT PARALLEL CIRCUIT The brightness of each bulb is equally the same. Brightness of each bulb is greater If one bulb blow out, the circuit is broken. V = V 1  = V 2  =V 3 R = R 1  + R 2  + R 3 1/R = 1/R 1  + 1/R 2 + 1/R 3
Electromotive force (e.m.f), E ,[object Object],[object Object],What does the label 1.5 V  on the battery mean? ,[object Object],[object Object]
Compare e.m.f. and potential difference
Electromotive force, E Potential difference, V Indicates the  electrical energy  given to  1 C of charge flowing through the cell or source . Indicates the  electrical energy  that is  transformed to other forms of energy  when  1 C of charge  passes between  two point  in a circuit. Represented by the voltmeter reading in an open circuit (when switch is opened) Represented by the voltmeter reading in a closed circuit (when switch is closed) Measured in JC -1  or Volts,V Measured in JC -1  or Volts,V Formula   E = I (R + r) (R+r) = total external resistance and total internal resistance Formula V = IR R = Total external resistance
Internal resistance, r ,[object Object]
How to measure internal resistance? ,[object Object],[object Object]
Graph V against I ,[object Object],[object Object],[object Object],[object Object],[object Object],V /V I /A E - V E V I
Exercises  ,[object Object],[object Object],[object Object],[object Object]
Exercises  ,[object Object],[object Object],[object Object],[object Object],[object Object]
Exercises  ,[object Object],[object Object],[object Object]
Comparison between total e.m.f and total internal resistance in a series and parallel circuit ,[object Object],E 1 E 2 E 1 E 2 E = E 1  + E 2 Total e.m.f = 2 x 1.5 = 3.0 V E = E 1  = E 2 Total e.m.f = 1.5 V r =  r 1  +  r 2   Total r = 2 x 0.5 = 1.0 Ω 1/r = 1/ r 1  + 1/ r 2 Total 1/r = 1/0.5 + 1/0.5  r = 0.25 Ω
These appliances are labeled with values such as 240 V 60 W..What do these labels mean?
Electrical energy  and  Electrical Power
E /J V/ V Q /C E /J P/W t/s Electrical energy, E Electrical power, P defined as the ability of the electric current to do work. defined as the rate of energy dissipated or transferred Since  V = E/Q Q =It V = IR Since  P = E/t  E = VIt V = IR Then ,  E = VIt Then,  P = VI and  E = I 2 Rt and  P = I 2 R P =  V 2 R
Exercise  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Power rating and Energy Consumption of Electrical Appliances ,[object Object],[object Object],[object Object],E :unit Joule P :unit Watt T :unit seconds
[object Object],[object Object]
How to calculate the cost of electrical energy? ,[object Object],Example   An appliance with a power of 2 kW is used for 10 minutes, three times a day. If the cost of electricity is 25 cents per unit, what is the cost of operating the appliance in the month of April?  [RM 7.50]
Efficient Use of Electrical Energy ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Exercise  ,[object Object]

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Chapter1: Electricity

  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.  
  • 8.
  • 9.
  • 10.  
  • 11. + - + + - - - + + + + + + - a) d) c) b) e) f) h)
  • 12. 1.2 Analysing the relationship between electric current and potential difference.
  • 13.
  • 14.
  • 15.
  • 16.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 22.
  • 23.
  • 24.
  • 25.  
  • 26. 1.3 Analysing Series and Parallel circuit.
  • 27. SERIES CIRCUIT PARALLEL CIRCUIT I 1 = I 2 = I 3 I = I 1 +I 2 + I 3 V = V 1 + V 2 + V 3 V = V 1 = V 2 =V 3 R = R 1 + R 2 + R 3 1/R = 1/R 1 + 1/R 2 + 1/R 3
  • 29. SERIES CIRCUIT PARALLEL CIRCUIT The brightness of each bulb is equally the same. Brightness of each bulb is greater If one bulb blow out, the circuit is broken. V = V 1 = V 2 =V 3 R = R 1 + R 2 + R 3 1/R = 1/R 1 + 1/R 2 + 1/R 3
  • 30.
  • 31. Compare e.m.f. and potential difference
  • 32. Electromotive force, E Potential difference, V Indicates the electrical energy given to 1 C of charge flowing through the cell or source . Indicates the electrical energy that is transformed to other forms of energy when 1 C of charge passes between two point in a circuit. Represented by the voltmeter reading in an open circuit (when switch is opened) Represented by the voltmeter reading in a closed circuit (when switch is closed) Measured in JC -1 or Volts,V Measured in JC -1 or Volts,V Formula E = I (R + r) (R+r) = total external resistance and total internal resistance Formula V = IR R = Total external resistance
  • 33.
  • 34.
  • 35.
  • 36.
  • 37.
  • 38.
  • 39.
  • 40. These appliances are labeled with values such as 240 V 60 W..What do these labels mean?
  • 41. Electrical energy and Electrical Power
  • 42. E /J V/ V Q /C E /J P/W t/s Electrical energy, E Electrical power, P defined as the ability of the electric current to do work. defined as the rate of energy dissipated or transferred Since V = E/Q Q =It V = IR Since P = E/t E = VIt V = IR Then , E = VIt Then, P = VI and E = I 2 Rt and P = I 2 R P = V 2 R
  • 43.
  • 44.
  • 45.
  • 46.
  • 47.
  • 48.