4. device that stores
electric potential
energy and electric
charge
Two conductors
separated by an
insulator form a
capacitor.
The net charge on a
capacitor is zero.
To charge a capacitor,
wires are connected to
the opposite sides of a
battery.
This gives a fixed
potential difference Vab
= voltage of battery.
CAPACITANCE:
constant equal to the
ratio of the charge on
each conductor to the
potential difference
between them
𝑪 =
𝑸
𝑽𝒂𝒃
CAPACITANCE:
Units: 1 Farad (F)
= Q/V = C2/J = C2/Nm
5. PARALLEL PLATE
CAPACITOR:
Uniform electric field
between the plates,
charge uniformly
distributed over
opposite surfaces
𝐸 =
𝑄
𝜀0𝐴
𝑉𝑎𝑏 = 𝐸 ∗ 𝑑 =
1
𝜀0
𝑄𝑑
𝐴
C=
𝑄
𝑉𝑎𝑏
= 𝜀0
𝐴
𝑑
8. Consider a parallel-plate capacitor that is about the
size of your fingernail. The plates are squares with
edges of length L = 1.0 cm, separated by d=10𝜇m,
which is about the diameter of human air. a.) Find the
capacitance.
b.) If the potential across the capacitor is ∆V = 12 V,
what is the energy stored?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵 𝑼𝑵𝑲𝑵𝑶𝑾𝑵
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵 𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹
9. Consider a parallel-plate capacitor that is about the size of your fingernail. The plates are squares
with edges of length L = 1.0 cm, separated by d=10𝜇m, which is about the diameter of human air.
a.) Find the capacitance.
b.) If the potential across the capacitor is ∆V = 12 V, what is the energy stored?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵
L = 1.0 cm or 0.010 m
d = 10 𝜇m or 10 x 10-5 m
𝜀0 = 8.85 𝑥 10 − 12 C2/Nm2
UNKNOWN
C
10. Consider a parallel-plate capacitor that is about the size of your fingernail. The plates are squares
with edges of length L = 1.0 cm, separated by d=10𝜇m, which is about the diameter of human air.
a.) Find the capacitance.
b.) If the potential across the capacitor is ∆V = 12 V, what is the energy stored?
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵
𝐶 = 𝜀0
𝐴
𝑑
= 𝜀0
𝐿2
𝑑
C =
(8.85 𝑥
10−12𝐶2
𝑁𝑚2 )(0.010𝑚)2
(1.0𝑥10−5𝑚)
C = 8.9 x 10-11 F
𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹
11. Consider a parallel-plate capacitor that is about the size of your fingernail. The plates are squares
with edges of length L = 1.0 cm, separated by d=10𝜇m, which is about the diameter of human air.
a.) Find the capacitance.
b.) If the potential across the capacitor is ∆V = 12 V, what is the energy stored?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵
C = 8.9 X 10-11 F
∆V = 12 V
UNKNOWN
PEcap
12. Consider a parallel-plate capacitor that is about the size of your fingernail. The plates are squares
with edges of length L = 1.0 cm, separated by d=10𝜇m, which is about the diameter of human air.
a.) Find the capacitance.
b.) If the potential across the capacitor is ∆V = 12 V, what is the energy stored?
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵
𝑃𝐸𝑐𝑎𝑝 =
1
2
𝐶(∆𝑉)2
𝑃𝐸𝑐𝑎𝑝 =
1
2
(8.9𝑥10−11
)(12𝑉)2
PEcap = 6.4 x 10-9
J
𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹
13. Modern computer memories use parallel-plate capacitors to store
information, and these capacitors are the basic elements of a random-
access memory (RAM) chip. Assume one of these capacitors has
plates with area L x L, where L = 1.0 x 10-7m, and a plate separation
d = 10 nm.
a.) Find the capacitance of such a capacitor.
b.) Calculate the amount of charge that must be placed onto the
plates to obtain a potential difference of 5.0 V across them.
c.) How many electrons does this charge correspond to?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵 𝑼𝑵𝑲𝑵𝑶𝑾𝑵
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵 𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹
14. Four capacitors are connected. If all have the same capacitance
(C1=C2=C3=C4=C), what is the equivalent capacitance of this
combination?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵 𝑼𝑵𝑲𝑵𝑶𝑾𝑵
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵 𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹
C1
C2
C3
C4
C12=2C C34=2C
Cequiv=C
15. 1. A voltage of 12 V is placed on a capacitor with C = 100 pF.
a.) What is the charge on the capacitor?
b.) How much energy is stored in the capacitor?
2. Two capacitors with C1=1.5𝜇F are connected in parallel. If the combined
charge on both capacitors is 25 𝜇F, what is the voltage across the capacitor?
3. A parallel-plate capacitor has square plates of edge length 1.0 cm and a plate
spacing of 0.10 mm. If the gap between the plates is filled with mica, what is the
capacitance?
𝑺𝑲𝑬𝑻𝑪𝑯 𝑮𝑰𝑽𝑬𝑵 𝑼𝑵𝑲𝑵𝑶𝑾𝑵
𝑺𝑶𝑳𝑼𝑻𝑰𝑶𝑵 𝑭𝑰𝑵𝑨𝑳 𝑨𝑵𝑺𝑾𝑬𝑹