Analyze the circuit below using an ideal diode + voltage source model, where Vf=0.7V. Consider all statements below and select all that are correct. a. If V1=2V and V2=2V, then the diode is OFF. b. If V1 is a ramp, V1=tV where t corresponds to time, and V2=0V, then the diode first turns on at t=0.7sec. c. If V1=0.5V and V2=0V, then the diode is ON. d. If V1=10V and V2=9V, then the diode is OFF. e. If V1 is a ramp, V1=2tV where t is in seconds, and V2=0V, then the diode first turns on at t=0.7sec. f. If V1=4V and V2=2V, then the diode is ON. Analyze the circuit below using an ideal diode + voltage source model, where Vf=0.7V. Consider all statements below and select all that are correct. a. If V1=2V and V2=2V, then the diode is OFF. b. If V1 is a ramp, V1=tV where t corresponds to time, and V2=0V, then the diode first turns on at t=0.7sec. c. If V1=0.5V and V2=0V, then the diode is ON. d. If V1=10V and V2=9V, then the diode is OFF. e. If V1 is a ramp, V1=2tV where t is in seconds, and V2=0V, then the diode first turns on at t=0.7sec. f. If V1=4V and V2=2V, then the diode is ON. Solution For the above circuit to turn on Diode the main condition is V1>(V2+diode voltage) V1>(V2+0.7) if the above condition satified then it is in ON position , so by checking this condition for the given options , the following are the correct :- a. If V1=2V and V2=2V, then the diode is OFF. since the requires 2.7 volts to turn ON at this positon but given input is 2V e. If V1 is a ramp, V1=2tV where t is in seconds, and V2=0V, then the diode first turns on at t=0.7sec. since V1=2t for t=0.7 V1=2X0.7=1.4V to turn on doide the V1>V2+0.7V V1>0+0.7 V1>0.7V f. If V1=4V and V2=2V, then the diode is ON. .