BBMP 1103
   Mathematic Management
Exam Preparation Workshop Sept 2011
    Part 6 - Partial Differentiation

       Presented By: Dr Richard Ng

              26 Nov 2011
                2ptg – 4ptg
6. Focus on Partial Differentiation

     Question: 14 (May 2010)

     Solve the following questions using partial differentiation:
     a) Given a function f ( x, y)         5x 3 4 x 2 y 3 3 y 2


         Find i) f x ( x, y )         iv) f yy ( x, y)

                   ii) f y ( x, y )   v) f yx ( x, y)

                  iii) f xx ( x, y)   vi) f xy ( x, y)



Prepared by Dr Richard Ng (2011)                                    Page 2
Suggested Answers:

  f ( x, y)           5x 3 4 x 2 y 3   3y 2

           i) f x         15x 2 (4 y 3 )[2 x]
                          15x 2 8xy3

           ii) f y       ( 4x 2 )[3 y 2 ] 6 y
                          12x 2 y 2 6 y

           iii) f x       15x 2 8xy 3
               f xx       30x (8 y 3 )[1]

               f xx       30x 8 y 3

Prepared by Dr Richard Ng (2011)                Page 3
iv)        fy        12x 2 y 2 6 y

                   f yy     ( 12x 2 )[2 y] 6

                   f yy       24x 2 y 6


         v)          fy        12x 2 y 2 6 y

                   f yx     ( 12y 2 )[2x]

                   f yx       24xy 2



Prepared by Dr Richard Ng (2011)               Page 4
vi)       fx        15x 2 8xy 3

                  f xy     ( 8x)[3 y 2 ]

                  f xy       24xy 2




Prepared by Dr Richard Ng (2011)           Page 5
End of
Part 6

BBMP1103 - Sept 2011 exam workshop - part 6

  • 1.
    BBMP 1103 Mathematic Management Exam Preparation Workshop Sept 2011 Part 6 - Partial Differentiation Presented By: Dr Richard Ng 26 Nov 2011 2ptg – 4ptg
  • 2.
    6. Focus onPartial Differentiation Question: 14 (May 2010) Solve the following questions using partial differentiation: a) Given a function f ( x, y) 5x 3 4 x 2 y 3 3 y 2 Find i) f x ( x, y ) iv) f yy ( x, y) ii) f y ( x, y ) v) f yx ( x, y) iii) f xx ( x, y) vi) f xy ( x, y) Prepared by Dr Richard Ng (2011) Page 2
  • 3.
    Suggested Answers: f ( x, y) 5x 3 4 x 2 y 3 3y 2 i) f x 15x 2 (4 y 3 )[2 x] 15x 2 8xy3 ii) f y ( 4x 2 )[3 y 2 ] 6 y 12x 2 y 2 6 y iii) f x 15x 2 8xy 3 f xx 30x (8 y 3 )[1] f xx 30x 8 y 3 Prepared by Dr Richard Ng (2011) Page 3
  • 4.
    iv) fy 12x 2 y 2 6 y f yy ( 12x 2 )[2 y] 6 f yy 24x 2 y 6 v) fy 12x 2 y 2 6 y f yx ( 12y 2 )[2x] f yx 24xy 2 Prepared by Dr Richard Ng (2011) Page 4
  • 5.
    vi) fx 15x 2 8xy 3 f xy ( 8x)[3 y 2 ] f xy 24xy 2 Prepared by Dr Richard Ng (2011) Page 5
  • 6.